Multiple sockets connected to one port

Hello I am running a LabVIEW VI that is based on the Labview TCPServer example. I am wondering what the best way to deal with multiple connections to a single port would be. For example I have a device(could be thought of as the same thing as the TCPClient vi) that connects to the server using the port number and the IP address. The communication works fine when there is only one device trying to connect to the server, the problem occurs when two devices try to connect to the server. When the first device connects all data sent shows up fine, when the second device connects, the status on the device indicates a proper connection but none of the data sent shows up on the server side. I assume that I must do something with the connection ID to distinguish between the two connections, but I was wondering if there was an example or something that deals with this issue, or if someone would like to explain how I could get the data to show up properly. Any help is appreciated, thanks!

I am hoping that there is something similar to the java api where there is some way I can start a new threads to handle multiple connections on the same port. I would assume that if java has it LabVIEW would have something similar. Unfortunately I am not sure how to go about finding out how to do such a thing in LabVIEW.
The way that I assume the TCPListen.vi works is that there is some mechanism polling the specified port and ip address waiting for a request for a connection. Once a request is received the VI creates a connection ID so that the other subvi's can perform operations on the specific connection. It also looks as though the TCPListen.vi continues to listen for new connections, because the clients indicate a connection when more then one of them are run trying to connect to the same port and IP.
So my question is either, how to start a parallel process to handle the new connections, or where can I find the new connection ID (because the indicator only shows the connection id of the first client to connect). Basically I am having trouble distinguishing between the multiple connections on the same port.I would like to keep all of the clients sending data through the same port if possible.Each client identifies itself in its data message so keeping the data organized is not a problem.
I also looked at the data socket examples, mainly because the Java examples I was looking at used "Sockets". I ran into similar troubles finding a way to create distinguishable connections using DS's as well. Anyways, any help is appreciated. Thanks.

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I need to open a socket connection from multiple MIDlets on the same port.
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Hello!
I connect TC65 with server by socket connection on port 23. I close this socket, output and input streams as well. Because I've read some information from server I want to connect to another device using socket connection on port 43 for example, but it seems it doesn't work. I guess in some way it could be done because I closed previous connection. Any advise?
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ok. dear
my another id is [email protected]
Right, I'm getting tired of this already.
NO, I'm not going to send you any code, you lazy nitwit. Neither will anybody here.
Your use of the imperative form in your question is rude. You may talk like that to your colleagues, but in a forum where people answer questions in their spare time and on a voluntary basis this is inacceptable.
You didn't even bother to say "please", at the least. Not that this would have changed much, but at least you wouldn't have been barking.
[url http://www.catb.org/~esr/faqs/smart-questions.html]This document might provide you some orientation.
As for your problem, first find out what exactly it is you want to do. Search the web, as kajbj counselled, it's quite a common task. If you have a specific problem, ask. But, take my advice and never, never ever ask people to "send you code" in a forum.

Multiple seperate streams to one port?

DEar all
Thanks for your help yesterday. I've given up trying to encode data and then tx it over TCP - instead I'm just going to use RTP and encode to a file at the server.
The next question I have is this:
The server will receive many connections from many clients. When a client
a) Can I use one (the same) port on the server for all clients to transmit their RTP to? If so how do I distinguish between the streams on the server? Or must I have separate ports for each incoming stream? If so, how do I find free ports for JMF to use?
b) How can I identify a particular stream as being from a particular PC (as many maybe behind the same nat). Ideally I'd like to send an identification number first.
c) How do I detect the end of the stream on the server? Or must the client tell the server via some other means?
Thanks
Gareth
Edited by: 831660 on 28-Jan-2011 02:53

a) Can I use one (the same) port on the server for all clients to transmit their RTP to? If so how do I distinguish between the streams on the server? Or must I have separate ports for each incoming stream? If so, how do I find free ports for JMF to use?You're supposed to use separate ports for each incoming stream. You should handle this situation using a normal "listen & fork" server routine.
If you're unfamiliar with the concept, you have a server that listens for incoming requests on a well-known port, and then serves the request on "any available port". Essentially it listens for a request, and then forks off a thread to handle the connection for the client on another port. That way, the well-known port isn't ever "in use"...
You'll just need to write a basic handshake protocol that your server and client can use. The server listens for requests on some defined port. When it receives a request from a client, it'll pick an unused port, transmit that port back to the client, and then start listening for an RTP connection on the port it told the client.
b) How can I identify a particular stream as being from a particular PC (as many maybe behind the same nat). Ideally I'd like to send an identification number first.A solves this issue.
c) How do I detect the end of the stream on the server? Or must the client tell the server via some other means?You're able to listen for the following events on an RTP session by registering a "ReceiveStreamListener" on your RTP session:
-- NewReceiveStreamEvent, when a new stream arrives
-- InactiveReceiveStreamEvent, when the stream becomes inactive
-- ActiveReceiveStreamEvent, when the stream becomes active again after a previous inactive event was generated
-- TimeoutEvent, when the stream times out.
-- ByeEvent, when the stream is done.
So, the end of a stream occurs when you receive a TimeoutEvent or a ByeEvent (which is a subclass of TimeoutEvent so you really only have to handle TimeoutEvents), and you may also possibly want to consider a InactiveReceiveStreamevent to be the end of a stream.

Multiple interfaces connected to one switch. Sol8 OK, Sol10 NOT.

Hello,
finally we got our T5220s and I connected everything as it should be mirroring our V880 with four QFE cards.
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ndd -get /dev/ip nxge0:ip_forwarding
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nxge0: flags=201100843<UP,BROADCAST,RUNNING,MULTICAST,ROUTER,IPv4,CoS> mtu 1500 index 4
inet 133.78.240.202 netmask fffffff0 broadcast 133.78.240.207
ether 0:21:28:30:1f:26
nxge1: flags=201100843<UP,BROADCAST,RUNNING,MULTICAST,ROUTER,IPv4,CoS> mtu 1500 index 6
inet 133.78.240.218 netmask fffffff0 broadcast 133.78.240.223
ether 0:21:28:30:1f:27
Solaris 8:
# ndd -get /dev/ip ip_forwarding
1
qfe0: flags=1000843<UP,BROADCAST,RUNNING,MULTICAST,IPv4> mtu 1500 index 3
inet 133.78.240.193 netmask fffffff0 broadcast 133.78.240.207
ether 0:3:ba:34:10:c
qfe4: flags=1000843<UP,BROADCAST,RUNNING,MULTICAST,IPv4> mtu 1500 index 4
inet 133.78.240.209 netmask fffffff0 broadcast 133.78.240.223
ether 0:3:ba:31:74:f9
This is a snoop of the second interface:
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45140 S=40051 Push Ack=1777937950 Seq=1225056817 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45141 S=40052 Push Ack=1778148585 Seq=1225166751 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45142 S=40053 Push Ack=1778403447 Seq=1225321085 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45143 S=40054 Push Ack=1778602744 Seq=1225572285 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45144 S=40055 Push Ack=1778775342 Seq=1225720418 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45147 S=40058 Push Ack=1779282787 Seq=1226316480 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45148 S=40059 Push Ack=1779556928 Seq=1226498643 Len=75 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45150 S=40061 Push Ack=1779894075 Seq=1226894702 Len=75 Win=33580
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40052 S=45141 Push Ack=1225166826 Seq=1778148585 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40054 S=45143 Push Ack=1225572360 Seq=1778602744 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40059 S=45148 Ack=1226498718 Seq=1779556928 Len=0 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40058 S=45147 Ack=1226316555 Seq=1779282787 Len=0 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40055 S=45144 Ack=1225720493 Seq=1778775342 Len=0 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40061 S=45150 Ack=1226894777 Seq=1779894075 Len=0 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40053 S=45142 Ack=1225321160 Seq=1778403447 Len=0 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40051 S=45140 Ack=1225056892 Seq=1777937950 Len=0 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40055 S=45144 Push Ack=1225720493 Seq=1778775342 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40058 S=45147 Push Ack=1226316555 Seq=1779282787 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40051 S=45140 Push Ack=1225056892 Seq=1777937950 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40053 S=45142 Push Ack=1225321160 Seq=1778403447 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40059 S=45148 Push Ack=1226498718 Seq=1779556928 Len=74 Win=24820
con3sun2-qfe9 -> con1pcc1-nxge1 TCP D=40061 S=45150 Push Ack=1226894777 Seq=1779894075 Len=74 Win=24820
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45141 S=40052 Ack=1778148659 Seq=1225166826 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45147 S=40058 Ack=1779282861 Seq=1226316555 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45144 S=40055 Ack=1778775416 Seq=1225720493 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45143 S=40054 Ack=1778602818 Seq=1225572360 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45140 S=40051 Ack=1777938024 Seq=1225056892 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45150 S=40061 Ack=1779894149 Seq=1226894777 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45148 S=40059 Ack=1779557002 Seq=1226498718 Len=0 Win=33580
con1pcc1-nxge1 -> con3sun2-qfe9 TCP D=45142 S=40053 Ack=1778403521 Seq=1225321160 Len=0 Win=33580
What is blocking the communication?
Kind regards. Oliver

hi, perhaps you have to do some configuration with routeadm ? and enable ip_forwarding ? (man routeadm)
root@sps-dump-001 /: routeadm
              Configuration   Current              Current
                     Option   Configuration        System State
               IPv4 routing   disabled             disabled
               IPv6 routing   disabled             disabled
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            IPv6 forwarding   disabled             disabled
           Routing services   "route:default ripng:default"
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jaggedmedia wrote:
> I have two ethernet connections in my computer (2 IP Addr) I would
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I hope I have answered your question to your satisfaction. Thank you for posting on the HP Forums. Have a wonderful day!
Please click the "Thumbs Up" on the bottom right of this post to say thank you if you appreciate the support I provide!
Also be sure to mark my post as “Accept as Solution" if you feel my post solved your issue, it will help others who face the same challenge find the same solution.
Dunidar
I work on behalf of HP
Find out a bit more about me by checking out my profile!
"Customers don’t expect you to be perfect. They do expect you to fix things when they go wrong." ~ Donald Porter

Multiple sockets connected to one port

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