Months between two date
There two ways of finding months between two dates
ROUND((Date1 – Date2) / 365.25 * 12,2) and
ROUND(months_between(date1,date2),2) There is a slight difference between output from these two.
I think the result from the second statement should be more accurate, confirm?
Abhishek
AbSHeik wrote:
There two ways of finding months between two dates
ROUND((Date1 – Date2) / 365.25 * 12,2) and
ROUND(months_between(date1,date2),2) There is a slight difference between output from these two.
I think the result from the second statement should be more accurate, confirm?
AbhishekHi Abhishek,
I also agree with this.
Coz 365.25 = (365 + (1/4))
This 0.25 actually the extra year of a Leap Year, distributed equally among 4 years. But, when the 1st formula is evaluated, the calculation might cause difference...
So as far as Oracle is concerned, MONTHS_BETWEEN should be used.
Please rectify me if i'm wrong.
Ranit B.
Similar Messages
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How to Calculate number of months between two dates
Hi All,
In one of the fomr developments, I have to calculate the
Number of Days
Number of Months ( Considering Leap Year) provided by the dates, end user enters in the form,
After going thorugh some forum discussion, I have come to know about so many things which were not clear till now.
I have gone through various forums too, some one suggets to make use of FORM CALC and some other JAVA SCRIPT. But the logic i want to build in java script.
The most interesting point is the DATE object is not getting created when i write the below code
var startDate = new DATE(oYear, oMonth, oDay);
I am still not clear, that really the date object gets created in Adobe form If so the why the alert box is getting populated when i write below lines
var oTemp = startDate.getFullYear();
xfa.host.messagebox(oTemp);
So, there are so many unclear things,
If any one can help me by suggesting the approach and how to build the logic in the JavaScript I would be really thankful
Regards
PavanChandHi,
ChakravarthyDBA wrote:
Hi
I want number of Sundays between two dates
example
number of Sundays count between '01-04-2013' and '30-04-2013' in one select query I have to include this as sub query in my select statement.Here's one way:
SELECT early_date
, late_date
, ( TRUNC (late_date + 1, 'IW')
- TRUNC (early_date, 'IW')
) / 7 AS sundays
FROM table_x
;This does not depend on your NLS settings.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only), and also post the results you want from that data.
Point out where the statment above is getting the wrong results, and explain, using specific examples, how you get the right results from the given data in those places.
Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
See the forum FAQ {message:id=9360002} -
Need Help on List of Months between Two Dates
Hello everyone,
I have a table which has startdate & enddate, and need a SELECT statement to list all months between these two dates for each given ID.
I did some test, and could not figure out how to get the startdate & enddate from testing table (instead of hard code them) in the select statement.
Could anybody please help on it (Oracle 11gR2),
Thanks in advance!!!
create table testing(
id number,
start_date date,
end_date date);
insert into testing values(100, to_date('05-FEB-2011', 'DD-MON-YYYY'), to_date('28-MAY-2011', 'DD-MON-YYYY'));
insert into testing values(200, to_date('20-JUN-2011', 'DD-MON-YYYY'), to_date('28-DEC-2011', 'DD-MON-YYYY'));
commit;
select * from testing;
ID START_DAT END_DATE
100 05-FEB-11 28-MAY-11
200 20-JUN-11 28-DEC-11
Elapsed: 00:00:00.01
*for testing.id = 100:*
select to_char(add_months(to_date('05-FEB-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
from (select level l
from dual
connect by level <= months_between(trunc(to_date('28-MAY-2011', 'DD-MON-YYYY'), 'MONTH'),
trunc(to_date('05-FEB-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);
DATES
2011-Feb
2011-Mar
2011-Apr
2011-May
Elapsed: 00:00:00.01
*for testing.id = 200:*
select to_char(add_months(to_date('20-JUN-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
from (select level l
from dual
connect by level <= months_between(trunc(to_date('28-DEC-2011', 'DD-MON-YYYY'), 'MONTH'),
trunc(to_date('20-JUN-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);
DATES
2011-Jun
2011-Jul
2011-Aug
2011-Sep
2011-Oct
2011-Nov
2011-Dec
7 rows selected.SQL> select * from testing
2 /
ID START_DAT END_DATE
100 05-FEB-11 28-MAY-11
200 20-JUN-11 28-DEC-11
SQL> select id,
2 to_char(add_months(start_date,column_value - 1),'YYYY-Mon') dates
3 from testing,
4 table(
5 cast(
6 multiset(
7 select level
8 from dual
9 connect by add_months(trunc(start_date,'MM'),level - 1) <= end_date
10 )
11 as sys.OdciNumberList
12 )
13 )
14 order by id,
15 column_value
16 /
ID DATES
100 2011-Feb
100 2011-Mar
100 2011-Apr
100 2011-May
200 2011-Jun
200 2011-Jul
200 2011-Aug
200 2011-Sep
200 2011-Oct
200 2011-Nov
200 2011-Dec
11 rows selected.
SQL> SY. -
Create a table with all the months between two dates
Hi all,
I have a purchase table recording individual purchases. One of the fields is my Date field (date of purchase).
I would like to create a table 'All_months' with two entries ('month_no' and 'month') which will be based on the first and last date in the purchase table. Assuming the first purchase recorded in my purchase table was on the 12th of January 2008, the table should have the following structure:
month_no month
1 12JAN2008
2 12FEB2008
3 12MAR2008
It should continue in this fashion up-to the month where the last purchase was recorded.
I have been struggling with creating the query that would do that for days now and can't find anything when asking Mr Google.
Thanks,
ChrisWelcome to the forum!
Here's one way:
CREATE TABLE all_months
AS
SELECT LEVEL AS month_no
, ADD_MONTHS ( first_date
, LEVEL - 1
) AS month
FROM (
SELECT MIN (date_of_purchace) AS first_date
, MAX (date_of_putchase) AS last_date
FROM purchase
CONNECT BY LEVEL <= 1 + MONTHS_BETWEEN ( TRUNC (last_date, 'MONTH')
, TRUNC (first_date, 'MONTH')
;Do you really need a table like this? Every time you change the data in the purchase table, you won't know if all_months is still accurate or not. You can derive all_months in a sub-query every time you need it, or make all_months a view instead of a table.
Edited by: Frank Kulash on Jun 14, 2012 5:57 AM -
Calculation of MONTHS , YEARS , & DAYS between two dates
Hi Experts,
Currently i am using this functional Module. which calculates the number of months between two dates.
CALL FUNCTION 'FIMA_DAYS_AND_MONTHS_AND_YEARS'
EXPORTING
I_DATE_FROM = ITAB_PER-BEGDA
I_DATE_TO = ITAB_PER-ENDDA
IMPORTING
E_MONTHS = CMONTHS.
BUT this functional module Rounding off the Month...Say ..if the total numbr of days between from & to date is 105 it is showing as 4 months ...
<b>Is there any other Functional Module</b> ????which Calculates the EXACT MONTH between two dates...(in the above case the month is expected to be 3 only since it is 105 days only)..
Kindly help me regarding this....lakshimiraja,
You can use this function module.
report zrich_0003
no standard page heading.
data: duration_in_months type i.
parameters: s_date type sy-datum,
e_date type sy-datum.
call function 'DURATION_DETERMINE'
exporting
unit = 'MON'
factory_calendar = 'P6' " Your factory calendar
importing
duration = duration_in_months
changing
start_date = s_date
end_date = e_date
exceptions
factory_calendar_not_found = 1
date_out_of_calendar_range = 2
date_not_valid = 3
unit_conversion_error = 4
si_unit_missing = 5
parameters_not_valid = 6
others = 7.
write:/ duration_in_months.
Don't forget to reward if useful... -
How to calculate the month difference between two date char. in Query?
Customers would like to see how many months passed between two date type of characteristics (e.g., the month difference between the current date and the scheduled delivery date in the record) and put the result into the column as KF.
We would have to grab the fiscal year/period kind of value and then do the subtraction, e.g., if the current date value is 2/28/2008 and the scheduled delivery date value in the record is 12/01/2007, the correct result should be 2 month difference between these two date values, but could someone here give us the technical light on how to make this happen in query design?
Thanks and we will give you reward points for the correct anwsers!Hi Kevin,
The Badi is RSR_OLAP_BADI.
You can create an implementation using Transaction SE18.
The implementation is per cube and is defined in the filters.
In the Implementation you have the following methods :
1. Define : Here you will provide the Keyfigure you need as a virtual one.
2. Initilialize : Any Init Function you want to do.
3. Compute. This is called per datarecord and here you can cimpute your value.
Hope this helps.
Pralay Ahluwalia -
Find the difference between two dates for the specific month and year
Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition. -
How to get LASTDAY for each and every month between given dates..
Hi Friend,
I have a doubt,How to get LASTDAY for each and every month between given dates..
for ex:
My Input will be look like this
from date = 12-01-2011
To date = 14-04-2011
And i need an output like
31-01-2011
28-02-2011
31-03-2011
is there any way to achieve through sql query in oracle
Advance thanks for all helping friendsHere's a 8i solution :
select add_months(
trunc(
to_date('12-01-2011','DD-MM-YYYY')
,'MM'
, rownum ) - 1 as results
from all_objects
where rownum <= ( months_between( trunc(to_date('14-04-2011','DD-MM-YYYY'), 'MM'),
trunc(to_date('12-01-2011','DD-MM-YYYY'), 'MM') ) );
The above two query is worked in oracle 11GActually the first query I posted is not correct.
It should work better with
months_between(
trunc(to_date(:dt_end,'DD-MM-YYYY'),'MM'),
trunc(to_date(:dt_start,'DD-MM-YYYY'),'MM')
)Edited by: odie_63 on 12 janv. 2011 13:53
Edited by: odie_63 on 12 janv. 2011 14:11 -
Date difference between two dates
hi All,
i have to right a stored proc to find the difference between two dates.
for example of i give
startdate as 4/1/2015 and enddate 14/1/2015
i should get 1 year , 10 days and 0 months .
i have tried the DateDiff function but it does not calculate the leap year.
please help.DECLARE @from datetime
DECLARE @to datetime
SET @from = '20150104 8:00'
SET @to = '20150114 10:30'
SELECT DATEDIFF(minute,@from, @to) % 60 as Minutes
SELECT (DATEDIFF(minute,@from, @to) / 60) % 24 as Hours
SELECT DATEDIFF(minute,@from, @to) / (60 * 24) as Days
SELECT DATEDIFF(month,@from, @to) as Months
SELECT DATEDIFF(year,@from, @to) as Year
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List Months between a date range
Hi, I'm trying to list the months between a given date range in an ABAP report to generate a MIS report(ALV).. Say I have 2 date ranges, 01.01.2006 to 01.04.2006.. I want to list
Jan 2006
Feb 2006
Mar 2006
Apr 2006.. Any FM in SAP to get this OP..hi vivek,
use this function module to get months beween two dates
1. MONTHS_BETWEEN_TWO_DATES or
2. MONTHS_BETWEEN_TWO_DATES_NEW
please reward the point if you are satisfied with answer
thanks,
john. -
How can I calculate the maximum number of days between two dates in a range of dates?
I have a column of dates spanning the couse of a few months. I would like to know if I can calculate the maximum number of days between each row and display the highest number. I currently have another column that calculates the days betwen the rows and I am currently just looking at the totals and highlighting the highest period.
Is this possible? Any help or suggestions are appreciated.
Thank you,
TrevorThis sounds totally possible, Can you post a screen shot of your table to make responding more focused? If you mean you want to:
A) compute the difference (in days) between two date in the same row, then
B) find the max duration (in days)
Here is my take on this problem:
D2 = C2-B2
select D2 and fill down
F1=MAX(D)
to perform the conditional formatting (to highlight the max duration) select column D, then set up conditional formatting as shown in the 1st image -
How to calculate number of days between two date in Template design?
Hello guys
I have a situation where I have to create a template that returns data, and one of the thing of the existing report is that there is a column that is actually the number of days between start date and end date columns..
So in template, how would I be able to do the same? I have start date and end date columns on the template, now when I created another column using expression like end date - start date and preview the template, I am getting errors saying :
Caused by: oracle.xdo.parser.v2.XPathException: Cannot convert 03/31/2009 to number.
at oracle.xdo.parser.v2.XSLStylesheet.flushErrors(XSLStylesheet.java:1534)
at oracle.xdo.parser.v2.XSLStylesheet.execute(XSLStylesheet.java:521)
at oracle.xdo.parser.v2.XSLStylesheet.execute(XSLStylesheet.java:489)
at oracle.xdo.parser.v2.XSLProcessor.processXSL(XSLProcessor.java:271)
at oracle.xdo.parser.v2.XSLProcessor.processXSL(XSLProcessor.java:155)
at oracle.xdo.parser.v2.XSLProcessor.processXSL(XSLProcessor.java:192)
Please advice
ThanksHi
There is an extension function you can use, from the javadoc:
date_diff
public static long date_diff(java.lang.String format,
java.lang.String fromDate,
java.lang.String toDate,
java.lang.String locStr,
java.lang.String tzID)
Method to get the difference between two dates in the given locale. The dates need to be in "yyyy-MM-dd" format. This function supports only Gregorian calendar.
Parameters:
format - the format to which the difference is required; allowed formats are y (for Year), m(for month), w(for week), d(for day), h(for hour), mi(for minute), s(for seconds) and ms(for milliseconds)
fromDate - the first date
toDate - the second date
locStr - locale string -> lang-Territory
tzID - timezone ID ->http://java.sun.com/j2se/1.4.2/docs/api/java/util/TimeZone.html
Returns:
the difference in dates in the desired format
For example
<?xdoxslt:date_diff(‘d’,’2009-09-14’, ‘2009-09-20’,’en-US’,1)?>
give a result of 6
You can substitute in columns for the dates, just remember the date format required.
Regards
Tim -
I wanted to know how do you calculate the number of days between two dates
i wanted to know how do you calculate the number of days between two dates in java ? i get both the dates from the database. i guess there are many issues like leap year and Febuary having diff no of months ..etc.
thanks..
I solve my problem as
public class MyExample {
public static void main(String a[]) {
String stdate = "2009-03-01";
java.sql.Date currentDate = new java.sql.Date(System.currentTimeMillis());
java.sql.Date preDate = java.sql.Date.valueOf(stdate);
System.out.println(currentDate);
System.out.println(preDate);
// int dateCom = preDate.compareTo(currentDate);
// System.out.println(dateCom);
long diff = currentDate.getTime() - preDate.getTime();
int days = (int) Math.floor(diff / (24 * 60 * 60 * 1000));
System.out.println(days);
} -
How to calculate number of sundays and saturdays between two Dates
friends i want to calculate how many Sundays come in two Dates
i have tried following code which is hard coded i have to impliment method which can give me number of Sundays between two Dates
please help me
import java.util.Date;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Calendar ;
import java.util.GregorianCalendar;
public class DateDiffCalculator {
private static final SimpleDateFormat SDF = new SimpleDateFormat("yyyy-MMM-dd");
public DateDiffCalculator() {
public static Date getDate (String date) throws Exception {
//log.debug(" "+date);
return SDF.parse(date);
public static Date getDate (Date date) throws Exception {
// log.debug("date is "+date);
return getDate(SDF.format(date));
public static long getDiffInDays(Date d1,Date d2) {
boolean isdiffGreaterThanYear=false;
long diffInMilliSeconds=d1.getTime()-d2.getTime();
return diffInMilliSeconds/(1000*60*60*24);
public static int getYear(String date) {
//String[] day= {Sun,Mon,Tue,Wed,Thu,Fri,Sat};
Integer year=new Integer(date.substring(0,4));
return year.intValue();
public static int getMonth(String date) {
//String date.substring(5,7);
System.out.println(" "+date.substring(5,8));
String m= date.substring(5,8);
int month=0;
if(m.equalsIgnoreCase("Jan")) {
month=1;
if(m.equalsIgnoreCase("Feb")) {
month=2;
if(m.equalsIgnoreCase("Mar")) {
month=3;
if(m.equalsIgnoreCase("Apr")) {
month=4;
if(m.equalsIgnoreCase("May")) {
month=5;
if(m.equalsIgnoreCase("Jun")) {
month=6;
if(m.equalsIgnoreCase("Jul")) {
month=7;
if(m.equalsIgnoreCase("Aug")) {
month=8;
if(m.equalsIgnoreCase("Sep")) {
month=9;
if(m.equalsIgnoreCase("Oct")) {
month=10;
if(m.equalsIgnoreCase("Nov")) {
month=11;
if(m.equalsIgnoreCase("Dec")) {
month=12;
return month;
public static int getDay(String date) {
Integer day=new Integer(date.substring(9,11));
return day.intValue();
public static int getNumberofSundays(String d1,String d2) throws Exception {
//d1 is leave start date d2 is leave end date
// get object in Date form
Date date1=getDate(d1);
Date date2=getDate(d2);
// now get calender objects from it
GregorianCalendar c1= new GregorianCalendar(getYear(d1),getMonth(d1),getDay(d1));
GregorianCalendar c2= new GregorianCalendar(getYear(d2),getMonth(d2),getDay(d2));
// get period
long leavePeriod = getDiffInDays(date1,date2);
return 12; // it should return number of sundays but we type 12 to perform compilation
public static void main(String[] arg)throws Exception {
System.out.println(" "+getNumberofSundays("2005-Oct-07","2006-Mar-01"));
}thanks now i have modified the get Month Code
as follows
public static int getMonth(String date) {
//String date.substring(5,7);
System.out.println(" "+date.substring(5,8));
String m= date.substring(5,8);
int month=0;
if(m.equalsIgnoreCase("Jan")) {
month=0;
if(m.equalsIgnoreCase("Feb")) {
month=1;
if(m.equalsIgnoreCase("Mar")) {
month=2;
if(m.equalsIgnoreCase("Apr")) {
month=3;
if(m.equalsIgnoreCase("May")) {
month=4;
if(m.equalsIgnoreCase("Jun")) {
month=5;
if(m.equalsIgnoreCase("Jul")) {
month=6;
if(m.equalsIgnoreCase("Aug")) {
month=7;
if(m.equalsIgnoreCase("Sep")) {
month=8;
if(m.equalsIgnoreCase("Oct")) {
month=9;
if(m.equalsIgnoreCase("Nov")) {
month=10;
if(m.equalsIgnoreCase("Dec")) {
month=11;
return month;
but question remains same how to calculate number of Sundays Between 2 Dates -
No.of feb 29's between two dates
Hi,
I would like to calculate feb29's between two dates currently using connect by level but it causes performance issue(50M data to process)
(SELECT SUM(DECODE(TO_CHAR(start_date + LEVEL - 1,'dd-mon'),'29-feb',1,0)) FROM dual CONNECT BY LEVEL <= SYSDATE - start_date+1) 'NO.OF.FEB29'Using Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit
Thanks-Small change required..
with t as
(select sysdate-10000 start_dt,to_date('01-Mar-2012','dd-Mon-yyyy') end_dt from dual)
select start_dt,end_dt,st_year,end_year,sum(case when mod(yr,400)=0 then 1
when mod(yr,4) = 0 then 1
else 0 end) cnt
from( select start_dt,end_dt,st_year,end_year,st_year+rownum-1 yr
from (
select start_dt,end_dt,
extract(year from start_dt)+
case when extract(month from start_dt) < 3 then 0 else 1 end st_year,
extract(year from end_dt)+
case when extract(month from end_dt) >= 3 then 0 else -1 end end_year
from t)
connect by st_year+rownum-1 <= end_year
group by start_dt,end_dt,st_year,end_year
SQL> /
START_DT END_DT ST_YEAR END_YEAR CNT
11-may-1985 28-feb-2012 1986 2011 6
SQL> /
START_DT END_DT ST_YEAR END_YEAR CNT
11-may-1985 29-feb-2012 1986 2011 6
SQL> /
START_DT END_DT ST_YEAR END_YEAR CNT
11-may-1985 01-mar-2012 1986 2012 7Edited by: jeneesh on Sep 26, 2012 11:44 AM
formatted
Edited by: jeneesh on Sep 26, 2012 12:07 PM
Subqueries can be avoided, added for understanding purpose
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