Javascript, string to int

Dear Sir:
I try to convert string to int in flash javascript:
temp="120";
temp2="140";
temp3=int ( temp );
but I got a message "int is not a function", can somebody tell me how to do this?
also, what if I want convert number back to string?
thanks a lot!

use:
temp="120";
temp2="140";
temp3=Number ( temp );
// to convert to a string, use:
var temp4:String=String(temp3);
// or
var temp5:String=temp3.toString();

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Hi Sergey,
I followed your methos but got the following error msg:
root cause
java.lang.IllegalStateException: Component javax.faces.component.UIViewRoot@7dcf98 not expected type. Expected: UIOutput. Perhaps you're missing a tag?
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and the declared resource bundle:
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<body onLoad="init()">
please help, Thanks !
regards,
kmthien

Please help me with my code (has conversion from string to int)

import javax.microedition.midlet.*;
import javax.microedition.lcdui.*;
public class Test3 extends MIDlet implements CommandListener
{   Form mForm;
    Command mCommandQuit;
    Command mCommandItem;
    TextField input,prime1,prime2,prime3,output;
    Display mDisplay;
    int i,j=0,k1,k2,p,q,b;
    //int [] current=new int [1000];
    String mstring,a="";
    String [] temp=new String [1000];
    public void startApp()
    {System.out.println("startApp");
     mForm=new Form("RSA Encryption");
     mCommandQuit=new Command("QUIT",Command.EXIT,0);
     mCommandItem=new Command("ENCRYPT",Command.ITEM,0);
     mForm.append("Enter text:\n");
     input=new TextField(null,"",100, TextField.ANY);
     mForm.append(input);
     mForm.append("Enter first prime number(p):\n");
     prime1=new TextField(null,"",100, TextField.ANY);
     mForm.append(prime1);
     mForm.append("Enter second prime number(q):\n");
     prime2=new TextField(null,"",100, TextField.ANY);
     mForm.append(prime2);
     mForm.append("Enter d:\n");
     prime3=new TextField(null,"",100, TextField.ANY);
     mForm.append(prime3);
     mForm.addCommand(mCommandQuit);
     mForm.addCommand(mCommandItem);
     mDisplay=Display.getDisplay(this);
     mDisplay.setCurrent(mForm);
     mForm.setCommandListener(this);
    public void pauseApp()
    {System.out.println("pauseApp");
    public void destroyApp(boolean unconditional)
    {System.out.println("destroyApp");
    public void commandAction(Command c, Displayable d)
    {System.out.println("commandAction");
     if(c==mCommandQuit)
        notifyDestroyed();
     else if(c==mCommandItem)
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         q = Integer.parseInt(prime2.getString());
         b = Integer.parseInt(prime3.getString());
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         mstring=input.getString();
         temp[0]="";
         for(i=1;i<mstring.length();i++)
            {if (mstring.charAt(i) == ' ')
                {j++;
                 temp[j]="";
             else
                {temp[j]=temp[j]+mstring.charAt(i);
         mForm.append("\n\nThe array is:\n");
         for(i=0;i<temp.length && temp!=null;i++)
{k1=Integer.parseInt(temp[i]); ***********************
k2=k1;
for(j=1;j<b;j++)
{k1=k1*k2;
k1=k1 %(p*q);
k2=k1 %(p*q);
a=a+new Character((char)k2).toString();
output=new TextField(null,a,100, TextField.ANY);
mForm.append(output);
}hi
this code basically takes an input of string like " 179 84 48 48 155 " (with spaces)
then it creates smaller strings in an array like "179","84","48","48","155" without the spaces
then it creates int values 179,84,48,48,155 and finally after some math functions it prints the corresponding letters.
the problem is that it is not printing the letter because of some exceptions-->java.lang.NumberFormatException .it comes in the line where i have put stars
could anybody please help me print the letters

thanks for all ur help guys, but me and my team member solved it on our own. here is the new code:
import javax.microedition.midlet.*;
import javax.microedition.lcdui.*;
public class Test3 extends MIDlet implements CommandListener
{   Form mForm;
    Command mCommandQuit;
    Command mCommandItem;
    TextField input,prime1,prime2,prime3,output;
    Display mDisplay;
    int i,j=0,l,k1,k2,p,q,n,b;
    String mstring,a = "";
    String [] temp=new String [1000];
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    {System.out.println("startApp");
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     mCommandItem=new Command("DECRYPT",Command.ITEM,0);
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     mForm.append(input);
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     prime1=new TextField(null,"",100, TextField.NUMERIC);
     mForm.append(prime1);
     mForm.append("Enter second prime number(q):\n");
     prime2=new TextField(null,"",100, TextField.NUMERIC);
     mForm.append(prime2);
     mForm.append("Enter d:\n");
     prime3=new TextField(null,"",100, TextField.NUMERIC);
     mForm.append(prime3);
     mForm.addCommand(mCommandQuit);
     mForm.addCommand(mCommandItem);
     mDisplay=Display.getDisplay(this);
     mDisplay.setCurrent(mForm);
     mForm.setCommandListener(this);
    public void pauseApp()
    {System.out.println("pauseApp");
    public void destroyApp(boolean unconditional)
    {System.out.println("destroyApp");
    public void commandAction(Command c, Displayable d)
    {System.out.println("commandAction");
     if(c==mCommandQuit)
        notifyDestroyed();
     else if(c==mCommandItem)
     {p = Integer.parseInt(prime1.getString());
         q = Integer.parseInt(prime2.getString());
         b = Integer.parseInt(prime3.getString());
         n=p*q;
         //breaking up of big string into ints
         mstring=input.getString();
         temp[0]="";
         for(i=1;i<mstring.length();i++)
            {if (mstring.charAt(i) == ' ')
                {j++;
                 temp[j]="";
             else
                {temp[j]=temp[j]+mstring.charAt(i);
         l=j;
         mForm.append("\n\nThe result is:\n");
         for(i=0;i<l;i++)
            {k1=Integer.valueOf(temp).intValue();
k2=k1;
for(j=1;j<b;j++)
{k2=k2*k1;
k2=k2 %n;
k1=k2 %n;
a=a+new Character((char)k1).toString();
output=new TextField(null,a,100, TextField.ANY);
mForm.append(output);

How to convert String to int in JSP?

Hi,
I set a session attribute in Servlet and want use it in JSP, How can I convert it to int or Integer?
the line in my code doesn't work:
int quantity=(int)session.getAttribute("vehiclequantity") ;
Thanks in advance.
Wolf
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++
<HTML>
<HEAD>
<TITLE>Using the for Statement</TITLE>
</HEAD>
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<H1>Using the for Statement</H1>
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<%
int loopIndex;
int quantity=(int)session.getAttribute("vehiclequantity") ;
out.println(quantity);
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Learning how to read errors and understand them will help you solve your problems quicker by yourself... So lets take a look at the error and classes involved...
The error says:
"Cannor Resolve Symbol: method valueOf(java.lang.Object) in the class java.lang.Integer" and gives you line line where the error occurs: Integer quantity = Integer.valueOf(session.getAttribute("vehiclequantity"));
Now, if we look at the API for the Integer we notice that are are only two valueOf methods: valueOf(java.lang.String s) and valueOf(java.lang.String s, int radix). Not valueOf(java.lang.Object) method.
Now we look at the getAttribute(java.lang.String name) method of HttpSession we see that the method returns a java.lang.Object. Now, you know you put a java.lang.String into that attribute, but the get method returns an Object. This is because you could have put any object in there, an Integer, a String, or some other class instance. But you know it is a String, so you can cast the returned value to a String, so that you will be calling the valueOf(java.lang.String s) method of Integer with the Object returned from the HtttpSession's getAttribute(java.lang.String name) method:
Integer quantity = Integer.valueOf((String)session.getAttribute("vehiclequantity"));

Kinda urgent please help pass strings to doubles and strings to ints

Need to know how to pass strings to doubles and strings to ints
and to check if a string is null its just if (name == null;) which means black right?
like size as a string and then make the string size a double

cupofjava666 wrote:
Need to know how to pass strings to doubles and strings to ints
and to check if a string is null its just if (name == null;) which means black right?
like size as a string and then make the string size a doubleThink he means blank.
Check the Wrapper classes (Double, Integer) in the api.
parseInt() parseDouble() both take a string and return a primitive.
String s = null;
if(s == null) should do the trick!
Regards.
Edited by: Boeing-737 on May 29, 2008 11:08 AM

Problem with String to Int conversion

Dear Friends,
Problem with String to Int conversion
I am having a column where most of the values are numeric. Only 4 values are non numeric.
I have replaces those non numeric values to numeric in order to maintain the data type.
CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END
This comes the result as down
Grade
_0_
_1_
_10_
_11_
_12_
_13_
_14_
_15_
_16_
_17_
_18_
_19_
_2_
_20_
_21_
_22_
_23_
_24_
_3_
_4_
_5_
_6_
_7_
_8_
_9_
Refresh
Now I want to convert this value to numeric and do some calculation
So I changed the formula as below
cast (CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END as INT)
Now I get the following error
View Display Error
_ Odbc driver returned an error (SQLExecDirectW)._
Error Details
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
_State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 17001] Oracle Error code: 1722, message: ORA-01722: invalid number at OCI call OCIStmtFetch. [nQSError: 17012] Bulk fetch failed. (HY000)_
SQL Issued: SELECT cast ( CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END as Int) saw0 FROM "Human Capital - Manpower Costing" WHERE LENGTH(CASE Grade.Grade WHEN 'E1' THEN '20' WHEN 'E2' THEN '21' WHEN 'E3' THEN '22' WHEN 'E4' THEN '23' ELSE Grade.Grade END) > 0 ORDER BY saw_0_
Refresh
Could anybody help me
Regards
Mustafa
Edited by: Musnet on Jun 29, 2010 5:42 AM
Edited by: Musnet on Jun 29, 2010 6:48 AM

Dear Kart,
This give me another hint, Yes you are right. There was one row which returns neither blank nor any value.
I have done the code like following and it works fine
Thanks again for your support
Regards
Code: cast (CASE (CASE WHEN Length(Grade.Grade)=0 THEN '--' ELSE Grade.Grade END) WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' when '--' then '-1' ELSE Grade.Grade END as Int)

Checking a value...String OR int

checking a value...String OR int
how to check a given value whether it is a String OR int
if(jTextField1.getText()...) is a String
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else //if it an int
     System.out.println("int");
How can i check this...
pls,tell.

getText of JTextField ALWAYS returns a String.
You can do this to see if it could be interpreted as an int:
String theText = jTextField1.getText();
try
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   System.out.println("int");
catch (NumberFormatException ex)
   System.out.println("String");
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How can i cast array of string to int ?

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                              test[count] = st.nextToken();
                              count++;
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             int questionnAireNum = 0;
             int postCode = 0;
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             int gender = 0;
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                while ( (dbRecord = dis.readLine()) != null) {
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                   gender = Integer.parseInt(rGender);
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Exception in thread "main" java.lang.NumberFormatException: For input string: " 3"
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     at java.lang.Integer.parseInt(Integer.java:447)
     at java.lang.Integer.valueOf(Integer.java:553)
     at test.main(test.java:43)

String into int & vice versa

Hi all
i cant convert the String into int although using
Integer.parseInt & vice versa
any ideas
here is the code
// fontCB & styleCB & sizeCB are ComboBoxes
String fontName,fontStyle,fontSize;
int fontStyleInt=1,fontSizeInt=1;
fontName                = (String)fontCB.getSelectedItem();
fontStyle               = (String)styleCB.getSelectedItem();
fontSize               = (String)sizeCB.getSelectedItem();
try
fontStyleInt      = Integer.parseInt(fontStyle);
fontSizeInt      = Integer.parseInt(fontSize);
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int size=Integer.parseInt(String.valueOf(sizeCB.getSelectedItem()));I think u r having plans for a text editor. right?

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Guys/Gals,
Here's an interesting problem to ponder...
I define the following values in my class:
private String descriptorClassName = null;
private String userObjectClassName = null;
private String name = null;
I run the following piece of code as part of the constructor:
descriptorClassName = this.getClass().getName();
userObjectClassName = descriptorClassName.substring(0, descriptorClassName.indexOf("Descriptor"));
name = userObjectClassName.substring(userObjectClassName.lastIndexOf(".")+1);
The first line assigns the value of "com.foo.user.UserDataDescriptor" to descriptorClassName.
The second line assigns the value of "com.foo.user.UserData" to userObjectClassName.
The third line assigns the value of "UserData" to name.
As I step through the code, I see the first two values being set, and yet the third value for name is reported by the debugger as:
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I added a call to log4j, which reports that that value of name has been correctly set!
This seems to be a result of the String.substing(int) call, as the call to Sring(substring(int, int) is fine.
Has anyone come accross this one before?
Does anyone have any workarounds other than:
name = userObjectClassName.substring(userObjectClassName.lastIndexOf(".")+1, userObjectClassName.length());
Cheers all.
Regards,
Chris.

I've been trying to reproduce this problem and it always works perfectly. The debugger tells me that name = "UserData". I'm using JDev 3.2.2 and my project is using JDK1.2.2_JDeveloper. Here's the exact source code I'm trying.
package com.foo.user;
public class UserDataDescriptor {
private String descriptorClassName = null;
private String userObjectClassName = null;
private String name = null;
public UserDataDescriptor() {
descriptorClassName = this.getClass().getName();
userObjectClassName = descriptorClassName.substring(0, descriptorClassName.indexOf("Descriptor"));
name = userObjectClassName.substring(userObjectClassName.lastIndexOf(".")+1);
System.out.println("end of constructor");
public static void main(String[] args) {
UserDataDescriptor userDataDescriptor = new UserDataDescriptor();
null

String.valueOf(int i) /   Integer.toString()

What's the difference between these methods? They seem to both do the same thing... convert an int into a string

No, they don't
static String valueOf(int i)
          Returns the string representation of the int argument.
String toString()
          Returns a String object representing this Integer's value. Perhaps you intended to compare the String.valueOf to this?
static String toString(int i)
          Returns a String object representing the specified integer. If so, then yes, they do the same thing.

Javascript, string to int

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