Need help with Pivoting rows to columns

Question

Hi,
I need help with pivoting rows to columns. I know there are other posts regarding this, but my requirement is more complex and harder. So, please give me a solution for this.
There are two tables say Table 1 and Table 2.
Table1
name address email identifier
x e g 1
f s d 2
h e n 3
k l b 4
Table2
identifier TRno zno bzid
1 T11 z11 b11
1 T12 z12 b12
1 T13 z13 b13
2 T21 z21 b21
2 T22 z22 b22
As you can see the identifier is the column that we use to map the two tables. The output should be like below
output
name address email identifier TRno1 zno1 bzid1 TRno2 zno2 bzid2 TRno3 zno3 bzid3
x e g 1 T11 z11 b11 T12 z12 b12 T13 z13 b13
f s d 2 T21 z21 b21 t22 z22 b22
Also we do not know exactly how many TRno's, zno's, etc each value in the identifier will have. There may be only 1 TRNO, zno and bzid, or there may be four.
All the values must be in separate columns, and not be just comma delimitted. There are also other conditions that i have to add to restrict the data.
So, can you please tell me what is should use to get the data in the required format? We are using Oracle 10g. Please let me know if u need any more information

Answer 1

Something like this ?
SCOTT@orcl> ed
Wrote file afiedt.buf
  1  select a.name,
  2  a.address,
  3  a.email,
  4  b.* from (
  5  select distinct identifier
  6  ,max(trno1) trno1
  7  ,max(zno1) zno1
  8  ,max(bzid1) bzid1
  9  ,max(trno2) trno2
10  ,max(zno2) zno2
11  ,max(bzid2) bzid2
12  ,max(trno3) trno3
13  ,max(zno3) zno3
14  ,max(bzid3) bzid3
15  ,max(trno4) trno4
16  ,max(zno4) zno4
17  ,max(bzid4) bzid4
18  from (select identifier
19  ,decode(rn,1,trno,null) trno1
20  ,decode(rn,1,zno,null) zno1
21  ,decode(rn,1,bzid,null) bzid1
22  ,decode(rn,2,trno,null) trno2
23  ,decode(rn,2,zno,null) zno2
24  ,decode(rn,2,bzid,null) bzid2
25  ,decode(rn,3,trno,null) trno3
26  ,decode(rn,3,zno,null) zno3
27  ,decode(rn,3,bzid,null) bzid3
28  ,decode(rn,4,trno,null) trno4
29  ,decode(rn,4,zno,null) zno4
30  ,decode(rn,4,bzid,null) bzid4
31  from (select identifier,
32  trno,bzid,zno,
33  dense_rank() over(partition by identifier order by trno,rownum) rn
34  from table2)
35  order by identifier)
36  group by identifier) b,table1 a
37* where a.identifier=b.identifier
SCOTT@orcl> /
NAME       ADDRESS    EMAIL      IDENTIFIER TRNO1      ZNO1       BZID1      TRNO2      ZNO2       BZID2      TRNO3      ZNO3       BZID3      TRNO4      ZNO4       BZID4
x          e          g          1          T11        z11        b11        T12        z12        b12        T13        z13        b13
f          s          d          2          T21        z21        b21        T22        z22        b22
SCOTT@orcl> select * from table1;
NAME       ADDRESS    EMAIL      IDENTIFIER
x          e          g          1
f          s          d          2
h          e          n          3
k          l          b          4
SCOTT@orcl> select * from table2;
IDENTIFIER TRNO       ZNO        BZID
1          T11        z11        b11
1          T12        z12        b12
1          T13        z13        b13
2          T21        z21        b21
2          T22        z22        b22
SCOTT@orcl>Regards
Girish Sharma