Need T-SQL query for Below condition, Thanks!

Question

experts,
i having a table with below data,
declare @tbl table (uid int, name varchar(10), id int)
insert table @tbl values (1, 'val1', 6)
insert table @tbl values (2, 'val2', 6)
insert table @tbl values (3, 'val2', 8)
insert table @tbl values (4, 'val1', 8)
insert table @tbl values (5, 'val2', 7)
insert table @tbl values (6, 'val1', 10)
need to get all rows for those "id"'s which having both "name" ("val1" & "val2")?
below should be output, thanks!@
declare @tbl table (uid int, name varchar(10), id int)
insert table @tbl values (1, 'val1', 6)
insert table @tbl values (2, 'val2', 6)
insert table @tbl values (3, 'val2', 8)
insert table @tbl values (4, 'val1', 8)

Answer 1

here you go with full illustration
declare @tbl table (uid int, name varchar(10), id int)
insert @tbl values (1, 'val1', 6)
insert @tbl values (2, 'val2', 6)
insert @tbl values (3, 'val2', 8)
insert @tbl values (3, 'val10', 8)
insert @tbl values (4, 'val1', 8)
insert @tbl values (5, 'val2', 7)
insert @tbl values (6, 'val1', 10)
insert @tbl values (6, 'val24', 11)
SELECT *
FROM @tbl t
WHERE EXISTS
SELECT 1
FROM @tbl
WHERE id = t.id
GROUP BY id
HAVING COUNT(DISTINCT CASE WHEN name IN ('val1','val2') THEN name END) = 2
and name IN ('val1','val2')
output
uid name id
1 val1 6
2 val2 6
3 val2 8
4 val1 8
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