Most recently entered records

Hi, I have table like below. I would like to return most recently entered records in the output.
I am able to write the query for most recently entered records, but i want to include all the table columns in the output.
can someone give me idea to write the query or view?
Thanks for help.
create table foo_a
          Key varchar2(10),
          Attr varchar2(100),
          Val varchar2(100),
          EntryDate date,
          EndDate date,
          EFDate date,
          ETDate date
DATA IN THE TABLE:
FS.1 || AAA || 200     || 31-DEC-2005 ||     31-DEC-2005 || 31-DEC-2005     || 31-DEC-2005
FS.1 || AAA     || 250     || 30-DEC-2005 || 31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.2 || BBB     || 300     || 12-JAN-2005 || 31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.1 || AAA     || 350     || 01-JAN-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.3 || CCC     || 200     || 09-FEB-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.3 || XXX     || 100     || 09-FEB-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.3 || YYY     || 100     || 10-FEB-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.3 || XXX     || 120     || 10-FEB-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.4 || aaa     || 'H'     || 02-FEB-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
FS.4 || aaa     || 'H'     || 11-FEB-2006 ||     31-DEC-2005 || 31-DEC-2005     ||     31-DEC-2005
QUERY:
select
     Key,
     Attr,
     max(EntryDate)
from
     foo_a
group by
     Key,Attr
OUTPUT FOR THE ABOVE QUERY:
KEY     ATTR     MAX(EntryDate)
FS.1 || AAA || 1/1/2006
FS.2 || BBB || 1/12/2006
FS.3 || CCC || 2/9/2006
FS.3 || XXX || 2/10/2006
FS.3 || YYY || 2/10/2006
FS.4 || aaa || 2/11/2006
OUTPUT I WANT IS:
KEY     ATTR     MAX(EntryDate)          ENDDATE          EFDATE               ETDATE
FS.1 || AAA || 1/1/2006 || 31-DEC-2005 || 31-DEC-2005 || 31-DEC-2005
FS.2 || BBB || 1/12/2006 || 31-DEC-2005 || 31-DEC-2005 || 31-DEC-2005
FS.3 || CCC || 2/9/2006 || 31-DEC-2005 || 31-DEC-2005 || 31-DEC-2005
FS.3 || XXX || 2/10/2006 || 31-DEC-2005 || 31-DEC-2005 || 31-DEC-2005
FS.3 || YYY || 2/10/2006 || 31-DEC-2005 || 31-DEC-2005 || 31-DEC-2005
FS.4 || aaa || 2/11/2006 || 31-DEC-2005 || 31-DEC-2005 || 31-DEC-2005

See the following link for a great discussion of this topic:
http://asktom.oracle.com/pls/ask/f?p=4950:8:::::F4950_P8_DISPLAYID:2165134263446

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Most recently inserted record

how can i get most recently inserted record?
note: there is no date columns.

It's possible, but not probable (given how your table is likely created).
TUBBY_ORCL?create table not_likely
2 (
3    column1 number
4 )
5 rowdependencies;
Table created.
Elapsed: 00:00:00.01
TUBBY_ORCL?
TUBBY_ORCL?begin
2    for i in 1 .. 100
3    loop
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5      commit;
6    end loop;
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8 /
PL/SQL procedure successfully completed.
Elapsed: 00:00:00.03
TUBBY_ORCL?
TUBBY_ORCL?select *
2 from not_likely
3 where ORA_ROWSCN =
4 (
5    select
6      max(ORA_ROWSCN)
7    from not_likely
8 );
           COLUMN1
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1 row selected.
Elapsed: 00:00:00.01Uses the pseudo column ORA_ROWSCN which increments with each commit performed against the table (as i've enabled row dependencies, otherwise it would track at the block level).
Assuming you don't have row dependencies enabled on your table, you could consider using flashback query if you know roughly when you are trying to compare to.
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Return most recent matching record on Sub Report

I am hoping there is an easier way to go about this.
REPORT 'A': I have already made a report (which will inevitably be a subreport) that only reports the first record of each Group2 (I used a counter formula and conditional suppress.) This enabled me to have a report full of only the most recent records.
As an example, let's say this first report contains Account#, Price, and Invoice Date (again, it only reports the most recent Invoice Date and corresponding price and account # - the other records for each account are supressed).
REPORT 'B': I have another report with Account Numbers and Category Numbers.
I want to Match the Account Numbers, lookup the numbers on the original report ('A'), and return the recent Prices and Invoice Dates to the 2nd report ('B'). So that Report B has Account#, Category#, Most Recent Price, & Most Recent Invoice Date.
A subreport has been my only idea because again, I only want the most recent prices from 'A' to report on 'B'. Any help is appreciated.
Edited by: Mara Nowak on Sep 4, 2008 9:39 AM

Mara,
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How to get most recent consecutive records with the same value

Hi,
Can someone please help me to solve my problem?
Below is my table
Prod_Code-----Purchase_date---Inv_number-------Inv_amt
MS_AV16850------18/01/2005-----------6575947----------------7.93
MS_AV16850------22/07/2005-----------7034012----------------51.82
MS_AV16850------04/01/2006-----------8719618----------------51.82
MS_AV16850------20/06/2006-----------9515864----------------104.69
MS_AV16850------16/04/2007-----------10353759----------------189.29
MS_AV16850------30/05/2007-----------10689899----------------189.29
MS_AV16850------06/01/2008-----------1653821----------------65.49
MS_AV16850------22/02/2009-----------10866311----------------189.29
I want my query to show the rows that has most recent purchase dates with same amount in consecutive purchase date.
So from the table above, the query should display:
Prod_Code-----Purchase_date---Inv_number-------Inv_amt
MS_AV16850------16/04/2007-----------10353759----------------189.29
MS_AV16850------30/05/2007-----------10689899----------------189.29
It should not get
MS_AV16850------16/04/2007-----------10353759----------------189.29
MS_AV16850------30/05/2007-----------10689899----------------189.29
MS_AV16850------22/02/2009-----------10866311----------------189.29
because inv_number 10866311 has a prvevious inv_amount of 65.49.
and not get this
MS_AV16850------22/07/2005-----------7034012----------------51.82
MS_AV16850------04/01/2006-----------8719618----------------51.82
because they are not the most recent purchase date even if they have the same inv_amount.
Thanks in advance.

Hi,
You're right; thanks for catching my mistake.
I changed the WHERE clause of the main query (including subquery there) to deal with that situation:
WITH     got_grp          AS
     SELECT      x.*
     ,      ROW_NUMBER () OVER ( ORDER BY      purchase_date )
            - ROW_NUMBER () OVER ( PARTITION BY inv_amt
                                         ORDER BY         purchase_date )     AS grp
--     ,      ROW_NUMBER () OVER ( ORDER BY      purchase_date )     AS r1
--     ,        ROW_NUMBER () OVER ( PARTITION BY inv_amt
--                                         ORDER BY         purchase_date )     AS r2
     FROM     table_x     x
SELECT     *     -- Or list all columns except grp
FROM     got_grp
WHERE     (inv_amt, grp) IN (
                           SELECT    MAX (inv_amt) KEEP (DENSE_RANK LAST ORDER BY MAX (purchase_date))
                    ,       MAX (MAX (grp))
                            FROM      got_grp
                            GROUP BY grp
                            ,       inv_amt
                            HAVING    COUNT (*)     > 1
;Thanks, too, for posting the sample data. Apparantly, you're more interested in solving this problem than OP is.
Edited by: Frank Kulash on Nov 22, 2010 1:36 PM
The r1 and r2 columns are not needed for the solution. You may want to display them, just to help see how the query works.

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Table Name: APPLICATION_MOVEMENT
Field 1: IS_WITH
Field 2: DATE_SENT
Field 3: APPLICATION_ID

This?
WITH application_movement AS
SELECT 1 application_id, 'Greg' is_with, to_date('01-jan-07') date_sent FROM dual
UNION ALL
SELECT 1 application_id, 'Steve' is_with, to_date('01-feb-07') date_sent FROM dual
UNION ALL
SELECT 2 application_id, 'Bill' is_with, to_date('01-feb-07') date_sent FROM dual
UNION ALL
SELECT 2 application_id, 'Fred' is_with, to_date('01-mar-07') date_sent FROM dual
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Need to retrieve the most recent record per deposit number

Can someone please show me a way to solve my problem or at least point me in the right direction.
I have a simple bibliography table called mdd_biblio that has 3 fields:
bib_mdd_no this is a deposit number
bib_upd_by person who updated the record
bib_upd_date date the record was updated (timestamp)
A deposit might have more than one bibliographic entry with either the same date or a newer date and, the deposit might have one or more person updating the bibliography
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The following query retrieves 1944 records (67 duplicates) and has eliminated 3000 duplicates but hasn't eliminated them all. Why?
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M64C/16-001 MDD 13-SEP-07
M64C/16-002 DPROUXE 30-NOV-07 *
M64C/16-002 MDD 13-SEP-07
M64C/16-002 MDD 13-SEP-07
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To Reiterate: What I really need is a simple query to retrieve the most recently edited record for each deposit number regardless of the updater's name. I need this in order to build a summary table from this and 15 other tables.
Thanks for any help you can give
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Usually it is done somehow like this
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          from mdd_biblio
where r = 1
order by bib_mdd_noRegards
Etbin

How to determine most recent date from the date column of internal table

Dear friends
would you like to tell me. how i determine the most recently changed record by looking at date and time from internal table i am not supposed to sort the table by date and time... I must check date and time with other records date and time to determine which record is most recently changed...
here the scenario is.
id idnumber chdate chtime
1 123456 20060606 135312
2 123456 20060606 135900
3 123456 20060606 132300
4 123457 20060606 140000
5 123457 20060606 142500
in the above scenario i must keep in my mind that the most recently changed record is identical to its idnumber i can say that:
the record should be fetched this way
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3 123456 20060606 132300
5 123457 20060606 142500
because here the id 3 is the most recently changed in the idnumber 123456
where id 5 is the most recently changed in the idnumber 123457
please help me to determin how i am supposed to carry out this task any suggestion, code will be great help of mine.
regards
Naim

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report zrich_0001.
types: begin of itab_type,
        id       type i,
        idnumber type i,
        chdate   like sy-datum,
        chtime   like sy-uzeit.
types: end of itab_type.
types: begin of itab_type2,
        id       type i,
        idnumber type i,
        index    type i,
        chdate   like sy-datum,
        chtime   like sy-uzeit.
types: end of itab_type2.
data: itab     type table of itab_type with header line,
      itab2    type table of itab_type2 with header line,
      prev_rec type itab_type.
data: v_id type i.
start-of-selection.
itab-id       = 1.
itab-idnumber = 123456.
itab-chdate   = '20060606'.
itab-chtime   = '135312'.
append itab. clear itab.
itab-id       = 2.
itab-idnumber = 123456.
itab-chdate   = '20060606'.
itab-chtime   = '135900'.
append itab. clear itab.
itab-id       = 3.
itab-idnumber = 123456.
itab-chdate   = '20060606'.
itab-chtime   = '142500'.
append itab. clear itab.
itab-id       = 4.
itab-idnumber = 123457.
itab-chdate   = '20060606'.
itab-chtime   = '140000'.
append itab. clear itab.
itab-id       = 5.
itab-idnumber = 123457.
itab-chdate   = '20060606'.
itab-chtime   = '120000'.
append itab.
clear itab.
<b> data: counter type i.
* Assign an index to each row per idnumber
loop at itab.
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    if sy-tabix > 1.
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      endif.
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sort itab2 by idnumber ascending
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delete adjacent duplicates from itab2 comparing idnumber.</b>
read table itab2 with key idnumber = '123456'.
write:/ itab2-chdate, itab2-chtime.
read table itab2 with key idnumber = '123457'.
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Regards,
Rich Heilman

Select most recent record prior to a target date

Let's say I have a set of unique records with the following dates:
11/15/08
11/30/08
Is it possible to select only the most recent record prior to a user-entered target date (e.g., 12/1/08)? So in this case, only the record dated 11/30/08 would be selected for the report.

Use the record selection formula like this
{Date field}<={?Date Parameter}
And also wrtite the group selection formula like this
{Date field}=maximum({Date field})
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Regards,
Raghavendra

Select "most recent" records in abap

Hi
how can I select the most recent records in a table by using the abap select statement.
Example: The 100 rows with the "highest" (most recent) sequence-numbers in a table with documents.
somehow like this:
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    INTO TABLE gt_doklist
    UP TO 100 ROWS
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Has anybody an idea?
Thanks in advance,
Willi

Actually I believe that all the answers are wrong.
I believe that there will never be a single statement. If you need to determine the last 100 records for a special user you first need to determine the highest document number.
this can be done by
select max( document_number ) into document_number from table where username = username.
Any descending sorting order or group by etc. will never make sure that you get the last one. For a simple reason What should the select statement look like that makes sure (in combination of any cursor applied)? Its impossible!
If you now need the latest 100 records for a single user its the same problem like buffered number ranges. There is no way to perform that task because there is no database routine or sql statement to do so. And 1.5 million records are too much to try out or select everything.
You could do an assumption that the last 100 for that user have been posted during the last 1000 or last 10.000 records, select them and filter out.
Alternative you can perform the following select statement for 100 times. Using an index on document number and user might not be such a performance killer if its only done for one user during his online dynpro process:
data: max_number type char10.
select max( documentnumber ) into max_number from table
where username = username into [structure].
max_number = max_number + 1.
do 100 times
select max( documentnumber ) from table intomax_number
where username = username and docnumber lt max_docnumber.
select * from [db_table] into [structure] where docnumber = max_number.
append [structure] to [table].
enddo.
Of course that just draft coding... apply if statements and so on...
Even though its pretty poor, its the only way to do. Any select statement will never garantee what records you will get if you do not restrict accordingly and if the restriction has to be made on document number, but if there is no way to get the max_number - [100 last records of this user], there is no solution using one statement.
Thats it.
Edited by: Rob Burbank on Feb 25, 2010 8:52 AM

Seelcting records with most recent date

Hello Friends
I am new to this group.
I am having a set of records as follows in a table
col1,col2, col3(dd/mm/yyyy)
1 abc 1/1/2007
1 def 2/1/2007
2 ghi 1/1/2007
2 --- 3/1/2007 (No value in col2)
3 jkl 1/1/2007
3 mno 4/1/2007
I would like the output as follows:
col1, col2,col3
1 abc 2/1/2007
2 3/1/2007
3 mno 4/1/2007
(ie with most recent update_dates)
How to implement this in SQL?

Double post.

Selcting records with most recent date

Hello Friends
I am new to this group.
I am having a set of records as follows in a table
col1,col2, col3(dd/mm/yyyy)
1 abc 1/1/2007
1 def 2/1/2007
2 ghi 1/1/2007
2 --- 3/1/2007 (No value in col2)
3 jkl 1/1/2007
3 mno 4/1/2007
I would like the output as follows:
col1, col2,col3
1 abc 2/1/2007
2 3/1/2007
3 mno 4/1/2007
(ie with most recent update_dates)
How to implement this in SQL?

or:
SQL> create table t
2 as
3 select 1 col1, 'abc' col2, date '2007-01-01' col3 from dual union all
4 select 1, 'def', date '2007-01-02' from dual union all
5 select 2, 'ghi', date '2007-01-01' from dual union all
6 select 2, null, date '2007-01-03' from dual union all
7 select 3, 'jkl', date '2007-01-01' from dual union all
8 select 3, 'mno', date '2007-01-04' from dual
9 /
Tabel is aangemaakt.
SQL> set autotrace on explain
SQL> select col1, col2, col3
2    from (select col1, col2, col3, row_number() over (partition by col1 order by col3 desc) rn
3            from t)
4   where rn = 1
5 /
      COL1 COL COL3
         1 def 02-01-2007 00:00:00
         2     03-01-2007 00:00:00
         3 mno 04-01-2007 00:00:00
3 rijen zijn geselecteerd.
Uitvoeringspan
   0      SELECT STATEMENT Optimizer=CHOOSE
   1    0   VIEW
   2    1     WINDOW (SORT PUSHED RANK)
   3    2       TABLE ACCESS (FULL) OF 'T' (TABLE)
SQL> select col1
2       , max(col2) keep (dense_rank first order by col3 desc) col2
3       , max(col3) col3
4    from t
5   group by col1
6 /
      COL1 COL COL3
         1 def 02-01-2007 00:00:00
         2     03-01-2007 00:00:00
         3 mno 04-01-2007 00:00:00
3 rijen zijn geselecteerd.
Uitvoeringspan
   0      SELECT STATEMENT Optimizer=CHOOSE
   1    0   SORT (GROUP BY)
   2    1     TABLE ACCESS (FULL) OF 'T' (TABLE)Regards,
Rob.

Choosing most recent records from multiple tables?

Let's say that you have two tables; one contains news
articles with the fields TITLE, ARTICLE, and a timestamp DATE and
the other contains different news articles with the fields TITLE,
DESCRIPTION, and a timestamp DATEPOSTED.
How would you go about selecting the (let's say) five most
recent articles with the corresponding fields? I'm relatively new
to CF but even the experienced guy in our office can't figure it
out. The following code is what we were working with -- which
doesn't quite work the way it should anyway -- but I'm thinking
there
must be an easier (or at least less convoluted) way.

Thank you so much! Azadi hit the nail on the head; I hadn't
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Select record having most recent date

Table: Order
Code ImportId EntryDate
1 100
10/11/2014
1 101
10/14/2014
1 102
10/10/2014
2 103 10/11/2014
2 104 10/15/2014
I want to select the record having the most recent EntryDate grouped by Code. In the select, i need to return the ImportId.
Anonymous

Please post DDL, so that people do not have to guess what the keys, constraints, Declarative Referential Integrity, data types, etc. in your schema are. Learn how to follow ISO-11179 data element naming conventions and formatting rules. Nothing you posted
was right. Temporal data should use ISO-8601 formats. This is the only format allowed in the ANSI-ISO SQL Standards and it is the most common IT standard on Earth; but you do not know it!
Code should be in Standard SQL as much as possible and not local dialect. There is no such crap as a generic “code” in RDBMS. Table have keys, so you have no table! Rows are not records; this is a basic concept.
This is minimal polite behavior on SQL forums. Here is my guess at what a polite, competent person might have posted.
CREATE TABLE Import_Orders
(order_type INTEGER NOT NULL
CHECK(order_type IN (1,2)),
import_id CHAR(3) NOT NULL PRIMARY KEY,
entry_date DATE NOT NULL);
INSERT INTO Import_Orders
VALUES
(1, 100, '2014-10-11'),
(1, 101, '2014-10-14'),
(1, 102, '2014-10-10'),
(2, 103, '2014-10-11'),
(2, 104, '2014-10-15');
I want to select the record [sic] having the most recent entry_date grouped by order_type. In the select, I need to return the import_id.
If you return only the import_id, then the most recent entry_date does not matter! Think about it! Did you want the whole row with the most recent entry_date? Here is a common idiom.
WITH X (import_id, order_type, entry_date, entry_date_max)
AS
(SELECT import_id, order_type, entry_date,
MAX(entry_date) OVER (PARTITION BY order_type)
FROM Import_Orders)
SELECT import_id, order_type, entry_date
FROM X
WHERE entry_date = entry_date_max;
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL

Select the Most Recent Record

I have a 2-page report that is grouped by employee, where the first page is a standard letter except for address, and the second page is a reproduction of a scanned form that the employee had returned. The employee may have returned several versions of the form over time, updating it each time.
I would like to have the report only pull in the most recent scanned image, ignoring all prior images. I'm struggling with the correct record selection criteria.
Any help would be appreciated.
Thank you.

Hi,
If you have any date field in the data base that updates the time whenever the image is updated then use that date field in the report-->record sort expert and use ascending order. Now place the image field from the data base in the group footer of Employee which shows the latest image. If you want the old one then goto record sort expert and change the order for date field to descending.
Regards,
Raghavendra

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