Open Dynpage from other Dynpage on clicking a link and get user parameter.

Hi All,
I have one application in which i am displaying the data based on the user data entered.
On that page i have written a loop to display the records. Also i have a link there stating "More Details".
If i click on the link of More Details, then remaining data for that should be displayed on the new page.
I am able to open a new page but unable to get the data which for that. in query.
I am using HTMLB control with javascript.
Pls help me out.
Regards,
Dhruv Shah

Hi,
You can do that in two ways...
1. If you are having QuickLink for your pages(of corrosponding Applications)
then,
On Click...
call a Java Script function where you can pass a request parametre to the new page...
some thing like this..
//Script
function onMyClick(parametertoPass)
location.href="/irj/portla/PageQuickLink?RequestParamName="+parametertoPass;
//Whre PageQuickLink is the QuickLink for the More Details Page that you set in Portal
//End Script
Now in the Details Applications(page what you are opening on click of more)
inside the component/DynPage
String s=request.getParametre("RequestParamName");
2. If you are not using Page QuickLinks...
Then,
only change you have to do is...
//Script
function onMyClick(parametertoPass)
location.href="/irj/servlet/prt/portal/prtroot/ApplicationYouWantToOpen.ComponentName?RequestParamName="+parametertoPass;
//For Ex. If the application you want to open is
//ProjectName : MyDetailsProj
//ComponentName : MyDetailsComp
//Then your
location.href="/irj/servlet/prt/portal/prtroot/MyDetailsProj.MyDetailsComp?RequestParamName="+parametertoPass;
//End Script
Regards,
Srinivas.
Edited by: srinivas sistu on Aug 12, 2008 11:10 AM

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Open Dynpage from other Dynpage on clicking a link and get user parameter.

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