Parsing XML inside JAR

Hello Everyone,
I would like to know if it is possible to parse an XML file(MyProps.xml) that is found in an Jar archive. The XML file has a DTD(MyProps.dtd) in the archive also.
I call the javax.xml.parsers.DocumentBuilder.parse method with the input source to the xml file.
InputStream is = ClassLoader.getSystemResourceAsStream("MyProps.xml");
I get then the exception:
org.xml.sax.SAXParseException: File "MyProps.dtd" not found.
        at org.apache.xerces.framework.XMLParser.reportError(XMLParser.java:1219)
        at org.apache.xerces.readers.DefaultEntityHandler.startReadingFromExternalEntity(DefaultEntityHandler.java:780)
        at org.apache.xerces.readers.DefaultEntityHandler.startReadingFromExternalSubset(DefaultEntityHandler.java:571)
        at org.apache.xerces.framework.XMLDTDScanner.scanDoctypeDecl(XMLDTDScanner.java:1139)
        at org.apache.xerces.framework.XMLDocumentScanner.scanDoctypeDecl(XMLDocumentScanner.java:2145)
        at org.apache.xerces.framework.XMLDocumentScanner.access$0(XMLDocumentScanner.java:2100)
        at org.apache.xerces.framework.XMLDocumentScanner$PrologDispatcher.dispatch(XMLDocumentScanner.java:831)
        at org.apache.xerces.framework.XMLDocumentScanner.parseSome(XMLDocumentScanner.java:381)
        at org.apache.xerces.framework.XMLParser.parse(XMLParser.java:1098)
        at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:195)
        at javax.xml.parsers.DocumentBuilder.parse(Unknown Source)Any idea?
Thanks and best regards,
Johnny
Edited by: smeag0l on Aug 4, 2008 6:57 PM

Your setup says that the DTD is in the same directory as the XML, doesn't it? The parser can deal with that if you give it a chance. But by giving the parser an InputStream, there is no way for it to know what directory the XML came from, and hence no way for it to find the DTD.
However if you used the getResource() method, which returns a URL, and gave that URL to the parser, it should be able to construct the relative URL for the DTD.

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BEA Systems, Inc.
[email protected]

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simple parser which give it XML and DTD, then return
to me Java objects ... I mean if that kind of parser
exists....It'll take you probably magnitude longer that that to get really familiar with JAXB, but believe me it's worth it. You'll save countless days if not weeks once you'll start developing serious software with it. How long did it take you to learn Java and it's main APIs? You'll either invest the time learning how to use the software others have written, or you invest it writing it yourself. I'll take the former any time. But it's only my opinion...
Jan

How to parse xml

Hi All
I want to parse xml document which contains more then one occurrence of particular element.
I want to get some sub elements of that element and want take action on the basis of param tag inside this sub element.
for example :
<appender name="first" class="tempclass...">
<param name="File" value="d:/test.log" />
<filter class="">
<param name="LevelToMatch" value="sdsds" />
<param name="OtherParam" value="bla bla" />
</filter>
</appender>
<appender name="second" class="tempclass...">
</appender>
my problem is how do i differentiate all "<appender>".
I want values of "File" and "LevelToMatch" for each declaired appender
and depending upon the values i want to take some decision.
I dont know XML much
I am using DOM parser.
Please help me ASAP.
Thanks in advance,

hi,
i hope u need to get the attribute values, right...
if yes..create the DocumentBuilderFactory for the xml the uisng buildFactory method u will get the parser...from parser u cann go for anything....
if u r not clearly, reply where do u struck...
bye,
suryakant.

How to parse XML for internal table

hi guys, I would like to know how to parse xml for an internal table. I explain myself.
Let's say you have a purchase order form where you have header data & items data. In my interactive form, the user can change the purchase order quantity at the item level. When I received back the pdf completed by mail, I need to parse the xml and get the po qty that has been entered.
This is how I do to get header data from my form
lr_ixml_node = lr_ixml_document->find_from_name( name = ''EBELN ).
lv_ebeln = lr_ixml_node->get_value( ).
How do we do to get the table body??
Should I used the same method (find_from_name) and passing the depth parameter inside a do/enddo?
thanks
Alexandre Giguere

Alexandre,
Here is an example. Suppose your internal table is called 'ITEMS'.
lr_node = lr_document->find_from_name('ITEMS').
lv_num_of_children = lr_node->num_children( ).
lr_nodechild = lr_node->get_first_child( ).
do lv_num_of_children times.
    lv_num_of_attributes = lr_nodechild->num_children( ).
    lr_childchild = lr_nodechild->get_first_child( ).
   do lv_num_of_attributes times.
      lv_value = lr_childchild->get_value( ).
      case sy-index.
         when 1.
           wa_item-field1 = lv_value
         when 2.
           wa_item-field2 = lv_value.
      endcase.
      lr_childchild = lr_childchild->get_next( ).
   enddo.
   append wa_item to lt_item.
   lr_nodechild = lr_nodechild->get_next( ).
enddo.

Javax.resource.ResourceException: : Error in parsing XML

Hi
Iam developing a connector application.
Iam using OC4J 9.0.4 version(standalone) for deployment of RAR file. We are parsing the below xml in our application using SAX parser.
<?xml version="1.0" encoding="utf-8"?>
<DocAnnoList xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" LibName="IMGSERV" DocID="1698353" SystemType="1">
<AnnoDefPermission>
<security>
<securityobject libraryid="IMGSERV" systemtype="idmis" objectid="" objecttype="annotation" clientpermission="change">
<permission id="1" name="Test1G" type="group" level="read" />
<permission id="2" name="Test1G" type="group" level="write" />
<permission id="3" name="Test1G" type="group" level="append" />
</securityobject>
</security>
</AnnoDefPermission>
</DocAnnoList>
But iam getting the below error while parsing this xml with OC4J running on Win2k/HPUX/Solaris.
Error in parsing XML Stream. The element "DocAnnoList" is not as per the XSD.
04/03/26 14:11:06 org.xml.sax.SAXException: : Error in parsing XML Stream. The element "DocAnnoList" is not as per the
XSD.
04/03/26 14:11:06 at com.abc.is.ra.util.AB_IS_XMLObjectHandler.startElement(Unknown Source)
04/03/26 14:11:06 at oracle.xml.parser.v2.NonValidatingParser.parseElement(NonValidatingParser.java:1181)
04/03/26 14:11:06 at oracle.xml.parser.v2.NonValidatingParser.parseRootElement(NonValidatingParser.java:300)
04/03/26 14:11:06 at oracle.xml.parser.v2.NonValidatingParser.parseDocument(NonValidatingParser.java:267)
04/03/26 14:11:06 at oracle.xml.parser.v2.XMLParser.parse(XMLParser.java:149)
04/03/26 14:11:06 at oracle.xml.jaxp.JXSAXParser.parse(JXSAXParser.java:286)
04/03/26 14:11:06 at oracle.xml.jaxp.JXSAXParser.parse(JXSAXParser.java:224)
I put the xSchema.jar,xml.jar & xmlparserv2.jar in java CLASSPATH as described at below URL.
http://otn.oracle.com/pub/articles/vohra_xmlschema.html
But problem is still there.
Can anyone tell me what is the problem. Iam sure, there is nothing wrong with our code as it is running well on Websphere 5, Weblogic 8.1, JBoss 3.2.3, SUN ONE 7.

will come if there are any tab spaces in the file..
delete the tab spaces from the file..

Parsing xml using DOM parser in java

hi there!!!
i don have much idea about parsing xml.. i have an xml file which consists of details regarding indentation and spacing standards of C lang.. i need to read the file using DOM parser in java n store each of the attributes n elements in some data structure in java..
need help as soon as possible!!!

DOM is the easiest way to parse XML document, google for JDOM example it is very easy to implement.
you need to know what is attribute, what is text content and what is Value in XML then easily you can parse your document with dom (watch for space[text#] in your XML document when you parse it).
you get root node then nodelist of childs for root then go further inside, it is easy believe me.

Ned help on JSP parsing XML

Hi all.
Im having problems on how to parse an xml by JSP
Can anyone teach me how to parse an the XML below by jsp, without using taglibs. Im using JDOM...
<Customer>
           <DetailsCustomer ID = 1>
           <Name>
                  John
           </Name>
           <DetailsCustomer ID = 2>
           <Name>
                 Michael
           </Name>
<Customer>Thankz :)
Hope for a kind reply :)

Hi,
Why would you like to parse the XML inside a JSP page? JSP are for rendering and not for parsing XML. The code to parse the XML should be put in an ordinary Java class instead.
Parsing XML can be done in a number of ways...it all depends on what you want to do with the XML. Are you looking for XML -> Java Object then maybe you should look at XStream or JAXB.
If you can tell me a little more about your use case maybe I can help you a little bit more.
/klejs

How to parse xml file in midlet

Hi Guys,
i wish to parse xml file and display it in my midlet. i found api's supporting xml parsing in j2se ie., in java.net or j2se 5.0. Can u please help me what package to use in midlet?
how to parse xml info and display in midlet? Plz reply soon......Thanks in advance....

i have exactly the same problem with KXml2, but using a j2me-polish netbeans project.
i've tried to work around with similar ways like you, but none of them worked. now i've spent 3 days for solving this problem, i'm a bit disappointed :( what is wrong with setting the downloaded kxml2 jar path in libraries&resources?
screenshot

Parsing XML inside JAR

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