Number of occurence of substring in a string ?.

Hi,
Are there any direct functions available in oracle to count the occurence of a substring in a main string. instr function gives only the position. for e.g: We wanted to count the number of "." in a string
"oracle.co.in" . It should return 2.
Any thoughts ?
With thanks in advance
Ranjeesh

Purushotham:
You are right about the casewhen the string and the substring are the same, the query will return NULL. However, it will return 0 if the substring is not in the string. The NVL version would be:
NVL((Length(string) - length(replace(string, substring, null)))/length(substring),1);The other consideration is whether you want this case sensitive or not. or case insensitivity, you will need to user UPPER or LOWER on both string and substr inside the REPLACE function.
John

Similar Messages

How to find the number of occurence of a string

String str="The AR tech seeks experienced candidates in java,jsp. The candidates should have atleast 1 year of experience in the specified skills.";
here i need to find the number of occurence of the string "experience".
how to find it out?

String str="The AR tech seeks experienced candidates in java,jsp. The candidates should have atleast 1 year of experience in the specified skills.";
String findStr = "experience";
int count = 0;
int index = 0;
while(index != -1) {
index = str.indexOf(findStr, (count == 0 ? 0 : index + findStr.length()));
if(index != -1) {
count++;

I need to WAP to count the number of occurences of an alphabet in a string.

I need to WAP to count the number of occurences of an alphabet in a string.I tried a lot and have surfed a lot regarding this problem.
I m not the most proficient with java.but this is all i could come up with,and would appreciate some help here.I hope you guys would help me find a solution to this.
e.g String : abcabrty
Result should be
a:2
b:2
c:1
r:1
t:1
y:1
public class chkoccurences
     public static void main(String args[ ])
          String user_Data=args[0];
          int counter=0;
          try
               for(int i=0;i<user_Data.length( );i++)
                    for(int j=0;j<user_Data.length( );j++)
                         if(user_Data.charAt(i) == user_Data.charAt(j))
                         counter++;
                    System.out.println(user_Data.charAt(i)+" exists "+counter+" time(s) in the word.");
               System.out.println(" ");
          catch(ArrayIndexOutOfBoundsException e)
               System.out.println("Check the array size.");
}This is the output i get out of the program:
a exists 2 time(s) in the word.
b exists 4 time(s) in the word.
c exists 5 time(s) in the word.
a exists 7 time(s) in the word.
b exists 9 time(s) in the word.
r exists 10 time(s) in the word.
t exists 11 time(s) in the word.
y exists 12 time(s) in the word.What i think is i need an array to store the repeated characters because the repeated characters are getting counted again in the loop,if you know what i mean.
Please, i would appreciate some help here.

Criticism is welcomed
public class tests {
     final int min = 10;
     final int max = 35;
     final char[] chars = new char[] {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h',
               'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u',
               'v', 'w', 'x', 'y', 'z'};
     public static void main(String[] args){
          tests t = new tests();
          String[] strings = new String[] {"aabcze", "att3%a", ""};
          for(String s : strings){
               System.out.println(t.getAlphaCount(s));
     public String getAlphaCount(String s){
          int[] alphaCount = new int[26];
          int val;
          for(char c : s.toCharArray()){
               val = Character.getNumericValue(c);
               if( (val>=min) && (val<=max)){
                    alphaCount[val-min]++;
          StringBuilder result = new StringBuilder();
          for(int i=0; i<alphaCount.length; i++){
               if(alphaCount[i] > 0){
                    result.append(chars[i] + ":" + alphaCount[i] + ", ");
          if(result.length() != 0){
               result.delete(result.length()-2, result.length());
          return result.toString();
}

How to find out the number of occurence of special character

Hi ,
I have a string coming coming in I/p which is like '1;2;100;201;'
I need to break up this string and run my process for each value ( i.e for 1,2,100 and 201).
How i can know the count of number of occurences of ';' character?
How i can loop so that it runs once for each value?

1. Split, pre Oracle 10g...
===========================
with t as (select '10,aaaa,20,vvvvv,30,xxx''xx,12,12,56' txt from dual)
select substr( txt
             , decode(level, 1, 1, instr(txt, ',', 1, level-1)+1)
             , decode(instr(txt, ',', 1, level), 0, length(txt), instr(txt, ',', 1, level)
               - decode(level, 1, 0, instr(txt, ',', 1, level-1))-1)
             ) val
from t
connect by level <= length(txt)-length(replace(txt,','))+1
VAL
10
aaaa
20
vvvvv
30
xxx'xx
12
12
56
9 rows selected.2. Split, 10g onwards using regular expressions
===============================================
with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' as txt from dual)
-- end of sample data
select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
from t
connect by level <= length(regexp_replace(txt,'[^,]*'))+1
REGEXP_SUBSTR(TXT,'[^,]+',1,LE
aaaa
bbbb
cccc
dddd
eeee
ffff
7 rows selected.example usage with varying IN clause...
SQL> ed
Wrote file afiedt.buf
1 select *
2 from emp
3 where ename in (
4    with t as (select '&input_string' as txt from dual)
5    select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
6    from t
7    connect by level <= length(regexp_replace(txt,'[^,]*'))+1
8*   )
SQL> /
Enter value for input_string: SCOTT,JAMES
old   4:   with t as (select '&input_string' as txt from dual)
new   4:   with t as (select 'SCOTT,JAMES' as txt from dual)
     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO
      7788 SCOTT      ANALYST         7566 19-04-1987 00:00:00       3000                    20
      7900 JAMES      CLERK           7698 03-12-1981 00:00:00        950                    30
SQL>3. Split 10g onwards using XMLTABLE...
======================================
SQL> ed
Wrote file afiedt.buf
1 with t as (select 'This is some sample text that needs splitting into words' as txt from dual)
2 select x.*
3 from t
4      ,xmltable('x/y'
5                passing xmltype('<x><y>'||replace(t.txt,' ','</y><y>')||'</y></x>')
6                columns word varchar2(20) path '.'
7*              ) x
SQL> /
WORD
This
is
some
sample
text
that
needs
splitting
into
words
10 rows selected.

Searching for a substring within a string

can someone reccomend a simple way to search for a substring within a string and count the number occurences of that substring.
The substring and the string will be provided as command line parameters.
Thanks
gg

A simple way would be to use the indexOf methods in String:
http://java.sun.com/j2se/1.5.0/docs/api/java/lang/String.html
Not sure what this has to do with event handling though :-P

Looking for a substring within a string (regexp)

Hi folks,
I want to select a substring from a string
string:
21;0000;4145054;4;A;4 mit ALU XEOFX,117107,XEOFX YWY,1,YWY
or
21;0000;4145054;4;A;4 goldglamsnu XEOFX,198877,XEOFX YWY,1,YWY
I'm looking for the substring:
YWY,1,YWY
and try this SQL statement
SQL> select REGEXP_substr('21;0000;4145054;4;A;4 mit ALU XEOFX,117107,XEOFX YWY,1,YWY' ,',[^YWY]+[0-9]')
2 from dual;
REGEXP_
,117107
I don't know where my mistake is. Can anybody please help me?
Database Version 11G R2
Thanks,
ben
Edited by: ben512 on May 14, 2013 5:05 PM

Hi,
ben512 wrote:
Hi folks,
I want to select a substring from a string
string:
21;0000;4145054;4;A;4 mit ALU XEOFX,117107,XEOFX YWY,1,YWY
or
21;0000;4145054;4;A;4 goldglamsnu XEOFX,198877,XEOFX YWY,1,YWY
I'm looking for the substring:
YWY,1,YWYWhy do you want that substring. Do you always want the last 9 characters of the string?
If you're looking for a substring that starts with 'YWY', and then has any number (including 0) of commas, digits, and additional 'YWY' strings after it, then:
REGEXP_SUBSTR ( str
, 'YWY[,[:digit:]]*)
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, maybe 5 or 10 rows), and also post the results you want from that data. Include examples of any special cases you need to handle (e.g., the target pattern is not found at all, or it is found at 2 different places in the string).
Explain, using specific examples, how you get those results from that data. Say what your business rules are.
Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
See the forum FAQ {message:id=9360002}

How to count the number of occurences of a character

hi
wat command is used to count the number of occurences of a charcter in a line?
i have to count the number of '.' in a line

FIND
Searches for patterns.
Syntax
FIND <p> IN [SECTION OFFSET <off> LENGTH <len> OF] <text>
            [IGNORING CASE|RESPECTING CASE]
            [IN BYTE MODE|IN CHARACTER MODE]
            [MATCH OFFSET <o>] [MATCH LENGTH <l>].
The system searches the field <text> for the pattern <p>. The SECTION OFFSET <off> LENGTH <len> OF addition tells the system to search only from the <off> position in the length <len>. IGNORING CASE or RESPECTING CASE (default) specifies whether the search is to be case-sensitive. In Unicode programs, you must specify whether the statement is a character or byte operation, using the IN BYTE MODE or IN CHARACTER MODE (default) additions. The MATCH OFFSET and MATCH LENGTH additions set the offset of the first occurrence and length of the search string in the fields <p> and <l>.

To count the number of occurences of a character

Hi All,
Is there a particular function to count the number of occurences of a particular character in a string...?
Let me know if u know the same.
Thanx and regards
Akshat

A method with a test driver:
public class a {
     public static void main(String args[]) {
          System.out.println(howmany(args[0],args[1].charAt(0)));
     public static int howmany(String what,char c) {
          String regexp = "" + c;
          String s=null;
          try     {
               s=what.replaceAll(regexp,"");
          catch (Exception e) {
                regexp = "\\" + c;
               s=what.replaceAll(regexp,"");
          return what.length() - s.length();
}

How to replace multiple occurences of space in a string to a single space?

How to replace multiple occurences of space in a string to a single space?

Hi,
try this code.
data : string1(50) type c,
          flag(1) type c,
          dummy(50) type c,
          i type i,
          len type i.
string1 = 'HI READ    THIS'.
len = strlen( string1 ).
do len times.
if string1+i(1) = ' '.
flag = 'X'.
else.
if flag = 'X'.
concatenate dummy string1+i(1) into dummy separated by space.
clear flag.
else.
concatenate dummy string1+i(1) into dummy.
endif.
endif.
i = i + 1.
enddo.
write : / string1.
write : / dummy.

How to search for perticular substring in given string.

Hi, Can any one tell me how to search for perticular substring in given string.
example:
I have to search for CA in given Order type it may be CA10 or CA15. Please Do the needful.

Hi Aniruddha,
check this...
Data var string,
var = 'India'.
search var for 'Ind'.
if sy-subrc = 0. " var having ind
Message 'Ind found' type 'I'.
else . "var not having ind
Message 'Ind not Found' type 'I'.
endif.
thanx
bgan.

Get the number of occurences in a text

Hi,
Is there any way by which i can check the number of occurences of a word in a text ???
for eg. i an have 'i am a good boy and i am a good man'
i wnt to check the number of occurences of good in the above statemnt
Ny way to do that..........
Thanks

Well, it was a silly suggestion from me regarding ";" or "." - of course they are nonword characters.
Basically, the issue is the same as with
SQL> with t as (
2    select ' good good good good good good ' s from dual
3 )
4 select
5 s,
6 regexp_count(s,' good ') reg_count
7 from t
8 ;
S                                REG_COUNT
good good good good good good           3And i don't see at the moment a simple workaround...
Best regards
Maxim

Count the number of occurence in table with toplink

Hi !
there is no way to build a query with expressionbuilder or .... to count the number of occurences in my table ?
i don't want use query " select count(*) from table "
thanks

Not sure of the question. Are you looking to get the sql "select count(*) from table" from using the TopLink expression framework or are you getting that SQL already and want something else?
If you are looking just to get the count from a table/class, you can use a ReportQuery:
ReportQuery rquery = new ReportQuery(ClassToQueryOn.class);
rquery.addCount(); //equivalent to count(*);
session.executeQuery(rquery);
You can use a report query to return data instead of objects, and use selection criteria just like a normal read query.
Best Regards,
Chris

Sql query: number of occurence of cellData on more thann one column in tabl

I have employee table contains following rows.
INSERT INTO employee VALUES (105, 'Srinath','vijay','Aeronautics', 27, 33000);
INSERT INTO employee VALUES (105, 'Kumble','Anil','Aeronautics', 27, 33000);
INSERT INTO employee VALUES (105, 'Prabhakar','Manoj','Aeronautics', 27, 33000);
INSERT INTO employee VALUES (105, 'Srinath','Jawagal','Aeronautics', 27, 33000);
INSERT INTO employee VALUES (105, 'Jawagal','Srinath','Aeronautics', 27, 33000);
INSERT INTO employee VALUES (105, 'Mishra','Anil','Aeronautics', 27, 33000);
INSERT INTO employee VALUES (105, 'Kumble','Prabhakar','Aeronautics', 27, 33000);select distinct first_name firstName,count(1) over (partition by first_name) firstNameCount from employee;
and i got the follwoing result.
(Srinath 2,Kumble 2,Prabhakar 1,Jawagal 1,Mishra 1)
Now i want to consider second and third column both and want to number of occurence of table data on these two columns
(Srinath 3,Kumble 2,Prabhakar 2,Jawagal 2,Mishra 1,vijay 1,Anil 2,Manoj 1)As Srinath is coming 3 times, kumble 2 times, Prabhakar 2 times,Jawagal 2 times,Mishra 1 times,vijay 1 times,Anil 2 times and Manoj 1 times.
What will be my sql query?

Try this
select name, count(name) over(partition by name) cnt
from (select first_name from employee union all select last_name from employee)

Count the number of occurences of a pattern in some files

Hi,
I am trying to extract some patterns in files using regex. I can easily extract the patterns using my program. I also wanted to count the number of occurences of the pattern in the files. For that I have written this code:
int count=0;
          while (m.find())
             System.out.println("Found Patterns: "+m.group());
             count++;
       System.out.println(count); //giving error saying identifier expectedUnfortunately I am getting an error saying identifier expected at the count line. What to do?
Thanks

Cheapside-Poultry wrote:
Move the } down one line so the count is in scope.No, it looks like he just forgot the opening { with the while.

Reliable detect number of occurences (table lock needed or ?)

Hi all,
I got an issue with detecting duplicate messages. Database clients process files and messages and create a hash value that is passed on to the database. The database should return the number of occurences of this hash value in the last (e.g) 14 days.
create table HashHistory ( ID NUMBER,
MESSAGEHASH VARCHAR2 (20),
TS TIMESTAMP);
create sequence SomeSequence;
insert into HashHistory values (SomeSequence.nextval,'first hash', systimestamp);
insert into HashHistory values (SomeSequence.nextval,'second hash', systimestamp);
create or replace procedure DuplDetection (p_HashIn varchar2,
                                     p_occurences OUT number) AS
l_timestamp timestamp default systimestamp;
begin
-- possible exclusive table lock here... lock table HashHistory in exclusive mode;
insert into HashHistory values (SomeSequence.nextval, p_HashIn, l_timestamp);
select count (1)
into p_occurences
FROM HashHistory
where MESSAGEHASH = p_HashIn
and   TS < l_timestamp
and   TS > l_timestamp-14;
commit; --to release the table lock if applicable
end;When this procedure is called by two different machines at the same time with the same new hash value ('third hash'). One session should return 0 while the other should return 1 as number of occurences.... With default Oracle behaviour using row level locks, and executing them in parallel both sessions will not be able to see the others sessions hash values, and both will return 0 occurences. Is an exclusive table lock my only option to enforce this behaviour or can I trust Oracle to handle this correctly?
I expect 10^6 hashes each day and possible up to 10 or 20 clients running at the same time generating and checking these hash values. What are the changes of both sessions returning the same value without an exclusive table lock (as in this example)? What other parameters would you consider?
I am on Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi

Nicosa wrote:
Hi,
Wouldn'that work if you do it as follows ?insert into HashHistory values (SomeSequence.nextval, p_hashIn,...);
commit;
select count (1)
into p_occurences
FROM HashHistory
where MESSAGEHASH = p_HashIn
and   TS > l_timestamp-14
and ID!=SomeSequence.currval;The second session should see that some others existing hash were inserted, and hence an be warned.No, it wouldn't work. Some kind of synchronization is required.
In multi-threaded environment you cannot predict the order of execution of this program.
Let say we have a server with only one processor and 3 users (sessions) connected to that server.
Three users (let say U1, U2 and U3) call this procedure to insert the same hash. The procedure has 3 operations: insert, commit, select,
and assume theoretically that these 3 operation are atomic (each takes only one processor cycle - in reality each of these operations can consume thousands of cycles).
Server can execute these calls in this order:
U1-insert (sequence + 1)
U1-commit
U1-select (returns 0)
U2-insert (sequence + 1)
U2-commit
U2-select (returns 1)
U3-insert (sequence + 1)
U3-commit
U3-select (returns 2)
- in this scenario results will be OK.
But the order might be:
U1-insert (sequence + 1)
U1-commit
- here server decides to switch to another process/thread
U2-insert (sequence + 1)
U2-commit
- server switches to proccess 3
U3-insert (sequence + 1)
U3-commit
- server switches back to U2
U2-Select (user 2 sees record commited by U1 and U3 and returns 2)
- server switches to U3
U3-Select (user 1 sees record commited by U1 and U2 and returns 2)
- server switches to U1
U1 - Select (this also returns 2)
- results are 2,2,2, but should be 0,1,2
If 20 users cal this procedure at the same moment with the same hash value, it is even possible that each user gets 19 as the final result,
but proper results should be 0, 1, 2, 3 .... 19 ;)
Without some kind of synchronization this a lottery.
There is also another trap with the sequence - consider this example:
Session 1
SQL> create sequence abc;
Sequence created.
SQL> select abc.nextval from dual connect by level <=5;
   NEXTVAL
      1
      2
      3
      4
      5
SQL> select abc.currval from dual;
   CURRVAL
      5Session 2
SQL> select abc.nextval from dual;
   NEXTVAL
      6
SQL> select abc.nextval from dual connect by level <=5;
   NEXTVAL
      7
      8
      9
     10
     11
SQL> select abc.currval from dual;
   CURRVAL
     11Back to session 1
SQL> select abc.currval from dual;
   CURRVAL
      5What happens in this scenario:
- user 1 does insert (select nextval from the sequence)
- user 2,3,4,5,6 ..... 100 call the procedure just 3 microseconds after U1 and do insert (increase the sequence)
- user 1 retrieve currval from the sequence ?

Number of occurence of substring in a string ?.

Similar Messages

Maybe you are looking for