Open a popup window by clicking the icon on the datagrid

Question

I am using PopUpManager class to displayed the popup. While clicking the datagrid popup will display.
Now i have a change in requirement that i need to open popup window when the user clicks the icon on the datagrid itemrenderer. Expecting valuable response to complete the requirement.

Answer 1

Hi David,
Thanks for the prompt response.
In our application, while clicking the datagrid column, we have calculate
some values based on the datagrid and show the results in the another
datagrid placed below. Also if the user wants some info about the customer
we have some it in a popup by
private function custPopUp(event:ListEvent):void {
if(event.columnIndex==3){
     hiddenActionpopup = "OpenPopUp";     
     requestPopUp.send();                    
}else
          // when the user clicks the column other than columnIndex 3,
we      //have show the calculate results in another datagrid.
Now what we r going to do is, instead of protecting a column, we have an
icon for customer details, other than that If an user clicks anywhere it
will show the calculation.
For that, I need to set action for the icon in the itemrenderer.
Thanks in Advance.
Jude Paul
hi
If you want have an action dependendant on a cell in the grid you can use
itemclick rather than doing the operation from renderer.
protected function dataGrid_itemClickHandler(event:ListEvent):void
   if (dg.columns[event.columnIndex].dataField =="whatever the datafieldname
is") doPopup();
<mx:DataGrid x=0" y="0" width="100%" height="100%" id="dg"
itemClick="dataGrid_itemClickHandler(event)"/>
David.