List all files in a directory, not including the sub directories if any

Question

Hi,
I have been looking around php.net for a bit and can not work
out how i list the files that are in a directory i.e.
www.site.com/directory/
I would like the names of each file to be placed in an array,
but not to have the sub directories in this list should there be
any.
I was given some code a while ago that done this but it
listed the sub directories and i would like them not in this list.
I do not have this code anymore and do not know where i got
it, so i can not get it amended to what i need.
please can someone tell me what line of code i should be
using.
thank you in advance for your help.

Answer 1

(_seb_) wrote:
> not very clever wrote:
>> Hi,
>>
>> I have been looking around php.net for a bit and can
not work out how
>> i list the files that are in a directory i.e.
>>
>> www.site.com/directory/
>>
>> I would like the names of each file to be placed in
an array, but not
>> to have the sub directories in this list should
there be any.
>>
>> I was given some code a while ago that done this but
it listed the
>> sub directories and i would like them not in this
list.
>>
>> I do not have this code anymore and do not know
where i got it, so i
>> can not get it amended to what i need.
>>
>> please can someone tell me what line of code i
should be using.
>>
>> thank you in advance for your help.
>>
>>
>>
>
> The follwoing PHP code will do just that. Just replace
"pathToFolder"
> with the path to your folder.
> I made the list of files also link to each file. Just
remove the link
> echo if you don't them to be links.
>
> <?php
> // FUNCTION TO LIST FILES:
> function listFiles($path){
> if($handle = opendir($path)){
> while(false !== ($file = readdir($handle))){
> if (is_file($path.'/'.$file) &&
!preg_match('/^\./',$file)){
> $files_array[]=$file;
> }
> }
> }
> return($files_array);
> }
> $path = 'pathToFolder';
>
> // CALL THE FUNCTION:
> $files_array = listFiles($path);
> foreach($files_array as $file){
> echo '<p><a
href="'.$path.'/'.$file.'">'.$file,'</a></p>';
> }
>
> ?>
>
I spotted one error:
foreach($files_array as $file){
echo '<p><a
href="'.$path.'/'.$file.'">'.$file,'</a></p>';
should be:
foreach($files_array as $file){
echo '<p><a
href="'.$path.'/'.$file.'">'.$file.'</a></p>';
(a dot after $file, not a coma)
seb ( [email protected])
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