OPEN SQL - use of subquery to get max date

Hello,
I am trying to use a subquery to get the latest record, but cannot get the syntax correct.
select single from hrp1001 into mydata
where objid = '122334'
where begda = ( select max ( begda ) from hrp1001 where objid = '122334' )
but cannot get it right.
I am just trying to get the record with the max(date).
Thanks

Hello,
To get a better performance, I suggest you the following:
select single * from hrp1001 into corresponding fields of mydata
where objid = '122334'
order by begda descending.
Regards,

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Hi,
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Hi gurus, Here is my situation:
Here is the sample data:
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123_____10/30/2008 __ 333
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123_____ 08/30/2008___443
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I thought to use lag - maybe not as appropriate a ranking functions.
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drop table Max_but_One;
create table Max_but_One
Policy_Id      integer      not null,
Policy_Expires date         not null,
Policy_Note    varchar2(20) not null
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insert into Max_but_One values (123, to_date('30-08-2008','dd-mm-yyyy'), 'First note');
insert into Max_but_One values (123, to_date('25-09-2008','dd-mm-yyyy'), 'Second note');
insert into Max_but_One values (123, to_date('30-10-2008','dd-mm-yyyy'), 'Third note');
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insert into Max_but_One values (223, to_date('02-11-2008','dd-mm-yyyy'), 'Second note');
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insert into Max_but_One values (323, to_date('01-12-2008','dd-mm-yyyy'), 'First note');
-- Two or more records for a policy both having the same date which is prior to the max
insert into Max_but_One values (423, to_date('10-12-2008','dd-mm-yyyy'), 'First note');
insert into Max_but_One values (423, to_date('10-12-2008','dd-mm-yyyy'), 'Second note');
insert into Max_but_One values (423, to_date('11-12-2008','dd-mm-yyyy'), 'Third note');
break on Policy_ID
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from Max_but_One
order by Policy_Id, Policy_Expires
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           25-SEP-08 Second note
           30-OCT-08 Third note
       223 01-NOV-08 First note
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       323 01-DEC-08 First note
       423 10-DEC-08 First note
           10-DEC-08 Second note
           11-DEC-08 Third note
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from (select Policy_Id, Policy_Expires, Policy_Note
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Asset
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User
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Bob
CTUT222
ZZ221144
Susy
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Hi
Version is 11g
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hi
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25-05-07 30
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ans " suppose current date is 25 "
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try like this..
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SQL>

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Code1    Code2   Code3     Date1         RTCODE
A           A1        A2         1/1/2012     SER
A           A1        A2         1/1/2013     SER
A           A1        A2         1/1/2015     TER
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B          B1        B2         1/1/2012     JTR
C          C1       C2         1/1/2010      HYR
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A           A1        A2         1/1/2015     TER
B          B1        B2         1/1/2012      JTR
C          C1       C2         1/1/2011       JST

Hi,
You can try this:
CREATE TABLE #T
CODE1 VARCHAR(5),
CODE2 VARCHAR(5),
CODE3 VARCHAR(5),
DATE1 DATE,
RTCODE VARCHAR(5)
--DROP TABLE #T
INSERT INTO #T
VALUES
('A','A1','A2','20120101','SER'),
('A','A1','A2','20130101','SER'),
('A','A1','A2','20150101','TER'),
('B','B1','B2','20110101','JTS'),
('B','B1','B2','20120101','JTR'),
('C','C1','C2','20100101','HYR'),
('C','C1','C2','20110101','JST');
--TRUNCATE TABLE #T
WITH TEST AS
SELECT CODE1, CODE2, CODE3, MAX(DATE1) AS DT_MAX
FROM #T
GROUP BY CODE1, CODE2, CODE3
SELECT T.CODE1,T.CODE2, T.CODE3, T.DT_MAX,#T.RTCODE
FROM TEST AS T
INNER JOIN #T ON T.CODE1=#T.CODE1
AND T.CODE2=#T.CODE2
AND T.CODE3=#T.CODE3
AND T.DT_MAX=#T.DATE1
ORDER BY T.CODE1,T.CODE2,T.CODE3
Regards,
Reshma
Please Vote as Helpful if an answer is helpful and/or Please mark Proposed as Answer or Mark As Answer when question is answered

OPEN SQL - use of subquery to get max date

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