Order by the names in hashMaps which are contained within a collection

Question

Hi All,
Is there a way to order by the names in hashMaps which are contained within a collection?
Collection-->hmp1(nrPerson1, nameB);
hmp2(nrPerson2, nameC);
hmp3(nrPerson3, nameA);
Now what i need to display is (nrPerson3,nameA), (nrPerson1,nameB), (nrPerson2, nameC)...
Any suggestion will be greatly appreciated!
Shuaibing

Answer 1

I just set the TreeSet with the values as you suggested, but the results seems to the same as usual, Can you check the following codes? I think I need have to give a initial parameter for the TreeSet constructor, but I do not know how to write the Comparator.
public String getIntermediaryCO(){
Contact contact=new Contact();
          Collection colnNrContactsInterCo=contact.getAllIntermediaryCompany();
          //test
          TreeSet treeSet=new TreeSet();
          HashMap hmpForOrder=new HashMap();
          if(colnNrContactsInterCo!=null && !colnNrContactsInterCo.isEmpty()){
               Iterator iter=colnNrContactsInterCo.iterator();
               while(iter.hasNext()){
                       HashMap hmp=(HashMap)iter.next();
                       hmpForOrder.put(hmp.get("name"),hmp.get("nrContact"));
          treeSet.add(hmpForOrder.keySet());
          //print the ordered, unique set
        Iterator iterator = treeSet.iterator();
        while( iterator.hasNext() ) {           
            System.out.println( "the list of sorted intermediary companies' names="+iterator.next() );
          //test
public Collection getAllIntermediaryCompany(){
           Collection colnContacts=new ArrayList();
           ContactCov contactCov=new ContactCov();
         try{
                String sql="SELECT DISTINCT NR_CONTACT from CONTACT_TYPE where CD_CONTACT_TYPE=5";
                jdbc = new JDBCConnection("1");
                rs=jdbc.executeQuery(sql);
                if(rs!=null){
                     while(rs.next()){
                               String nrContact=rs.getString("NR_CONTACT");
                               VOContact voContact=contactCov.getContactByNrContact(nrContact);
                               if(voContact!=null){
                                    HashMap hmp=new HashMap();
                                    hmp.put("name",voContact.getName());
                                    hmp.put("nrContact",nrContact);
                                    colnContacts.add(hmp);
              }catch(Exception e){
                  logger.error(e.toString());
               }finally{
                   try{
                        if(rs!=null)rs.close();
                        if(jdbc!=null)jdbc.close();
                   }catch(Exception e){}
           return colnContacts;     
        }