Open an xml file from a URL

i am trying to open an xml file from a URL.
i have been using the standard (i think!) xml suite, part of the System Events. is this possible? is this the best way? are there alternatives? any good tutorials of how to use it too?
the file i am trying to open is: http://www.tvrage.com/feeds/episode_list.php?sid=xxxx
where "xxxx" is a number of a show, e.g. 2930 is buffy
regards
jingo_man

It works!!
I used the URL and BufferedReader classes to fill the parser. Here's how:
// create a new object of type URL
URL xmlURL = new URL( "http://ServerName/DbName/PageName?OpenPage&username=myname&password=mypassword");
// Create the SAX2 parser
SAXParser saxParser = spf.newSAXParser();
xr = saxParser.getXMLReader();
// Set the ContentHandler
DefHandlerClass myHandler = new DefHandlerClass();
xr.setContentHandler( myHandler );
// read the URL stream into the BufferedReader
BufferedReader in = new BufferedReader( new InputStreamReader(xmlURL.openStream()));
// parse the document
xr.parse( new InputSource( in ) );
// close the input stream
in.close();
PjR

Similar Messages

Can Document Builder parse an XML file from a URL?

Warning: Java newbie here...
My problem is that I am able to parse an XML file if it is copied into my project, but not if it is a full URL. Here is what I got so far, that works.
import java.io.*;
import java.net.*;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
try {
    File file = new File("path/to/file.xml");
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db = dbf.newDocumentBuilder();
    Document doc = db.parse(file);
    doc.getDocumentElement().normalize();
    NodeList nodeLst = doc.getElementsByTagName("Names");
    for (int s = 0; s < nodeLst.getLength(); s++) {
        Node parentNode = nodeLst.item(s);
        if (parentNode.getNodeType() == Node.ELEMENT_NODE) {
            Element parentElmnt = (Element) parentNode;
            NodeList nameElmntLst = parentElmnt.getElementsByTagName("Name");
            //etc.
} catch (Exception e){
    e.printStackTrace();
}So building off of this I have tried to parse an input stream like this:
URL url = new URL("http://example.com/file.xml");
InputStream is = url.getInputStream();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(is);which gives me the following error
[Fatal Error] :-1:-1: Premature end of file.
LOG: HME receiver connected
org.xml.sax.SAXParseException: Premature end of file.
I also even tried to write the file locally like this:
URL url = new URL("http://example.com/file.xml");
HttpURLConnection urlcon = (HttpURLConnection) url.openConnection();
urlcon.connect();
InputStream is = urlcon.getInputStream();
File file = new File("path/to/file.xml");
OutputStream out = new FileOutputStream(file);
byte buf[] = new byte[1024];
int len;
while((len=is.read(buf))>0)
    out.write(buf,0,len);
out.close();
is.close();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(file);This gives the same error.
If anyone can point me in the right direction I would forever thankful. I've tried search Google and the Sun forums, but haven't quite found the solution. I think it is because I need to try something else completely. Thank you for reading.
~~~~ Jeremy

jmose wrote:
If I copy the page, it works as shown in the first code block. In the third codeblock the file is never even created, so I cannot tell if that works or not.So: having the parser access the URL fails, and having some other Java code access the URL also fails in the identical way? That suggests the problem is simply accessing the URL via Java code. Presumably when you downloaded the data from the URL, you used a browser to do it and not wget or something like that?

Need HELP! Opening a PDF file from different URL

I have a application that links to viewpdf.class. This class file will go to the FTP where the pdf file is located and open it. How do i do this using java? Here is what I have.. .i'm stuck
URL url = new URL("ftp://user01:[email protected]/"+ folder_name +"README.pdf;type=i");
URLConnection urlc = url.openConnection();
InputStream is = urlc.getInputStream();thanks Tony
here is how it looks like if it is on the local host.
import java.io.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class viewpdf extends HttpServlet
    private ResourceBundle rb;
    public viewpdf()
        rb = ResourceBundle.getBundle("LocalStrings");
    public static void streamCopy(FileInputStream fileInputStream, ServletOutputStream servletOutputStream)
        throws IOException
        if(fileInputStream == null || servletOutputStream == null)
            return;
        byte abyte0[] = new byte[8192];
        int i;
        synchronized(fileInputStream)
            synchronized(servletOutputStream)
                while((i = fileInputStream.read(abyte0)) != -1)
                    servletOutputStream.write(abyte0, 0, i);
    public void doGet(HttpServletRequest req, HttpServletResponse res)
        throws ServletException, IOException
        ServletOutputStream servletOutputStream;
        String filename;
        String output;
        FileInputStream fileInputStream;
        servletOutputStream = res.getOutputStream();
        res.setContentType("application/pdf");
        ServletContext servletcontext = getServletContext();
        filename = req.getParameter("file");
        String folder_code = req.getParameter("fold");
        try{
            filename = servletcontext.getRealPath(rb.getString("file_location")) + "/" + fold + "/" + file;
        fileInputStream = null;
        fileInputStream = new FileInputStream(file);
        streamCopy(fileInputStream, servletOutputStream);
        catch(FileNotFoundException e)
        filename = servletcontext.getRealPath(rb.getString("file_location")) + "/filenotfound.pdf";
        fileInputStream = null;
        fileInputStream = new FileInputStream(file);
        streamCopy(fileInputStream, servletOutputStream);
}

That servlet already is Java. And the servlet code isn't what "opens" the PDF, it's the browser that sends the request that does that. I'm assuming that when you say "open it" you mean to start up an instance of Adobe Acrobat and ask it to display the document.

Problems opening a pdf file from a URL protected by OAM with M.Explorer

Hello,
we have protected a web portal with OAM. When we access a URL which is a pdf file with Mozilla Firefox, the file is retrieved and opened correctly, but when we try to open it using Microsoft Explorer it won't open. If we disable OAM the pdf is opened without problems. We set Microsoft Explorer security level to the lowest possible value but the problem persists.
Can anyone give us a hand to solve this issue?
Thank you

Hi Francisco,
In the AccessGate screen for the WebGate, if you have the CachePragmaHeader and CacheControlHeader set to "no-cache", try setting them to "public" (or blank), restart the web server, and see if that resolves the issue.
Regards,
Colin

Loading XML files from URL

Hi.
My PL/SQL procedure loading xml files from oracle logical directory ("c:\temp") and inserting values into columns of the table. I use XSU with procedure:
create or replace procedure insProc(xmlDoc IN CLOB, tableName IN VARCHAR2) is
insCtx DBMS_XMLSave.ctxType;
rows number;
begin
insCtx := DBMS_XMLSave.newContext(tableName); -- get the context handle
rows := DBMS_XMLSave.insertXML(insCtx,xmlDoc); -- this inserts the document
DBMS_XMLSave.closeContext(insCtx); -- this closes the handle
end;
For translate xml document to CLOB, I use :
CREATE OR REPLACE function getdocument(
p_directory in varchar2,
p_filename in varchar2)
return clob
is
l_bfile bfile;
l_clob clob;
begin
l_bfile := bfilename(p_directory, p_filename);
dbms_lob.open(l_bfile);
dbms_lob.createtemporary(l_clob, true, dbms_lob.session);
dbms_lob.loadfromfile(l_clob, l_bfile, dbms_lob.getlength(l_bfile));
dbms_lob.close(l_bfile);
return l_clob;
end getdocument;
I didn't have problem with this procedures. But now i want load my xml files from another computer (i want use URL, not oracle logical directory).
How can i do it, using standart PL/SQL methods?

Since you are parsing the XML what prevents you from delaying your requests for the image URL's? You can just as well add the image URL's to some kind of collection and load them after you have processed all the text content.

How to retrieve elements from 3 different xml file in one url

Hi all,
Could anyone please let me how can we retrieve elements from 3 different xml file in one url?
i just can only do it with one file only, any help would very appreciate.
Thank in advance
Jim

Hi Philip
Thanks for replying me.
I tried on that way, In my mdx query i am using one slice attribute (i.e [Customer].[Gender].allmembers) in rows so getting error "The Hierarchy already appears in Axis1".
SELECT
{[Measures].[Internet Sales Amount] } ON 0,
NON EMPTY
{[Customer].[Gender].allmembers } ON 1 -- Used
FROM
[Adventure Works]
WHERE
[Customer].[Gender].&[M]
,[Product].[Size Range].[(All)]
,[Customer].[Country].[All Customers]
[Customer].[Gender].[All Customers]
,[Product].[Size Range].&[XL]
,[Customer].[Country].[All Customers]
[Customer].[Gender].[All Customers]
,[Product].[Size Range].[(All)]
,[Customer].[Country].&[Australia]
Can you provide alternate ways to get resolved.
Thanks in advance

How to open a XML file in internet explorer from labview

I need to open the xml file and see the content in the internet explorer through labview. clicking the button in labview front panel i need to see the same view as we double click the xml file as it open in internet explorer .

Hi parthipan,
you can use the "Open URL in Default Browser.vi".
Mike

Uploading an XML file from SAP into third party URL

Hi,
I need to Upload an XML file from sap into Third party URL. Can any body tell me the possible ways in SAP to achieve this task. Also explain me the proceedure.
Thanks in advance.
-Namdev

Sorry. If they only said HTTP/HTTPS and didn't say explicitly web service, it means they don't want it.
One thing I'm not sure is, do you have an URL at the third-party system that you need to contact, or should you provide one at your SAP system that they will contact?
If it is the first one, to send an HTTP request to a given URL using ABAP, you'll find an example here: [SAP Library: Example Program: Executing an HTTP Request|http://help.sap.com/saphelp_nw70/helpdata/en/1f/93163f9959a808e10000000a114084/frameset.htm]
Sandra

[b]Urgent How to send XML file from forms 6.0 to a url to access database[/

hi
i need to create an XML with some values file from Oracle Forms 6.0 and then send this XML file To a URL to access the database,which in turn will send me XML file with new values.Can any body help me out as i don't have any ideas
Regards
Sunil

Sunil,
and this must be using a URL and can't be handled by a database stored procedure ?
Anyway, your scenario can be achieved using teh Java Importer in Forms 6i and above. You woudl write a Java program that takes a String and loads it to an URL. It then checks the response URL for its content.
Frank

Send xml file from sap to third party url through https

Hi,
I have a requirement to send the xml file from ecc to a 3rd party url through HTTPS. How can we achieve this using ABAP.
Client doesn't have XI enviroment. The client has provided the 3rd party url where the file needs to be uploaded.
Please help ! <removed by moderator>
Thanks in advance.
Regards,
Chitra.K
Edited by: Thomas Zloch on Sep 12, 2011 12:58 PM

Hi Chitra,
I had similar requirement and here is what I did: -
REPORT Z_HTTP_POST_TEST_AMEY.
DATA: L_URL               TYPE                   STRING          ,
      L_PARAMS_STRING     TYPE                   STRING          ,
      L_HTTP_CLIENT       TYPE REF TO            IF_HTTP_CLIENT ,
      L_RESULT            TYPE                   STRING          ,
      L_STATUS_TEXT       TYPE                   STRING          ,
      L_HTTP_STATUS_CODE TYPE                   I               ,
      L_HTTP_LENGTH       TYPE                   I               ,
      L_PARAMS_XSTRING    TYPE                   XSTRING         ,
      L_XSTRING           TYPE                   XSTRING         ,
      L_IS_XML_TABLE      TYPE STANDARD TABLE OF SMUM_XMLTB      ,
      L_IS_RETURN         TYPE STANDARD TABLE OF BAPIRET2        ,
      L_OUT_TAB           TYPE STANDARD TABLE OF TBL1024
MOVE 'https://<hostname>/xxx/yyy/zzz' TO L_URL.
MOVE '<XML as string>' TO L_PARAMS_STRING.
*STEP-1 : CREATE HTTP CLIENT
CALL METHOD CL_HTTP_CLIENT=>CREATE_BY_URL
    EXPORTING
      URL                = L_URL
    IMPORTING
      CLIENT             = L_HTTP_CLIENT
    EXCEPTIONS
      ARGUMENT_NOT_FOUND = 1
      PLUGIN_NOT_ACTIVE = 2
      INTERNAL_ERROR     = 3
      OTHERS             = 4 .
"STEP-2 : AUTHENTICATE HTTP CLIENT
CALL METHOD L_HTTP_CLIENT->AUTHENTICATE
EXPORTING
    USERNAME             = 'testUser'
    PASSWORD             = 'testPassword'.
"STEP-3 : SET HTTP HEADERS
CALL METHOD L_HTTP_CLIENT->REQUEST->SET_HEADER_FIELD
      EXPORTING NAME = 'Accept'
                VALUE = 'text/xml'.
CALL METHOD L_HTTP_CLIENT->REQUEST->SET_HEADER_FIELD
    EXPORTING NAME = '~request_method'
               VALUE = 'POST' .
CALL METHOD L_HTTP_CLIENT->REQUEST->SET_CONTENT_TYPE
    EXPORTING CONTENT_TYPE = 'text/xml' .
"SETTING REQUEST DATA FOR 'POST' METHOD
IF L_PARAMS_STRING IS NOT INITIAL.
   CALL FUNCTION 'SCMS_STRING_TO_XSTRING'
     EXPORTING
         TEXT   = L_PARAMS_STRING
     IMPORTING
           BUFFER = L_PARAMS_XSTRING
     EXCEPTIONS
        FAILED = 1
        OTHERS = 2.
CALL METHOD L_HTTP_CLIENT->REQUEST->SET_DATA
    EXPORTING DATA = L_PARAMS_XSTRING .
ENDIF.
"STEP-4 : SEND HTTP REQUEST
CALL METHOD L_HTTP_CLIENT->SEND
    EXCEPTIONS
      HTTP_COMMUNICATION_FAILURE = 1
      HTTP_INVALID_STATE         = 2.
"STEP-5 : GET HTTP RESPONSE
    CALL METHOD L_HTTP_CLIENT->RECEIVE
      EXCEPTIONS
        HTTP_COMMUNICATION_FAILURE = 1
        HTTP_INVALID_STATE         = 2
        HTTP_PROCESSING_FAILED     = 3.
"STEP-6 : Read HTTP RETURN CODE
CALL METHOD L_HTTP_CLIENT->RESPONSE->GET_STATUS
    IMPORTING
      CODE = L_HTTP_STATUS_CODE
      REASON = L_STATUS_TEXT .
WRITE: / 'HTTP_STATUS_CODE = ',
          L_HTTP_STATUS_CODE,
         / 'STATUS_TEXT = ',
         L_STATUS_TEXT .
"STEP-7 : READ RESPONSE DATA
CALL METHOD L_HTTP_CLIENT->RESPONSE->GET_CDATA
        RECEIVING DATA = L_RESULT .
"STEP-8 : CLOSE CONNECTION
CALL METHOD L_HTTP_CLIENT->CLOSE
EXCEPTIONS
    HTTP_INVALID_STATE = 1
    OTHERS             = 2   .
"STEP-9 : PRINT OUTPUT TO FILE
CLEAR : L_XSTRING, L_OUT_TAB[].
CALL FUNCTION 'SCMS_STRING_TO_XSTRING'
    EXPORTING
      TEXT   = L_RESULT
    IMPORTING
      BUFFER = L_XSTRING
    EXCEPTIONS
      FAILED = 1
      OTHERS = 2.
CALL FUNCTION 'SCMS_XSTRING_TO_BINARY'
EXPORTING
    BUFFER                = L_XSTRING
TABLES
    BINARY_TAB            = L_OUT_TAB .
CALL FUNCTION 'GUI_DOWNLOAD'
EXPORTING
   FILENAME                        = 'C:AMEYHTTP_POST_OUTPUT.xml'
TABLES
    DATA_TAB                        = L_OUT_TAB .
Also, following is the detailed link for use of HTTP_CLIENT class: -
http://help.sap.com/saphelp_nw70ehp1/helpdata/EN/1f/93163f9959a808e10000000a114084/content.htm
Also, in below link, you can ignore XI specific part and observe how its sending XML to external URL:-
(I know it describes call to SAP XI server's URL, but it can be used to call any URL)
http://www.sdn.sap.com/irj/scn/index?rid=/library/uuid/ae388f45-0901-0010-0f99-a76d785e3ccc
In addition to all above, following configs to be present at ABAP application server: -
1. The hostname used to URL should be present in SAP ABAP application server's 'hosts' file.
2. Security certificate (if available) for URL to be called must be installed in SAP ABAP application server.
Let me know if you achieve any progress with it...

How to create xml file from Oracle and sending the same xml file to an url

How to create xml file from Oracle and sending the same xml file to an url

SQL/XML (XMLElement, XMLForest, XMLAgg, etc) and UTL_HTTP.
Whether that works for you with the version of Oracle you have, your requirements, and needs is another story. A little detail goes a long way.

Error while opening the XML file

Hi all,
i'am trying to download data from internal table to XML file with root node and its
corresponding child nodes.i have written the program in this way.
tables: mara.
include bcciixml_decl.
include bcciixml_impl.
parameters: p_matnr like mara-matnr.
start-of-selection.
data: piXML          type ref to if_ixml,
        pDocument      type ref to if_ixml_document,
        pStreamFactory type ref to if_ixml_stream_factory,
        pIStream       type ref to if_ixml_istream,
        pParser        type ref to if_ixml_parser,
        pNode          type ref to if_ixml_node,
        pText          type ref to if_ixml_text,
        string         type string,
        count          type i,
        index          type i,
        totalSize      type i,
        dsn(40)        type C,
        xstr           type xstring.
types: begin of it_mara,
            matnr like mara-matnr,
            ernam like mara-ernam,
            aenam like mara-aenam,
            vpsta like mara-vpsta,
        end of it_mara.
data: itab_mara type table of it_mara.
select matnr ernam aenam vpsta from mara into table itab_mara where
       matnr = p_matnr.
types: begin of xml_line,
        data(256) type X,
      end of xml_line.
data: xml_table type table of xml_line.
parameters: filename like rlgrap-filename.
pixml = cl_ixml=>create( ).
*-- create the initial document
pDocument = pixml->create_document( ).
pStreamFactory = pixml->create_stream_factory( ).
*-- create an input stream for the table
*pIStream = pStreamFactory->create_istream_itable( table = xml_table
                                                 size = totalSize ).
pParser = piXML->create_parser( stream_factory = pStreamFactory
                                  istream        = pIStream
                                  document       = pDocument ).
data: pOStream type ref to if_ixml_ostream.
pOStream = pStreamFactory->create_ostream_itable( table = xml_table ).
call method pDocument->render( ostream   = pOStream ).
*-- how many bytes were written to the table?
totalSize = pOStream->get_num_written_raw( ).
*-- write the XML document back to the frontend
concatenate filename '.out' into filename.
condense filename no-gaps.
CALL FUNCTION 'WS_DOWNLOAD'
     EXPORTING
          BIN_FILESIZE            = totalSize
          FILENAME                = filename
          FILETYPE                = 'BIN'
     TABLES
          DATA_TAB                = itab_mara
     EXCEPTIONS
          OTHERS                  = 11
IF SY-SUBRC <> 0.
ENDIF.
*-- print the whole DOM tree as a list...
pNode = pDocument.
perform print_node using pNode.
      FORM print_node                                               *
form print_node using value(pNode) type ref to if_ixml_node.
data: indent      type i.
data: pText       type ref to if_ixml_text.
data: string      type string.
indent = pNode->get_height( ) * 2.
case pnode->get_type( ).
    when if_ixml_node=>co_node_element.
      string = pNode->get_name( ).
      write: at /indent '<', string, '> '.
    when if_ixml_node=>co_node_text.
       pText ?= pNode->query_interface( ixml_iid_text ).
       if pText->ws_only( ) is initial.
        string = pNode->get_value( ).
        write: at /indent string.
       endif.
endcase.
pNode = pNode->get_first_child( ).
while not pNode is initial.
     perform print_node using pNode.
     pNode = pNode->get_next( ).
endwhile.
endform.
but when open the XML file which i created on the desktop it shows the following error.
The XML page cannot be displayed
Cannot view XML input using style sheet. Please correct the error and then click the Refresh button, or try again later.
XML document must have a top level element. Error processing resource 'file:///C:/Documents and Settings/anilda/Desktop/sim...
how to rectify this error.
Regards,
satish.

You are going to need to provide more details about this shell script file you are executing and the environment it is in. Beyond being on a Windows box, you have provided none of those details.
If the SQL statement will execute cleanly in SQLDeveloper but not your script, then the issue lies in the script. How do you know the error is that SQL statement? Can your script even "select * from dual;" successfully?
Also, SQLDeveloper (which I don't use) may contain its own libraries for accessing the DB. You probably should consider upgrading to a SQL*Plus client that is at least the same version or later as your database.
Note:
As I recall, xmlgen in 9.2 is now a synonym for dbms_xmlgen. You should change the package name accordingly [url http://docs.oracle.com/cd/B10501_01/appdev.920/a96612/d_xmlge2.htm#1010709]dbms_xmlgen.getXML

Creating an xml file from recordset

Hi...
XML newbie here - so.
Is it possible to create and xml file from a recordset?
I need to create a datafeed of our e-commerce products.
Also, some of the db data contains HTML Code (product
description field),
how will this effect the xml file?
Another problem is that my xml file needs to contain url's
for the products
and product images. My ASP pages contain these URL in hard
code and then
pull the actual file names from the db
Hope that makes some sense
Thanks for any help
Andy

Hi David
Thanks for your help.
I think it will have to be option 1 as i am using Access DB.
I don't know how to go about it but will serach good old
Google.
Here is my recordset below, that pulls the required data from
Access.
The product and product image URL's need to be in the xml
file but only the
product image name and product id are in the database, e.g
image name
(imagename.jpg) productid (21)
The actual URL's are hardcoded in my ASP pages, e.g <img
src="products/medium/<%=(RSDetails.Fields.Item("Image").Value)%>"
Not sure if this makes things any clearer :-|
Thanks Again
Andy
<%
Dim RSdatafeed
Dim RSdatafeed_numRows
Set RSdatafeed = Server.CreateObject("ADODB.Recordset")
RSdatafeed.ActiveConnection = MM_shoppingcart_STRING
RSdatafeed.Source = "SELECT Products.Product,
Products.Description,
Products.Image, Products.image2, Products.ListPrice,
Products.Price,
Products.xml_feed, Manufacturers.Manufacturer,
Shipping.ShippingCost FROM
Shipping, Products INNER JOIN Manufacturers ON
Products.ManufacturerID =
Manufacturers.ManufacturerID WHERE
(((Products.xml_feed)=No));"
RSdatafeed.CursorType = 0
RSdatafeed.CursorLocation = 2
RSdatafeed.LockType = 1
RSdatafeed.Open()
RSdatafeed_numRows = 0
%>
"DEPearson" <[email protected]> wrote in
message
news:[email protected]...
> Andy,
>
> There are two ways you can create a xml file from a
recordset
>
> 1. Is to code it using Server.CreateObject(XMLDOM)
> 2. If you are using SQL server 2005, just request the RS
returns as XML
> data. using FOR XML AUTO after the where cause ( the
best way with 2005
> and
> higher sql server)
>
> The db data containing HTML code should not effect your
xml file, unless
> it
> is bad markup. You could wrap the data with
<![CDATA[the data or html
> markup, or javascript]]>
>
> If the url is a recordset field, then it will return
with the xml data.
> If
> not you can create a storage procedure that will build
your URL from the
> data
> in the database.
>
> It is best to use storage procedure (SP )for security
reason when pulling
> data
> from a MS Sql server, make all calls to the database in
a SP. Also be sure
> to
> validate the values in the querystrings before accepting
them, check for
> hack
> code.
>
> David
>

Load XML file from different location?

Hi All,
I've been going through an exercise by Karl Matthews to load XML data into an AIR App:
http://www.adobe.com/devnet/air/flex/articles/xml_viewer_on_air.html
but I would like to change where the XML file used in the project is retrieved from.
Currently the XML file is loaded from here:

<mx:HTTPService id="srcData" url="
assets/UserGuide.xml" result="loadModelData(event)"
/>
but I would like to load the XML file from one of these locations instead:
File.userDirectory:
File.documentsDirectory:
Can someone please show me how I should change the above code to accomplish this, as my efforts to date have not been successful :-(
I am using Flex Builder 3 and Air 1.5.
Thanks heaps!
Tim

Hi Bhasker,
Thank you for replying.
I am not very good at all this coding, but I am assuming I should now be doing entering the following:
=======================
<?xml version="1.0" encoding="utf-8"?>
<mx:WindowedApplication
xmlns:mx="http://www.adobe.com/2006/mxml" layout="vertical"width="
800" height="660"xmlns:comp="
*" xmlns:fmtComp="fmtComps.*"creationComplete="srcData.send()"
paddingLeft="
0" paddingRight="0" paddingTop="0" paddingBottom="0">
<mx:Script>
<![CDATA[
import mx.utils.ObjectProxy;
import mx.rpc.events.ResultEvent;
Bindable]
private var userManualObj:ObjectProxy;
private function loadModelData(event:ResultEvent):void
userManualObj=event.result.UserManual;
private function readXMLContent(xmlFile:File,objContentView:Object):Array{
var reportDir:File = File.userDirectory.resolvePath("assets");
var xmlFile:File;
var fileStream:FileStream = new FileStream(); xmlFile = reportDir.resolvePath(
"UserGuide.xml");
if(xmlFile.exists && xmlFile.size > 0)// Checking if the impressions.xml file already exists and the file is not empty
var stream:FileStream = new FileStream();
var xml:XML = new XML();stream.open(xmlFile, FileMode.READ);
xml = XML(stream.readUTFBytes(stream.bytesAvailable));
stream.close();
]]>
</mx:Script>

<mx:VBox width="100%" horizontalAlign="left" height="100%" paddingBottom="
0" paddingLeft="0" paddingRight="0" paddingTop="0">
<mx:TabNavigator width="100%" height="100%"paddingBottom="
0" paddingLeft="0" paddingRight="0" paddingTop="0">
<mx:Repeater id="modelsRep" dataProvider="{userManualObj.Product.Model}">
<mx:VBox label="{modelsRep.currentItem.Name}" width="100%" height="100%">
<comp:ModelDesc model="{modelsRep.currentItem}"/>
</mx:VBox>
</mx:Repeater>
<mx:VBox label="Troubleshooting" width="100%" height="100%"paddingBottom="
0" paddingLeft="0" paddingRight="0" paddingTop="0">
<comp:Troubleshooting issues="{userManualObj.Product.Troubleshooting.Issue}" />
</mx:VBox>
</mx:TabNavigator>
</mx:VBox></mx:WindowedApplication>
=======================
and create and "assets" folder in my user directory placing the XML file in there?
However when I do all that, I get this error when I try to compile:
Encountered errors or warnings while building project main.mxml.
main.mxml: Function does not return a value.
Any thoughts?
Many thanks,
Tim

Can I load xml file from SWC without using @embed

I'm developing a mobile application in which I need to load xml files from File.applicationDirectory. This works great if the xml files are part of the main application swf. But I would like to move these xml files into a SWC so they could be shared across multiple applications.
Using FlashBuilder 4.5, when a SWC is built, I can specify files to embed in the library that are not assets (Assets Tab of Flex Library Build Path). For various design reasons, I do NOT want to embed the xml files via @embed.
When the swc is built and I open it up using a zip utility, I see the xml files in there just fine. So they are being bundled with the SWC. But how can I load these files in my main application that does not involve using @embed? When the main application is built, the swc setting for link type is "merged into code".
I wouldn't expect the application to automatically pull out the xml files from the swc and place them in the File.applicationDirectory on the mobile device. I've tried loading from there just in case but file.exists is false (as expected).
I've searched the web (and continue to do so) and all the answers seem to be to use @embed. Is there another way?
Randy

It's actually a lot easier than you think.
Just reference the file like any'ol URL using a path relative to the SWC's src directory.
So if you include the file "assets/xml/some.xml", just use that same string like you would any remote resource.
For example:
var loader:URLLoader = new URLLoader( new URLRequest("assets/xml/some.xml"));
I believe it would also work like this "/assets/xml/some.xml", but I prefer relative paths so the link doesnt break if moved out of the SWC...

Open an xml file from a URL

Similar Messages

Maybe you are looking for