Oracle reverse date : inupt (number of the week, number of the date, year)

Hi experts,
*I have a date that has been stored in three separated columns in a oracle data base 10g:
-number of week: for example 30. (range 1-53)
-number of the day: for example 5. (range 1-7).
-year : for example 2010.
*i need to write a SQL code which concate and convert this three columns to one signle date in the format dd/mm/yyyy.
*This a concrete example:
-input:
number of the day: 2, number of the week :23, year 2010.
-ouput:
07/06/2010
Any idea will be welcome
Best regards.

Hi,
Here's one way :
alter session set nls_date_language = "english";
alter session set nls_territory = "america";
WITH date_parts AS (
select 2010 yr, 23 wk, 2 dy from dual union all
select 2010 yr, 39 wk, 2 dy from dual
SELECT next_day(to_date('0101'||yr,'DDMMYYYY')-7, 'SUN') - 1
       + 7*wk
       + dy
       AS dt
FROM date_parts;You might have to make some adjustments due to your nls settings.

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969752
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