NEED SQL QUERY writing help
oracle 10g.
os : linux
table data appears like this
SQL> select * from test_grp;
COL1 COL2
aaa 111
aaa 444
aaa 222
bbb 333
bbb 555
SQL> select * from test_grp order by 2;
COL1 COL2
aaa 111
aaa 222
bbb 333
aaa 444
bbb 555
As per my application requirement I need to seggerage the data as
follows
aaa (2) ie --- 111,222
bbb(1) is --- 333
aaa(1) is --- 444
bbb(1) is -- 555
I am not able to frame this. Any help ?
SQL> create table test_grp
2 as
3 select 'aaa' col1, 111 col2 from dual union all
4 select 'aaa', 444 from dual union all
5 select 'aaa', 222 from dual union all
6 select 'bbb', 333 from dual union all
7 select 'bbb', 555 from dual
8 /
Tabel is aangemaakt.
SQL> select col1
2 , col2s
3 from ( select col1
4 , rtrim(col2s,',') col2s
5 , rn
6 , sumn
7 from ( select col1
8 , col2
9 , sum(n) over (order by col2) sumn
10 from ( select col1
11 , col2
12 , case when col1 = lag(col1) over (order by col2) then 0 else 1 end n
13 from test_grp
14 ) t
15 )
16 model
17 partition by (sumn)
18 dimension by (row_number() over (partition by sumn order by col2) rn)
19 measures (col1, cast(col2 as varchar2(100)) col2s)
20 rules
21 ( col2s[any] order by rn desc = col2s[cv()] || ',' || col2s[cv()+1]
22 )
23 )
24 where rn = 1
25 order by sumn
26 /
COL COL2S
aaa 111,222
bbb 333
aaa 444
bbb 555
4 rijen zijn geselecteerd.Regards,
Rob.
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data stores based on value type like
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Country
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True
2
Country
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Austrilia
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True
3
Country
Usa
United States of America
NULL
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True
4
Country
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5
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Andhrapradesh
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1
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6
State
MH
Maharastha
NULL
1
True
7
State
TN
Tamilnadu
NULL
1
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8
State
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Sydney
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9
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Melbourne
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10
Location
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11
Location
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1 Country
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3 Country
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1
6 State
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1
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Tamilnadu TN
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8 State
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in edusource database i have location and columns like countryname,statename,feildtext,descriptiom,isactive
i need to insert data in edusource
database of tbl_ maplocation from that that databaseTry this out:
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(7 , 'State' ,'TN ', 'Tamilnadu ', 1 , 'TRUE'),(8 , 'State' ,'Sdy ', 'Sydney ', 2 , 'TRUE'),
(9 , 'State' ,'MEL ', 'Melbourne ', 2 , 'TRUE'),(10 , 'Location' ,'IN-Hyd', 'Hyderabad ', 1 , 'TRUE'),
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10 2450 1300
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20 3000 800
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10 1300 1300
2450 1300
5000 1300
20 800 800
1100 800
2975 800
3000 800
800 800
30 1100 800
2975 800
40 3000 800
4000 900
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(SELECT 1435177 qte_id, 2 seq_no
FROM dual
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UNION ALL
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8 )
9 ,t2 as
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9 ,t2 as
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14 select 4 if from dual union all
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Hi All,
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Need sql query or pl/sql query urgent
Hi Experts,
The requirement is that
SELECT 'N' flag, sysdate init_date,
'' vendor_name,
DECODE (pa.address_type,
'P', 'Present Address',
'R', 'Permanent Address',
pa.address_type
) address_type,
pa.address_line1
|| ','
|| pa.address_line2
|| ','
|| pa.town_or_city
|| ','
|| meaning
|| ','
|| pa.POSTAL_CODE "Address",
TRUNC (TO_CHAR (pa.date_from, 'YYYY')) YEAR,
TO_CHAR (pa.date_from, 'MON') MONTH,''station
FROM per_addresses pa, fnd_lookup_values, per_all_people_f pf
WHERE (pf.employee_number = :1 or pf.APPLICANT_NUMBER = :2)
and pf.EFFECTIVE_END_DATE='31-DEC-4712'
AND pa.person_id = pf.person_id
AND pa.business_group_id = 42
--AND pa.date_to IS NULL
AND lookup_type = 'PER_US_COUNTRY_CODE'
AND lookup_code = pa.country
AND enabled_flag = 'Y'
AND (end_date_active IS NULL OR end_date_active > SYSDATE)
if i run the above query the output is coming like that
Present Address | Flat No. 1201, OC - 15, Orange County, Plot No. GH - 4,Ahinsa Khand 1st, Indrapuram,Ghaziabad,India,201010| 2,010| JUL
Permanent Address | Q.No. 354, Sector - 3 / B,,Bokaro Steel City,India,827003 |2,010 |JUL
Present Address | 4, Sitara,Chandra Reddy layout, S.T. Bed,Bangalore,India,0| 2,006| JAN
Present Address | 101,,Ushma Urja Apartments,Noida,India,201301 | 2,006 | JUL
Permanent Address | F-19, Maccon Colony, Opp. DAV Shyamali School,,Ranchi,India,834002 | 2,009 | FEB
Present Address | Flat no. 604, B - 1, Krishna Apra Gardens,Vaibhav Khand, Plot - 7,Ghaziabad,India,201010 | 2,009 FEB
But the requirement is the output should come like that
Permanent Address |Q.No. 354, Sector - 3 / B,,Bokaro Steel City,India,827003| 2,010 |JUL
Permanent Address 1| F-19, Maccon Colony, Opp. DAV Shyamali School,,Ranchi,India,834002| 2,009 | FEB
Present Address | Flat No. 1201, OC - 15, Orange County, Plot No. GH - 4,Ahinsa Khand 1st, Indrapuram,Ghaziabad,India,201010| 2,010 | JUL
Present Address 1 | Flat no. 604, B - 1, Krishna Apra Gardens,Vaibhav Khand, Plot - 7,Ghaziabad,India,201010| 2,009 | FEB
Present Address 2 | 101,,Ushma Urja Apartments,Noida,India,201301| 2,006| JUL
Present Address 3 | 4, Sitara,Chandra Reddy layout, S.T. Bed,Bangalore,India,0 | 2,006| JAN
Please provide logice how i need to write a sql query or procedure or function or package
Thanks & Regards
VenuYou can use analytics here :
SELECT
flag,
init_date,
vendor_name,
address_type ||' ' ||rn AS address_type,
Address,
YEAR,
MONTH,
station
FROM
SELECT
'N' flag,
sysdate init_date,
'' vendor_name,
DECODE (pa.address_type, 'P', 'Present Address', 'R','Permanent Address', pa.address_type ) address_type,
row_number() over(partition BY pa.address_type order by 1) AS rn,
pa.address_line1
|| ','
|| pa.address_line2
|| ','
|| pa.town_or_city
|| ','
|| meaning
|| ','
|| pa.POSTAL_CODE "Address",
TRUNC (TO_CHAR (pa.date_from, 'YYYY')) YEAR,
TO_CHAR (pa.date_from, 'MON') MONTH,
'' station
FROM
per_addresses pa,
fnd_lookup_values,
per_all_people_f pf
WHERE
pf.employee_number = :1
OR pf.APPLICANT_NUMBER = :2
AND pf.EFFECTIVE_END_DATE='31-DEC-4712'
AND pa.person_id = pf.person_id
AND pa.business_group_id = 42
--AND pa.date_to IS NULL
AND lookup_type = 'PER_US_COUNTRY_CODE'
AND lookup_code = pa.country
AND enabled_flag = 'Y'
AND
end_date_active IS NULL
OR end_date_active > SYSDATE
); -
HI
I want a sql query i.e., all employees list which are having lessthan maximum salary of manager in same departmnet;
my table is like this
employees
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
EMAIL NOT NULL VARCHAR2(25)
PHONE_NUMBER VARCHAR2(20)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(8,2)
COMMISSION_PCT NUMBER(2,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
if need the department table
departments:
DEPARTMENT_ID
NOT NULL NUMBER(4)
DEPARTMENT_NAME
NOT NULL VARCHAR2(30)
MANAGER_ID
NUMBER(6)
LOCATION_ID
NUMBER(4)Try this:
select
employees.last_name || ', ' || employees.first_name “Employee”,
employees.salary “Emp Salary”,
sub.salary “Mgr Salary”,
employees.department_id “Department”
from
employees,
( select
mgr.department_id dept,
max(mgr.salary) salary
from
employees,
employees mgr
where
employees.mgr = mgr.employee_id
group by
mgr.department_id) sub
where
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Jeff -
Need SQL query to get the result.
Region
Month
Trx Type
Resolution Summary
AMERICAS
May-13
Adjustments
Correct
EMEA
May-13
Adjustments
Incorrect
AMERICAS
May-13
Credit Memo
Incorrect
EMEA
May-13
Invoice
Correct
AMERICAS
May-13
Credit Memo
Correct
OFD
May-13
Adjustments
Correct
AMERICAS
May-13
Invoice
Incorrect
LAD
May-13
Adjustments
Correct
LAD
May-13
Adjustments
Correct
OFD
May-13
Adjustments
Correct
Above is my Table and find below the required result.Similarly for other regions as well. Can anyone help me with the SQL Query?
Region
Resolution Summary
Adjustment
Credit Memo
Invoice
Grand Total
AMERICAS
Correct
1
1
2
Incorrect
0
1
1
2Like this?
SQL> select * from transaction_audit;
REGION MTH TRX_TYPE RESOLUTIO
AMERICAS may-13 ADJUSTMENTS CORRECT
EMEA may-13 ADJUSTMENTS INCORRECT
AMERICAS may-13 CREDIT MEMO INCORRECT
EMEA may-13 INVOICE CORRECT
AMERICAS may-13 CREDIT MEMO CORRECT
OFD may-13 ADJUSTMENTS CORRECT
AMERICAS may-13 INVOICE INCORRECT
LAD may-13 ADJUSTMENTS CORRECT
LAD may-13 ADJUSTMENTS CORRECT
OFD may-13 ADJUSTMENTS CORRECT
10 rows selected.
SQL> select region
2 , resolution_summary
3 , count(decode(trx_type, 'ADJUSTMENTS', trx_type)) adjustments
4 , count(decode(trx_type, 'CREDIT MEMO', trx_type)) credit_memo
5 , count(decode(trx_type, 'INVOICE' , trx_type)) invoice
6 from transaction_audit
7 group
8 by region
9 , resolution_summary
10 order
11 by region
12 , resolution_summary
13 /
REGION RESOLUTIO ADJUSTMENTS CREDIT_MEMO INVOICE
AMERICAS CORRECT 1 1 0
AMERICAS INCORRECT 0 1 1
EMEA CORRECT 0 0 1
EMEA INCORRECT 1 0 0
LAD CORRECT 2 0 0
OFD CORRECT 2 0 0
6 rows selected.
SQL>
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