Javadoc --giving link to other classes
Hi.
I am trying to generate javadoc for my application..But When I see the docs.It doesnt have the links for String and other used classes.
What should I do to give the links
Thanks in advance,
A.
Umar
Use the -link or -linkoffline option:
http://java.sun.com/j2se/1.4.1/docs/tooldocs/solaris/javadoc.html#link
For example:
javadoc -link http://java.sun.com/j2se/1.4/docs/api com.mypackage
-Doug Kramer
Javadoc team
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I created a Java class diagram in a certain package (e.g. com.mycompany.p1) and placed some classes on this diagram from the same package and from other packages. Then I created JavaDocs. When I click on the classes in the created JavaDoc diagram, only the links of the classes in the same package as the diagram (com.mycompany.p1) wor correctly. When I click on a class outside this package I get an error message that the file is not found. It looks for the class documentation in the package of the diagram and this is obviousely wrong!
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I don't use the diagrammers much, so I cannot comment on this directly; however, based on your description, it does sound like a defect. Do you have access to Oracle Support to file an SR?
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I have successfully loaded Class A (that has no references to other class) in Oracle DB using SQL Developer.
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Well I've got a class for running a text based interface for a simple queue system. All I need to do is link it to the GUI i have designed. Below is the code for both. Anyone that can give me code to link the classes between them (I'm going to change the uuInOut statements to .getText() where relevant).
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import uuInOut;
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QueueNode end;
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QueueNode temp = new QueueNode();
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System.out.println("Error there are no documents in the queue.");
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do
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temp.next = after;
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Here's the code for the GUI (there seems to be a problem with it which I cant seem to figure out)
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import Queue.*;
import QueueNode;
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JTextField nameBox, userBox, sizeBox, numberBox, totalBox;
JButton addButton, removeButton, printButton, purgeButton, exitButton;
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super("Queue System");
setSize(350,360);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
nameLabel = new JLabel("Name:");
userLabel = new JLabel("User:");
sizeLabel = new JLabel("Size:");
numberLabel = new JLabel("No. Of Items in Queue:");
totalLabel = new JLabel("Total Size of the Queue:");
nameBox = new JTextField(15);
userBox = new JTextField(15);
sizeBox = new JTextField(5);
numberBox = new JTextField(3);
totalBox = new JTextField(15);
addButton = new JButton("Add Document");
removeButton = new JButton("Remove Document");
printButton = new JButton("Print Document");
purgeButton = new JButton("Purge the Queue");
exitButton = new JButton("Exit");
JPanel pane = new JPanel();
setContentPane(pane);
show();
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setLayout(new BoxLayout(this,BoxLayout.Y_AXIS));
contentPane.add(nameLabel);
contentPane.add(nameBox);
contentPane.add(userLabel);
contentPane.add(userBox);
contentPane.add(sizeLabel);
contentPane.add(sizeBox);
contentPane.add(numberLabel);
contentPane.add(numberBox);
contentPane.add(totalLabel);
contentPane.add(totalBox);
setLayout(new BoxLayout(this,BoxLayout.Y_AXIS));
contentPane.add(addButton);
contentPane.add(removeButton);
contentPane.add(printButton);
contentPane.add(purgeButton);
contentPane.add(exitButton);
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removeButton.setLocation(10, 100);
printButton.setLocation(20,100);
purgeButton.setLocation(30,100);
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addButton.addActionListener(this);
removeButton.addActionListener(this);
printButton.addActionListener(this);
purgeButton.addActionListener(this);
exitButton.addActionListener(this);
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System.exit(0);
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userBox.setText("");
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}It is simple and very annoying.
I think you should try to do it yourself to learn how Java works, it is a good exercise for you.
The forum is used to work together on different problems, giving tips and ideas but not coding for other people.
About your problem, two things : you should rewrite all the code (not trying to link these two classes) and you will have serious problems wityh the different setLayout you use !
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Asset Evaluation Group Link to Asset Class
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I encountered serious problem when generating data control from a revised version of our xml schema (top link classes).
We change the structure by inserting element representing a node before the element that occurs more than once.
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<xs:element name="classification-language-list">
<xs:annotation>
<xs:documentation xml:lang="fr">Liste des langues supportées par la classification</xs:documentation>
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<xs:complexType mixed="false">
<xs:sequence>
<xs:element name="classification-language" type="classification-languageType" maxOccurs="unbounded">
<xs:annotation>
<xs:documentation xml:lang="fr">Langue gerée par la classification</xs:documentation>
</xs:annotation>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
As you can see the element that represent the list is not inherited from a type. It is described locally in the schema. This mean that top link generate a class in the parent implementation class. In our case classification-language-list is defined in the interface ClassificationType.java and in the class ClassificationTypeImpl.java.
The data control xml file for Classification class is as below:
<?xml version="1.0" encoding="UTF-8" ?>
<JavaBean xmlns="http://xmlns.oracle.com/adfm/beanmodel" version="10.1.3.39.14"
id="Classification"
BeanClass="classification.toplinkInterface.Classification"
Package="classification.toplinkInterface" isJavaBased="true">
<Attribute Name="schemaVersion" Type="java.lang.String"/>
<AccessorAttribute id="classificationCategoryList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationCategoryListType"/>
<AccessorAttribute id="classificationEntryList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationEntryListType"/>
<AccessorAttribute id="classificationExternalSystemList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationExternalSystemListType"/>
<AccessorAttribute id="classificationLanguageList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationLanguageListType"/>
<AccessorAttribute id="classificationNameList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationNameListType"/>
<AccessorAttribute id="classificationVersionList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationVersionListType"/>
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The data control xml file for ClassificationLanguageListType class is as below:
<?xml version="1.0" encoding="UTF-8" ?>
<JavaBean xmlns="http://xmlns.oracle.com/adfm/beanmodel" version="10.1.3.39.14"
id="ClassificationLanguageListType"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationLanguageListType"
Package="classification.toplinkInterface.ClassificationType"
isJavaBased="true">
<Attribute Name="schemaVersion" Type="java.lang.String"/>
<AccessorAttribute id="classificationCategoryList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationCategoryListType"/>
<AccessorAttribute id="classificationEntryList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationEntryListType"/>
<AccessorAttribute id="classificationExternalSystemList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationExternalSystemListType"/>
<AccessorAttribute id="classificationLanguageList" IsCollection="false"
BeanClass="classification.toplinkInterface.ClassificationType.ClassificationLanguageListType"/>
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BeanClass="classification.toplinkInterface.ClassificationType.ClassificationNameListType"/>
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This last data control definition is completely wrong.
Here is the corresponding interface in ClassificationType.java:
public interface ClassificationLanguageListType
java.util.List<ClassificationLanguageType> getClassificationLanguage();
The type was added manually.
Here is the corresponding interface
public interface ClassificationLanguageType
public void setClassificationLanguageCode(java.lang.String value);
public java.lang.String getClassificationLanguageCode();
public void setClassificationLanguageLabel(java.lang.String value);
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It seem like a big bug ... in data control generationSolve the problem by generating a data control for the implementation class also. This will cause the data control xml file to be created for the java class also (if not only the interface will have a data control xml file generated).
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I have a movieclip in my library, that is linked to a class.
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Now when I wanted to delete my class, I would delete all
event listeners, and make sure there are no references to it. Then
I remove it from it's parent. It's a public class, so there will be
no vars to delete (right?).
Now here's the deal:
in the library, I open the movieclip, which has 10 frames,
and in frame 1, I put:
trace("still here");
now when I run the program, and delete that class instance,
not totally surprisingly, it will keep tracing "still here".
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And can I be sure the class will be deleted when the "still here"
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Help would be very much appreciated!
Edit:
I made a document of the situation :
downloadquote:
Originally posted by:
kgladi'm not sure what you mean by that.
I mean the reference: If you have a function inside a class,
and declare a var in that function, that var will not mean anything
to the class itself. It's only usable inside the function you
declare it in. That's why I don't set it to null. The reference
will disappear anyway.
example:
function Func() {
var a = "hello";
trace("a: " + a);
Func();
trace("a: " + a);
//output:
//"a: hello"
//"a: "
quote:
Originally posted by:
kgladsetting it to null after it's created is ok for
testing, but is a very poor programming technique.
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Most of the documents opened from our SharePoint libraries appear to open in a timely fashion.
But...one user has noticed an issue, and I just noticed something with her files that are a little less common than other stuff we've seen.
she has a lot of pricelist excel files. there are some master price list files, and then other files that link to fields from within the master files.
the files that contain links to other files appear to be the ones that open very slowly.
the files are being opened via excel itself, not the owa viewer or editor.
is there a trick to setting up either the library, the site, site collection or web app... or some client-side setting that affects how quickly/efficiently excel will open files that link to other excel files shared within sharepoint?Hi carphuntin_god,
According to your description, my understanding is that when you click a hyperlink which redirect to other files , the file are opened very slowly via excel client.
How about you download the same file and open it using excel client? If it is opened quite fast, the issue should be caused by some third-party add-ins in the office program or antivirus soft.
Here is a similar thread you can have a look:
http://social.technet.microsoft.com/Forums/en-US/ff0c5306-5300-4010-a760-c4cca320b6fc/excell-file-taking-long-time-to-open-and-edit?forum=officesetupdeploylegacy
http://social.technet.microsoft.com/Forums/en-US/5c746958-418a-44f6-a777-9f8bddf6dbb6/sharepoint-file-open-takes-long-time?forum=sharepointdevelopmentlegacy
If you want to open the files using excel service after click the link in the excel file, you can create the hyperlink in the following way:
General Syntax:
http://<server_name>/<site_name>/_layouts/ xlviewer.aspx?id=<workbook path>&range=<location>
For example:
http://CorpServer/DeptA89/_layouts/ xlviewer.aspx?id=http://Mfct/Stats/Shared%20Documents/Parts.xlsx&range=Widgets!A1:F25
For more information:
http://office.microsoft.com/en-001/sharepoint-server-help/using-hyperlinks-in-excel-services-HA010173679.aspx
If you want to open the files using Office Web Apps after click the link in the excel file, you can create the hyperlink in the following way:
http://<server name> / <site name> / <library name>/<your file name> ?web=1
For example:
http://sp/Shared%20Documents/exceltest.xlsx?Web=1
Best Regards,
Eric
Eric Tao
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