More than 10 cards in a Snapshot Query
Can the 5.0 UI be changed to allow more than 10 cards to appear in a Snapshot Query? 10 is currently the largest value available in the dropdown.
Has anyone come up with a solution to this problem? In 4.5ws it was quite easy to fix.
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Query on a table runs more than 45mins(after stats) and same query runs 19secs(before stats - rebuild) - Not sure what the cause is.
- Analysed the explain the plan
- different explain plan used afterr stats gather.
Any idea what could be the cause with this kind of difference.
Thank you!What is the difference you see in the explain plan ? Where it spends most time. All these needs to be analysed.
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Can't SSAS engines make use of more than one aggregation to answer a query?!
I have a very simple cube (just for testing and training) . This cube contains two dimensions: [Dim Soccer Player] contains one attribute hierarchy [player name], the other dimension
is [Dim Match Acts] contains also one attribute [Acts] which has values like fouls, goals, saves, tackles… etc. And of course a Fact that contains one measure of Just Count ... that simple ... so this cube can
answers a question like how many goals scored by "Messi", for example ... a very simple trivial cube.
I'm testing aggregations and their effect. so first I've designed one aggregation (Aggregation 0) on the granularity level of [Player name], then
I run a query to get the count of ALL the[Acts] done by each [Player name] ... I've checked the SQL Profiler and I found that the aggregation was used.
Then I cleared the cache, and I run another query, but this time to get just the number of Fouls committed by each [Player name], I checked the Profiler but the Aggregation 0 was NOT used.
I went back to the aggregations design tab in BIDS, and I added another new aggregation (Aggregation 1) on the level of [Acts], so now I have two aggregation one on the granularity level of
[Player name] and the second on the level of the [Acts].... I cleared the cache again and rerun the last query. NONE of the aggregation was used!
In the third test I deleted Aggregation 1 and added [Acts] to Aggregation 0. so Aggregation 0 now on both [Player name] AND [Acts]... cleared the cache and rerun the last query. Aggregation
0 appeared again.
I just want to make sure (and if possible know why) the SSAS engine can't make use of and combine more than one aggregation to serve a query (point number 2), and that to design an aggregation
that will serve a query which contains attributes from different dimensions, I have to add ALL the attributes in that query in that one aggregation, like point 3 ... is this true?!I think you are on the right track. You need to include all the attributes used in one query in the same aggregation (like #3) for it to be used. Example #2 works as I would expect. Queries above the grain of the agg (query by player name and an agg by
player/act can be used) can be used. Queries below grain of the agg (example #2) can't use the agg.
http://artisconsulting.com/Blogs/GregGalloway -
How to use more than one ":1" in a ViewObject query
I have a ViewObject,which has a SQL glued below.In this sql I am using ":1" twice but while I try to run this sql I am getting this error message
"JBO-29000: Unexpected exception caught: oracle.jbo.SQLStmtException, msg=JBO-27122: SQL error during statement preparation."
SELECT * FROM ACTIVITIES
WHERE
SUB_TYPE_CODE =
case
when(:1 IS NULL) THEN SUB_TYPE_CODE ELSE :1
END
If I remove one :1 then it is working fine.
Can any one help me out plss?Hi,
you can use the bind variable more than once. Can you put your SQL into another query tool such as SQL Developer and run it?
ps, looking at your code what you may actually want its:
SELECT * FROM ACTIVITIES
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bit simpler?
Brenden -
More than 2 structures in a BEx query
Hi guys,
Is it possible to define more than 2 local/global STRUCTURE for a particular query ?Eugene mate,
Okay, so now I understood that I need one Structure just for Key Figure
Now, my precise question is this !
I need Profit Centre to be on my Row.
Here, I need to make 'Selections' where I make restrictions based on my Hierarchy such as Business Units, Function Units, Subsidiaries.
I also need Cost Elements to be on my Column.
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More than one card in an order
Can anyone figure out how to add more than one type of card to a single order to save on shipping?
Warren:
Welcome to the Apple Discussions. If it's anything like ordering books and calendars, no. Only one type of card per order. Be sure to post your request at the iPhoto feedback page,http://www.apple.com/feedback/iphoto.html.
G4 DP-1G, 1.5G RAM, 22 Display, 2-80G HD, QT 7.0.4P Mac OS X (10.4.4) Canon S400, i850 & LIDE 50, Epson R200, 2G Nano -
How to use between more than 3 times in a single query?
is there any other query to run this query??
SELECT IDSITE,IDVISIT,trim(initcap(page_path)),KEYWORDS,LOCATION_IP,REFERER_NAME,REFERER_URL,VISIT_ACTION_TIME,count(DISTINCT location_ip) from web_stats where idvisit between '441' and '456' and where idsite='1' and visit_action_time between '4-jun-11' and '6-jun-11' group by trim(initcap(page_path)) and order by visitid;
Edited by: 863765 on Jul 7, 2011 4:21 AM863765 wrote:
is there any other query to run this query??
SELECT IDSITE,IDVISIT,trim(initcap(page_path)),KEYWORDS,LOCATION_IP,REFERER_NAME,REFERER_URL,VISIT_ACTION_TIME,count(DISTINCT location_ip) from web_stats where idvisit between '441' and '456' and where idsite='1' and visit_action_time between '4-jun-11' and '6-jun-11' group by trim(initcap(page_path)) and order by visitid;That query doesn't even have valid syntax. Too many WHERE's and too many AND's and dates being treated as strings, and not the right number of grouping columns...
Something like this is more likely to work.
SELECT IDSITE
,IDVISIT
,trim(initcap(page_path))
,KEYWORDS
,LOCATION_IP
,REFERER_NAME
,REFERER_URL
,VISIT_ACTION_TIME
,count(DISTINCT location_ip)
from web_stats
where idvisit between '441' and '456'
and idsite='1'
and visit_action_time between to_date('04-jun-2011','DD-mon-YYYY') and to_date('06-jun-2011','DD-mon-YYYY')
group by IDSITE
,IDVISIT
,trim(initcap(page_path))
,KEYWORDS
,LOCATION_IP
,REFERER_NAME
,REFERER_URL
,VISIT_ACTION_TIME
order by visitid;Note: assuming visit_action_time is a DATE datatype, the comparison should be against DATE datatypes also, rather than strings, so you should use TO_DATE to conver those strings to dates. It's also good practice to use 4 digit years rather than 2 digit years, as we had to solve all the 2 digit year millenium bug issues back in the late 90's; we don't want to have to do that again now do we? -
HT204364 How do I purchase more than one card at a time?
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ThanksYou can't. Apple will ship multiple cards of the same project together but not multiple card projects.
OT -
Group by returning more than one column in a single query
Hello,
Sorry to ask such a simple question I guess, but here is my problem.
I'm building a query to get say the smallest user_id from employees in the company by department.
The query goes like :
select emp..department,
min(emp.user_id)
from employee emp
group by emp.department
This gives me the smallest user id by department, which is what I want. But how can I also get the name of that person ?
I know that the "min" condition singles out a unique record (there are no two persons with the same user_id in the department).
But how can I also get the name without turning the above query in a subquery that I would link to the employee table yet again ?
I know the following works but I don't think it's the best option:
select v1.department,
v1.user_id,
emp1.name
from employee emp1,
( select emp..department,
min(emp.user_id)
from employee emp
group by emp.department) v1
where emp1.user_id = v1.user_id
This is just an example of data. It is the principle that I don't quite get.
Any advice would be very much appreciated.
CyrilHi, Cyril,
To find the name of the person who has the lowest user_id
SELECT department
, MIN (user_id) AS lowest_user_id
, MIN (name) KEEP (DENSE_RANK FIRST ORDER BY user_id) AS person_with_lowest_user_id
FROM emp
GROUP BY department;"MIN (name)" above means that if there is a tie for the lowest user_id, then the contender with the first name will be chosen.
If you want to display several columns from the row with the lowest user_id, you have to have a separate "KEEP (DENSE_RANK ...)" expression for each column. In that case, you may find it easier to use the analytic RANK or ROW_NUMBER in a sub-query, like this:
WITH sub_query AS
SELECT department
, user_id
, name
, col2, col3, col4, col5
, RANK () OVER ( PARTITION BY department
ORDER BY user_id
) AS r_num
FROM emp
SELECT * -- or list all columns EXCEPT r_num
FROM sub_query
WHERE r_num = 1; -
Can't upload from more than one card
I recently upgraded to Snow Leopard, and now when I use Aperture 3, either in 32-bit or 64-bit mode, I can upload images from one of my CF cards just fine, but if I try to upload from a second card, everything looks like it's going to work fine, but then it doesn't upload any of the images. I have to quit and restart A3 and then it works fine for a card or two, and then the same thing. Any suggestions?
It is never recommended to erase memory cards in Aperture or any photo application. Best to Reformat in the camera. Can lead to errors saving in the camera, or maybe reduce recognizable free space for the camera. Perhaps it even has some lingering impact as you erase one card, and then immediately try to download from a new card?
I go a step further, and never eject the card in Aperture, but rather wait to eject with the Finder. This is due primarily to the fact that I use a Firewire CF reader, and had some suspicions about release of Firewire devices in Snow Leopard.
I would recommend that you cycle two or three cards where you wait and reformat in the camera, and then see if this behavior persists. I have never encountered any balkiness going from one card to other where I have need to download from multiple cards after shooting.
Ernie -
Ordering more than 1 card created in iPhoto
I have created 5 different personalised cards in iPhoto and want to order 1 of each. Is there any way to order multiple different cards? I don't want to pay £1.99 for delivery of each card when the cards only cost 66p each!
Any help much appreciated!
ThanksNo. Only multiple copies of the same card (or book or calendar) can go on the same order.
OT -
JMF more than one Card Sound installed
Hi !
I have 2 Sound Cards installed in my PC. How i can send audio to distinct Sound Cards ?
Is this possible with JMF ?
Thnx !Warren:
Welcome to the Apple Discussions. If it's anything like ordering books and calendars, no. Only one type of card per order. Be sure to post your request at the iPhoto feedback page,http://www.apple.com/feedback/iphoto.html.
G4 DP-1G, 1.5G RAM, 22 Display, 2-80G HD, QT 7.0.4P Mac OS X (10.4.4) Canon S400, i850 & LIDE 50, Epson R200, 2G Nano -
How to find out which sub query returns more than one row
Hi all,
Can any one give me clue ,how to find out which sub query returns more than one row in the following query .
/* Formatted on 2011/05/17 19:22 (Formatter Plus v4.8.8) */
SELECT a.*, ROWNUM AS rnm
FROM (SELECT DISTINCT '1' AS "Page View", ou.org_unit_name AS "Org",
prxm.mbr_idntfr AS "Beneficiary ID",
md.last_name
|| ', '
|| md.first_name AS "Beneficiary Name",
pci.idntfr AS "Tracking No.",
TO_CHAR (TRUNC (req.pa_rqst_date),
'MM/dd/yyyy'
) AS "Request Date",
sts.status_name AS "Status",
req.pa_rqst_sid AS "Request #",
prxm.mbr_sid AS "Mbr_sid",
TO_CHAR
(TRUNC (req.pa_revision_date),
'MM/dd/yyyy'
) AS "Last Updated",
TO_CHAR (psd.TO_DATE, 'MM/dd/yyyy') AS "TO_DATE",
prxpl.prvdr_lctn_iid AS "PRVDR_LCTN_IID",
pd.prvdr_sid AS "PRVDR_SID", 'Y' AS "State View",
DECODE
((SELECT DISTINCT pd.national_prvdr_idntfr
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid =
req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR'),
0, (SELECT prxplo.prvdr_lctn_idntfr
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid = req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR'),
NULL, (SELECT prxplo.prvdr_lctn_idntfr
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid = req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR'),
(SELECT DISTINCT pd.national_prvdr_idntfr
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid =
req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR')
) AS "NPI/ID",
DECODE
((SELECT pd.org_bsns_name
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid = req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR'),
NULL, (SELECT pd.last_name
|| ', '
|| pd.first_name
|| ' '
|| pd.middle_name
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid = req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR'),
(SELECT pd.org_bsns_name
FROM pa_request_x_provider_location prxplo
WHERE prxplo.pa_rqst_sid = req.pa_rqst_sid
AND prxplo.oprtnl_flag = 'A'
AND prxplo.pa_prvdr_type_lkpcd = 'RR')
) AS "Prvdr Name",
TO_CHAR (psd.from_date,
'MM/dd/yyyy'
) AS "Srvc From Date",
TO_CHAR (req.validity_start_date,
'MM/DD/YYYY'
) AS "Due Date",
(fn_get_busniess_days (TRUNC (req.validity_start_date))
) AS "Days<br>Left",
req.pa_mode_type_lkpcd AS "Source",
TO_CHAR (TRUNC (wmdtl.rtng_date),
'MM/dd/yyyy'
) AS "Assigned On",
NVL (wmdtl.assigned_to_user_name,
'Not Assigned'
) AS "Assigned To",
req.org_unit_sid AS "OrgUnitSid",
TO_CHAR
(wmdtl.modified_date,
'MM/dd/yyyy hh24:mi:ss'
) AS "WTRD_MODIFIED_DATE",
TO_CHAR (wmdtl.rtng_date,
'MM/dd/yyyy'
) AS "WTRD_RTNG_DATE",
req.status_cid AS "PA_STATUS_CID",
TO_CHAR (req.modified_date,
'MM/dd/yyyy'
) AS "PA_REQ_MODIFIED_DATE",
prs.state_pa_srvc_type_code
AS "STATE_PA_SRVC_TYPE_CODE",
wmdtl.wm_pa_task_rtng_dtl_sid
AS "WM_TASK_RTNG_DTL_SID",
wmdtl.assigned_to_user_acct_sid
AS "WTRD_Assigned_to_user_acct_sid",
(fn_get_busniess_days (TRUNC (req.validity_start_date))
) AS "Days<br>LeftSort",
wmdtl.assigned_to_org_unit_sid
AS "WTRD_Assigned_to_OrgUntSid",
DECODE
((SELECT COUNT (*)
FROM pa_request_status prs
WHERE prs.pa_rqst_sid = req.pa_rqst_sid
AND prs.status_cid = 5
AND prs.oprtnl_flag = 'I'),
0, 'N',
'Y'
) AS "SHOW_UTILIZATION"
FROM pa_request req,
pa_certification_identifier pci,
status sts,
pa_request_x_member prxm,
wm_pa_task_routing_detail wmdtl,
pa_service_date psd,
org_unit ou,
pa_request_service prs,
pa_request_x_provider_location prxpl,
provider_location pl,
provider_detail pd,
provider p,
mbr_dmgrphc md
WHERE req.oprtnl_flag = 'A'
AND req.status_cid NOT IN
(20, 30, 70, 25, 80, 96, 85, 5, 97, 98, 101)
AND req.org_unit_sid IN
(3057, 3142, 3058, 3143, 3059, 3144, 3060, 3145,
3061, 3146, 3062, 3147, 3063, 3148, 3064, 3149,
3065, 3150, 3066, 3151, 3067, 3152, 3068, 3153,
3069, 3154, 3070, 3155, 3071, 3156, 3072, 3157,
3073, 3158, 3074, 3159, 3075, 3160, 3076, 3161,
3077, 3162, 3078, 3163, 3079, 3164, 3080, 3165,
3081, 3166, 3082, 3167, 3083, 3168, 3084, 3169,
3085, 3170, 3086, 3171, 3087, 3172, 3088, 3173,
3089, 3174, 3090, 3175, 3091, 3176, 3092, 3177,
3093, 3178, 3094, 3179, 3095, 3180, 3096, 3181,
3097, 3182, 3098, 3183, 3099, 3184, 3100, 3185,
3101, 3186, 3102, 3187, 3103, 3003, 75000104,
75000108, 2006, 75000103, 75000102, 75000113,
75000111, 75000109, 2001, 2009, 75000105,
75000107, 2004, 2010, 2013, 2014, 2005, 2011,
75000112, 2002, 1001, 2012, 75000106, 2007,
75000101, 2003, 75000110, 2008, 3001, 3002, 3019,
3104, 3020, 3105, 3021, 3106, 3022, 3107, 3023,
3108, 3024, 3109, 3025, 3110, 3026, 3111, 3027,
3112, 3028, 3113, 3029, 3114, 3030, 3115, 3031,
3116, 3032, 3117, 3033, 3118, 3034, 3119, 3035,
3120, 3036, 3121, 3037, 3122, 3038, 3123, 3039,
3124, 3040, 3125, 3041, 3126, 3042, 3127, 3043,
3128, 3044, 3129, 3045, 3130, 3046, 3131, 3047,
3132, 3048, 3133, 3049, 3134, 3050, 3135, 3051,
3136, 3052, 3137, 3053, 3138, 3054, 3139, 3055,
3140, 3056, 3141)
AND req.pa_rqst_sid = prs.pa_rqst_sid
AND prs.oprtnl_flag = 'A'
AND prs.pa_rqst_srvc_sid = psd.pa_rqst_srvc_sid
AND psd.oprtnl_flag = 'A'
AND req.pa_rqst_sid = pci.pa_rqst_sid
AND pci.oprtnl_flag = 'A'
AND req.pa_rqst_sid = prxm.pa_rqst_sid
AND prxm.oprtnl_flag = 'A'
AND md.oprtnl_flag = 'A'
AND md.status_cid = 2
AND TRUNC (SYSDATE) BETWEEN md.from_date AND md.TO_DATE
AND prxm.mbr_sid = md.mbr_sid
AND ou.org_unit_sid = req.org_unit_sid
AND ou.oprtnl_flag = 'A'
AND req.pa_rqst_sid = prxpl.pa_rqst_sid
AND prxm.pa_rqst_sid = prxpl.pa_rqst_sid
AND pci.pa_rqst_sid = prxm.pa_rqst_sid
AND pci.pa_rqst_sid = wmdtl.subsystem_task_sid
AND pci.pa_rqst_sid = prxpl.pa_rqst_sid
AND prxpl.pa_prvdr_type_lkpcd = 'RR'
AND prxpl.oprtnl_flag = 'A'
AND req.status_cid = sts.status_cid
AND sts.status_type_cid = 3
AND sts.oprtnl_flag = 'A'
AND prxpl.prvdr_lctn_iid = pl.prvdr_lctn_iid
AND p.prvdr_sid = pd.prvdr_sid
AND p.prvdr_sid = pl.prvdr_sid
AND pd.oprtnl_flag = 'A'
AND pd.status_cid = 2
AND TRUNC (SYSDATE) BETWEEN pd.from_date AND pd.TO_DATE
AND wmdtl.subsystem_task_sid = req.pa_rqst_sid
AND wmdtl.subsystem_lkpcd = 'PA'
AND wmdtl.oprtnl_flag = 'A'
AND req.pa_rqst_date > (SYSDATE - 365)
ORDER BY TO_DATE ("Request Date", 'MM/dd/yyyy hh24:mi:ss') DESC,
"Beneficiary Name" ASC) a
WHERE ROWNUM < 102;regards,
P Prakash
Edited by: BluShadow on 17-May-2011 15:01
added {noformat}{noformat} tags around the code833560 wrote:
Can any one give me clue ,how to find out which sub query returns more than one row in the following query .This is why smaller, simpler queries are easier to work with than huge ones - when something like this goes wrong smaller queries are much eaiser to debug. Unfortunately using smaller, easier-to-work with queries is not always an option
Ganesh is right - you will have to dissect the big query bit by bit until you find the offending subquery. If there is another way I would like to find out about it too.
The easiest way to do this is probably to use block comments to isolate parts of the query bit by bit until you find the offending part. If you carefully examine the subqueries you might be able to figure out which one is returning multiple rows without commenting everything
Good luck! -
Query taking long time for EXTRACTING the data more than 24 hours
Hi ,
Query taking long time for EXTRACTING the data more than 24 hours please find the query and explain plan details below even indexes avilable on table's goe's to FULL TABLE SCAN. please suggest me.......
SQL> explain plan for select a.account_id,round(a.account_balance,2) account_balance,
2 nvl(ah.invoice_id,ah.adjustment_id) transaction_id,
to_char(ah.effective_start_date,'DD-MON-YYYY') transaction_date,
to_char(nvl(i.payment_due_date,
to_date('30-12-9999','dd-mm-yyyy')),'DD-MON-YYYY')
due_date, ah.current_balance-ah.previous_balance amount,
decode(ah.invoice_id,null,'A','I') transaction_type
3 4 5 6 7 8 from account a,account_history ah,invoice i_+
where a.account_id=ah.account_id
and a.account_type_id=1000002
and round(a.account_balance,2) > 0
and (ah.invoice_id is not null or ah.adjustment_id is not null)
and ah.CURRENT_BALANCE > ah.previous_balance
and ah.invoice_id=i.invoice_id(+)
AND a.account_balance > 0
order by a.account_id,ah.effective_start_date desc; 9 10 11 12 13 14 15 16
Explained.
SQL> select * from table(dbms_xplan.display);
PLAN_TABLE_OUTPUT
| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)|
| 0 | SELECT STATEMENT | | 544K| 30M| | 693K (20)|
| 1 | SORT ORDER BY | | 544K| 30M| 75M| 693K (20)|
|* 2 | HASH JOIN | | 544K| 30M| | 689K (20)|
|* 3 | TABLE ACCESS FULL | ACCOUNT | 20080 | 294K| | 6220 (18)|
|* 4 | HASH JOIN OUTER | | 131M| 5532M| 5155M| 678K (20)|
|* 5 | TABLE ACCESS FULL| ACCOUNT_HISTORY | 131M| 3646M| | 197K (25)|
| 6 | TABLE ACCESS FULL| INVOICE | 262M| 3758M| | 306K (18)|
Predicate Information (identified by operation id):
2 - access("A"."ACCOUNT_ID"="AH"."ACCOUNT_ID")
3 - filter("A"."ACCOUNT_TYPE_ID"=1000002 AND "A"."ACCOUNT_BALANCE">0 AND
ROUND("A"."ACCOUNT_BALANCE",2)>0)
4 - access("AH"."INVOICE_ID"="I"."INVOICE_ID"(+))
5 - filter("AH"."CURRENT_BALANCE">"AH"."PREVIOUS_BALANCE" AND ("AH"."INVOICE_ID"
IS NOT NULL OR "AH"."ADJUSTMENT_ID" IS NOT NULL))
22 rows selected.
Index Details:+_
SQL> select INDEX_OWNER,INDEX_NAME,COLUMN_NAME,TABLE_NAME from dba_ind_columns where
2 table_name in ('INVOICE','ACCOUNT','ACCOUNT_HISTORY') order by 4;
INDEX_OWNER INDEX_NAME COLUMN_NAME TABLE_NAME
OPS$SVM_SRV4 P_ACCOUNT ACCOUNT_ID ACCOUNT
OPS$SVM_SRV4 U_ACCOUNT_NAME ACCOUNT_NAME ACCOUNT
OPS$SVM_SRV4 U_ACCOUNT CUSTOMER_NODE_ID ACCOUNT
OPS$SVM_SRV4 U_ACCOUNT ACCOUNT_TYPE_ID ACCOUNT
OPS$SVM_SRV4 I_ACCOUNT_ACCOUNT_TYPE ACCOUNT_TYPE_ID ACCOUNT
OPS$SVM_SRV4 I_ACCOUNT_INVOICE INVOICE_ID ACCOUNT
OPS$SVM_SRV4 I_ACCOUNT_PREVIOUS_INVOICE PREVIOUS_INVOICE_ID ACCOUNT
OPS$SVM_SRV4 U_ACCOUNT_NAME_ID ACCOUNT_NAME ACCOUNT
OPS$SVM_SRV4 U_ACCOUNT_NAME_ID ACCOUNT_ID ACCOUNT
OPS$SVM_SRV4 I_LAST_MODIFIED_ACCOUNT LAST_MODIFIED ACCOUNT
OPS$SVM_SRV4 I_ACCOUNT_INVOICE_ACCOUNT INVOICE_ACCOUNT_ID ACCOUNT
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_ACCOUNT ACCOUNT_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_ACCOUNT SEQNR ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_INVOICE INVOICE_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_ADINV INVOICE_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_CIA CURRENT_BALANCE ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_CIA INVOICE_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_CIA ADJUSTMENT_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_CIA ACCOUNT_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_LMOD LAST_MODIFIED ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_ADINV ADJUSTMENT_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_PAYMENT PAYMENT_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_ADJUSTMENT ADJUSTMENT_ID ACCOUNT_HISTORY
OPS$SVM_SRV4 I_ACCOUNT_HISTORY_APPLIED_DT APPLIED_DATE ACCOUNT_HISTORY
OPS$SVM_SRV4 P_INVOICE INVOICE_ID INVOICE
OPS$SVM_SRV4 U_INVOICE CUSTOMER_INVOICE_STR INVOICE
OPS$SVM_SRV4 I_LAST_MODIFIED_INVOICE LAST_MODIFIED INVOICE
OPS$SVM_SRV4 U_INVOICE_ACCOUNT ACCOUNT_ID INVOICE
OPS$SVM_SRV4 U_INVOICE_ACCOUNT BILL_RUN_ID INVOICE
OPS$SVM_SRV4 I_INVOICE_BILL_RUN BILL_RUN_ID INVOICE
OPS$SVM_SRV4 I_INVOICE_INVOICE_TYPE INVOICE_TYPE_ID INVOICE
OPS$SVM_SRV4 I_INVOICE_CUSTOMER_NODE CUSTOMER_NODE_ID INVOICE
32 rows selected.
Regards,
Bathula
Oracle-DBAI have some suggestions. But first, you realize that you have some redundant indexes, right? You have an index on account(account_name) and also account(account_name, account_id), and also account_history(invoice_id) and account_history(invoice_id, adjustment_id). No matter, I will suggest some new composite indexes.
Also, you do not need two lines for these conditions:
and round(a.account_balance, 2) > 0
AND a.account_balance > 0
You can just use: and a.account_balance >= 0.005
So the formatted query isselect a.account_id,
round(a.account_balance, 2) account_balance,
nvl(ah.invoice_id, ah.adjustment_id) transaction_id,
to_char(ah.effective_start_date, 'DD-MON-YYYY') transaction_date,
to_char(nvl(i.payment_due_date, to_date('30-12-9999', 'dd-mm-yyyy')),
'DD-MON-YYYY') due_date,
ah.current_balance - ah.previous_balance amount,
decode(ah.invoice_id, null, 'A', 'I') transaction_type
from account a, account_history ah, invoice i
where a.account_id = ah.account_id
and a.account_type_id = 1000002
and (ah.invoice_id is not null or ah.adjustment_id is not null)
and ah.CURRENT_BALANCE > ah.previous_balance
and ah.invoice_id = i.invoice_id(+)
AND a.account_balance >= .005
order by a.account_id, ah.effective_start_date desc;You will probably want to select:
1. From ACCOUNT first (your smaller table), for which you supply a literal on account_type_id. That should limit the accounts retrieved from ACCOUNT_HISTORY
2. From ACCOUNT_HISTORY. We want to limit the records as much as possible on this table because of the outer join.
3. INVOICE we want to access last because it seems to be least restricted, it is the biggest, and it has the outer join condition so it will manufacture rows to match as many rows as come back from account_history.
Try the query above after creating the following composite indexes. The order of the columns is important:create index account_composite_i on account(account_type_id, account_balance, account_id);
create index acct_history_comp_i on account_history(account_id, invoice_id, adjustment_id, current_balance, previous_balance, effective_start_date);
create index invoice_composite_i on invoice(invoice_id, payment_due_date);All the columns used in the where clause will be indexed, in a logical order suited to the needs of the query. Plus each selected column is indexed as well so that we should not need to touch the tables at all to satisfy the query.
Try the query after creating these indexes.
A final suggestion is to try larger sort and hash area sizes and a manual workarea policy.alter session set workarea_size_policy = manual;
alter session set sort_area_size = 2147483647;
alter session set hash_area_size = 2147483647; -
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I am trying to add a photo to a card, but I can only print one at a time. How do I print more than one copy of a photo at a time?
Do you want to print more than one card or more than one photo on a card?
To print multiple photos on one page select the photos and print, select the printer, paper size, photo size (obviously the photos will have to be sized so the number you want will fit inclusing a small border) and click customize - in teh settings select multiple photos per page (the preview will reflect your selection) and click print - make any printer specific selections and click print to print
LN
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