Loading a long string from a CSV

I'm loading data from a third party CSV file which contains a field which could be up to 8000 characters long. If I put varchar2(8000) into the model for the file I get error ORA-00910 as varchar2 can only be up to 4000 characters long.
Is there a way of telling the ODI model for the file that the column is a CLOB field rather than varchar2(8000)?
Ironically, it's a column I'm not actually loading into the target table!

Hi,
We do this thing every morning. The source datastore is a file with a string(8000) column. The target datastore is Oracle with CLOB column. The size has never been a problem.

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select     Account     C1_ACCOUNT,
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     Two Pass Calculation     C9_TWO_PASS_CALCULATION,
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     Time Balance     C14_TIME_BALANCE,
     Data Type     C5_DATA_TYPE,
     Variance Reporting     C10_VARIANCE_REPORTING,
     Source Plan Type     C13_SOURCE_PLAN_TYPE,
     Plan Type (FinStmt)     C7_PLAN_TYPE__FINSTMT_,
     Aggregation (FinStmt)     C8_AGGREGATION__FINSTMT_,
     Plan Type (WFP)     C15_PLAN_TYPE__WFP_,
     Aggregation (WFP)     C4_AGGREGATION__WFP_,
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/*$$SNPS_START_KEYSNP$CRDWG_TABLESNP$CRTABLE_NAME=Account.csvSNP$CRLOAD_FILE=Y:/1 Metadata/Account//Account.csvSNP$CRFILE_FORMAT=DSNP$CRFILE_SEP_FIELD=2CSNP$CRFILE_SEP_LINE=0D0ASNP$CRFILE_FIRST_ROW=1SNP$CRFILE_ENC_FIELD=SNP$CRFILE_DEC_SEP=SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=AccountSNP$CRTYPE_NAME=STRINGSNP$CRORDER=1SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=ParentSNP$CRTYPE_NAME=STRINGSNP$CRORDER=2SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Alias: DefaultSNP$CRTYPE_NAME=STRINGSNP$CRORDER=3SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Data StorageSNP$CRTYPE_NAME=STRINGSNP$CRORDER=4SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Two Pass CalculationSNP$CRTYPE_NAME=STRINGSNP$CRORDER=5SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Account TypeSNP$CRTYPE_NAME=STRINGSNP$CRORDER=6SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Time BalanceSNP$CRTYPE_NAME=STRINGSNP$CRORDER=7SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Data TypeSNP$CRTYPE_NAME=STRINGSNP$CRORDER=8SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Variance ReportingSNP$CRTYPE_NAME=STRINGSNP$CRORDER=9SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Source Plan TypeSNP$CRTYPE_NAME=STRINGSNP$CRORDER=10SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Plan Type (FinStmt)SNP$CRTYPE_NAME=STRINGSNP$CRORDER=11SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Aggregation (FinStmt)SNP$CRTYPE_NAME=STRINGSNP$CRORDER=12SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Plan Type (WFP)SNP$CRTYPE_NAME=STRINGSNP$CRORDER=13SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=Aggregation (WFP)SNP$CRTYPE_NAME=STRINGSNP$CRORDER=14SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CRSNP$CRDWG_COLSNP$CRCOL_NAME=FormulaSNP$CRTYPE_NAME=STRINGSNP$CRORDER=15SNP$CRLENGTH=150SNP$CRPRECISION=150SNP$CR$$SNPS_END_KEY*/
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     C2_PARENT,
     C12_ALIAS__DEFAULT,
     C3_DATA_STORAGE,
     C9_TWO_PASS_CALCULATION,
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     C8_AGGREGATION__FINSTMT_,
     C15_PLAN_TYPE__WFP_,
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values
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     :C7_PLAN_TYPE__FINSTMT_,
     :C8_AGGREGATION__FINSTMT_,
     :C15_PLAN_TYPE__WFP_,
     :C4_AGGREGATION__WFP_,
     :C11_FORMULA
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decrypted_raw RAW (2000); -- stores decrypted binary text
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encryption_type PLS_INTEGER; -- total encryption type
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Thanks
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smith_apex wrote:
My client is using Java and they are saying that they are using this key for their AES256 Encryption and working fine. I have asked them to provide me 32 bytes key as in Oracle 256bit is 32 character string.
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BANNER
Oracle Database 10g Release 10.2.0.5.0 - Production
PL/SQL Release 10.2.0.5.0 - Production
CORE     10.2.0.5.0     Production
TNS for Linux: Version 10.2.0.5.0 - Production
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   output_string      VARCHAR2 (200);
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   decrypted_raw      RAW (2000);             -- stores decrypted binary text
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         key => key_bytes_raw
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         typ => encryption_type,
         key => key_bytes_raw
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32   33   34 /
Original string: Secret Message
Encryption Type: 4360
Key Bytes(RAW): 52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF
Encrypted string: 0BDDC2B94F7044700D85624297A39025
Decrypted string: Secret Message
PL/SQL procedure successfully completed.
SQL> select length('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF') from dual ;
LENGTH('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF')
                                             64
SQL> select dump('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF') from dual ;
DUMP('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF')
Typ=96 Len=64: 53,50,69,67,54,54,53,48,56,70,68,70,49,69,53,68,69,53,70,68,51,56,69,67,50,52,54,55,70,65,65,57,49,48,48,57,66,55,51,56,65,50,57,50,54,65,65,56,55,48,69,49,
52,50,67,48,56,48,67,55,50,69,66,70Your example:
declare
   input_string       VARCHAR2 (200) := 'SomeText';
   output_string      VARCHAR2 (200);
   encrypted_raw      RAW (2000);             -- stores encrypted binary text
   decrypted_raw      RAW (2000);             -- stores decrypted binary text
   key_bytes_raw      RAW (32);               -- stores 256-bit encryption key
   encryption_type    PLS_INTEGER;          -- total encryption type
begin
   DBMS_OUTPUT.PUT_LINE ('Original string: ' || input_string);
   encryption_type :=   DBMS_CRYPTO.ENCRYPT_AES256 + DBMS_CRYPTO.CHAIN_CBC + DBMS_CRYPTO.PAD_PKCS5;
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   DBMS_OUTPUT.PUT_LINE ('Key Bytes(RAW): ' || key_bytes_raw);
   encrypted_raw := DBMS_CRYPTO.ENCRYPT
         src => UTL_I18N.STRING_TO_RAW (input_string, 'AL32UTF8'),
         typ => encryption_type,
         key => key_bytes_raw
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   decrypted_raw := DBMS_CRYPTO.DECRYPT
         src => encrypted_raw,
         typ => encryption_type,
         key => key_bytes_raw
   output_string := UTL_I18N.RAW_TO_CHAR (decrypted_raw, 'AL32UTF8');
   DBMS_OUTPUT.PUT_LINE ('Decrypted string: ' || output_string);
end;
27   28   29   30 /
Original string: SomeText
declare
ERROR at line 1:
ORA-06502: PL/SQL: numeric or value error: raw variable length too long
ORA-06512: at line 12
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Typ=96 Len=64: 101,105,99,99,109,107,106,100,57,52,106,102,103,110,105,119,48,51,108,106,107,100,108,102,117,116,99,110,118,51,50,48,57,107,102,106,100,54,55,48,50,51,106,
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Extract multiple data from long string

I am working in Crystal Reports XI looking at an SQL database. How can I pick up several different data bits from a realy long string? Each element I want is preceded by "Old Value =" or "New Value =". The problem is that there are up to 4 different sets of these "Old Value =", "New Value =" so I can only get the first set if I use "InStr" to find "Old Value =" or "New Value =".
Since they are preceded by unique headings like "RuntimeMinutes", I thought I could use "InStr" to find that "RuntimeMinutes" or whichever and then use that value as the location number nested in another "InStr" to find "New Value =" and nest it all in a "Mid" expression. But however I did it I got an error highlighting that "InStr" nested in "InStr" saying it was not an integer or the value was less than 1.
Any ideas?

The way that I'd deal with this is by creating formula fields for each value that you want to extract. In the sample below, I'm assuming your string looks something like this:
RuntimeMinutes OldValue=123 NewValue=234 DbReads OldValue=12345 NewValue=34567
The formula for {@Runtime Minutes Old Value} would then look like (basic syntax):
dim pos as number
' Find where RuntimeMunutes old and new values start:
pos = InStr({really long string}, "RuntimeMinutes")
' Find first OldValue after RuntimeMinutes:
pos = InStr(pos + 14, {really long string}, "OldValue") ' 14 = Len("RuntimeMinutes")
' Pull out the value:
formula = val(mid({really long string}, pos + 9,
Instr(pos + 9, {really long string}, " ") - pos - 9)) ' 9=Len("OldValue=")
And do the same for all of the other values you need.
HTH,
Carl

Loading a long string from a CSV

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