Need help to zip the files? ? ? ?

Question

hello friends
i am unable to zip the files in my directory by using this program
import java.io.*;
import java.util.zip.*;
public class Zip {
static final int BUFFER = 2048;
public static void main (String argv[]) {
try {
BufferedInputStream origin = null;
FileOutputStream dest = new
FileOutputStream("c:\\zip\\myfigs.zip");
ZipOutputStream out = new ZipOutputStream(new
BufferedOutputStream(dest));
//out.setMethod(ZipOutputStream.DEFLATED);
byte data[] = new byte[BUFFER];
// get a list of files from current directory
File f = new File(".");
String files[] = f.list();
for (int i=0; i<files.length; i++) {
System.out.println("Adding: "+files);
FileInputStream fi = new
FileInputStream(files[i]);
origin = new
BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(files[i]);
out.putNextEntry(entry);
int count;
while((count = origin.read(data, 0,
BUFFER)) != -1) {
out.write(data, 0, count);
origin.close();
out.close();
} catch(Exception e) {
e.printStackTrace();
but it is working fine for compress the files in the current directory
but
File f = new File("C:\\ramu");
it shows the error like this
C:\j2sdk1.4.2_09\bin>javac Zip.java
C:\j2sdk1.4.2_09\bin>java Zip
Adding: okh.txt
java.io.FileNotFoundException: C:\ramu (Access is denied)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:106)
at java.io.FileInputStream.<init>(FileInputStream.java:66)
at Zip.main(Zip.java:21)
can any body help to rectify this problem

Answer 1

Don't cross-post!
http://forum.java.sun.com/thread.jspa?threadID=5184841&tstart=0
And use code tags already.
The referenced thread already has advice for you (and no, we will not do it for you, you've already been given an example of how to do it, it is up to you to at least attempt it).