Multiple Aggregate function

Hi, I need a help here. Supposedly I want to do a percentage formula based on count(loss_evnt_sr_key)/max(rsum(count(loss_evnt_fact.loss_evnt_sr_key)*100
The scenario given that I need to count for each individual loss_evnt_type_dsc divided by total of loss_evnt_type_dsc
The problem now, when I’ve set the “max(rsum(count(loss_evnt_fact.loss_evnt_sr_key)” column to number, I can do the division but it gives me wrong answer.
Do you have any ways that I can collect the total of loss_evnt_type_dsc ?
I really hope that you can help me in this. Thank you

hi,
i've tried your way, but i give me a wrong total. :(
btw, i have put another thread regarding the issue. you can refer to this forum post: Drill down: Wrong percentage shown
that's actually my real problem. i was thinking to get the total so that it would be easier, but still it gives me wrong number. maybe you can take a look there, and get the real situation of my issue.
Thank you!

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    or (better)
    SELECT REGION_NODES     AS REGIONS,
           DEPARTMENT_NODES AS DEPARTMENTS,
           AREA_NODES       AS AREAS,
           CENTRE_NODES     AS CENTRES
      FROM (SELECT NODE_LEVEL, TREE_NODE(NODE_ID, NODE_VALUE) AS NODE
              FROM TREE_COLL
    PIVOT (CAST(COLLECT(NODE) AS TREE_NODES) FOR NODE_LEVEL IN (1 AS REGION_NODES,
                                                                 2 AS DEPARTMENT_NODES,
                                                                 3 AS AREA_NODES,
                                                                 4 AS CENTRE_NODES
           );yet, both fail with
    ORA-56902: expect aggregate function inside pivot operationInvestigating further, I found the same behaviour when using XMLAGG as the aggregate function in the PIVOT clause.
    Is this normal ? And if it is, is there any other way to achieve the result I was anticipating ?
    My version is
    SQL> SELECT BANNER FROM V$VERSION;
    BANNER
    Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
    PL/SQL Release 11.2.0.3.0 - Production
    CORE    11.2.0.3.0      Production
    TNS for 64-bit Windows: Version 11.2.0.3.0 - Production
    NLSRTL Version 11.2.0.3.0 - ProductionThanks in advance
    Best Regards
    Philip

    Most likely a bug. But you can bypass it by using any other aggregate making sure group consists of a single row and apply collect to a pivoted value. Yes, the cost is double aggregation. And also there is another cost - you would need to create MAP member function otherwise aggreations like MAX/MIN, etc. will not work:
    CREATE OR REPLACE TYPE TREE_NODE AS OBJECT
       NODE_KEY  VARCHAR2( 15 CHAR),
       NODE_NAME VARCHAR2(127 CHAR),
       map member function f return varchar2
    Type created.
    CREATE OR REPLACE TYPE BODY TREE_NODE AS
      map member function f return varchar2 is
      begin
         return NODE_NAME;
      end f;
    end;
    Type body created.
    CREATE OR REPLACE TYPE TREE_NODES AS TABLE OF TREE_NODE NOT NULL
    Type created.
    SQL> select  *
      2    from  test_coll
      3  /
    NODE_ID NODE_VALUE NODE_LEVEL
    1       A                   1
    2       B                   2
    3       C                   3
    4       D                   4
    5       E                   1
    6       F                   2
    7       G                   3
    8       H                   4
    8 rows selected.
    SQL> Now:
    SELECT CAST(COLLECT(REGION_NODES)     AS TREE_NODES) AS REGIONS,
           CAST(COLLECT(DEPARTMENT_NODES) AS TREE_NODES) AS DEPARTMENTS,
           CAST(COLLECT(AREA_NODES)       AS TREE_NODES) AS AREAS,
           CAST(COLLECT(CENTRE_NODES)     AS TREE_NODES) AS CENTRES
      FROM (
            SELECT  ROWID RID,
                    NODE_LEVEL,
                    TREE_NODE(NODE_ID, NODE_VALUE) AS NODE
              FROM  TEST_COLL
    PIVOT (MAX(NODE) FOR NODE_LEVEL IN (
                                         1 AS REGION_NODES,
                                         2 AS DEPARTMENT_NODES,
                                         3 AS AREA_NODES,
                                         4 AS CENTRE_NODES
    REGIONS(NODE_KEY, NODE_NAME)                         DEPARTMENTS(NODE_KEY, NODE_NAME)                     AREAS(NODE_KEY, NODE_NAME)                           CENTRES(NODE_KEY, NODE_NAME)
    TREE_NODES(TREE_NODE('1', 'A'), TREE_NODE('5', 'E')) TREE_NODES(TREE_NODE('6', 'F'), TREE_NODE('2', 'B')) TREE_NODES(TREE_NODE('7', 'G'), TREE_NODE('3', 'C')) TREE_NODES(TREE_NODE('8', 'H'), TREE_NODE('4', 'D'))
    SQL> SY.

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