JbyteArray - char * and jlong - long

Hi,
I've been trying to figure out how to convert the following:
jbyteArray to a char *, void *, or something similar
jlong to a long
This is for C++ code.
I can't seem to figure it out, or find any documentation about this conversion online!!
Thanks.

Generally, avoid casting from jlong to long as the definition of long is platform dependent and not necessarily a 64 bit wide. Otherwise a regular cast works here although you may lose bits when casting to a 32-bit integer.
A byte array can be accessed through the following:
jsize len = (*env)->GetArrayLength(env, arr);
jbyte *body = (*env)->GetByteArrayElements(env, arr, 0);Casting jbyte to char should not be critical as both are most likely single-byte entities.
http://java.sun.com/docs/books/tutorial/native1.1/implementing/array.html
http://java.sun.com/docs/books/tutorial/native1.1/implementing/cpp.html

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Char and varchar

There are great differences between a char(1999) and varchar2(1999) as the CHAR is always 1999 characters long physically AND logically. the varchar is physically 1999 bytes but logically can be any size in between 0 and 1999.
What does it mean when this sentence says that char is 1999 long physically and logically ,,,,,,and varchar is 1999 long physically and logically could be between 0 and 1999 .
for char i guess it means 1999 bytes are alocatted in memory on the disk ? And all that memory is taken up !!!!
for varchar how is it interpreted ?
thanks!!!!

Hi,
I will try to explain in simpe way, if you perform and see the steps provided in the link
[http://www.orafaq.com/wiki/SQL_FAQ#What_is_the_difference_between_VARCHAR.2C_VARCHAR2_and_CHAR_data_types.3F]
then check the user_tab_columns table and check the column data_length, this displays the length of the Column by which it validates length.
Then try and see the char_test table with single "A" and check the dump of that Column as he said that spaces are padded and memory is fully filled.
When compared to Varchar the memory is dynamically filled as need (based on Updated), internally the it allocates the required memory using the realloc() function or extends the memory further (not sure about the function).
you have keed in mind that it stored the length of the data along with the Column.
When you compare with the varchar, it will not stored or will not pad the spaces in the remaing memory, so that can be utlizied by remaining blocks of data in the Row.
- Pavan Kumar N

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Difference between char and varchar, also the difference between varchar2

Hi,
Can anyone explain me the difference between char and varchar, and also the difference between varchar and varchar2...

Varchar2 is variable width character data type, so if you define column with width 20 and insert only one character to tis column only, one character will be stored in database. Char is not variable width so when you define column with width 20 and insert one character to this column it will be right padded with 19 spaces to desired length, so you will store 20 characters in the dattabase (follow the example 1). Varchar data type from Oracle 9i is automaticlly promoted to varchar2 (follow example 2)
Example 1:
SQL> create table tchar(text1 char(10), text2 varchar2(10))
2 /
Table created.
SQL> insert into tchar values('krystian','krystian')
2 /
1 row created.
SQL> select text1, length(text1), text2, length(text2)
2 from tchar
3 /
TEXT1 LENGTH(TEXT1) TEXT2 LENGTH(TEXT2)
krystian 10 krystian 8
Example 2:
create table tvarchar(text varchar(10))
SQL> select table_name,column_name,data_type
2 from user_tab_columns
3 where table_name = 'TVARCHAR'
4 /
TABLE_NAME COLUMN_NAME DATA_TYPE
TVARCHAR TEXT VARCHAR2
Best Regards
Krystian Zieja / mob

Difference between CHAR and VARCHAR2 datatype

Difference between CHAR and VARCHAR2 datatype
CHAR datatype
If you have an employee name column with size 10; ename CHAR(10) and If a column value 'JOHN' is inserted, 6 empty spaces will be inserted to the right of the value. If this was a VARCHAR column; ename VARCHAR2(10). How would it handle the column value 'JOHN' ?

The CHAR datatype stores fixed-length character strings, and Oracle compares CHAR values using blank-padded comparison semantics.
Where as the VARCHAR2 datatype stores variable-length character strings, and Oracle compares VARCHAR2 values using nonpadded comparison semantics.
This is important when comparing or joining on the columns having these datatypes;
SQL*Plus: Release 10.2.0.1.0 - Production on Pzt Au 6 09:16:45 2007
Copyright (c) 1982, 2005, Oracle. All rights reserved.
SQL> conn hr/hr
Connected.
SQL> set serveroutput on
SQL> DECLARE
2 last_name1 VARCHAR2(10) := 'TONGUC';
3 last_name2 CHAR(10) := 'TONGUC';
4 BEGIN
5 IF last_name1 = last_name2 THEN
6 DBMS_OUTPUT.PUT_LINE ( '-' || last_name1 || '- is equal to -' || last_name2
|| '-');
7 ELSE
8 DBMS_OUTPUT.PUT_LINE ( '-' || last_name1 || '- is NOT equal to -' || last_n
ame2 || '-');
9 END IF;
10 END;
11 /
-TONGUC- is NOT equal to -TONGUC -
PL/SQL procedure successfully completed.
SQL> DECLARE
2 last_name1 CHAR(6) := 'TONGUC';
3 last_name2 CHAR(10) := 'TONGUC';
4 BEGIN
5 IF last_name1 = last_name2 THEN
6 DBMS_OUTPUT.PUT_LINE ( '-' || last_name1 || '- is equal to -' || last_name2
|| '-');
7 ELSE
8 DBMS_OUTPUT.PUT_LINE ( '-' || last_name1 || '- is NOT equal to -' || last_n
ame2 || '-');
9 END IF;
10 END;
11 /
-TONGUC- is equal to -TONGUC -
PL/SQL procedure successfully completed.
Also you may want to read related asktom thread - "Char Vs Varchar" http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1542606219593
and http://tahitiviews.blogspot.com/2007/05/less-is-more-more-or-less.html
Best regards.

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The method includes if you do not have access to your original email account.
The
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Please see Kappy's User Tip here:
https://discussions.apple.com/docs/DOC-4551

I have Iphone 4 and its lock from at&t, but my contract is getting over in short time. And no longer i want to use this service. So after contract gets over its my right to get factory unlock my iphone 4. so help me

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jatpri1730 wrote:
I have Iphone 4 and its lock from at&t, but my contract is getting over in short time. And no longer i want to use this service. So after contract gets over its my right to get factory unlock my iphone 4.
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Stedman

The footer is moving to the left and no longer centered. It is like it is no longer in the container

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    <h2>Check Back Soon</h2>
</div>
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You have an extra closing </div> where none is required.
Beggining on line 215 of your code, change this:
</div>
</div>
to this:
</div>
When problems occur, the W3C code validation tools will help you find errors in your code.
Code Validation Tools
CSS - http://jigsaw.w3.org/css-validator/
HTML - http://validator.w3.org/
Nancy O.
Alt-Web Design & Publishing
Web | Graphics | Print | Media Specialists
http://alt-web.com/
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Just updated Itunes to 11.1.4.62 and no longer synchs to iphone

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SOLVED:
refer to this forum if in need: https://discussions.apple.com/message/24603547#24603547

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Try:
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Apple Retail Store - Genius Bar

JbyteArray - char * and jlong - long

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