Limit decimal place

Question

Hello, I am totally new to Java,
Basically I am subtracting 2 numbers, (2 floats)
How do I limit the answer to just 2 decimal places , so the answer is something like 1.45 , .45 and so on ?

Answer 1

i like this (The Sue will not mind, i guess :))
*   -description :<p> Sets the number of decimal places to the argument specified
*     the class is overloaded to return float and double data types. The parameter
*     named 'places' is the number of decimal places returned by the method.
*     Note: the parameter int will also work (without amendment) for byte and short.</p>
*     // <b>EXAMPLE:</b><br>
*     <code>
*          double d = 1.250550123456789;
*          System.out.print( Fraction.digits(d,4) );
*     // will output the double as : 1.2506
*          float f = (float)1.2505012;
*          System.out.print( Fraction.digits(f,3) );
*     // will output the double as : 1.251
*     </code>
*     This has the advantage over other methods in that the data type retains its
*     integrity as a double or a float data-type, instead of converting it to a String
*     as in java.text.DecimalFormat and rounding off the additional data.<br>
*     The class could be also used to avoid the pitfalls of floating point
*     innacuracies;<br>
*     // <b>EXAMPLE:</b><br>
*     <code>
*         double d1 = 3.0 * 0.1;
*         System.out.println(d1*10);
*     // will output : 3.0000000000000004
*         double d2 = 3.0 * 0.1;
*         byte b = (byte)14; // works with other data type widths
*         System.out.println(Fraction.digits(d2*10, b)); // slice off the last digit
*     // will output : 3.0
*     </code>
*  @author Sum-shusSue
public class Fraction {
   public static double digits(double d, int places) {
      return (long)(d*Math.pow(10,places)+0.5)/Math.pow(10,places);
   public static double digits(double d, long places) {
      return (long)(d*Math.pow(10,places)+0.5)/Math.pow(10,places);
   public static float digits(float d, int places) {
      return (int)(d*Math.pow(10,places)+0.5)/(float)Math.pow(10,places);
   public static float digits(float d, long places) {
      return (int)(d*Math.pow(10,places)+0.5)/(float)Math.pow(10,places);
}