One client and two servers

Question

hi,
how a client can communicate to two servers by socket connection (parallel) ?
here is my code, when i run one server at a time it works but if i run both server programs and then the client i dont get any exception and it does not get my data from servers it generates "press any key to continue..."
server 1 --------------
public static void main(String[] args)
ServerOne so = new ServerOne(7500);
so.accept();
public void accept(){
try{
System.out.println("Server");
Socket s;
while(true)
s = sock.accept();
}catch()...
server 2 -----
exact like server 1
klient---------------------------
public static void main(String[] args)
try{
System.out.println("Client");
MyThread MT = new MyThread();
MT.startThread();
Socket s = new Socket("127.0.0.1",7500);
InputStream is = s.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(is));
while(in.ready())
String str = in.readLine();
System.out.println(str);
s.close();
}catch(IOException e){e.printStackTrace();}
mythread --------------------
public void run()
? try
Socket s = new Socket("127.0.0.1",1234);
InputStream is = s.getInputStream();
BufferedReader in= new BufferedReader(new InputStreamReader(is));
while(in.ready())
String str = in.readLine();
System.out.println(str);
s.close();
catch(Exception e){System.out.println(e.toString());}
Message was edited by:
cyrus

Answer 1

You cannot run two servers on exactly the same socket. Are you aware of this?
At least the port number has to be different.
// Server 1:
try {
    serverSocket = new ServerSocket(4444);
} catch (IOException e) {
    System.out.println("Could not listen on port: 4444");
    System.exit(-1);
Socket clientSocket = null;
try {
    clientSocket = serverSocket.accept();
} catch (IOException e) {
    System.out.println("Accept failed: 4444");
    System.exit(-1);
// now the connection is established
// do the same for the other server, but for another port
// The client has to explicitly call each Server, to establish each connection.