Obtaining the template of the current page in extJS

Hi,
How can I obtain the template of the current page in the design dialog of a component?

Found a solution to it. All the properties of the page gets stored in an json object which can be accessed by appending .1.json to the page url. If http://localhost:4502/content/en.html is your page, then http://localhost:4502/content/en.1.json gives your page properties. Hence, we can extract the required property(cq:template) from the object using getJSON() method.

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How do I programmatically reference the current page in 902?

Hello,
How do I programmatically reference the current page in 902?
The Portal Smart Text option for Current Page is not flexible enough, and I wish to create my own custom greeting using PL/SQL.
Cheers,
John

hi,
If you are developing a PLSQL Portlet, then you do have a way for getting the page URL.
The page URL can be obtained from the record, portlet_runtime_record. There is a filed page_urlavailable with portlet_runtime_record.
The portlet_runtime_record is passed as a argument to the show_portlet procedure.
--Sriram

Is there any API to obtain the current Folder ID where the user is located??

how can obtain the current folder id where the user is?
tks in advance

Folder Id is one of the attributes you can pass to a custom item
type procedure. In the custom item type, go to the Procedures
tab. At the bottom of the page, under "Pass Attributes as
Parameters" select Folder Id from the list. Under "Pass As" you
have to provide the name of the parameter in your custom
procedure.
For example, here is a procedure that displays a list of
subfolders for a given folder:
<pre>
create or replace procedure SCOTT.DISPLAY_SUBFOLDERS AS
p_folderid IN VARCHAR2,
p_siteid IN VARCHAR2)
as
begin
for c in
(select '<a href="PORTAL30.wwv_main.main?p_cornerid=' || f.id
|| '&p_siteid=' || f.caid || ">'
|| f.display_name || '</a>' theURL
from portal30.wwsbr_all_folders f, portal30.wwv_user_corners c
where c.id = f.id
and c.parentid = p_folderid
and f.caid = p_siteid ) loop
htp.p(c.theURL || '<br>');
end loop;
exception
when others then
null;
end;
</pre>
This procedure takes both the folder id and the site id as
parameters.
Regards,
Jerry

How to achieve SUBMIT for the current page when I click other tab?

Problem: How to achieve SUBMIT for the current page when I click other tab?
Description: I have a two-page application and each page associates with a tab. Say page1 associates tab1 and page2 associates tab2. In each page, I have a submit button, a after submit process associated to the submit button, and a tabular form. For page1, I fill out the fields and hit the button. The page1 will appear again and I can see the data I have insert. However, If I fill out the fields and click the tab2 (page 2) instead. when I come back to page1, the data I filled out are all gone. Is there any way in HTML DB to force the submit in the current page after you click other page. If use JavaScript, what is code looks like.
Appreciate your time and your answer.
Mike

Scott,
just for clarity, if I understood correctly what you said there are two possibilities:
1) keep the standard tab branch and give up the possibility of validating page items. Below you can find an example of such cases.
2) Replace the template substitution string and perform a "custom" button-like submit also adding a branch to the main page associated with the tab. Page items will be validated if the branch firing point is set after the validations.
I couldn't find an example of the latter, but I found easily an example of the former:
it's the "Report attributes", page 420 of app 4000.
If you enter 'aaa' in the "Number of rows" form field and then you press "apply changes", htmldb correctly displays an inline error message saying that the value must be numeric. On the contrary, if you click on the "Region Definition" tab, htmldb takes you to a page showing an oracle exception:
ORA-20001: Error in DML: p_rowid=4785927011172906402, p_alt_rowid=ID, p_rowid2=, p_alt_rowid2=. ORA-20001: Invalid numeric value aaa for column PLUG_QUERY_NUM_ROWS
Bye,
Flavio

I am trying to print all the PDF pages in a range of 5 pages but can only print one page at a time . . . It will print the current page, but not all or pages 1-5. Can this be overcome?

I am trying to print all the PDF pages in a range of 5 pages but can only print one page at a time . . . It will print the current page only, but not all or pages 1-5. I need to go to the next subsequent page and command to print current page; continuing with this procedure until all pages are printed one at a time. Can this be overcome?

You can use printPages(1, 5), however I need to know how you print current page.

How do I determine whether the current page in Forms is the last page.

I have a requirement of printing amount in words using SPELL_AMOUNT Funtion Module, in SAP Scripts.
When I have only one Item Line, I am able to successfully, print the amount.
The moment i have line items pouring to the next page, I see that the I am unable to retrieve the spelled amount from the Function Module.
I think may be i need to find out if the current page is the last page, and if it is so, print the amount on the last page, .i.e., the page where the item lines have overflowed to. How do i find this out.
Can anybody, suggest something.
Regards,
Owais...

I wonder if you could do something like this. Wrap your logic with this IF statement.
/: IF &PAGE& = &SAPSCRIPT-FORMPAGES&
/: ENDIF
Regards,
Rich Heilman

How can I make a link a different color than the other links according to the current page?

Hello. I have created a navigation bar. And I would like to style the links to have the current page link a different color than the other links. For example, if all of the links have a black background, I would like to have the current page link to have a white background. The reason that I would like to style them this way is so that the visitor knows what page is being visitied.
I tried different ways but all of them did not show to make any change to the links. This is what I have so far. The links work, but all of them have the same color and background. When on the home page, I would like to have the home page link to have a white background with black letters. I would appreciate your advice.
<head>
ul {
    list-style-type: none;
    text-align: right;
    padding-top: 10px;
    padding-bottom: 6px;
    padding-right: 10px;
li {
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a:link {
    color: #FFF;
    background-color: #000;
    text-align: center;
    padding-top: 8px;
    padding-right: 8px;
    padding-bottom: 8px;
    padding-left: 7px;
    text-decoration: none;
a:visited {
    color: #FFF;
    background-color: #000;
    text-decoration: none;
a:hover {
    color: #000;
    background-color: #FFF;
    text-decoration: none;
a:active {
    color: #FFF;
    background-color: #000;
    text-decoration: none;
a.menu:link {
     color: #000
     background-color: #FFF;
     text-decoration: none;
</head>
<body>
<div class="navigation">
    <ul>
        <li class="menu"><a href="index.html" target="_self">HOME</a></li>
</body>
Thank you very much.

http://www.itworld.com/development/351097/setting-active-menu-item-based-current-url-jquer y

How to get the current page URL

HI All
I am working in oracle apps 4.0
I have one page called history in that i have one page item called Application url. My application id is 122 but its a copy of application 106
How to get the current page url for the page item.
Any steps should be help ful
Thanks & Regards
Srikkanth.M

I'm not 100% clear on what the requirement is from the description, however it does sound like you are making things unnecessarily complicated.
If you want permanent/ID-independent links then use application and page aliases.
so here we used to display the url like this: <tt>{noformat}http://81.131.254.171:8080/apex/f?p=122{noformat}</tt>
Do you mean that the URL is displayed like that? If so that doesn't seem particularly helpful. How is anyone supposed to know what it is?
There are many ways to provide links in APEX—including lists and nav bars.
Where the link is to another resource located on the same server (such as another page in the same app, or a different app in the workspace), relative addressing can be used, making it unecessary to include scheme, domain and port information in the URL. For example, if the page to be linked to has a page alias <tt>ABOUT</tt> in an application with alias <tt>UNITY</tt>, and the apps share an authentication scheme/cookie to permit shared sessions, then the link URL is simply
f?p=UNITY:ABOUT:&APP_SESSION.

How to get the function name/ID of the current page

HI,
I searched the forum and google, but it is not clear on how to get the function name of the current page.
I have 4 functions in my self service A ,B,C,D (seeded page links ) they all have to go to a page called hhhPG. Based on which function user is clicks I have to show the data in hhhPG.
so my question is how to get the function name ? I mean I need to know if user click on link A , B, C or D link and came to this page.
I found below in one forum and also there is getfunctionID in pageContext , but I do not know what to pass to getfunctionid("???") to get value.
FunctionSecurity funcSecurity = pageContext.getFunctionSecurity();
Or is there a better way of know where user is coming from ? like geturl....
Please help, I need this ASAP.
Thank you.

Use below to find out how the user came into the page
FunctionSecurity funcSecurity = pageContext.getFunctionSecurity();
boolean isFunc1 = funcSecurity.testFunction(funcSecurity.getFunction("YOUR_FUNCTION_SHORT_NAME1"));
boolean isFunc2 = funcSecurity.testFunction(funcSecurity.getFunction("YOUR_FUNCTION_SHORT_NAME2"));
boolean isFunc3 = funcSecurity.testFunction(funcSecurity.getFunction("YOUR_FUNCTION_SHORT_NAME3"));
boolean isFunc4 = funcSecurity.testFunction(funcSecurity.getFunction("YOUR_FUNCTION_SHORT_NAME4"));
So one of them will be true based on the function the user came in.
Write your logic based on these flags.
Regards,
Peddi.

How can I get the current user and the current page?

Hi everyone
Question..
It is possible to get the current user (from the user's database on apex) and the current page? (I mean, if I'm in page 4 be able to query a variable / function or something which could give me the current displayed page)
Thank you very much... I'd been researching without success :-S so I'll appreciate your help
Regards,
Fury

Fury,
If the user has authenticated, :APP_USER is the name that was used. The current page id is in :APP_PAGE_ID.
Although I showed bind variable notation for those, & substitution format and v() notation are also available for referencing developer-defined items or built-in names. See the User's Guide for more details.
Scott

Using Acrobat Reader activeX to get the current page views in a document

Hello,
I'm using the Acrobat Reader ActiveX control.
How can I use this API (or any other way) to get the current page of the PDF document inside the Acrobat reader ActiveX control ?
Thanks
Ariel

Aandi,
I reckon that you might be right.
But as side note, maybe Adobe will lose me and others as contributers for her PDF oriented solutions for other formats.
In the long run experts can tell which approach is better: a .Net like approach (no limitations upon development issues for ) or this kind of an approach.
Thank you very very much for you help!
Ariel

[CS5.5] How to import a snippet into the current page

Hi All,
I got the IDOMElement from the document UIDRef and imported the snippet into it. Here's the code-
InterfacePtr<IDOMElement> documentElement(docRef, UseDefaultIID());
if (documentElement == NULL)
    break;
if ((status = Utils<ISnippetImport>()->ImportFromStream(tStream, documentElement)) == kSuccess)
    //success
( tStream is the IPMStream of the snippet I'm importing)
This code above is able to import the snippet successfully to the first page of the active document, but I want it to be imported in the current active page instead. So for this, I tried getting the IDOMElement from the current page's UIDRef instead (logically I thought that this will import the snippet to the current page)-
InterfacePtr<IDOMElement> documentElement(currentPageUIDRef, UseDefaultIID());
But the result is just the same— the documentElement is not null, but the snippet is imported to the first page only.
May be that the concept of IDOMElement is not clear to me, but I cant find any documentation of it in the SDK guides too. Can anyone explain to me what's an IDOMElement and how can I import a snippet to the current page?
Any help will be highly appreciated. Thanks.

@mfreitag, thanks a lot for your reply.
I havent tried it yet, will let you know after I try it- but I want to ask that how will that help me placing elements to the page? Can you please elaborate a bit.
Actually in CS3, I used to follow this implementation to place the snippet into the current page-
1. Create a dummy textframe in the current page (needed just to create a group).
2. Create a Group using that dummy frame.
3. Get the IDOMElement of the UIDRef of that group-
   InterfacePtr<IDOMElement> documentElement(groupUIDRef, UseDefaultIID());
4. Import snippet to this DOM Element
5. Delete the dummy frame
The snippet items were added into the group beautifully in the active page. But when I was porting the plugin to CS5.5, steps after step-3 failed, and the snippet is imported to the 1st page/spread of the document.
I'm not sure, but seems that things related to IDomElement are changed for CS3+. May be you have an idea whether I could use the similar implementation to get this thing work?

How to you reference the current page number and total pages in a script?

I'm trying write a small script to make field invisible when the current page equals the total number of pages, but with no luck.
Can anyone advise how to do this?
I've tried various ways to reference my fields, this being the most basic:
if(pageNumber == totalPages) {
continuedBase.presence = "invisible";
// pageNumber has a run time property as "Current Page Number"
// totalPages has a run time property as "Number of Pages"
// continuedBase is a text field within the same subform as pageNumber and totalPages
Thanks for any help offered.
Russell

If you are asking how to get the current page and total pages you acn use these commands:
current page ----- xfa.layout.page(this)
total pages ------ xfa.layout.pageCount()
so your code woudl look like this:
app.alert("The curent page is: " + xfa.layout.page(this));
app.aler("The total number of pages is: " + xfa.layout.pageCount());
if(xfa.layout.page(this) == xfa.layout.pageCount()) {
continuedBase.presence = "invisible";

I can only print the current page of downloaded pdf's. Not able to print "all". I'm using a Macbook air.

I can only print the current page of downloaded pdf's. Not able to print "all". I'm using a Macbook air.

it says "the document could not be printed". "There were no ages selected to print".
I selected "all". I always tried selecting pages "1-3".
The only choice that works is current page. Very strange.

How to exit the session at the end of the current page

hi gurus,
i want to exit the session at the end of the current page, so that when i am trying to open some other page in the same browser it should ask for login id & pwd and should not pick the previous session-id.
Regards,
srikar

Look at the below links, it might help you..
[Link1|Re: Navigation with a new session]
[Link2|how to end a session in bsp ?]
Raja

Obtaining the template of the current page in extJS

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