On-line Fireworks Class
Has anyone taken the on-line Fireworks class with the
HTML Writers Guild?
Was it worth your time and money?
Thanks.
-Tom
There are more up-to-date online training offerings
available:
http://movielibrary.lynda.com/html/modPage.asp?ID=333
http://www.totaltraining.com/prod/outlines/adobe/fireworkscs3.asp
http://www.vtc.com/products/Adobe-Fireworks-CS3-Quickstart-Tutorials.htm
Regards
John Waller
Similar Messages
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Reflection errors in Field Data Edit Scripting context(Line Item class)
Hello Experts,
I have a script that does some validation in the Field Data Edit Scripting context of the "Line Item" class, and I have "MATERIAL" as my target. when i try throwing an Application Exception in this context I get a reflection error message box instead of the message I have passed to the Application Exception constructor.
your help will be greatly appreciated.
kind regards,One thing to be aware of is that no matter how you choose to construct your exception in field, field data edit and collection scripts, the attribute is always set to the be the taget field/collection. Have you noticed that? The script designers made things that way. What's going on here is that the exception raised in the Interprer is caught by the Script Manager and rethrown with the script target as the attribute and your raised exception as the exception.
One other thing I would point out is that scripts set to execute on the Collection Member Lifecycle event tend to be poor performers. You can get a faster result if you edit whole collection and chain the errors onto one ChainException. I can only speculate as to why, but I have seen major improvements in complex scripts if I iterate the whole collection, versus implementing a collection memeber lifecycle validate event. This is counter-intuitive, but there it is.
Finally, exceptions raised in Collection Lifecycle Events that interupt the overall save process in the prescence of parent document Lifecycle Validation events can result in partially saved data. I observed this issue a few years back and it may be resolved now. The only member lifecycle event I use is Created, to lock, default, etc.
So, for your particular problem, you may want to rethink your strategy and see if you can get things to work for you bypassing that reflection issue. If you still can't raise the exception on MATERIAL, maybe you can raise it on another field, because another advantage of this approach is that you have full control to raise any error on any field on the Line Items. -
I am trying to watch an on-line video class and "missing plug-in" is displayed. Help!
I am trying to watch an on-line video class and "missing plug-in" is displayed. Help!
More information. What web site? Provide a link.
-
No association lines in class diagram
In my class diagram, there are no association lines connecting the classes.
I notice that in the BankApplication tutorial, the class diagram has full lines and dashed lines. The structure in the "Model" folder is different from mine. Will this have any effect?
Model
bankpac
BankAccount
Checking
etcMy structure is:
Model
org
CompanyName
sample
Class1
Class2
Class3
etc"Class1" contains "main"
I selected everything under "Model".sherylsu wrote:
If they are listed under project tree but not shown on diagram, then it could be something wrong with diagram presentation logic The relationships shown in the model tree are the same as shown in the class diagram. That is consistent.
I think the issue is due to way my non-techie mind works.
Here is how I produce diagrams. Most of the projects are samples for a manual, so only contain one class.
1) I select the (only) class for a project, and create the dependency diagram.
2) From the dependency diagram, I reverse engineer every operation for that class in sequence diagrams.
Obviously, the master class sends messages to many other instances of many other slave classes. I assumed that the class diagram for the master would show the aggregation of all the slave classes that appear on all the sequence diagrams. Even if the internal structure of the slave classes (attributes, operations) would not be known, at least the class names would be known.
Even after reading "UML Distilled" and reading the Agile web pages, I still think that would be the case.
It seems that Studio only displays a slave class on the class diagram if the internal structure of the slave is known. Maybe that's the correct convention. -
Line number in a *.class file, please help, advanced language guys
dear all,
i use c++ to open a *.class file and try to read line number of code in the file, i have 2 questions:
1. i read line number in a method successfully, but i can not understand the meaning of start_pc, following are one of those data, please explain:
s = start_pc,n = line_number
s , n
0 , 123
8 , 125
23 , 126
29 , 127
34 , 129
38 , 130
2. i can not find where the class's line number are, i.e. class start line and class end line, or field's line number.
does these info exist inside a *.class file?
thx for any lightjdb gets line number of fields from class file, not
source file definitely.I'm not really sure how you tested this, but here's my test, and JDB definitely gets its listing from the source file.
First, I created and compiled class Tester:
public class Tester
public static void main( String[] argv )
throws Exception
Tester x = new Tester();
System.out.println(x.toString());
int x;
int y;
private Tester()
x = 0;
y = 1;
}Then, I ran this in JDB. Note lines 16 and 17 in the output from "list":
H:\Workspace>jdb Tester
Initializing jdb ...
stop in Tester.mainDeferring breakpoint Tester.main.
It will be set after the class is loaded.
runrun Tester
Set uncaught java.lang.Throwable
Set deferred uncaught java.lang.Throwable
>
VM Started: Set deferred breakpoint Tester.main
Breakpoint hit: "thread=main", Tester.main(), line=12 bci=0
12 Tester x = new Tester();
main[1] list
8 {
9 public static void main( String[] argv )
10 throws Exception
11 {
12 => Tester x = new Tester();
13 System.out.println(x.toString());
14 }
15
16 int x;
17 int y;
main[1] quit
Tester@b82368Then I edited the source file. Again, look at lines 16 and 17:
H:\Workspace>jdb Tester
Initializing jdb ...
stop in Tester.mainDeferring breakpoint Tester.main.
It will be set after the class is loaded.
runrun Tester
Set uncaught java.lang.Throwable
Set deferred uncaught java.lang.Throwable
>
VM Started: Set deferred breakpoint Tester.main
Breakpoint hit: "thread=main", Tester.main(), line=12 bci=0
12 Tester x = new Tester();
main[1] list
8 {
9 public static void main( String[] argv )
10 throws Exception
11 {
12 => Tester x = new Tester();
13 System.out.println(x.toString());
14 }
15
16 int a;
17 int b;
main[1] -
Is it too much lines of code inside a class file?
Hi,
I was wondering about how many lines can be considered too much in a java class file. I saw some class files with more the two thousand lines of code and even more than three thousand lines. When we have so many lines in the code I've realized that the file becomes slow for edition and it's not readable as it should be. So, as a best practice, or even due to technical issues, in average how many lines of code we'd write in order to keep the readability and avoid compile and build issues? How many lines a class should have without putting our code and performance at risk ?
thanks a lotMy general rule of thumb--in a class everything shold be very consistent, that is to say: you should be focusing on 1 idea in your class. IMO: If you have a class for users, you need to consistent in just what that class does. When the class becomes large, then look for related themes that run through methods of that class, and if here are many, you should make a "related class" that does satelite functions of the "core" offered in the main user class.
Thousands of lines do not a good class make, I break in to related categories of classes long before then, and as a rule I keep under 500 lines in a class--usually under 300. In any case, no more lines of code need go into a class than that to implement the core features in the main idea for that class--and no less lines of code than is needed too, don't religate a method to another class just becasue you feel it would make the class it belongs too big.
Along the idea of the user class:
Storage for the user data
Home information
Work information
physical information
tastes and preferences
family
and etc
all of these could be a class in and of themselves, but definetely are closely related to the user class. -
How to draw only straight line instead of angled one??
Dear friends,
I saw a very good code posted by guru here(I think is camickr),
But I tried to change it and I hope to draw only straight line instead of angled one, can you help how to do it??
Thanks so much.
import java.util.*;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.event.*;
public class DrawingArea extends JPanel
Vector angledLines;
Point startPoint = null;
Point endPoint = null;
Graphics g;
public DrawingArea()
angledLines = new Vector();
setPreferredSize(new Dimension(500,500));
MyMouseListener ml = new MyMouseListener();
addMouseListener(ml);
addMouseMotionListener(ml);
setBackground(Color.white);
public void paintComponent(Graphics g)
// automatically called when repaint
super.paintComponent(g);
g.setColor(Color.black);
AngledLine line;
if (startPoint != null && endPoint != null)
// draw the current dragged line
g.drawLine(startPoint.x, startPoint.y, endPoint.x,endPoint.y);
for (Enumeration e = angledLines.elements(); e.hasMoreElements();)
// draw all the angled lines
line = (AngledLine)e.nextElement();
g.drawPolyline(line.xPoints, line.yPoints, line.n);
class MyMouseListener extends MouseInputAdapter
public void mousePressed(MouseEvent e)
if (SwingUtilities.isLeftMouseButton(e))
startPoint = e.getPoint();
public void mouseReleased(MouseEvent e)
if (SwingUtilities.isLeftMouseButton(e))
if (startPoint != null)
AngledLine line = new AngledLine(startPoint, e.getPoint(), true);
angledLines.add(line);
startPoint = null;
repaint();
public void mouseDragged(MouseEvent e)
if (SwingUtilities.isLeftMouseButton(e))
if (startPoint != null)
endPoint = e.getPoint();
repaint();
public void mouseClicked( MouseEvent e )
if (g == null)
g = getGraphics();
g.drawRect(10,10,20,20);
class AngledLine
// inner class for angled lines
public int[] xPoints, yPoints;
public int n = 3;
public AngledLine(Point startPoint, Point endPoint, boolean left)
xPoints = new int[n];
yPoints = new int[n];
xPoints[0] = startPoint.x;
xPoints[2] = endPoint.x;
yPoints[0] = startPoint.y;
yPoints[2] = endPoint.y;
if (left)
xPoints[1] = startPoint.x;
yPoints[1] = endPoint.y;
else
xPoints[1] = endPoint.x;
yPoints[1] = startPoint.y;
public static void main(String[] args)
JFrame frame = new JFrame("Test angled lines");
frame.setDefaultCloseOperation( JFrame.EXIT_ON_CLOSE );
DrawingArea d = new DrawingArea();
frame.getContentPane().add( d );
frame.pack();
frame.setVisible(true);
}Change the AngledLine class to store two points instead of 3 points (I would rename the class to be StraightLine). The code is much simpler because you just store the starting and ending points and you don't need to calculate the middle point.
-
a number of site say done and we see a blank page. on-line calculus class, last week could view more than 1 video at a time now only 1 can be viewed. this course need to be completed by may 3. career builders some of the drop downs aren't working. need to find a job. these are serious errors that we did not experience before. we haven't updated to 4.0. now i see the one's who have are having these problems. daughter can't gt to e-mail. wish i could talk to someone. i'm going to try the live session at 2 but i'm not a techy. can take care of most problems, but this seems beyond me. HELP
sIf you are wondering why you are not getting any responses, it is because you have vented a complaint without any details that make any sense or give anyone something to work on.
If you want help, I suggest actually detailing what has happened, with versions of software etc. Anything that would let us assist.
As a start I am guessing that you have not really got the hang of "How it all works". Firstly download the Pages09_UserGuide.pdf from under the Help menu. Read that and view the Video Tutorials in the same place. A good addition would be the iWork 09 Missing manual book and something to help you learn how to use your Mac.
If there are specific tasks you need help with:
http://www.freeforum101.com/iworktipsntrick/index.php?mforum=iworktipsntrick
Is a good resource.
Peter -
<Data>
<Brand BName='ICICI Bank' MainId='276439c0a2e886311a426147'>
<Name Main='(author unknown)' Count='305' />
<Name Main='intellibitz' Count='30' />
<Name Main='bankcodes' Count='25' />
<Name Main='info2india' Count='24' />
<Name Main='amitkarnani' Count='9' />
</Brand>
<Brand BName='Yes Bank' MainId='276439cd8a4514807d7180d0'>
<Name Main='(author unknown)' Count='32' />
<Name Main='STOCKSTIPS' Count='5' />
<Name Main='stockezymobile' Count='4' />
<Name Main='Intraday Ideas' Count='4' />
<Name Main='Infopiper' Count='3' />
</Brand>
</Data>
This is my xml data.It can bo vary as per data changes.but i need to draw linechart by using actionscript.In this case draw two line .But if Brand will increases
the a line is automatically increase.
PLease help me for making a line chart.....
please reply anybodyYou should learn
- how to load an XML file (URLLoader class)
- read XML data (XML class)
- draw lines (graphics class) -
Extending Line Items collection in Master Agreements
Hi All
I wanted to add a custom field to Line Items Collection - but I guess it is not possible to add a custom field to a standard collection, next what I tried is to add an extension field to the Line Item Class(1007). But I could not find the Line Item class listed in the dropdown field "Extended Class Name" while creating an extension definition.
Please tell me if it is possible at all to add a custom field for this collection - either to the collection itself or on the Line Items page (page id - contracts.lineitem.ui.buyside.default)
Thanks!Hi
Plz check the following thread.
Need to add new field in Rfx Line Item Page
Regards
Mudit Saini -
Calling Custom XSLT java class from BPEL in SOA Suite 11g
Hi All,
Morning...need some help with this issue...we are currently on SOA Suite 11g (11.1.1.4) version.
Earlier while we were on SOA Suite version 10g (10.1.3.3) we were calling the custom java classes from the xsl mapping for complex transformation and for this we were placing the .class file as .jar file at the location mentioned here $OC4J_HOME/j2ee/home/applib directory and then mentioning the namespace as http://www.oracle.com/XSL/Transform/java/{$classname$} in the XSLT mapping file.
Now in SOA Suite 11g if we need to retain similar functionality for external custom java calls could someone please help us where do we need to put the .jar file now ..
exactly at which directory location/path and on which instance/server (application server instance or middle tier instance ) we need to put this .jar file
Currently we are stuck and need some help with this.
With thanks & RegardsHi Eric & Anuj,
Thanks for replying , sorry for checking on this now...
here at this path /opt101/app/oracle/SOAD/SOA11gR1/fmw/Oracle_SOA1/soa/modules/oracle.soa.ext_11.1.1
we got the ora.soa.ext.jar file and extracted it to get the MANIFEST.mf file ..have mentioned below.
Now if we need to link our custom .jar file named customfunctions.jar so we need to mention it as below is this correct :
Manifest-Version: 1.0
Ant-Version: Apache Ant 1.7.1
Created-By: 17.0-b17 (Sun Microsystems Inc.)
Implementation-Vendor: Oracle
Implementation-Title: Oracle SOA EXT
Implementation-Version: 11.1.1
Product-Name: Oracle SOA EXT
Product-Version: 11.1.1.4.0
Specification-Version: 11.1.1
Extension-Name: oracle.soa.ext
Class-Path: classes/
Class-Path:customfunctions.jar classes/ -- is this the way to mention (means we need to add this additional line or we need to add to the existing line at Class-Path: classes/)
2.
Eric the Alternative method mentioned in your update :
Open a command prompt and change the current directory to the oracle.soa.ext_11.1.1 directory ,
then execute the build.xml file in the oracle.soa.ext_11.1.1 folder using Ant
Now could someone please guide us regards this ANT means how does it work and its relation to the build.xml file and how do we check whether we have ANT utility available or not..
not much conversant with this ANT hence asking here..would lookout for your reply
thank you -
I'm trying to implement a line reader class, but my code does not seem to compile, giving the error that there is no return statement. here's my code.
import java.io.*;
import java.util.*;
public class InputLineReader
public static String lineRead (BufferedReader buff)
try {
return buff.readLine();
catch (IOException e)
System.out.println("IO Error");
}You have to return after try..catch statement.
import java.io.*;
import java.util.*;
public class InputLineReader {
public static String lineRead (BufferedReader buff) {
String line = null;
try {
line = buff.readLine();
} catch (IOException e) {
System.out.println("IO Error");
return line;
}Regards, -
"Could ntot find the main class : PdfToImage"
I am trying to produce a jar that I can execute from the command line. Currently it executes fine if I hit F6 to run the code in the Netbeans IDE.
I read this article:
http://java.sun.com/developer/Books/javaprogramming/JAR/basics/run.html
but still can't get it to run from the command line. The error I get when clicking on the jar file is:
"Could not find the main class PdfToImage"
The source code is this:
package converttoimage2;
...import statements here
public class PdfToImage{
public static void main(String[] args) {
To build a jar file I navigated to the NetbeansProjects folder and typed the following (is this wrong?)
jar cfm PdfToImage.jar ConvertToImage2\manifest.mf ConvertToImage2
No error messages occured here. The manifest file originally was this (BTW I don't understand what that X-comment is trying to say)
Manifest-Version: 1.0
X-COMMENT: Main-Class will be added automatically by build
so I added this line:
Main-Class: PdfToImage
and yes, I pressed Enter at the end of this line. This is the manifest that generates the error. I get the same error this way:
Main-Class: converttoimage2.PdfToImage
The code I'm using from the Windows command line to execute the jar (after I copy the jar file to the c-drive) is this:
java -jar C:\PdfToImage.jar
This errors out with
Could not find the main class: PdfToImage
I've also tried this;
java C:\PdfToImage.jar
The next thing i tried was to navigate to the class folder containing the PdfToImage.class. I copied the manifest into this class folder as well.From there I typed:
jar cfm PdfToImage.jar manifest.mf PdfToImage
This produced a jar file with no error messages, but I get the original error messsage when I try to execute. Also I doubt this last jar file is complete since it is only 2KB in size (My code references a library called PdfRenderer which is a 2MB jar).
I'm completely lost here.I am trying to produce a jar that I can execute from the command line. Currently it executes fine if I hit F6 to run the code in the Netbeans IDE.You can make a jar from NetBeans, "Build > Build Main Project" (Shortcut - F11). Or right click the project in the project window and select "Build".
I read this article:
http://java.sun.com/developer/Books/javaprogramming/JAR/basics/run.html
OK, if you want to create a jar without Netbeans, then following link would help you a lot:
[http://java.sun.com/docs/books/tutorial/deployment/jar/index.html]
Thanks! -
"Could not find the main class" when running a jar
Hi, I'm trying to create and run a jar from my application, but I can't figure out how to properly set an entry-point. Looking at the Java Tutorials http://java.sun.com/docs/books/tutorial/deployment/jar/index.html I still can't get it to work.
I have a directory myApp, which contains a directory images and some class files, including mainClass.class. I also have a manifest Manifest.txt in the directory myApp with the following line:
Main-Class: mainClass.class
+ one empty line
I create a jar successfully, while inside the myApp directory, with the following command:
jar cfm myApp.jar Manifest.txt *.class images\*.*
I then proceed to run the jar with the following command:
java -jar myApp.jar
and receive the following error:
Exception in thread "main" java.lang.NoClassDefFoundError: myApp/class
My completely uneducated guess is that there is something wrong with my manifest. The tutorial says that the line should be:
Main-Class: MyPackage.MyClass
I'm assuming that I get the error because I didn't specify a package, which I didn't do because I didn't know what to put there. Do I even have a package?
Can anyone tell me what I've done wrong? thanks.
Message was edited by:
SmurfZGOne problem is you are specifying a file name instead of a class name. It probably should beMain-Class: mainClassA good test is to run your app before jaring it - if you run it with "java mainClass" then the Main-Class attribute must be mainClass.
Also class naming conventions say that class names should start with a capital letter - MainClass for example. It is just a convention, but it is easier to get help when you follow conventions. -
JAR "could not find the main class"
I'm running applications under XP.
In my profile:
I have a lot of problems double clicking on a jar file.... it always gives me this error: "could not find the main class"...
In other XP profiles:
All jar files run properly!
Help me!Is your manifest correct? Does it contain the line
Main-Class: Application
or
Main-Class: package/Application
in the main section of the manifest (case sensitive)? Can the interpreter find all the required class files?
Stephen
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