Java.security.AccessControlException while trying to run the server app

ok, pretty new with java and rmi, so I wanted to run the application from the sun rmi tutorial
http://java.sun.com/docs/books/tutorial/rmi/TOC.html.
It all builds ok, i run the rmiregistry ,but when i try to run the server i get :
java.security.AccessControlException: access denied (java.net.SocketPermission 127.0.0.1:1099 connect,resolve)
     at java.security.AccessControlContext.checkPermission(AccessControlContext.java:323)
     at java.security.AccessController.checkPermission(AccessController.java:546)
     at java.lang.SecurityManager.checkPermission(SecurityManager.java:532)
     at java.lang.SecurityManager.checkConnect(SecurityManager.java:1034)
     at java.net.Socket.connect(Socket.java:513)
     at java.net.Socket.connect(Socket.java:469)
     at java.net.Socket.<init>(Socket.java:366)
     at java.net.Socket.<init>(Socket.java:180)
     at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirectSocketFactory.java:22)
     at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMasterSocketFactory.java:128)
     at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:595)
     at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:198)
     at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:184)
     at sun.rmi.server.UnicastRef.newCall(UnicastRef.java:322)
     at sun.rmi.registry.RegistryImpl_Stub.rebind(Unknown Source)
     at engine.ComputeEngine.main(ComputeEngine.java:30)
what i noticed is that this output is similar to not running rmiregistry at all, so i guess the problem is with the way i'm running rmiregistry
thx in advance

You're running the server with a SecurityManager. There's no need to do that at first. Get rid of it. When you have it working, write yourself a .policy file that grants that permission, and any others you discover it needs, and name that as your security policy file, e.g.
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