List of indexes and columns for a database.

Question

Hi
Do you know the SQL command to get the list of indexes and associated columns for all tables for a given database ?
The following only shows me the table and index name but I would also like to get the colums for each index
SELECT o.name,       i.name  FROM sysobjects o  JOIN sysindexes i    ON (o.id = i.id)
Can you pls help
Thanks
H.

Answer 1

There isn't a single command that will do that.
There is the sp_helpindex stored procedure which will give you the information on indexes one table at a time, you could call it in a loop, but there is other information in there as well, so the output would be messy.
You can look at the source code for sp_helpindex to find out how it decodes the key column names. 
use sybsystemprocs
go
sp_helptext sp_helpindex
go
The core of it is this loop, which builds up a list of the column names in @keys, a varchar(1024) declared earlier.
        **  First we'll figure out what the keys are.
        declare @i int
        declare @thiskey varchar(255)
        declare @sorder char(4)
        declare @lastindid int
        declare @indname varchar(255)
        select @keys = "", @i = 1
        set nocount on
        while @i <= 31
        begin
                select @thiskey = index_col(@objname, @indid , @i)
                if (@thiskey is NULL)
                begin
                        goto keysdone
                end
                if @i > 1
                begin
                        select @keys = @keys + ", "
                end
                /*select @keys = @keys + index_col(@objname, @indid, @i)*/
                select @keys = @keys + @thiskey
                ** Get the sort order of the column using index_colorder()
                ** This support is added for handling descending keys.
                select @sorder = index_colorder(@objname, @indid, @i)
                if (@sorder = "DESC")
                        select @keys = @keys + " " + @sorder
                **  Increment @i so it will check for the next key.
                select @i = @i + 1
        end
        **  When we get here we now have all the keys.
        keysdone:
                set nocount off
-bret