Munky's SQL performance challenge [APEX Chart]

Hi,
I have a chart currently being used but it takes around 45 seconds to load (or worse). One of the tables (corcon01_hour_chg_totals) has almost 20 million rows. Currently I'm doing them as separate queries but I assume they could be placed into a single query with multiple values (?). This means that I have 4 queries, all relating to the same x-axis values but different y-axis values (1 uses left, the other 3 use right). Perhaps there is a way to make use of the 2 previous parts (15 and 16) rather than doing a new query to discover the total of the 2? Thanks for any help. Here's my current code:
Series 1 using left y-axis: http://www.pastebin.ca/1585574
Series 2 using right axis -- cpu usage of one node: http://www.pastebin.ca/1585575
Series 3 using right axis -- cpu usage of other node: http://www.pastebin.ca/1585577
Series 4 using right axis -- total cpu usage of both nodes: http://www.pastebin.ca/1585578
The following indexes are specified:
corcon01_hour_chg_totals indexes: http://i36.tinypic.com/296die0.png
corcon01_db_perform indexes: http://i34.tinypic.com/nff8g2.png
The function based ones relate to the part of query used e.g. IDX_ACTUAL_WEEK's expression is: TO_CHAR(TO_DATE(RPAD("TD_HR",10),'yyyy-mm-dd'),'iw')Lets see some magic :)
Mike

Mike
Be a happy boy!
If you want SQL tuning advice, then throw it on the PL/SQL and SQL forum and I'm sure we can help you - Mr Kulash, Alex, Karthick, BluShadow and especially Boneist shall be your friend. Just be sure that you have read about SQL tuning and can provide the DDL (I mean the creation scripts, not just DESCRIBE output - if you don't have SQL developer or Toad or wotnot then look up DBMS_METADATA.GET_DDL) for your tables and indexes and the execution plan of the queries, a 10046 trace file might be handy too (google it, 10053 could be required later if necessary).
You've had expert input from 2 Aces, neither of whom I would be comfortable in a debate with, I'm just a SQL monkey (just cause I'm not happy with a 10 sec load does not mean that you should not be). So you've already had good advice from the best - you can't beat that sir!
Oh, and you have a select max in one of your select clauses that doesn't reference owt in the actual query (the 'actual count' bit). It's always gonna be 1 row with one result given the nature of the sub-query so you might want to WITH blah that, materialize (just to test) and then select from the sub-factored temporary table... Don't forget to always run twice to test so that you can disregard parsing time as the execution plan is sitting pretty in the shared pool by the second time...
Cheers
Ben
Edited by: Munky on Sep 30, 2009 10:26 PM

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Help needed in SQL performance - Using CASE in SQL statement versus 2 query

Hi,
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The SQL I have gives the count of all members.
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The key difference is only the active dates.
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I modified the SQL to use CASE statement in the SELECT.
So after the data is fetched the CASE statement will evaluate the active date and gives 2 counts (active and inactive)
Is it advisable to use this approach. Will CASE improve SQL performance ? I have to justify this.
Please let me know your thoughts.
Thanks,
J

Hi,
If it can be done in single SQL do it in single SQL.
You said:
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In your case you should tell us how it is.
Regards,
Bhushan

SQL Performance issue: Using user defined function with group by

Hi Everyone,
im new here and I really could need some help on a weird performance issue. I hope this is the right topic for SQL performance issues.
Well ok, i create a function for converting a date from timezone GMT to a specified timzeone.
CREATE OR REPLACE FUNCTION I3S_REP_1.fnc_user_rep_date_to_local (date_in IN date, tz_name_in IN VARCHAR2) RETURN date
IS
tz_name VARCHAR2(100);
date_out date;
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TIME ZONE (tz_name_in) AS DATE),'dd-mm-yyyy hh24:mi:ss'),'dd-mm-yyyy hh24:mi:ss')
INTO date_out
FROM dual;
RETURN date_out;
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select
stp_end_stamp,
count(*) noi
from step
where
stp_end_stamp
BETWEEN
to_date('23-05-2009 00:00:00','dd-mm-yyyy hh24:mi:ss')
AND
to_date('23-07-2009 00:00:00','dd-mm-yyyy hh24:mi:ss')
group by
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If i use the function it selects the same number of rows ;-) and takes ~ 4 sec ...
select
fnc_user_rep_date_to_local(stp_end_stamp,'Europe/Berlin'),
count(*) noi
from step
where
stp_end_stamp
BETWEEN
to_date('23-05-2009 00:00:00','dd-mm-yyyy hh24:mi:ss')
AND
to_date('23-07-2009 00:00:00','dd-mm-yyyy hh24:mi:ss')
group by
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select
fnc_user_rep_date_to_gmt(stp_end_stamp,'Europe/Berlin','ny21654'),
noi
from
select
stp_end_stamp,
count(*) noi
from step
where
stp_end_stamp
BETWEEN
to_date('23-05-2009 00:00:00','dd-mm-yyyy hh24:mi:ss')
AND
to_date('23-07-2009 00:00:00','dd-mm-yyyy hh24:mi:ss')
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and
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Hi,
The execution plan for all three statements is EXACTLY the same!!!Not exactly. Plans are the same - true. They uses slightly different approach to call function. See:
drop table t cascade constraints purge;
create table t as select mod(rownum,10) id, cast('x' as char(500)) pad from dual connect by level <= 10000;
exec dbms_stats.gather_table_stats(user, 't');
create or replace function test_fnc(p_int number) return number is
begin
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end;
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select * from table(dbms_xplan.display(null,null,'advanced'));
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select * from table(dbms_xplan.display(null,null,'advanced'));
explain plan for select test_fnc(id) from (select id from t group by id);
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PLAN_TABLE_OUTPUT
Plan hash value: 47235625
| Id | Operation          | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT   |      |    10 |    30 |   162   (3)| 00:00:02 |
|   1 | HASH GROUP BY     |      |    10 |    30 |   162   (3)| 00:00:02 |
|   2 |   TABLE ACCESS FULL| T    | 10000 | 30000 |   159   (1)| 00:00:02 |
Query Block Name / Object Alias (identified by operation id):
   1 - SEL$1
   2 - SEL$1 / T@SEL$1
Outline Data
/*+
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      FULL(@"SEL$1" "T"@"SEL$1")
      OUTLINE_LEAF(@"SEL$1")
      ALL_ROWS
      OPTIMIZER_FEATURES_ENABLE('10.2.0.4')
      IGNORE_OPTIM_EMBEDDED_HINTS
      END_OUTLINE_DATA
Column Projection Information (identified by operation id):
   1 - (#keys=1) "ID"[NUMBER,22]
   2 - "ID"[NUMBER,22]
34 rows selected.
SQL>
Explained.
SQL>
PLAN_TABLE_OUTPUT
Plan hash value: 47235625
| Id | Operation          | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT   |      |    10 |    30 |   162   (3)| 00:00:02 |
|   1 | HASH GROUP BY     |      |    10 |    30 |   162   (3)| 00:00:02 |
|   2 |   TABLE ACCESS FULL| T    | 10000 | 30000 |   159   (1)| 00:00:02 |
Query Block Name / Object Alias (identified by operation id):
   1 - SEL$1
   2 - SEL$1 / T@SEL$1
Outline Data
/*+
      BEGIN_OUTLINE_DATA
      FULL(@"SEL$1" "T"@"SEL$1")
      OUTLINE_LEAF(@"SEL$1")
      ALL_ROWS
      OPTIMIZER_FEATURES_ENABLE('10.2.0.4')
      IGNORE_OPTIM_EMBEDDED_HINTS
      END_OUTLINE_DATA
Column Projection Information (identified by operation id):
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34 rows selected.
SQL>
Explained.
SQL> select * from table(dbms_xplan.display(null,null,'advanced'));
PLAN_TABLE_OUTPUT
Plan hash value: 47235625
| Id | Operation          | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT   |      |    10 |    30 |   162   (3)| 00:00:02 |
|   1 | HASH GROUP BY     |      |    10 |    30 |   162   (3)| 00:00:02 |
|   2 |   TABLE ACCESS FULL| T    | 10000 | 30000 |   159   (1)| 00:00:02 |
Query Block Name / Object Alias (identified by operation id):
   1 - SEL$F5BB74E1
   2 - SEL$F5BB74E1 / T@SEL$2
Outline Data
/*+
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      FULL(@"SEL$F5BB74E1" "T"@"SEL$2")
      OUTLINE(@"SEL$2")
      OUTLINE(@"SEL$1")
      MERGE(@"SEL$2")
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      ALL_ROWS
      OPTIMIZER_FEATURES_ENABLE('10.2.0.4')
      IGNORE_OPTIM_EMBEDDED_HINTS
      END_OUTLINE_DATA
Column Projection Information (identified by operation id):
   1 - (#keys=1) "ID"[NUMBER,22]
   2 - "ID"[NUMBER,22]
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Sql problem in apex LOV

I am not able to use this SQL statement for apex LOV, any ideas?
select username, id
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I get the following error message:
1 error has occurred
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Re: How to concatenate two sql statements?

Hi
Remove the semi-colon at the end.
Cheers
Ben
http://www.munkyben.wordpress.com
Don't forget to mark replies helpful or correct ;)

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I have a question with regard to "group by" inline view ,
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I will give you simple table definitions in order for you
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C1
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HO.
Message was edited by:
user507290

For such big sources check that
1) you use full scans, hash joins or at least merge joins
2) you scan your source data as less as possible. In the best case each necessary table only once (for example not using exists clause to effectively scan all table via index scan).
3) how much time you are spending on sorts and hash joins (either from v$session_longops directly or some tool that visualises this info). If you are using workarea_size_policy = auto, probably you can switch to manual for this particular select and adjust sort_area_size and hash_area_size big enough to do as less as possible sorts on disk
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5) if your full scans are taking big time check what is your db_file_multiblock_read_count, probably increasing it for this select will give some gain.
6) run trace and check on what are you waiting for
7) most probably your problem is IO bound so probably you can do something from OS side to make IO faster
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Gints Plivna
http://www.gplivna.eu

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Hello.
I am using Apex 4.1.0 with Oracle 11gR2 and Oracle App Server (mod_plsql).
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EEG wrote:
Hello fac586.
Thank you very much for responding/helping.
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Username: [email protected]
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How does the table size effects sql performance?
I am comparing 2 tables , with same number of rows(54 million rows) ,
table1(columns a,b,c,d,e,f..) has 40 columns
table2 (columns (a,b,c,d)
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SQL using table1 runs in 30 min.
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Thanks
jeevan.

user600431 wrote:
This is a general question. I just want to compare table with more columns and table with less columns with same number of rows .
I am finding that table with less columns is good in performance , than the table with more columns.
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Regards,
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Oracle related stuff blog:
http://oracle-randolf.blogspot.com/
SQLTools++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676/
http://sourceforge.net/projects/sqlt-pp/

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I think, it impacts only the session where
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Although the major impact should be on the current session, there will be some impact on every other session in the system.
BY the way, there is an 'edit' button available to you for every post you create. As a courtesy, you could edit the title of the duplicate and let us know it is indeed a duplicate - or you could edit that other thread to ask that other question you were going to ask.

SQL Performance and Security

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e.g
Project: xxxxxxxxxxxxxx
Activity Code          planned     actual (to date)
     1          20          25
     2          30          30
     3          40          24
Total               300          200
Note that actual time spent on an activity must be calculated from the WORK UNIT table.
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2. Security: Justify and implement solutions at the server that meet the following security requirements
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(ii)Employees should only be able to read information from the project table (excluding the budget) for projects they are assigned to.
(iii)Only the manager of a project should be able to update (insert, update, delete) any non-key information in the project table relating to that project.
Here is the project tables
set echo on
* Changes
* 4.10.00
* manager of employee on a project included in the employee on project table
* activity table now has compound key, based on ID dependence between project
* and activity
drop table org_unit cascade constraints;
drop table project cascade constraints;
drop table employee cascade constraints;
drop table employee_on_project cascade constraints;
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drop table activity_order cascade constraints;
drop table work_unit cascade constraints;
* org_unit
* type - for example in lmu might be FACULTY, or SCHOOL
CREATE TABLE org_unit
ou_id               NUMBER(4)      CONSTRAINT ou_pk PRIMARY KEY,
ou_name          VARCHAR2(40)     CONSTRAINT ou_name_uq UNIQUE
                         CONSTRAINT ou_name_nn NOT NULL,
ou_type          VARCHAR2(30) CONSTRAINT ou_type_nn NOT NULL,
ou_parent_org_id     NUMBER(4)     CONSTRAINT ou_parent_org_unit_fk
                         REFERENCES org_unit
* project
CREATE TABLE project
proj_id          NUMBER(5)     CONSTRAINT project_pk PRIMARY KEY,
proj_name          VARCHAR2(40)     CONSTRAINT proj_name_uq UNIQUE
                         CONSTRAINT proj_name_nn NOT NULL,
proj_budget          NUMBER(8,2)     CONSTRAINT proj_budget_nn NOT NULL,
proj_ou_id          NUMBER(4)     CONSTRAINT proj_ou_fk REFERENCES org_unit,
proj_planned_start_dt     DATE,
proj_planned_finish_dt DATE,
proj_actual_start_dt DATE
* employee
CREATE TABLE employee
emp_id               NUMBER(6)     CONSTRAINT emp_pk PRIMARY KEY,
emp_name          VARCHAR2(40)     CONSTRAINT emp_name_nn NOT NULL,
emp_hiredate          DATE          CONSTRAINT emp_hiredate_nn NOT NULL,
ou_id               NUMBER(4)      CONSTRAINT emp_ou_fk REFERENCES org_unit
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* note each activity is associated with a project
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* each activity has a people budget , in other words an amount to spend on
* wages
CREATE TABLE activity
act_id               NUMBER(6),
act_proj_id          NUMBER(5)     CONSTRAINT act_proj_fk REFERENCES project
                         CONSTRAINT act_proj_id_nn NOT NULL,
act_name          VARCHAR2(40)     CONSTRAINT act_name_nn NOT NULL,
act_type          VARCHAR2(30)     CONSTRAINT act_type_nn NOT NULL,
act_planned_start_dt     DATE,
act_actual_start_dt      DATE,
act_planned_end_dt     DATE,
act_actual_end_dt     DATE,
act_planned_hours     number(6)     CONSTRAINT act_planned_hours_nn NOT NULL,
act_people_budget     NUMBER(8,2)      CONSTRAINT act_people_budget_nn NOT NULL,
CONSTRAINT act_pk PRIMARY KEY (act_id, act_proj_id)
* employee on project
* when an employee is assigned to a project, an hourly rate is set
* remember that the persons manager depends on the project they are on
* the implication being that the manager needs to be assigned to the project
* before the 'managed'
CREATE TABLE employee_on_project
ep_emp_id          NUMBER(6)     CONSTRAINT ep_emp_fk REFERENCES employee,
ep_proj_id          NUMBER(5)     CONSTRAINT ep_proj_fk REFERENCES project,
ep_hourly_rate      NUMBER(5,2)      CONSTRAINT ep_hourly_rate_nn NOT NULL,
ep_mgr_emp_id          NUMBER(6),
CONSTRAINT ep_pk PRIMARY KEY(ep_emp_id, ep_proj_id),
CONSTRAINT ep_mgr_fk FOREIGN KEY (ep_mgr_emp_id, ep_proj_id) REFERENCES employee_on_project
* employee on activity
* type - for example in lmu might be FACULTY, or SCHOOL
CREATE TABLE employee_on_activity
ea_emp_id          NUMBER(6),
ea_proj_id          NUMBER(5),
ea_act_id          NUMBER(6),
ea_planned_hours      NUMBER(3)     CONSTRAINT ea_planned_hours_nn NOT NULL,
CONSTRAINT ea_pk PRIMARY KEY(ea_emp_id, ea_proj_id, ea_act_id),
CONSTRAINT ea_act_fk FOREIGN KEY (ea_act_id, ea_proj_id) REFERENCES activity ,
CONSTRAINT ea_ep_fk FOREIGN KEY (ea_emp_id, ea_proj_id) REFERENCES employee_on_project
* activity order
* only need a prior activity. If activity A is followed by activity B then
(B is the prior activity of A)
CREATE TABLE activity_order
ao_act_id          NUMBER(6),
ao_proj_id          NUMBER(5),
ao_prior_act_id      NUMBER(6),
CONSTRAINT ao_pk PRIMARY KEY (ao_act_id, ao_prior_act_id, ao_proj_id),
CONSTRAINT ao_act_fk FOREIGN KEY (ao_act_id, ao_proj_id) REFERENCES activity (act_id, act_proj_id),
CONSTRAINT ao_prior_act_fk FOREIGN KEY (ao_prior_act_id, ao_proj_id) REFERENCES activity (act_id, act_proj_id)
* work unit
* remember that DATE includes time
CREATE TABLE work_unit
wu_emp_id          NUMBER(5),
wu_act_id          NUMBER(6),
wu_proj_id          NUMBER(5),
wu_start_dt          DATE CONSTRAINT wu_start_dt_nn NOT NULL,
wu_end_dt          DATE CONSTRAINT wu_end_dt_nn NOT NULL,
CONSTRAINT wu_pk PRIMARY KEY (wu_emp_id, wu_proj_id, wu_act_id, wu_start_dt),
CONSTRAINT wu_ea_fk FOREIGN KEY (wu_emp_id, wu_proj_id, wu_act_id)
          REFERENCES employee_on_activity( ea_emp_id, ea_proj_id, ea_act_id)
/* enter data */
start ouins
start empins
start projins
start actins
start aoins
start epins
start eains
start wuins
start pmselect
I have the tables containing ouins and the rest. email me on [email protected] if you want to have a look at the tables.

Answer to your 2nd question is easy. Create database roles for the various groups of people who are allowed to access or perform various DML actions.
The assign the various users to these groups. The users will be restricted to what the roles are restricted to.
Look up roles if you are not familiar with it.

How to improve my pls/sql performance tunning skills

Hi All , I would like to learn more about pl/sql performance tunning , where or how can i get more knowledge in this area ?
Is there any tutorials which can help me to understand the Explain plan, Dbms_Profiler, Dbms_Advisor more etc ........Thanks . Bcj

Explain plan
http://www.psoug.org/reference/explain_plan.html
DBMS_PROFILER (10g)
http://www.psoug.org/reference/dbms_profiler.html
DBMS_HPROF (11g)
http://www.psoug.org/reference/dbms_hprof.html
DBMS_ADVISOR
http://www.psoug.org/reference/dbms_advisor.html
DBMS_MONITOR
http://www.psoug.org/reference/dbms_monitor.html
DBMS_SUPPORT
http://www.psoug.org/reference/dbms_support.html
DBMS_TRACE
http://www.psoug.org/reference/dbms_trace.html
DBMS_SQLTUNE
http://www.psoug.org/reference/dbms_sqltune.html

Best Performance for apex over Linux+HW RAID

Dear Experts,
Given:
-- Server Specs:
---- HP ProLiant ML370 G6 E5540
---- Processor name: Intel® Xeon® E5540 (4 core, 2.53 GHz, 8MB L3, 80W)
---- Storage Controller: (1) Smart Array P410i/256MB
---- 8 SAS HardDisks with 320 GB for each
---- 12 GB RAM
Required:
1)) What are the best practice bring the best performance to Apex for the following solution stack
---- Oracle Linux 6.3 x86_64
---- Grid Infrastructure 11g R2
---- Database 11g R2
---- Oracle Apex 4.2.1
2)) What is the best hardware RAID configuration?
3)) What is the maximum concurrent users of applications on apex according to the above specs+software stack ?
Regards
Mahmoud

Dear Alvaro
Thank you for your response.
The current status
When I entered HP ACU from bootable Smart Start CD, I found under the configuration of Smart Array P410i in Embedded Slot, the following:
-Smart Array P410i in Embedded Slot
---Internal Drive Cage at Port 1I : Box 1
------300 GB 2-Part SAS Drive at Part 1I : Box 1 : Bay 1
------300 GB 2-Part SAS Drive at Part 1I : Box 1 : Bay 2
------300 GB 2-Part SAS Drive at Part 1I : Box 1 : Bay 3
------300 GB 2-Part SAS Drive at Part 1I : Box 1 : Bay 4
---Internal Drive Cage at Port 2I : Box 1
------300 GB 2-Part SAS Drive at Part 2I : Box 1 : Bay 5
------300 GB 2-Part SAS Drive at Part 2I : Box 1 : Bay 6
------300 GB 2-Part SAS Drive at Part 2I : Box 1 : Bay 7
------300 GB 2-Part SAS Drive at Part 2I : Box 1 : Bay 8
The questions now:
1) Do you recommend the following configuration for RAID's logical arrays:
Using Logical View:
SAS Array A - 4 Logical Drive(s)
--- Logical Drive 1 (50.0 GB, RAID 1+0) ---> for OS
--- Logical Drive 2 (24.0 GB, RAID 0) ---> for SWAP
--- Logical Drive 3 (200.0 GB, RAID 1+0) ---> for ASM DATA
--- Logical Drive 4 (296.7 GB, RAID 1+0) ---> for ASM FRA
SAS Array B - 1 Logical Drive(s)
--- Logical Drive 5 (1.1 TB, RAID 0) ---> for non-critical applications and sources
2) What are your recommendations for the following steps to reach oracle apex 4.2 installed?
Best Regards
Mahmoud

EXEC SQL PERFORMING

when run the following program ,it reported error as
"the error occurred in the current database connection "DEFAULT".
how to solve the problem ?
=================================
DATA : BEGIN OF WA,
CLIENT(3),
ARG1(3),
ARG2(3),
END OF WA.
DATA F3 VALUE '1'.
EXEC SQL PERFORMING LOOP_OUTPUT.
SELECT CLIENT , ARG1 INTO :WA FROM TABLE_001 WHERE ARG2 = :F3.
ENDEXEC.
FORM LOOP_OUTPUT.
WRITE : / WA-CLIENT,WA-ARG2.
ENDFORM.
==================================

hi
try
SELECT * FROM TABLE_001 INTO CORRESPONDING FIELDS OF WA WHERE ARG2 = F3.
KUMAR

Munky's SQL performance challenge [APEX Chart]

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