ORA-06503 ERROR IN ORACLE REPORT.

Question

[Error message is fucntion without a value, the solution is er-write function to return a value. I know this much about the error, but i want someone look at my function and tell me what's the problem with it. The error not going anywhere.]
(here is my function which i defined in column level)
(function CF_1Formula return date is)
(VAR_DATE DATE;)
(ORD_DATE DATE;)
(begin)
( select max(mit_date)
into var_date
from mit_d
where mit_d.uic_well_seq = :seq1;
SELECT MAX(mit_orders.ORDER_DATE)
INTO ORD_DATE
FROM mit_ORDERS, WELL_ORDERS
WHERE mit_ORDERS.SEQ = WELL_ORDERS.UIC_ORDER_SEQ
AND WELL_ORDERS.UIC_WELL_SEQ = :SEQ1;
IF VAR_DATE >= ORD_DATE THEN
return(var_date);
END IF;
end;)
appreciate any help.

Answer 1

Hi,
Your function doesnt return a value.
Functions always need to return a value.
You can use an exception handler or code an alternative in case your if doesn't apply:
IF VAR_DATE >= ORD_DATE THEN
   return(var_date);
ELSE
   return(an_alternative_date); -- or raise an error, follow your requirements in this
END IF;Also realize that you SELECT INTO, maybe you need also to catch NO_DATA_FOUND and/or TOO_MANY_ROWS exceptions there, and provide alternative values for your variables.
Edited by: hoek on Apr 1, 2009 5:37 PM