Listing all files in folder as document file

How can I import all file names in a folder into a document file?
With DOS I used the DIR-command for example "dir c: > filename.doc"

Hi and welcome to Discussions,
have a look at PrintFinder http://www.macupdate.com/info.php/id/16935/printfinder
Hope it helps
Stefan

Similar Messages

List all files in a directory on a server that hosts the applet

Hei :)
I have a problem. I want to list all files in a directory on my server. ( http://www.foo.bar/tw )
The applet is in the root folder ( http://www.foo.bar ).
So i tried it like this
File fi = new URL(getCodeBase() + "/all/").getFile();But when I try to list the files, I get a SecurityException.
Can anyone help me out?
Peace!
LoCal

http://search.java.sun.com/search/java/index.jsp?col=javaforums&qp=&qt=%2Blist+%2Bfile+%2Bserver

How to list all files in my system

Hi there,
I want to list all files in my system. My system is Windows XP, can anybody help me please? Any can you recommend me if java is suit for such processing?
Thx in advance.

public void showFilesIn(File dir) {
 File[] files = dir.listFiles();
 for (int i = 0 ; i < files.length ; i++)
 if (files.isDirectory())
showFilesIn(files[i]);
else
System.out.println(files[i]);
showFilesIn(new File("C:\\"));
notice that it won't show directories, but only files

Database query in MaxL DBS-Name list all file information failed

When I tried list all file information command in MaxL it gave me an error saying the user doesn't exist. When I check the user through display user; command in MaxL I get the information as listed below.
Is there something wrong with the way the user was created ?
How can I (Admin) get the index and data file information?
MAXL> query database Application.Database list all file information;
   ERROR - 1051012 - User ADMIN@Native Directory does not exist.
MAXL> display user;
user                description         logged in           password_reset_days enabled             change_password     type                protocol
   conn param          application_access_
+-------------------+-------------------+-------------------+-------------------+-------------------+-------------------+-------------------+-----------------
--+-------------------+-------------------
ADMIN@Nati                                    TRUE                   0                TRUE               FALSE                   3 CSS
   native://DN=cn=911,                   1

Has anyone resolved the problems with using TNSFormat?
As is, I want to move to a shared server setup and to do that I want to use TNSFormat and point to a tns entry which is setup for IPC+Shared connection.
But the Oracle Home that has the Oracle HTTP Server (from the companion CD) does not have SQL*net installed and does not seem to understand TNS.
I have TNS_ADMIN setup, I have ORACLE_HOME_LISTENER poiting to the DB Home.
for the OHS home, using "sqlplus login/pw@ipcshared" works, but "tnsping ipcshared" does not, since tnsping does not exist in the OHS home.
I cannot install SQL*Net from the CD1, since it requires a dedicated/new home and does not want to install in the OHS Home.
The only format that works in a dedicated OHS Home setup is ServiceNameFormat.
Any help or input would be very helpful.
Regards
ps. This is a redhat linux setup.
Message was edited by:
Oli_t

List all files in project

Hello,
Is there any way to list all files and their paths used in a after-effect project (using extended script)?
Thanks

David Torno already wrote that wonderful script.
You can get it here:
http://aescripts.com/projectinfolistexporter/

List all file namess under a dba_directory.

Guys,
It there any way that I can get all the file names in a dba_directory..
ie.
SQL> select * from dba_directories;
OWNER DIRECTORY_NAME DIRECTORY_PATH
SYS ATTACH_FILES C:\PLSQL
Now I'm looking for a SQL query\PL-SQL block to list all file names under C:\PLSQL.
Guidance plz.
Thanks,
Bhagat

There's an Ask Tom thread here:
http://asktom.oracle.com/pls/ask/f?p=4950:8:::::F4950_P8_DISPLAYID:439619916584
shows how to do this with a Java stored procedure.
HTH
Regards Nigel

CDM 4650 / ACNS - List all files in a channel?

Hello,
I am looking for a non-cumbersome way to list all files in a channel. The only way I know of right now is to go to the CDM Admin Page, go to Previewer, and then view the channel, which is split among many pages and has much extraneous information I don't care about -- I just want the filename in the channel for any given channel.
I was given a way to do this by Cisco which doesn't work, so I was looking for any other solutions. Thanks!

I have not seen a non-cumbersome way to do this. You say that a Cisco engineer gave you a way to do it but it did not work. You should contact them to let them know it did not work and maybe they can work with you to get it to work.

Snow Leopard finder doesn't list all files on Windows 7 volumes

From my Macbook Pro (10.6.8), I can connect to my Mac Pro, while it is running Windows 7 in Boot Camp, in order to access the Mac Pro's 6 volumes (1 Boot Camp, 5 Mac volumes). This is using SMB via Finder's 'Connect to server…' on an Airport network.
However, Finder never displays all the files and folders on any of the Mac volumes it connects to through Windows 7. It seems to show approximately the first 18-9 files and folders, and then nothing. The same applies when I open a nested folder — it doesn't list all of its contents.
Any ideas as to what's causing this and how I can fix it? I have searched all over but can't find any answers yet, so I'm hoping someone here has seen this before.

Thanks for the reply, but I do have the Restore Windows box checked (see below). And the Resume features info (cnet link) only addresses how to turn the feature off, either selectively or globally. I'm simply looking for the functionality that I had with Snow Leopard and now seems to be absent. Maybe it's a bug in my Finder.

List all file names in a directory

Hello everybody,
I need to write a script in PL/SQL (oracle 10g) that lists all filenames in a specific directory on a client machine and import the files into the database (xml files). After the file is imported they have to be removed.
I was searching for a solution for this because I have never come accross a challenge like this.
What I found was that I could use the procedure dbms_backup_restore.searchfiles of the SYS schema.
Now I need to know how this procedure works. There is very little documentation available.
Can I give the procedure a folder name on my client computer that has the xml files and let the procedure list these files?
Can someone please help me with this. I haven't got a clue.
Thanks in advance.
regards,
Mariane

Hello Justin,
Thank you for your reply.
You have just confirmed what I already was thinking: that the server cannot read files from the client.
I haven't got a client application running to do this. My customer wants me to write a script in PL/SQL that enables users to run an import of xml files in the database by giving in a directory name on the client.
I told my customer that they have to put the xml files on a server directory. Should that always be the server where the database resides on?
Is there another way to solve this request?
Thanks in advance.
regards,
Mariane

List all files in a directory

How can I list all the files in a directory which has folders and files as well? I just wanna files..
File dataDir = new File("c:/data/);
File[] listing = dataDir.listFiles();
but it list the immediate no of folders in the data directory. Is there a way to get all the files in the subdirectories in data folder and excluding the folders?
thanks!

Iterate over the returned array, ignoring those whose isDirectory() returns true.
Alternatively, you could call listFiles(fileNameFilter) instead, with an implementation of FileNameFilter which rejects File objects whose isDirectory() returns true.

List all files in a directory, not including the sub directories if any

Hi,
I have been looking around php.net for a bit and can not work
out how i list the files that are in a directory i.e.
www.site.com/directory/
I would like the names of each file to be placed in an array,
but not to have the sub directories in this list should there be
any.
I was given some code a while ago that done this but it
listed the sub directories and i would like them not in this list.
I do not have this code anymore and do not know where i got
it, so i can not get it amended to what i need.
please can someone tell me what line of code i should be
using.
thank you in advance for your help.

(_seb_) wrote:
> not very clever wrote:
>> Hi,
>>
>> I have been looking around php.net for a bit and can
not work out how
>> i list the files that are in a directory i.e.
>>
>> www.site.com/directory/
>>
>> I would like the names of each file to be placed in
an array, but not
>> to have the sub directories in this list should
there be any.
>>
>> I was given some code a while ago that done this but
it listed the
>> sub directories and i would like them not in this
list.
>>
>> I do not have this code anymore and do not know
where i got it, so i
>> can not get it amended to what i need.
>>
>> please can someone tell me what line of code i
should be using.
>>
>> thank you in advance for your help.
>>
>>
>>
>
> The follwoing PHP code will do just that. Just replace
"pathToFolder"
> with the path to your folder.
> I made the list of files also link to each file. Just
remove the link
> echo if you don't them to be links.
>
> <?php
> // FUNCTION TO LIST FILES:
> function listFiles($path){
> if($handle = opendir($path)){
> while(false !== ($file = readdir($handle))){
> if (is_file($path.'/'.$file) &&
!preg_match('/^\./',$file)){
> $files_array[]=$file;
> }
> }
> }
> return($files_array);
> }
> $path = 'pathToFolder';
>
> // CALL THE FUNCTION:
> $files_array = listFiles($path);
> foreach($files_array as $file){
> echo '<a
href="'.$path.'/'.$file.'">'.$file,'</a>';
> }
>
> ?>
>
I spotted one error:
foreach($files_array as $file){
echo '<a
href="'.$path.'/'.$file.'">'.$file,'</a>';
should be:
foreach($files_array as $file){
echo '<a
href="'.$path.'/'.$file.'">'.$file.'</a>';
(a dot after $file, not a coma)
seb ( [email protected])
http://webtrans1.com | high-end web
design
Downloads: Slide Show, Directory Browser, Mailing List

How to list all files in a given directory?

How to list all the files in a given directory?

A possible recursive algorithm for printing all the files in a directory and its subdirectories is:
Print the name of the directory
for each file in the directory:
if the file is a directory:
Print its contents recursively
else
Print the name of the file.
Directory "games"
blackbox
Directory "CardGames"
cribbage
euchre
tetris
The Solution
This program lists the contents of a directory specified by
the user. The contents of subdirectories are also listed,
up to any level of nesting. Indentation is used to show
the level of nesting.
The user is asked to type in a directory name.
If the name entered by the user is not a directory, a
message is printed and the program ends.
import java.io.*;
public class RecursiveDirectoryList {
public static void main(String[] args) {
String directoryName; // Directory name entered by the user.
File directory; // File object referring to the directory.
TextIO.put("Enter a directory name: ");
directoryName = TextIO.getln().trim();
directory = new File(directoryName);
if (directory.isDirectory() == false) {
// Program needs a directory name. Print an error message.
if (directory.exists() == false)
TextIO.putln("There is no such directory!");
else
TextIO.putln("That file is not a directory.");
else {
// List the contents of directory, with no indentation
// at the top level.
listContents( directory, "" );
} // end main()
static void listContents(File dir, String indent) {
// A recursive subroutine that lists the contents of
// the directory dir, including the contents of its
// subdirectories to any level of nesting. It is assumed
// that dir is in fact a directory. The indent parameter
// is a string of blanks that is prepended to each item in
// the listing. It grows in length with each increase in
// the level of directory nesting.
String[] files; // List of names of files in the directory.
TextIO.putln(indent + "Directory \"" + dir.getName() + "\":");
indent += " "; // Increase the indentation for listing the contents.
files = dir.list();
for (int i = 0; i < files.length; i++) {
// If the file is a directory, list its contents
// recursively. Otherwise, just print its name.
File f = new File(dir, files);
if (f.isDirectory())
listContents(f, indent);
else
TextIO.putln(indent + files[i]);
} // end listContents()
} // end class RecursiveDirectoryList
Cheers,
Kosh!

How to list all files of an ibook in the OPF manifest?

I have this message error when i DELIVERED my iBooks with I Tunes Producer.
ERROR ITMS-9000: "A5809-7_Math_Venture_3rd_Operations.ibooks: The book asset contains file(s) not listed in the OPF manifest: A5809-7_Math_Venture_3rd_Operations.ibooks:/OPS/assets/widgets/Activite? 1 english-1.kpf/images-1/s1.a.jpeg. All files must be listed in the OPF manifest, or there is no way to confirm that they are intended for distribution. For more information refer to http://idpf.org/epub" at Book (MZItmspBookPackage)
Like it is written, All files must be listed in the OPF manifest, or there is no way to confirm that they are intended for distribution.
What that means?
Need help please, for the last step before publishing my first book on iBookStore :-(
Tx

Hi, I've got the same issue here, there was something to do to get it fixed?
I've read that my file (i suppouse the .ibooks file) should be named as the cover file (i suppouse the .jpg that shows the cover)
Well, i renamed almost all files: the .iba file, the .ibooks and the .jpg cover file with the same name: Jalisco Auge de México (right, with accents)
Then, in the list of issues i got this issues above the ones as listed by you:
1: Apple's web service operation was not successful
2: Unable to authenticate the package: (package number.itmsp)

How to list all files and directories in another directory

I need to be able to list all the directories and files in a directory. I need to write a servlet that allows me to create an html page that has a list of files in that directory and also list all the directories. That list of files will be put into an applet tag as a parameter for an applet that I have already written. I am assuming that reading directories/files recursively on a web server will be the same as reading directories/files on a local system, but I don't know how to do that either.

Hi,
Here is a method to rotate through a directory and put all the files into a Vector (files).
 * Iterates throught the files in the root file / directory that is passed
 * as a parameter. The files are loaded into a <code>Vector</code> for
 * processing later.
 * @param file the root directory or the file
 * that you wish to have inspected.
 public void loadFiles(File file) {
 if (file.isDirectory()) {
 File[] entry= file.listFiles();
 for (int i= 0; i < entry.length; i++) {
 if (entry.isFile()) {
 //Add the file to the list
 files.add(entry[i]);
 } else {
 if (entry[i].isDirectory()) {
 //Iterate over the entries again
 loadFiles(entry[i]);
 } else {
 if (file.isFile()) {
 //Add the file
 files.add(file);
See ya
Michael

How can I list all files in a subdirectory in a jar

Hello.
I have wrote a program which lists all class files in given directory.
I used Class.getResource(""), and File.list().
Now I turned the program into single jar file.
It never works.
I know the reason but do not know how to fix the problem.
What can I do?
Thank you in advance.

If you are trying to list the files of jar file from java code you can use this code.
Try with the below code
=============================================
try {
// Open the JAR file
JarFile jarfile = new JarFile("filename.jar");
// Get the manifest
Manifest manifest = jarfile.getManifest();
// Get the manifest entries
Map map = manifest.getEntries();
// Enumerate each entry
for (Iterator it=map.keySet().iterator(); it.hasNext(); ) {
// Get entry name
String entryName = (String)it.next();
// Get all attributes for the entry
Attributes attrs = (Attributes)map.get(entryName);
// Enumerate each attribute
for (Iterator it2=attrs.keySet().iterator(); it2.hasNext(); ) {
// Get attribute name
Attributes.Name attrName = (Attributes.Name)it2.next();
// Get attribute value
String attrValue = attrs.getValue(attrName);
} catch (IOException e) {
=================================================
use import java.util.*;
and import java.io.*;

Listing all files in folder as document file

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