Multicast and WebcamSubscriber issues for 10.1

Question

Hi,
I'm trying to subclass WebcamSubscriber in 10.1 lib to create a custom video subscriber.
When multicast is on, a subclass of WebcamSubscriber for flash 10.1 does not always act as expected. Specially, after playing a stream, it does not seem to send a "NetStream.Play.Start" event.
Since the 10.1 lccs library is not open source (why?), the best I could do was by subclassing and overriding, here is a simple test to reconstruct the problem:
public class TestSub extends WebcamSubscriber {
     public function TestSub() { super(); }
     override protected function onNetStatus(e:NetStatusEvent):void {
          trace(">> onNetStatus: " + e.info.code);
          super.onNetStatus(e);
Given the above code, a full cycle events of a subscriber in a p2p state (multicast = true) is like this:
>> onNetStatus: NetGroup.Neighbor.Connect
>> onNetStatus: NetGroup.MulticastStream.PublishNotify
>> onNetStatus: NetStream.MulticastStream.Reset
>> onNetStatus: NetGroup.MulticastStream.UnpublishNotify
>> onNetStatus: NetGroup.Neighbor.Disconnect
The above shows a publisher playing an stream, waiting for some time and then closing the connection.
The question is: why is that the 10.1 version never sends a "NetStream.Play.Start" event in the p2p state?
The problem could be traced to WebcamSubscriber#playStream(), but the source code for 10.1 is not available. Also when I tried overriding playStream() using the code in 10.0 lib, I got a peer timeout message. Is the code for WebcamSubscriber#playStream() in 10.0 the same as 10.1?

Answer 1

Raff. wrote:
Can you try to run your application linked to the 10.1 LCCS lib on a machine that only has FlashPlayer 10.0 installed ?
Can an application which is linked to lccs for player 10.1, run on a 10.0 player?
This sounds like a problem in lccs. Could you check the difference in code in WebcamSubscriber#playStream() between 10.0 and 10.1? (I cannot do this as 10.1 is not open source.) Whatever the problem is, it's initiated from that method.