Linkage of different ChaRM tickets as parent child
Hi All,
We are planning to use Solution Manager ChaRm with the to log change requests. In some cases we have global change requests which when required to be implemented - we need to create regional / country specific change requests.
Now the condition is the Global change request should be connected to the regional / country specific change requests and Global change request should get closed only when all the childu2019s have got closed. One of the probable solution to have the reference between the parent and child requests is u2013 maintaining the global change request number maintained in External reference number.
Just want to know if there is any better solution. Thanks a lot for all your time.
Best regards,
vithal
we need multiple change requests as the implementation of the changes getting carried out using these change requests will happen at different times. Fro example. on 31st March ofr India, on 31st dec for Swiss and like this.. So there is business case for this...
Similar Messages
-
Multiple Transports included in different ChaRM tickets on same objects
Hi Experts,
We have ChaRM tickets created for different business CRs, and often a same object has to be changed for different CRs. A question is that is there a way of checking if an object is included in more than one different transports under different ChaRM tickets? How can we best organise the order of the ChaRM tickets so that there will not be a collision?
Many thanks for your insights shared!
BR Li LiHi Experts,
We have ChaRM tickets created for different business CRs, and often a same object has to be changed for different CRs. A question is that is there a way of checking if an object is included in more than one different transports under different ChaRM tickets? How can we best organise the order of the ChaRM tickets so that there will not be a collision?
Many thanks for your insights shared!
BR Li Li -
Parent Child Hierarchy causes numbers to be different
Hello,
We have a parent child hierarchy in our chart of account dimensions. When the hierarchy is included in an analysis, the numbers are correct. If the hierarchy is not included in the analysis and a column from the dimension with the hierarchy is included, the numbers are very different. They are overstated by a large amount.
For Example, I have two analysis:
-In the first analysis the hierarchy is included and the grand total is 2,383,080,784.
-The second analysis has simply excluded the hierarchy from the analysis and the total shoots all the way up to 6,901,729,527.
I have screen shots but don't know how to include them in this kind of a post.
Has anybody else seen such behavior? This seems like it would be a big deal so either we are doing something wrong or this is a bug that needs fixed.
We are on 11.1.1.6
Thanks in advance,
BrianHi,
Thanks for the reply, I'm actually using snapshots. But even with the Type 2 Dim I don't think it will work.
When OBIEE generates the very first sql against the Parent-Child table the fact table is not included in the query. It seems to create 2 queries - one to find the top level parent (ancestor key is null) and then one to find all the leaf nodes.
It does not have any join to the fact table when it does this. So if you have multiple rows in the table (with date stamps) for a single row (person in this case) - it picks up both rows. Therefore, when you have a person who was, say, promoted to manager, and WAS a leaf node, and is now a manager, they show up in the leaf query and don't display in the hierarchy as a manager.
Once it has the leaf nodes and it joins to the fact table everything works (ie the surrogate key join).
I'm trying to figure out if there is any way to influence those initial queries against the parent-child table.
Hopefully that made sense.
Thanks,
Tori -
Is it possible to put two different colors in tree parent
node background and child nodes background?
Any help will be very helpful.
ThanksHi PanosE,
Yes, you can set up another Standard Edition Server in child domain and then deploy pool pairing.
You need to deploy a new Front End Pool for the new Standard Edition Server.
A similar case for your reference.
https://social.technet.microsoft.com/Forums/office/en-US/eca4299c-8edb-481e-b328-c7deba2a79ba/lync-2013-standard-edition-lync-fe-pools-in-multiple-domain-single-forest-senario?forum=lyncdeploy
Best regards,
Eric
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact [email protected] -
Query Help with Parent, Child, Child's Child
Hi all,
Need some help with a query. I'm trying to create a stored procedure that is sort of like a Customer, Order, Order, Details. In my situation the tables are different but nevertheless, I want to grab all the fields from the Parent, Child,
and Childs' Child, where the Parent.ParentID = @Parameter. I tried this:
CREATE PROCEDURE [dbo].[spGetCompleteProjectXML]
@ProjectID int = 0
AS
SELECT *,
(SELECT *,
(SELECT *
FROM PageControls
WHERE (PageControls.ProjectPageID = ProjectPages.ProjectPageID))
FROM ProjectPages
WHERE (ProjectPages.ProjectID = @ProjectID))
FROM Projects
WHERE (ProjectID = @ProjectID)
FOR XML AUTO, ELEMENTS
RETURN 0
I think I'm close, but it was my best effort. Could someone help?
thanks in advanceHi TPolo,
Regarding your description, are you looking for a sample like below?
CREATE TABLE customer(customerID INT, name VARCHAR(99))
INSERT INTO customer VALUES(1,'Eric')
INSERT INTO customer VALUES(2,'Nelson')
CREATE TABLE orders(orderID INT,customerID INT)
INSERT INTO orders VALUES(1,1);
INSERT INTO orders VALUES(2,1)
INSERT INTO orders VALUES(3,2)
INSERT INTO orders VALUES(4,2)
CREATE TABLE orderDetails(orderID INT,item VARCHAR(99))
INSERT INTO orderDetails VALUES(1,'APPLE1')
INSERT INTO orderDetails VALUES(1,'BANANA1')
INSERT INTO orderDetails VALUES(2,'APPLE2')
INSERT INTO orderDetails VALUES(2,'BANANA2')
INSERT INTO orderDetails VALUES(3,'APPLE3')
INSERT INTO orderDetails VALUES(3,'BANANA3')
INSERT INTO orderDetails VALUES(4,'APPLE4')
INSERT INTO orderDetails VALUES(4,'BANANA5')
SELECT customer.customerID,customer.name,
(SELECT orderId,
SELECT item FROM orderDetails WHERE orderID=orders.orderID FOR XML AUTO,TYPE,ELEMENTS
FROM orders Where customerID=customer.customerID FOR XML AUTO,TYPE,ELEMENTS)
FROM customer WHERE customerID=1
FOR XML AUTO,ELEMENTS
DROP TABLE customer,orderDetails,orders
If you have any feedback on our support, please click
here.
Eric Zhang
TechNet Community Support -
How to Differentiate between Parent & child item of material determination
Hi Experts
I have a list of material & the Business requirement is to found that whether a material is a Parent material , Child material or Both ( a parent to other children and a child to another parent).
I tried using table KONDD & KONDDP but I was not able to differeniate between Parent & Child item.
I even cant use item category to diferentaite the two as by item categairy i can only find that it is a Prent material but cant find whether this material is a Child material or not.
Is there any table in which i can enter the Parent material & the output would be child material or any other table which contain both parent & child material.
Note : In Material determination ( VB11) , the material which is entered is Parent material & the material with which it would be replaced is Child material.
Kindly Guide.
Thanks in AdvanceHi
The wording of Parent and Child sounds like using a BOM material. In material determination...these two items can be called as Material entered and material determined or Main Item and Sub Item.
In the sales order overview screen...at line item level check the field 'HLvItem' (Higher Level Item). It will show the POSNR of the main item to which this item is linked. Since this can also happen in the case of free goods and BOM...you have make another check for these items with the item category.
If the substitue material is not determined as a sub item... you can check the material number in the field 'Material Entered' in the sales tab of the item and compare the material number with that exists in the VBAP-MATNR. If both are different, then this material can be considered as a determined material.
Thanks,
Ravi -
Dynamic hierarchy in parent child hierarchy table??
Do you have any experience to handle the requirement of dynamic hierarchy in universe/webi?
We have some data in parent child hierarchy as below u201CCustomeru201D table.
Customer
Parent Child
Z A
Z B
A AA
B BB
AA AAA
For example, Company Z is the parent company of Company A.
Another table, Amount is the amount value of different Customers.
Amount
ID Amt
AA 10
AAA 1
BB 2
Is there any functionality in Universe designer to build related Classes and objects, So that the web intelligence documents represent the following report with the drilling results?
When we want to see the ID and Amt, the expected result should be:
Z 13
when we drill down Z
the result should be:
A 11
B 2
when we drill down A:
the result should be:
AA 11
notes **
the level of hierarchy is dynamic
Any suggestion is appreciated. Thanks.Hi,
The only way to do it is to create recursive derived table that flatten you parent child hierarchy with a given maximum depth.
Here is a sample I built a long time ago to flatten a parent-child hierarchy on Employees table in Foodmart database (SQL Server).
Didier
SELECT DISTINCT
Z.employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
A.supervisor_id_6,
A.employee_id_6,
A.full_name_6,
Z.supervisor_id AS supervisor_id_7,
Z.employee_id AS employee_id_7,
Z.full_name AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
Z.supervisor_id AS supervisor_id_6,
Z.employee_id AS employee_id_6,
Z.full_name AS full_name_6
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
WHERE A.employee_id_5 = Z.supervisor_id
) A
WHERE A.employee_id_6 = Z.supervisor_id
UNION
SELECT DISTINCT
A.employee_id_6 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
A.supervisor_id_6,
A.employee_id_6,
A.full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
Z.supervisor_id AS supervisor_id_6,
Z.employee_id AS employee_id_6,
Z.full_name AS full_name_6
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
WHERE A.employee_id_5 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_5 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_4 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_3 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_2 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
NULL AS supervisor_id_3,
NULL AS employee_id_3,
NULL AS full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_1 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
NULL AS supervisor_id_2,
NULL AS employee_id_2,
NULL AS full_name_2,
NULL AS supervisor_id_3,
NULL AS employee_id_3,
NULL AS full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A -
Hi All
Fairly new at this and am a bit confused.
I have been given the task of cleaning up certain tables in my DB. I am running into parent / child issues.
I want to remove all entries from Table A. When i try and delete one row it gives me a constraint violation. It tells me there is a child record out there. So i go ahead and disable that constraint, go back to table A and try the delete again. I get a different another violation telling me that there is a child record on a different table. And on and on the story goes.
Now I could keep doing this but the schema i am working on has 1051 tables and just over 6000 constraints. So as you can see this might take me a month to sit here and do that. Not very keen on that.
What I am after is:
1. A program / script that will lay out all the parent child relationships for me. Coming across each one as i try and delete is painful
Would it be possible to get something like:
Table A
-- Table B
-- Table C
Table D
-- Table E
-- Table G
-- Table F
2. All the constraints have been created with a delete rule of 'No Action'. I think the easiest thing to do would be to go to the parent table (or what I think is the parent table) and change this to on delete Cascade. From what it looks like I don't think you can do this. Does anybody know how to? Or if its possible?
3. The third option I am thinking of is:
Disable All the constraints on what I think is the parent table. Remove entries from the child tables. Enable the constraints.
Now my issue here is, how do i know all of the child tables? I guess that goes back to my question 1.
Thanks in advance. Sorry for the story.
The lack of documentation / diagrams here is driving me nuts :)You can use tools like Microsoft Visio to reverse engineer the tables and their relationships.
You can also generate a list of parent-child related tables from user_constraints.
something like:
SQL> SELECT TABLE_NAME,
2 (SELECT TABLE_NAME
3 FROM ALL_CONSTRAINTS R
4 WHERE R.OWNER = U.R_OWNER
5 AND R.CONSTRAINT_NAME = U.R_CONSTRAINT_NAME) PARENT_TABLE
6 FROM USER_CONSTRAINTS U
7 WHERE U.CONSTRAINT_TYPE = 'R'
8 /
TABLE_NAME PARENT_TABLE
EMP DEPT
SQL> -
Parent-child hierarcy - row level security
Hi,
Im using OBI 11.1.1.5 and have a problem about row-level security in parent-child dimension.
I have created a parent-child dimension, simlar to:
a1
--a1.1
----a1.1.1
----a1.1.2
--a1.2
----a1.2.1
By using a session variable 'SESVAR1', I want to restrict the visible hierarcy. For instance user 'a1.1' should only see:
a1.1
--a1.1.1
--a1.1.2
To do this I created a parent-child closure table with the whole dataset. Then I created a physical table using select statement with my session variable in repository. Whenever I viewed data in repository, it showed the correct set.
I created a parent-child dimension, using the original parent-child closure table. But since current distance values are different from the original hierarcy, I can not managed to build a security such a security system with this method.
How can I build a security system, that a member can only see its child hierarchy only?
Thanks for answers and links...
Edited by: user4516917 on 16.Nis.2012 06:54
Edited by: user4516917 on 16.Nis.2012 06:55According to searches I made in support.oracle and google, it seems that it is not possible to view just a branch of a parent-child tree. Because the closure table is static. Therefore, you can not change the distances of objects dynamically.
This parent-child ability is very frustrating for me. As I understand, parent-child dimension ability can only be used in read-only sources. Any filtering or dynamic changes does not seem possible in this structure. Any changes on parent-child table requires parent-child relation table to be rebuilt.
I couldnt find any functionality of indexcol or choose functions in parent-child dimensions. I think they can only be used in level based dimensions.
Any comments appriciated.. -
Parent Child heirarchies in OBIEE11g
Hello Experts
I have got a requirement from the client that they need to have multiple version of Parent child heirarchies coming out from a particulat dimension. To elaborate furthet say suppose there is a dinemsion called Profit Center where we need to create Parent child heirarchy. This is good if only one heirarchy needs to be created out of it. But instead there are three heirarchies - One MAster and two Custom.
There would changes in the various parent child level in the reporting that's why different version of heirarchies.
Having said that , one more issue is every month the heirarchies will changes that means the child can move to different parent . Some new parent/ child could be added etc. SO every month the Master and two custom heirarchy need to be refreshed.
So my question is :
1. How to achieve three version of Parent Child heirarchies. I know how to create Parent child heriarchies but three differnt heirarchy version out of a single dimension is the issue.
2. How to automatocally refresh these heirarchies every month.
Any help /pointer would be of great help.
RegdsHello All
Can anyone put some light on this pls... -
Graphs and parent-child with loops and duplicates
There is a parent-child relation in the table t(prnt, chld) which allows duplicates (A->B, A->B) and opposite paths (A->B, B->A), and complicated loops. Is there a way to identify rows that form any separate "connections network" and assign a "name" to them of any kind (letter, number, wahtever)? I try to use WITH recursive clause to identify and group rows belonging to one graph but with no luck. Any help would be appreciated.
thank youFrank, I posted inputs for all graphs (multiple inserts) and some allowable outputs for one graph. For all cases (ie. graphs) the rule is the same:
1. identify all nodes belonging to a graph
2. "name" that graph (min, max or whatever you like)
3. print the output in the form (node_belonging_to_a_graph, name_of_the_graph) for all identified graphs
And as you said, I am somewhat flexible. I don't want to constrain the problem with saying min, max because it's not important how you name it, but the way which is somehow natural and fits with requirements is the usage of nodes' values.
You ask me if (1,1),(2,1),(3,1) is also OK as an output for sample graph (1,2)+(2,3). Yes it is. It is one of those I posted but with additional node which is chosen as a name for a graph. But as you can guess it doesn't matter which node you choose, and the additional information about a node named with its own name is not as important and the information that all other nodes are named with that name but it is 100% acceptable. If you changed the naming convention and started to use letters instead of node values then yes, it would be a must to have the output in the form (1,a),(2,a),(3,a).
You also ask me about the result for 90x data inserted as 5 rows: (901,902)..(906,904) and present sample result:
901 902
905 902
906 902
And the answer is no, it is not good result. It misses the information about the nodes 904 and 903 which belong to this graph too. The correct result could be:
901 902
905 902
906 902
903 902
904 902
or any other "combination" which presents 5 nodes with the name of the sixth (in this case of 6-node graph). Just one have to be picked, it doesn't matter which one. The "vertical" order is also irrelevant.
As you can see there is a lot of room that gives acceptable result. I don't want to constraint it because it can influence performance which is important when dealing with graph structures in relational databases (RDBMS are not predestined to easily cope with that sort of information). It can also influence the chosen algorithm and I'd like to pick the fastest one which gives acceptable result.
Two numbers x and y are in the same group (graph) if (and only if) at least one of the following is true:
(1) they appear on the same row together (it doesn't matter which number is in which of the 2 columns), or
--(2) x appears on the same row with a third number, z, and z is in the same group as y--
(2) there are other edges (entries) in the table that form a "path" from x to y. And because the direction of the path is not important for the problem (ie. the parent-child table structure can be forgotten for a moment), the path means "there exists connection" between x and y aka "you can walk from x to y".
The output consists of 2 columns: id (which is unique in the result set) and grp (which identifies the group) *[correct]*
The id column will always be one of the numbers in the group *[correct]*
It doesn't matter what the grp column is, or even what data type, as long as it distinguishes between the different groups. *[correct, but as you noted using one, picked number from a graph is the prefferable way]*
If there are N distinct numbers in the group, I need N rows of output for that group, with id showing all those distinct numbers. *[correct, but if you choose your naming convention as naming a graph with the value of the node belonging to it you can ommit the node which is named for itself (but it doesn't hurt is such row appear in the result)]*
You ask me if the graph is directed. No it's not. Your example (x,y) and (y,x) is great, and it can be concluded from my first post when I say that "opposite paths" (A->B, B->A) exists. What matters is the connection between the nodes. The parent-child table somehow imposes that direction is important, but for this problem it is not.
One of the motivations for my post is to know what other people think without affecting their minds with my approach. I don't want to skew anybody's mind into my solution which works, but it's not effective. I don't mind showing it but I kindly ask you to think about the problem before I post it. Diversity of approaches helps to distill the best one.
As I said I did it with the usage of sys_connect_by_path. If it doesn't appear to you as possible usage then it is likely that I don't use it efficiently. Please understand, I will post it if you ask me one more time but if you can live for a while without my inefficient solution and suggest something with WITH clause I would appreciate it.
There is no exact result I expect. There are many results which are correct and acceptable. They all must follow the rules described at the beginning.
Thank you
Edited by: 943276 on Jun 28, 2012 1:32 AM -
Hey Forum
Wondering if its possible to setup a parent/child relationship with customer accounts. For example, Let's say I have company A that is a dealer. That dealer may submit forms and such and I would like to associate three accounts under that dealer so the different accounts can see the other forms or information for that dealer. Is this possible with bc?
I'm fairly new and getting handle on this platform but have to say its growing on me.
Thanks!
DerekDerek, Not out of the box, if you really wanted to do this and stick with BC you could sync BC's CRM databases externally using the API and build the functionality off BC but utilizing BC as the database.
-
Parent-Child Relationships in Essbase Studio
In Essbase Studio, I am defining a hierarchy in which a parent member (Wholesaler) is from one dimension table and child member (Rep) is from another. When I preview this hierarchy or build an outline to include it, a few of the Reps that should rollup to a certain Wholesaler are missing. They are not dropped, but Essbase Studio just never recognizes these Reps as being children of that Wholesaler in the first place. However, if I run a sql query against the source data mart with the correct joins, these missing reps do show up in the records of that Wholesaler. Also, the missing Reps are showing up fine in the hierarchy preview as long as I don't make them children of anything in the Wholesaler dim. So Essbase Studio is able to see these Reps, but just can't figure out how they are related to the given Wholesaler. Again, this is only happening for about 10% of the Reps for the Wholesaler. Other Reps are showing up fine in the parent-child relationship.
In the source data mart, I don't see any NULLs or anything amiss in the records for the missing Reps. What other reasons would Essbase Studio not recognize a particular joined record?it really does sound like a join issue. You say if you just load the children without the parent, they load, but if you associte them to the parent, they don't. You might try when creating the joins to do a full outter join to see if they load and to what.
One other thing you could try would be to create a user defined table that has the join in it. I've found data atype issues in joins from different tables before. Studio is very pickey about this
Edited by: GlennS_3 on Oct 20, 2010 9:12 AM -
I have a parent/child relatonship between 2 tables. Both tables have dataless keys (both just populated by different sequence numbers starting at 1). I want to create Parent and Child processes (in the same workflow itemtype) to represent the records in the application tables.
What should the "itemkey" be for the child process? (I can't have the same "itemkey" as the parent record).
-- using the Oracle demo Survey workflow names:
begin
-- PK of parent record=1
wf_engine.CreateProcess(ItemType => 'WFSURV',
ItemKey => to_char(1),
process => 'SURVEY2');
-- PK of child record=1
wf_engine.CreateProcess(ItemType => 'WFSURV',
ItemKey => to_char(1),
process => 'CHILDSURVEY');
end;
ORA-20002: 3122: Duplicate item 'WFSURV/1' could not be created.
ORA-06512: at "OWF_MGR.WF_ENGINE", line 3000
ORA-06512: at line 5
Can I build up my child "itemkey" by having {PK of parentrec}||'-'||{PK of childrec} to ensure that it wont conflict with the "itemkey" for the parentprocess?
e.g.
begin
wf_engine.CreateProcess(ItemType => 'WFSURV',
ItemKey => to_char(1),
process => 'SURVEY2');
wf_engine.CreateProcess(ItemType => 'WFSURV',
ItemKey => to_char(1)||'-'||to_char(1),
process => 'CHILDSURVEY');
end;
I'd like to implement this as cleanly as possible. Any suggestions welcome.You could just prefix each item key with the process name or some other distinguishing string -
'SURVEY2:' || {PK of parent table}
'CHILDSURVEY:' || (PK of child table)
or
'P' || {PK of parent table}
'C' || (PK of child table) -
I have a parent/child domain structure. The parent domain consists of domain controllers in three different locations (HO1, HO2, HO3). I have set Sites and Services up so that each remote VPN site (Child domain) has a site link to HO1 and HO2 only. When
I attempt to ping the parent domain name from a site server it sometimes resolves to HO3 and times out as there isn't an active VPN tunnel between the 2. My question is why would HO3 be replying when it doesn't have a site link to the remote site and in turn
how can I stop that from being the domain controller that replies?
Thanks for any advice
ChrisHi,
To add, Mr. Ace got a good blog regarding Site and Site links, see if it could help here:
AD Site Design and Auto Site Link Bridging, or Bridge All Site Links (BASL)
http://blogs.msmvps.com/acefekay/2013/02/24/ad-site-design-and-auto-site-link-bridging-or-bridge-all-site-links-basl/
Best regards
Michael
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