Last Char on a line

I have a file that cat -e shows that the last char of each line is M-J.
(" Non-ASCII characters (with the high bit set) are printed as `M-' (for meta) followed by the character for the low 7 bits.)
Now, I can remove this with sed 's/.$//' but, what is char M-J, if I wanted to remove this with the actual char in sed (instead of using the wildcard ".$") ?

Glad it worked. At first I was sure the M-J was somehow really ^M so I thought it was just a DOS/Windows CRLF file, especially since the 0xCA character didn't make any sense to me. Now I see (thanx to Niel!) that the character is the non-breaking space of the MacRoman character set. Still, not a common thing to see.
BTW, this example uses a bash feature to insert the 0xCA character into the command line, so it probably won't work with other shells. If you put this line into a shell script, be sure to add
"#!/bin/bash" at the top.
Quoting special characters in the shell can be tricky and you don't show your entire command line, so I can't be sure if you had quoting around what you show. I showed the entire command, which worked for me, so I assume the difference is accounted for quoting that you didn't show.

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Read last char of a String

I have the following code that functions like a basic RPN calculator:
public class Main {
     * @param args the command line arguments
     static public ArrayList<Double> stack = new ArrayList<Double>();
     static double numberInput;
     static double answer;
     static String operation;
//Prints Welcome screen, initialized checkforInput
     public static void main(String[] args) {
         System.out.println();
         System.out.println("Welcome to RPNCalc by theCoffeeShop()");
         checkForInput();
//Checks for input, redirects to appropriate method
     public static void checkForInput() {
         Scanner reader = new Scanner(System.in);
      String input = reader.nextLine();
         if(isDouble(input) == true) {
            double number = Double.parseDouble( input );
            stack.add(0, number);
            repeat();
         } else {
            operation = input;
            operation();
//Processes numeric operations
     public static void operation () {
         if(operation.equals("+")) {
             answer = stack.get(1)+stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else if (operation.equals("-")) {
             answer = stack.get(1)-stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else if (operation.equals("*")) {
             answer = stack.get(1)*stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else if (operation.equals("/")) {
             answer = stack.get(1)/stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else {
             System.out.println("Incompatible operation");
             repeat();
//Called when ready to recheck for input
     public static void repeat() {
         checkForInput();
//Checks if string is double
     public static boolean isDouble( String input )
        try
            Double.parseDouble( input );
            return true;
        catch(Exception e)
           return false;
}To perform a basic operation (5+2), you would do the following
5
enter
2
enter
(plus)
enter
Computer prints 7.
I would like it to function like this:
5
enter
2(plus)
enter
Computer prints 7.
To do this, I have to be a be to split a string into 2 parts, the operation and the number. I think I could do this with a StringBuffer, but How to read the LAST char of a StringBuffer, instead of just a specific char? If there is a way to do it w/out a StringBuffer, I'm open to suggestions.

Hint:
The last character of a String (or StringBuilder or StringBuffer, etc.) is at the index (length_of_string - 1).
Are you sure you're supposed to solve the problem this way? Usually homework assignments of this sort involve writing a whole parser.

How to delete the last char in a String?

i want to delete the last char in a String, but i don't want to convert the String to a StringBuffer or an array, who knows how to do?

Try it in this way
String MyString = "ABCDEF";
MyString = MyString.substring(0,MyString.length()-1);

Cutting last char in the XI

hello experts
I have a scenario RFC2WS and sending
<?xml version="1.0" encoding="UTF-8" ?>
- <rfc:ZRFC_POLICY_OR_INSURANCE xmlns:rfc="urn:sap-com:document:sap:rfc:functions">
<PASSWORD>kf001</PASSWORD>
<USERNAME>kfirg001</USERNAME>
</rfc:ZRFC_POLICY_OR_INSURANCE>
but in the XI I am recieving
<?xml version="1.0" encoding="UTF-8" ?>
- <rfc:ZRFC_POLICY_OR_INSURANCE xmlns:rfc="urn:sap-com:document:sap:rfc:functions">
<PASSWORD>kf00</PASSWORD>
<USERNAME>kfirg00</USERNAME>
</rfc:ZRFC_POLICY_OR_INSURANCE>
it is always cutting the last char in the username\password. in the RFC it is defined as a String.
I couldnt find out why it is cutting the last char and help would be great.
Thanks
Kfir

Hi,
Is it possible for you to send it with Filed type as CHAR instead of String..
In RFC source code you could handle this kind of conversion.
Try with CHAR...instead of string.
Thanks
Swarup

Character mode report cuts off last character on a line

Reports 9i, Windows 2003 Server. Printing character mode reports to IBM 6400 printer. I have a variable text column (multi line) and randomly the last character on a line gets cutoff. I'm using Courier 10 as my font. It is only 1 character that ever cuts cutoff. Any ideas? I'm desperate.
Tom

Hi,
change the reports height& width for landscape /portait.
and go to edit margin in layout.
see the layout and move to left if it has lot of gap in left side.
we can get correct output if the right side border is upto 8.2.
try with this.
--Basava.s

Remove last char

Ok i am trying to make just a simple calculator program for a class. I am trying to get the backspace button to work. How would i delete the last char in the string.

use a substring, the last char. will be:
myString.length
that will give you the length and from that you know what the last char. is

Deleting the last char of a string

How can I Delete the last char of a string???
example:
asd@fdg@vvdfgfd@gdgdfgfd@gdfgdf@
I want delete the last @!
Tks in advance!

hi,
try this:
lv_count = strlen(string).
lv_count_last = lv-count - 1.
replace string+lv_count_last(lv_count) in string by ' '.
This should work.
thnx,
ags.
Edited by: Agasti Kale on Jun 4, 2008 9:03 PM

How to remove last char in a string by space

I have to implement backspace application(remove a last char in a string , when we pressed a button).
for ex: I enter the no
1234
instead of 1236
So when i press a button on the JWindow... it should display
123
so that i can enter 6 now.
I tried to display the string "123 " instead over "1234" but it is not working when the no background is specified. but works fine when a background color is specified.
The string is displayed as
Graphics2D g = (Graphics2D)window.getGraphics();
AttributedString as = new AttributedString(string, map);
g.drawString(as.getIterator(),x,y);
In the map, the background is set to NO_BACKGROUND.
Thanks and regards

Deja vu. I saw this kind of post before, and I'm sure
it was today.http://forum.java.sun.com/thread.jspa?threadID=588110&tstart=0
Here it is.

Deleting last char in a string...

I have a string that is created as follows: strBuffer += k.getKeyChar();(k is KeyPressed ...KeyEvent) How can I delete the last Char in the string strBuffer?

Hi
// simply substring
if (strBuffer.length() > 1)
    strBuffer = strBuffer.substring(0, strBuffer.length()-1);
// you may also use
if (strBuffer.length() > 1)
    StringBuffer buffer = new StringBuffer(strBuffer).
                               deleteCharAt(strBuffer.length()-1);
    strBuffer = buffer.toString();
}I've not tested the above code myself & I've written the above code on the go after reading your query. The above code definitely work & help you.
Regards,
JPassion

Compare the last Char to the First Char in a Sting

Hello, this should be easy but I'm having problems so here goes.
I get the user to input a Stirng and I want it to compare the last Char to the first Char. I have writen this but StartWith can take a Char?
public static void main(String[] args) {
        // TODO code application logic here
        String strA = new String();
        int length = 0;
        char lastLetter;
        System.out.println("Please input your first String: ");
               strA = EasyIn.getString();
             length = strA.length()-1;
               lastLetter = strA.charAt(length);
       if( strA.endsWith(lastLetter))
            System.out.println("The first letter matches the last");
       else
                   System.out.println("They Don't match");
}I have tried lastLetter.endsWith(strA) but that dosn't work some thing to do with it not taking Char
From reading you can go strA.startWith("R") and that would look for R but you can't put a char in that would be a single letter.
I also tried to lastletter to a string but then charAt wouldn't work.

fixed it I used substring as its a string object any one recomend a better way let me know
public static void main(String[] args) {
        // TODO code application logic here
        String strA = new String();
        int length = 0;
        String lastLetter;
        System.out.println("Please input your first String: ");
               strA = EasyIn.getString();
             length = strA.length()-1;
               lastLetter = strA.substring(length);
       if( strA.startsWith(lastLetter))
            System.out.println("The first letter matches the last");
       else
                   System.out.println("They Don't match");
}

Finding last char in the string

Hi
i need to find out whether the last char of a string is '/' (forward slash). please let me know if there's a FM to do that. Other post me the logic for this ASAP.
thanks

len = strlen(char).
len = len - 1.
if char+len(1) = '/'.
*write ur code
endif.
chk this code
REPORT ychatest.
DATA : str(5) VALUE '123/',
len TYPE i.
len = STRLEN( str ).
len = len - 1.
IF str+len(1) = '/'.
WRITE : '/ found'.
ENDIF.
<b>Reward points if helpful and close thrad if solved</b>
Message was edited by: Chandrasekhar Jagarlamudi

Can i use the char (defined as line iteam dim) in Aggregates

Hi
I am maintaining aggregates on cube. can i use char which is defined as line iteam dimenstion.if i use how will be the effect.
thanks
Shaliny

Hi,
of course you can use it!
The behaviour is the same than with the other characteristics: you will have as many records as DISTINCT ocurrences of the combination of all CHARS you have included in your aggregate.
I suggest to first create your aggregate with a fixed value on another characteristic so you can have a feeling about how many records it will have and how long it will take to create it.
In general if you have flagged your char in a line itm DIM it means that this CHAR has very high cardinality (nearly the same number of records than the fact table itself) therefore it wouldn't make sense to include it in a ggregate except if your filter it for particluar fixed value.
The only difference you have with this line itm DIM is that there is no DIM table as such; the chars is accessed firectly from the cube fact(s) table. This will be the same for your aggregate (no aggr dim table created, access form your aggr fact(s) tables).
hoping this help...
Olivier.

Remove last char of string

Hi Guys
How can I remove the last char of a String ?

With [the substring method|http://java.sun.com/javase/6/docs/api/java/lang/String.html#substring(int,%20int)] .

User defined function for getting last string in the line

Hi Experts,
I am not java expert, can anyone give me user defined function for getting last string in the line.
for example if the source field is "NEW ARBOUR SQUARE" i want to pass to target field only last string that is "SQUARE"
please help me out of this.
Kind Regards.
Praveen.

You don't even need a UDF for this. In the graphical editor look for the standard functions and once you do a scroll over on 'text functions; you will find what you are looking for.
Just a piece of advice, try keeping UDF's to minimum unless really required or it is complicated without it.
regards

Split Last Word into New Line

Hello,
Any pointers to below :-
When entering data in column of size say 4000 the last word in the line should not be split if it cud not fit,
if the last word does not fit then it should appear in new line and cursor should be placed at last of the word (if its last word of sentence).
Note that multiline is set to yes and item is text item with form layout, although i have one solution but its not the best one.
Thoughts are appreciated if there is any built in property for this or some other way?
Forms version 10g
Database 9i
br
atul

Hello,
This could be the starting point of an algorythme:
SQL> set serveroutput on
SQL>
SQL> DECLARE
2    LC$c    VARCHAR2(1000);
3    v       VARCHAR2(1000);
4    LN$MAX PLS_INTEGER := 20 ;
5    i       PLS_INTEGER;
6 BEGIN
7    LC$c := 'Here is a text to test the split of a large sentence into multiple sub fields';
8    LOOP
9      v := SUBSTR(LC$c, 1, LN$MAX);
10      i := INSTR(v,' ',-1);
11     IF i > 0 AND i < LENGTH(v) THEN
12       v := SUBSTR(v,1,i);
13       LC$c := SUBSTR(LC$C,i+1,1000);
14     ELSE
15       LC$c := SUBSTR(LC$C,LN$MAX+1,1000);
16     END IF ;
17     DBMS_OUTPUT.PUT_LINE('[' || v || ']');
18     EXIT WHEN LENGTH(LC$C) = 0 OR LENGTH(LC$c) <= LN$MAX;
19    END LOOP;
20    IF LENGTH(LC$c) > 0 THEN
21      DBMS_OUTPUT.PUT_LINE('[' || LC$C || ']');
22    END IF ;
23 END;
24
25 /
[Here is a text to ]
[test the split of a ]
[large sentence into ]
[multiple sub fields]
Procédure PL/SQL terminée avec succès.Francois

Last Char on a line

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