OBIEE Subquery Join

Hi All,
I am able to join 2 reports using 'Filter Is Based on Results of Another Analysis' based on e_id and m_timestamp to build report for below query
select a.e_id ,count(distinct a.m_timestamp) from
raw_data a, (
select count(*),e_id,m_timestamp from raw_data
group by e_id,m_timestamp
having count(*) > 1) b
where a.eq_id = b.e_id and a.m_timestamp = b.m_timestamp
group by a.e_id
But i want eliminate join and build a report based on this (to improve performance )
select b.e_id ,count(*) from
select count(*),e_id,m_timestamp from raw_data
group by e_id,m_timestamp
having count(*) > 1) b
group by b.e_id
Which gives same result but with joins eliminated - Can someone help how to implement this in OBIEE 11g ?

Try something like
select e_id ,count(distinct m_timestamp) from
raw_data
having count(1) > 1
group by e_id
If helps mark
~ http://cool-bi.com

Similar Messages

  • OBIEE - Outer Joins

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  • OBIEE - table join across databases

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    Wo_task_labor
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    | 4            | 2            | 11:00      | 11:20     |
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    Message was edited by:
    user574699

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    http://108obiee.blogspot.com

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