Meter removal date the same as estimated reading
meter removal date is the same as date of estiamated reading, but readings are not the same. system does not take into account removal reading (22)
Example:
meter (XXX) reason 22 RR 01 date 20.01.2011 reading 1000
meter (XXX) reason 01 RR 03 date 20.01.2011 reeading 900
difference on reading 1000-900 = 100 is never billed.
is this contoled on custo?
where?
Hi,
Meter removal reading does not create a billable billing order. So it will be taken into consideration for billing when you will be entering the next billable meter reading order.
If the property is a metered property, then you need to install a new meter on 21.01.2011. After few days / months you will be entering a periodic / interim meter for the new meter. Then SAP will consider the consumption of the old meter for billing.
The total consumption for billing will be the sum of old meter consumption + new meter consumption.
Where old meter consumption will be (1000- 900) = 100
And new meter consumption will be ( Schedule periodic reading / interim reading - meter reading during meter installation).
Hope it clarifies.
Thanks.
Nirmalya
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Generat two signals at the same time and reading voltage
Hii
i have try to generate two signals at the same time and read voltage from another port on the board(not have to be at the same time), i have not alot of expriens in labview
and i based my code of example(http://zone.ni.com/devzone/cda/epd/p/id/5197) from yours site and try to suit to my needs
now my problem is when i generat the 2 signals(that work perfect) i canot read voltage from another port on my CB-68LP
i can not find the problem and make it over i hope there is away to figer out and fix it.
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labview 8.5.
my code is look like this - http://img142.imageshack.us/my.php?image=scrennshot2no2.png
(this works perfect).
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the exception-
Possible reason(s):
Specified route cannot be satisfied, because it requires resources that are currently in use by another route.
Property: RefClk.Src
Source Device: Dev1
Source Terminal: 10MHzRefClock
Required Resources in Use by
Task Name: _unnamedTask<0>
Source Device: Dev1
Source Terminal: None
Destination Device: Dev1
Destination Terminal: RefClock
Task Name: _unnamedTask<1>
eyalsorry...
The AO tasks is very important they will be synchronize ,it is very importent the two tasks will start at the same time
and after it run at synchronize mode i will need to make reading of voltage
i gust try to make simulation of machin (i give that machin AO and reading from it voltage that all)
first of all i make the two signals(synchronize signals).
and after it i will need to reading voltage.
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i can make reading voltage
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it throw to me this error message.
i am looking for away to figer this out.
thank's for any help
eyal
Attachments:
test11.vi 130 KB -
Shared variable, missing data, the same timestamp for two consecutively data
hello
I have a problem with missing data when I read from a network published shared variable.
Host VI:
In a host VI on my Laptop (HP with WinXP Prof.) i'm writing data to the shared Variable "data". Between two consecutively write operations is a minimum of Milliseconds waiting time. I use that because I want to be sure that the timestamp for each new data value is different then the preview one (resolution shared variables is 1 ms)
Target VI:
the Target VI on a cRIO-9012 realtime device is reading only new data in the way that it compares the timestamp of a new value with the timestamp from the last value.
Problem:
rarely, I'm missing a datapoint (sometimes everything works fine for several hours, transferring thousands of data correctly before suddenly the failure happens). With some workaround I'm able to catch the missing data. I've discovered that the missing data has the exactly same timestamp then the last readed datapoint, therefore is ignored in my "legal" data.
To sum up, the missed value is written to the shared variable in the host, but the target ignores him because his timestamp is wrong, respectively the same as the last value has, despite the host waits every time for a minimum of 10 milliseconds before writing a new value.
Note:
The shared Variable is hosted on the Laptop and configured using buffering.
The example is simplified only to show the principle function, in real I use also a handshaking and I secure that there is no over- and underflow.
Simplified Example:
Question:
Has someone an idea why two consecutively data can have the same timestamp ?
Where is the (wrong) timestamp finally coming from (system?) ?
What would be a possible solution (at the moment with shared Variables) ?
-> I tried a workaround with clusters where each data gets a unique ID. It works but it is slower than comparing timestamps and I could get performance problems.
Would it change something when I host the shared Variable on the RT-System ?
Thanks for your help
Regards
Reto
Solved!
Go to Solution.Hi Reto,
I had a look on your modified Example.
Because the Shared Variables didn`t work like Queues or Notifiers (No Event or Interrupt when a new value has been written. And for sure the´re not possible over a network) you will see the issue, that the code is reading the values more often with the same timestamp (Polling Problematic) if the reader is faster then the writer. And because the timestamp is written with the value you´re able to program like you do. Filter out whats duplicated when you have the same timestamp.
Everything is described in here:
http://zone.ni.com/devzone/cda/tut/p/id/4679#toc1
Laurent talked about a second depth of buffer. Please have also a look at the link. Somewhere in the middle of the tutorial you see the explanations of Buffer and RT-Buffer.
Regarding your question: Would it change something when I host the shared Variable on the RT-System? --> No
In my experiences, you should consider to place the Shared Variable Engine after asking some questions regarding the application.
You will find the Answers to this 3 Questions also in the link:
Does the application require datalogging and supervisory functionality?
Does the computing device have adequate processor and memory resources?
Which system is always online?
And you`re right the smalles time interval you can see in the timestamp is 1ms.!
What you also can do is working with an enabled "timed out". This might be more performance efficient than reading the timestamp.
What I don`t know and not find up to now, is if LabVIEW or the OS adds the timestamp. It´s taken from the system time, this looks like LabVIEW is taking the value and adds it.
I hope this helps
Alex
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"Adam Russell" escribió en el mensaje
news:bkavdl$rd021$[email protected]..
> Create local variables from the control (or indicator) and you can make
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>
> "Urban" wrote in message
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> > I don't know how to use the same variable in a .vi like an indicator and
a
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Hi,
I've tried to understand the Oracle Read-Ahead systems, and I think I undersand how it works, though I'd like to assert that I am not mistaken.
From what I've managed to understand in the Oracle documentation, the Oracle read-ahead mechanism is mostly used for sequential accesses of data blocks. For example, to perform operations like table scans.
In such cases, Oracle will for example use a physical operation called scattered read.
The scattered read, in turn, is configured in the ini.ORA by a parameter name something like db_multiblock_read_count. Having a multiblock read count of 60, will make the scattered read operation read 60 sequential data blocks from disk, starting with the data block that was requested in the operation.
From what I've gathered, this is the basis of the Read-ahead mechanism. It is use mult block operations do read data instead of single bock operations.
If what I've said so far is correct. There are two things that I'd like to know:
1.
Those 60 blocks read by the sctarred read. Do they go directly into the database buffer cache? Or are they loaded first in to a lower level cache, like a scattered read cache?
Thus, if the table scan requested the page 1. And the scattered read operation fetched the database pages 1 to 60. I assume that only page 1 would be transfered to the buffer cache. Later on, when the table scan requested for page 2, the buffer cache would retrieve that page from the scattered read cache into the buffer cache. Or is this completly wrong? And when the scattered read gets pages 1 to 60. It automatically dumps those data pages into the buffer cache into random positions of the main buffer?
2.
With Oracle read-ahead, table scans and other such physical operations will always incur scattered read waits periodically. For example, every 60 pages the table scan incurs in another scattered read wait correct?
3.
Reading-ahead In oracle only anticipates the database page needs of a physical operator a specific point in time, yes? The following does not happen:
While the table scan is currently on page 50, having another 10 more pages left in the database buffer, some background process decides that it is a good idea request another fetch for 50 more data pages. In such a way that the forground thread processing the table scan never has stop in read IO.
This would be called looking-ahead, and it is not an Oracle feature, is it?
Thank you for your insight.
I've performed some tests where though the table size of a data transformations remain the same (1GB) but the time I take to process the source table into my output varies. The processing time for each record increased greatly from test to test. But I noticed that the wait time of the data transformation remained constant, though the cpu time increased greatly. THe increase in CPU time means that the Time Until Next Buffer fetch was reduced, which would give more time for the system to look-ahead. Eventally I could have made the CPU time so great, that if REad IO was being performed in anticipation it would be theortically possible for the READ wait time to be 0. Which I know is not going to happen. So I'd just to be certain of how the read-ahead works.
My best regards.sono99 wrote:
Hi,
I've tried to understand the Oracle Read-Ahead systems, and I think I undersand how it works, though I'd like to assert that I am not mistaken.
From what I've managed to understand in the Oracle documentation, the Oracle read-ahead mechanism is mostly used for sequential accesses of data blocks. For example, to perform operations like table scans.
In such cases, Oracle will for example use a physical operation called scattered read.
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From what I've gathered, this is the basis of the Read-ahead mechanism. It is use mult block operations do read data instead of single bock operations.
Am not sure if you meant reading multiple blocks at the same time or Read ahead cache features provided by some storage devices. But to me it seems you are talking about MBRC (Multiblock read count) and not about read ahead cache provided by storage vendors.
If what I've said so far is correct. There are two things that I'd like to know:
1.
Those 60 blocks read by the sctarred read. Do they go directly into the database buffer cache? Or are they loaded first in to a lower level cache, like a scattered read cache?
Thus, if the table scan requested the page 1. And the scattered read operation fetched the database pages 1 to 60. I assume that only page 1 would be transfered to the buffer cache. Later on, when the table scan requested for page 2, the buffer cache would retrieve that page from the scattered read cache into the buffer cache. Or is this completly wrong? And when the scattered read gets pages 1 to 60. It automatically dumps those data pages into the buffer cache into random positions of the main buffer?
If my mbrc is 60, and none of the blocks are in buffer and table size is more than 60 blocks then entire 60 blocks would get transferred to buffer cache. There is nothing called scattered read cache in the architecture of Oracle.
2.
With Oracle read-ahead, table scans and other such physical operations will always incur scattered read waits periodically. For example, every 60 pages the table scan incurs in another scattered read wait correct?
Yes db file scattered read wait event would mean that another physical IO has been initiated for fetching next blocks of records.
3.
Reading-ahead In oracle only anticipates the database page needs of a physical operator a specific point in time, yes? The following does not happen:
While the table scan is currently on page 50, having another 10 more pages left in the database buffer, some background process decides that it is a good idea request another fetch for 50 more data pages. In such a way that the forground thread processing the table scan never has stop in read IO.
This would be called looking-ahead, and it is not an Oracle feature, is it?
Yes I do not think so it is an Oracle feature but some storage vendor provides it. It is also known as Read ahead.
Thank you for your insight.
I've performed some tests where though the table size of a data transformations remain the same (1GB) but the time I take to process the source table into my output varies. The processing time for each record increased greatly from test to test. But I noticed that the wait time of the data transformation remained constant, though the cpu time increased greatly. THe increase in CPU time means that the Time Until Next Buffer fetch was reduced, which would give more time for the system to look-ahead. Eventally I could have made the CPU time so great, that if REad IO was being performed in anticipation it would be theortically possible for the READ wait time to be 0. Which I know is not going to happen. So I'd just to be certain of how the read-ahead works.
My best regards.I did not understood your last para.
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