Looking data from more than one table and inserting into another.

Question

Hello,
I am giving you the Table structures as per my requirement..
CREATE TABLE TEMP_A
(NAME VARCHAR2(100) primary key);
CREATE TABLE TEMP_B
(STRUCTURE VARCHAR2(10));
CREATE TABLE TEMP_C
( NAME VARCHAR2(100),
STRUCTURE VARCHAR2(10),
VALUE VARCHAR2(10));
Alter table TEMP_C
add constraint fk_name_tempc foreign key(name) references TEMP_A(name)
INSERT INTO TEMP_A VALUES('SMITH');
INSERT INTO TEMP_A VALUES('ALLEN');
INSERT INTO TEMP_A VALUES('WARD');
INSERT INTO TEMP_A VALUES('JONES');
COMMIT;
INSERT INTO TEMP_B VALUES('IN');
INSERT INTO TEMP_B VALUES('IN_MIN');
INSERT INTO TEMP_B VALUES('IN_TYP');
INSERT INTO TEMP_B VALUES('IN_MAX');
INSERT INTO TEMP_B VALUES('DIP');
INSERT INTO TEMP_B VALUES('TIM');
COMMIT;
INSERT INTO TEMP_c VALUES('SMITH','C1','');
INSERT INTO TEMP_c VALUES('SMITH','C2','');
INSERT INTO TEMP_c VALUES('SMITH','D1','');
INSERT INTO TEMP_c VALUES('ALLEN','D2','');
INSERT INTO TEMP_c VALUES('ALLEN','R1','');
INSERT INTO TEMP_c VALUES('WARD','R2','');
COMMIT;
i want to say is it should insert into table 'TEMP_C' values as :
For 'SMITH' there should be (6 * 3) = 18 records.
( 6 distinct values of TEMP_B for SMITH to be inserted into TEMP_C against 'C1')
( 6 distinct values of TEMP_B for SMITH to be inserted into TEMP_C against 'C2')
( 6 distinct values of TEMP_B for SMITH to be inserted into TEMP_C against 'D1')
For 'ALLEN' there should be (6 * 2) = 12 records.
( 6 distinct values of TEMP_B for ALLEN to be inserted into TEMP_C against 'D2')
( 6 distinct values of TEMP_B for ALLEN to be inserted into TEMP_C against 'R1')
For 'WARD' there should be (6 * 1) = 6 records.
( 6 distinct values of TEMP_B for WARD to be inserted into TEMP_C against 'R2')
Like this if there are records for JONES also , it should also do the same way( Depending on the No. of records present
in the table 'TEMP_C' for 'JONES').
Thanks in advance,
Amkotz

Answer 1

Is this what you are looking for?
SQL> insert into temp_c (name, structure, value)
  2  select c.name, c.structure, b.structure
  3  from temp_a a, temp_c c, temp_b b
  4  where a.name = c.name
  5  ;
36 rows created.
SQL> select * from temp_c;
NAME    STRUCTURE  VALUE
SMITH   C1
SMITH   C2
SMITH   D1
ALLEN   D2
ALLEN   R1
WARD    R2
SMITH   C1         IN
SMITH   C1         IN_MIN
SMITH   C1         IN_TYP
SMITH   C1         IN_MAX
SMITH   C1         DIP
SMITH   C1         TIM
SMITH   C2         IN
SMITH   C2         IN_MIN
SMITH   C2         IN_TYP
SMITH   C2         IN_MAX
SMITH   C2         DIP
SMITH   C2         TIM
SMITH   D1         IN
SMITH   D1         IN_MIN
SMITH   D1         IN_TYP
SMITH   D1         IN_MAX
SMITH   D1         DIP
SMITH   D1         TIM
ALLEN   D2         IN
ALLEN   D2         IN_MIN
ALLEN   D2         IN_TYP
ALLEN   D2         IN_MAX
ALLEN   D2         DIP
ALLEN   D2         TIM
ALLEN   R1         IN
ALLEN   R1         IN_MIN
ALLEN   R1         IN_TYP
ALLEN   R1         IN_MAX
ALLEN   R1         DIP
ALLEN   R1         TIM
WARD    R2         IN
WARD    R2         IN_MIN
WARD    R2         IN_TYP
WARD    R2         IN_MAX
WARD    R2         DIP
WARD    R2         TIM
42 rows selected.
SQL>