Need age in years based on his/her next birth day.

Question

Hi,
I need to Print age in years based on his/her next birth day.
SELECT TO_CHAR(TRUNC(MONTHS_BETWEEN((SYSDATE ), P.birth_date)/12)) A from employee I used the above code but I get the age with reference to the sysdate only. But what I require is the age based on next birthday.
For ex: Birth day: 24FEB2000
Then my expected output is 10.
If my birthday would have been 24DEC2000, then I would expect a result of '9', please help me with a function or a simple sql statement to code this.
Thank You

Answer 1

Maybe something like:
SQL> SELECT sysdate FROM Dual
  2  /
SYSDATE
17-JUN-09
1 row selected.
SQL> WITH test_tab AS
  2       (SELECT TO_DATE ('24FEB2000', 'DDMONYYYY') birth_date
  3          FROM DUAL
  4        UNION ALL
  5        SELECT TO_DATE ('24JUL2000', 'DDMONYYYY') birth_date
  6          FROM DUAL
  7        UNION ALL
  8        SELECT TO_DATE ('17JUN2000', 'DDMONYYYY') birth_date
  9          FROM DUAL)
10  SELECT birth_date,
11         CASE
12            WHEN SIGN (  TO_DATE (   TO_CHAR (birth_date, 'DDMON')
13                                  || TO_CHAR (SYSDATE, 'YYYY'),
14                                  'DDMONYYYY'
15                                 )
16                       - TRUNC (SYSDATE)
17                      ) <> 0
18               THEN TRUNC (MONTHS_BETWEEN (TRUNC (SYSDATE), birth_date) / 12)
19                    + 1
20            ELSE TRUNC (MONTHS_BETWEEN ((SYSDATE), birth_date) / 12)
21         END age
22    FROM test_tab
23  /
BIRTH_DAT        AGE
24-FEB-00         10
24-JUL-00          9
17-JUN-00          9
3 rows selected.
SQL> Hmm... Sean's Query is better....
Regards,
Jo