Select most recent record prior to a target date

Let's say I have a set of unique records with the following dates:
11/15/08
11/30/08
Is it possible to select only the most recent record prior to a user-entered target date (e.g., 12/1/08)?  So in this case, only the record dated 11/30/08 would be selected for the report.

Use the record selection formula like this
{Date field}<={?Date Parameter}
And also wrtite the group selection formula like this
{Date field}=maximum({Date field})
This returns the recent value nearer to the date entered in the prompt.
Regards,
Raghavendra

Similar Messages

  • Select "most recent" records in abap

    Hi
    how can I select the most recent records in a table by using the abap select statement.
    Example: The 100 rows with the "highest" (most recent) sequence-numbers in a table with documents.
    somehow like this:
        SELECT "most recent" * FROM draw
        INTO TABLE gt_doklist
        UP TO 100 ROWS
        where ...
    Has anybody an idea?
    Thanks in advance,
    Willi

    Actually I believe that all the answers are wrong.
    I believe that there will never be a single statement. If you need to determine the last 100 records for a special user you first need to determine the highest document number.
    this can be done by
    select max( document_number ) into document_number from table where username = username.
    Any descending sorting order or group by etc. will never make sure that you get the last one. For a simple reason What should the select statement look like that makes sure (in combination of any cursor applied)? Its impossible!
    If you now need the latest 100 records for a single user its the same problem like buffered number ranges. There is no way to perform that task because there is no database routine or sql statement to do so. And 1.5 million records are too much to try out or select everything.
    You could do an assumption that the last 100 for that user have been posted during the last 1000 or last 10.000 records, select them and filter out.
    Alternative you can perform the following select statement for 100 times. Using an index on document number and user might not be such a performance killer if its only done for one user during his online dynpro process:
    data: max_number type char10.
    select max( documentnumber ) into max_number from table
      where username = username into [structure].
    max_number = max_number + 1.
    do 100 times
    select max( documentnumber ) from table intomax_number
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    select * from [db_table] into [structure] where docnumber = max_number.
    append [structure] to [table].
    enddo.
    Of course that just draft coding... apply if statements and so on...
    Even though its pretty poor, its the only way to do. Any select statement will never garantee what records you will get if you do not restrict accordingly and if the restriction has to be made on document number, but if there is no way to get the max_number - [100 last records of this user], there is no solution using one statement.
    Thats it.
    Edited by: Rob Burbank on Feb 25, 2010 8:52 AM

  • How to select Most recent record with rest of record in ascending order...?

    Dear Expert,
    I have one table called Tab1 & have a lot columns. For this schenario, i mentioned few of the columns.
    The columns are
    product_type varchar2(100),
    curr_date date (storing with time stamp),
    other1_cloumn varchar2(10),
    other2_cloumn varchar2(10)
    Now I want to display all the records in ascending order except most recent record for every product_type || Union all || Most recent records in ascending order in single query.
    For example...
    product_type curr_date date other1_cloumn other2_cloumn
    1, "10-May-2005 10:10:10", 10, 10
    1, "10-May-2005 10:10:11", 10, 10
    1, "10-May-2005 10:10:12", 10, 10
    1, "10-May-2005 10:10:09", 10, 10
    2, "10-May-2005 10:10:10", 10, 10
    2, "10-May-2005 10:10:11", 10, 10
    2, "10-May-2005 10:10:12", 10, 10
    2, "10-May-2005 10:10:09", 10, 10
    3, "10-May-2005 10:10:10", 10, 10
    3, "10-May-2005 10:10:11", 10, 10
    3, "10-May-2005 10:10:12", 10, 10
    3, "10-May-2005 10:10:09", 10, 10
    Now I want to display (OUTPUT) like...
    1, "10-May-2005 10:10:10", 10, 10
    1, "10-May-2005 10:10:11", 10, 10
    1, "10-May-2005 10:10:09", 10, 10
    2, "10-May-2005 10:10:10", 10, 10
    2, "10-May-2005 10:10:11", 10, 10
    2, "10-May-2005 10:10:09", 10, 10
    3, "10-May-2005 10:10:10", 10, 10
    3, "10-May-2005 10:10:11", 10, 10
    3, "10-May-2005 10:10:09", 10, 10
    1, "10-May-2005 10:10:12", 10, 10
    2, "10-May-2005 10:10:12", 10, 10
    3, "10-May-2005 10:10:12", 10, 10
    Plz, provide a solution....

    I want to display like...
    select * from tab1 where (product_type,curr_date) in
    (select product_type,max(curr_date) from tab1 group by product_type)
    order by product_type
    Union All
    (select * from tab1 where (product_type,curr_date) NOT IN
    (select product_type,max(curr_date) from tab1 group by product_type)
    order by product_type)
    But, In the above case, The ORDER BY Clause will not work...How to get this one...?
    I mean.. I want to display all the records in ascending order except Most recent record base on Product type and next I want to display Most recent record in ascending order. I want to display both cases in a single query...?

  • Select the Most Recent Record

    I have a 2-page report that is grouped by employee, where the first page is a standard letter except for address, and the second page is a reproduction of a scanned form that the employee had returned.  The employee may have returned several versions of the form over time, updating it each time.
    I would like to have the report only pull in the most recent scanned image, ignoring all prior images.  I'm struggling with the correct record selection criteria. 
    Any help would be appreciated.
    Thank you.

    Hi,
    If you have any date field in the data base that updates the time whenever the image is updated then use that date field in the report-->record sort expert and use ascending order. Now place the image field from the data base in the group footer of Employee which shows the latest image. If you want the old one then goto record sort expert and change the order for date field to descending.
    Regards,
    Raghavendra

  • Need to retrieve the most recent record per deposit number

    Can someone please show me a way to solve my problem or at least point me in the right direction.
    I have a simple bibliography table called mdd_biblio that has 3 fields:
    bib_mdd_no this is a deposit number
    bib_upd_by person who updated the record
    bib_upd_date date the record was updated (timestamp)
    A deposit might have more than one bibliographic entry with either the same date or a newer date and, the deposit might have one or more person updating the bibliography
    The table has 4974 records but only 1867 are unique deposit numbers
    All I want to do is select a single record that indicates when the deposit was last edited and and who did the editing (as indicated by the *). I don't care which record it is as long as it is the most recent date.
    The following query retrieves 1944 records (67 duplicates) and has eliminated 3000 duplicates but hasn't eliminated them all. Why?
    select unique(bib_mdd_no), bib_upd_by, bib_upd_date from mdd_biblio
    order by bib_mdd_no
    M64C/16-001 MDD 13-SEP-07 *
    M64C/16-001 MDD 13-SEP-07
    M64C/16-002 DPROUXE 30-NOV-07 *
    M64C/16-002 MDD 13-SEP-07
    M64C/16-002 MDD 13-SEP-07
    M64C/16-003 DPROUXE 29-NOV-07 *
    M64C/16-003 MDD 13-SEP-07
    M64C/16-003 MDD 13-SEP-07
    M64C/16-004 MDD 13-SEP-07 *
    M64C/16-004 MDD 13-SEP-07
    M64C/16-005 MDD 13-SEP-07 *
    M64C/16-005 MDD 13-SEP-07
    M64C/16-006 DPROUXE 03-DEC-07 *
    M64C/16-006 MDD 13-SEP-07
    M64C/16-007 MDD 02-OCT-07 *
    M64C/16-008 MDD 02-OCT-07 *
    M64C/16-009 MDD 02-OCT-07 *
    M64C/16-010 MDD 02-OCT-07 *
    I don't understand why of these duplicates still show up here since 3000 have been eliminated..
    To Reiterate: What I really need is a simple query to retrieve the most recently edited record for each deposit number regardless of the updater's name. I need this in order to build a summary table from this and 15 other tables.
    Thanks for any help you can give
    Glenn

    Usually it is done somehow like this
    select bib_mdd_no,
           bib_upd_by,
           bib_upd_date
      from (select bib_mdd_no,
                   bib_upd_by,
                   bib_upd_date,
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              from mdd_biblio
    where r = 1
    order by bib_mdd_noRegards
    Etbin

  • Select most recent DATE for an ID.

    Hi All,
    I need to SELECT the records with the most recent DATE for each ID. A DATE range is part of the selection criteria.
    My data.
    MY_ID MY_DATE
    1684662 26-JAN-09
    1424097 27-JAN-09
    1684663 27-JAN-09
    1684664 27-JAN-09
    1684672 28-JAN-09
    0689073 28-JAN-09
    1052476 21-JAN-09
    1052476 21-JAN-09
    1360828 23-JAN-09
    1684661 23-JAN-09
    1052476 30-JAN-09
    1052476 30-JAN-09
    1052476 30-JAN-09
    1052476 30-JAN-09
    The code below works fine when selecting 1 ID in the SUBSELECT, but with multiple ID it still selects rownum=1 (of course). This as far as my thinking takes me.
    SELECT my_id,
    my_date
    FROM
    (SELECT my_id,
    my_date
    FROM my_table
    ORDER BY my_date DESC
    WHERE rownum = 1
    AND *{color:#ff0000}my_id = 1052476{color}*
    AND TO_CHAR(my_date,'YYYY/MM/DD') BETWEEN '2009/01/01' AND '2009/01/31';
    If I could somehow pass the SELECT ID into the SUBSELECT WHERE clause I should have this done.
    Any suggestions?
    Thank You in Advance for Your help,
    Lou

    One of many possible soultions.
    ME_XE?with data as
      2  (
      3     select 1684662 as id, to_date('26-JAN-09','dd-mon-yyyy') as the_date from dual union all
      4     select 1424097 as id, to_date('27-JAN-09','dd-mon-yyyy') as the_date from dual union all
      5     select 1684663 as id, to_date('27-JAN-09','dd-mon-yyyy') as the_date from dual union all
      6     select 1684664 as id, to_date('27-JAN-09','dd-mon-yyyy') as the_date from dual union all
      7     select 1684672 as id, to_date('28-JAN-09','dd-mon-yyyy') as the_date from dual union all
      8     select 0689073 as id, to_date('28-JAN-09','dd-mon-yyyy') as the_date from dual union all
      9     select 1052476 as id, to_date('21-JAN-09','dd-mon-yyyy') as the_date from dual union all
    10     select 1052476 as id, to_date('21-JAN-09','dd-mon-yyyy') as the_date from dual union all
    11     select 1360828 as id, to_date('23-JAN-09','dd-mon-yyyy') as the_date from dual union all
    12     select 1684661 as id, to_date('23-JAN-09','dd-mon-yyyy') as the_date from dual union all
    13     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual union all
    14     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual union all
    15     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual union all
    16     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual
    17  )
    18  select id, the_date
    19  from
    20  (
    21     select id, the_date, max(the_date) over (partition by id) as max_the_date
    22     from data
    23  )
    24  where the_date = max_the_date;
                    ID THE_DATE
                689073 28-JAN-0009 12 00:00
               1052476 30-JAN-0009 12 00:00
               1052476 30-JAN-0009 12 00:00
               1052476 30-JAN-0009 12 00:00
               1052476 30-JAN-0009 12 00:00
               1360828 23-JAN-0009 12 00:00
               1424097 27-JAN-0009 12 00:00
               1684661 23-JAN-0009 12 00:00
               1684662 26-JAN-0009 12 00:00
               1684663 27-JAN-0009 12 00:00
               1684664 27-JAN-0009 12 00:00
                    ID THE_DATE
               1684672 28-JAN-0009 12 00:00
    12 rows selected.
    Elapsed: 00:00:00.03

  • Choosing most recent records from multiple tables?

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  • Select Most recent Occurance

    Hi Friends,
    I have a strange requirement where in we need to select the most recent occurance of a record based on 2 columns, consider the below sample data:
    C1     C2     C3
    1234     0     abc
    1234     1     abc
    1234     0     def
    1234     1     def
    1345     20     fgh
    1345     30     fgh
    1345     20     ijk
    1345     30     ijk
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    C1     C2     C3
    1234     0     def
    1234     1     def
    1345     20     ijk
    1345     30     ijk
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    Please help me. Do let me know in case you need any thing.
    Thanks.

    Of course rowid not near always guarantees that:
    SQL> drop table t;
    Table dropped
    SQL> create table t as (
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      3  /
    Table created
    SQL> alter table t minimize records_per_block;
    Table altered
    SQL> insert into t
      2  select  1234, 1, 'abc' from dual union all
      3  select 1234, 0, 'def' from dual union all
      4  select 1234, 1, 'def' from dual union all
      5  select 1345, 20, 'fgh' from dual union all
      6  select 1345, 30, 'fgh' from dual union all
      7  select 1345, 20, 'ijk' from dual union all
      8  select 1345, 30, 'ijk' from dual
      9  /
    7 rows inserted
    SQL> select * from t;
            C1         C2 C3
          1234          0 abc
          1345         30 ijk
          1234          1 abc
          1234          0 def
          1234          1 def
          1345         20 fgh
          1345         30 fgh
          1345         20 ijk
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    SQL> select * from t where rowid in(
      2     select max(rowid) over(partition by c1,c2 order by null) from t
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            C1         C2 C3
          1234          0 def
          1234          1 def
          1345         30 fgh
          1345         20 ijk
    SQL> There is no guarantee that Oracle will insert your rows with continuously growing rowids especially if you have blocks with deleted rows, ASSM tablespaces etc. The only guarantee is to use some sequence column, because as I understand rows are inserted from flat file and therefore datetime also may be inappropriate due to the fact that rows can be inserted faster than datetime increases.
    See also this thread where a person had similar problem Row is changing position - ON INSERT
    Gints Plivna
    http://www.gplivna.eu

  • Select most recent date only

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    let me explain it to u in detail
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  • Select most recent post

    Hello everyone,
    I have 2 tables:
    - FORUM_MESSAGE
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    2 2 2 post 2 09/10/2005
    3 1 1 post 1 08/06/2005
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    but still does not compile If it does not compile there must be a compilation error. Please use cut'n'patse to snip your code and the results from SQL*Plus. Like this
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      2  /
    Table created.
    SQL>
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      2  /
    1 row created.
    SQL> INSERT INTO forum_user VALUES (2, 2, 'APC')
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    1 row created.
    SQL>
    SQL> CREATE TABLE forum_message (id number, forum_id number, user_id number , title varchar2(30), pd
    ate date)
      2  /
    Table created.
    SQL>
    SQL> INSERT INTO forum_message VALUES (1, 1, 1, 'post #1' ,to_date('10/11/2005', 'DD_MM-YYYY'))
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    SQL> INSERT INTO forum_message VALUES (2, 2, 2, 'post #2', to_date('09/10/2005', 'DD_MM-YYYY'))
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    1 row created.
    SQL> INSERT INTO forum_message VALUES (3, 2, 1, 'post #3', to_date('08/06/2005' ,'DD_MM-YYYY'))
      2  /
    1 row created.
    SQL>
    SQL> SELECT fm.title
      2  FROM forum_message fm, forum_user fu
      3  WHERE fm.pdate = (SELECT MAX(sq.pdate)
      4                                    FROM forum_message sq
      5                                    WHERE sq.forum_id = fm.forum_id)
      6  AND fm.user_id = fu.id
      7  AND fu.type = 1
      8  /
    TITLE
    post #1
    SQL> Cheers, APC

  • Select most recent file and display

    I've been considerig this and I am closer to how I expect it to work
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      key code 53
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      --if theWindow is close end applescript.
              end tell
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    Hi,
    If you don't want to use a folder action, try this :
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          return -- no Finder window
    end try
    set tDate to (current date) - 30
    repeat
          set b to false
          tell application "Finder"
                set fWindows to Finder windows whose it's name is currFolder
                if (fWindows is not {}) then
                      set tWind to item 1 of fWindows
                      set nFiles to document files of tWind whose creation date > tDate -- get newer files
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    on selectionfullScreen(tName, n)
          tell application "System Events"
                tell process "Finder"
                      set frontmost to true
                      keystroke "y" using {command down, option down}
                      repeat (15 * n) times
                            tell window 1 to if (exists) and (its title is tName) then return -- the user close QuickLook
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                      end repeat
                      tell window 1 to if (exists) and (its title is not tName) then key code 53 -- close QuickLook after (15 seconds X (number of images))
                end tell
          end tell
    end selectionfullScreen

  • Finding 5 most recent records for each customer with abnormal order amounts

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    create table dbo.purchase_order (
    purchase_order_id int identity primary key clustered
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    amount money not null,
    order_date date not null
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    abnormally high or low amounts (bigger or less than 3 times SDTDEV from AVG), for each of these dates output minimum and maximum amounts as well.
    Possible result: http://triontp.pop3.ru/333.gif

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    vice versa. 
     amount Not Between avg_amt - 3 * stdev_amt And avg_amt + 3 * stdev_amt)

  • HowTo?  find most recent checkins, by userID, sorted by date??

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  • Select statement for most recent value in a table

    Hi all,
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    Hi,
    Just check this thread:
    how to determine most recent date from the date column of internal table
    U will find the solution here.
    Regards,
    Kumar

  • Return most recent matching record on Sub Report

    I am hoping there is an easier way to go about this.
    REPORT 'A': I have already made a report (which will inevitably be a subreport) that only reports the first record of each Group2 (I used a counter formula and conditional suppress.)  This enabled me to have a report full of only the most recent records.
    As an example, let's say this first report contains Account#, Price, and Invoice Date (again, it only reports the most recent Invoice Date and corresponding price and account # - the other records for each account are supressed).
    REPORT 'B': I have another report with Account Numbers and Category Numbers.
    I want to Match the Account Numbers, lookup the numbers on the original report ('A'), and return the recent Prices and Invoice Dates to the 2nd report ('B').  So that Report B has Account#, Category#, Most Recent Price, & Most Recent Invoice Date.
    A subreport has been my only idea because again, I only want the most recent prices from 'A' to report on 'B'.  Any help is appreciated.
    Edited by: Mara Nowak on Sep 4, 2008 9:39 AM

    Mara,
    If Report B is the main report then I would suggest grouping on the same field as you used in Report A for Group 1. Place the subreport, Report A, in the GH1 and link it based on the Group 1 field. The subreport will then only display data for the same group instance.
    If you need to use the most recent data or price in Report B then assign those values to shared variables in the subreport and reference them in formulas in the main report in a section below where the subreport resides, GH1.

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