Opening a URL from an application

Hi everyone, am not quiet skilled with java but i would really appreciate your help with this, as i couldn't find a solution which made me doubt my whole basic knowledge of java. Now am doing this for my school project, it's a speech recognition application that will convert speech to text, there are 2 buttons in my interface, one "start" where you start speaking , the other one "stop" which would allow the engine to start processing the speech and converts it to text, it will then open a web page which in my case is a search engine(say google or yahoo) and searches for the matching documents of what has been spoken.
my problem is that i need to open that certain URL ( predefined) from a running application and not an applet, it hasn't worked for me, This is the only problem. is it possible ? please i need your help with this , i'd really appreciate it if someone would help ... thanks a lot for your time.

hii guys am really sorry for the confusion ,the problem was actually with the java security poilcy not with the code as i thought.. i thought my code was wrong but it turned out to be correct.. here it is for anyone who's interested... but thanks anyway for everything... tc
Runtime rt = Runtime.getRuntime();
rt.exec("C:/Program Files/Internet Explorer/iexplore.exe http://www.google.com/search?hl=en&q=hi+my+name+is+omaya");

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Want to open a URL from java application?

I want to open a URL (say http://yahoo.com) from my java application without using servlets. PLzzz help asap

Include these packages:
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import java.io.*;
Proxy Setting If any:
//getProxy your proxy address default "No Proxy".
if (!getProxy.equals("No Proxy"))
System.getProperties().put("proxySet","true");
System.getProperties().put("proxyHost",getProxy);
System.getProperties().put("proxyPort","80");
Main code:
URL url = new URL("http://mail.yahoo.com");
URLConnection connection1 = url.openConnection();
String filetext=postURL(connection1);
Function postURL:
public String postURL(URLConnection connection)
try
BufferedReader httpResponse = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line = new String();
StringBuffer buffer = new StringBuffer();
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System.out.println("Error:"+e);
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Open new url in java application

Hi,now i met a problem,i want to open a url in a application in any platform.It can descrips like this:In a java application ,there is a button ,when i clicked the button ,i can open the web browser and open the url like http://www.google.com in the browser.
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yeah,somebody do it in his software,but i can't find its sourcecode.
yesterday i did it and it works fine,but it can't work on windows platform and maybe it has bug.So i want to find a good way to solve it and it can works on any platform.
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I'm using jdev 10.1.2 and adf bc's. In my application i have a table which stores links for a number of websites. So I have a jsp which lists all the records from this table. When the user clicks on the link, the relevant page should open up in a new browser.
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Hello All,
Please guide me in below scenario as I am new to SAP UI5.
I have created a SHELL application with 5 tabs.
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I am attaching the screenshot.
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Hi Jagadeesh,
See this code for reference.
This is my view.
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<html>
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Dhananjay

Opening an URL from a JAVA application

hi,
iam new to Java.
Currently iam designing a simle GUI which takes input(URL) from user in a test field and has a button.Upon clicking button i want to open the webPage specified by that URL in a default webBrowser.
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getting an error on that line as follows: "unreported
exception; must be caught or declared to be thrown".exec() throws IOException so catch it.
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If you mean to read the contents of a URL, then see URL.getConnection. If
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