Help to get max date of the group

Question

Hi, How I can get the max(date1) for the group on the basis of Code1,Code2,Code3.
Code1    Code2   Code3     Date1         RTCODE
A           A1        A2         1/1/2012     SER
A           A1        A2         1/1/2013     SER
A           A1        A2         1/1/2015     TER
B          B1        B2         1/1/2011       JTS
B          B1        B2         1/1/2012      JTR
C          C1       C2         1/1/2010      HYR
C          C1       C2         1/1/2011       JST
Expected results from query should be:
Code1    Code2   Code3     Date1         RTCODE
A           A1        A2         1/1/2015      TER
B           B1        B2         1/1/2012      JTR
C          C1       C2          1/1/2011       JST

Answer 1

Hi,
You can try this:
CREATE TABLE #T
CODE1 VARCHAR(5),
CODE2 VARCHAR(5),
CODE3 VARCHAR(5),
DATE1 DATE,
RTCODE VARCHAR(5)
--DROP TABLE #T
INSERT INTO #T
VALUES
('A','A1','A2','20120101','SER'),
('A','A1','A2','20130101','SER'),
('A','A1','A2','20150101','TER'),
('B','B1','B2','20110101','JTS'),
('B','B1','B2','20120101','JTR'),
('C','C1','C2','20100101','HYR'),
('C','C1','C2','20110101','JST');
--TRUNCATE TABLE #T
WITH TEST AS
SELECT CODE1, CODE2, CODE3, MAX(DATE1) AS DT_MAX
FROM #T
GROUP BY CODE1, CODE2, CODE3
SELECT T.CODE1,T.CODE2, T.CODE3, T.DT_MAX,#T.RTCODE
FROM TEST AS T
INNER JOIN #T ON T.CODE1=#T.CODE1
AND T.CODE2=#T.CODE2
AND T.CODE3=#T.CODE3
AND T.DT_MAX=#T.DATE1
ORDER BY T.CODE1,T.CODE2,T.CODE3
Regards,
Reshma
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