Passing object references to methods

Question

i got the Foo class a few minutes ago from the other forum, despite passing the object reference to the baz method, it prints "2" and not "3" at the end.
but the Passer3 code seems to be different, "p" is passed to test() , and the changes to "pass" in the test method prints "silver 7".
so i'm totally confused about the whole call by reference thing, can anyone explain?
class Foo {
    public int bar = 0;
    public static void main(String[] args) {
            Foo foo = new Foo();
            foo.bar = 1;
            System.out.println(foo.bar);
            baz(foo);
            // if this was pass by reference the following line would print 3
            // but it doesn't, it prints 2
            System.out.println(foo.bar);
    private static void baz(Foo foo) {
        foo.bar = 2;
        foo = new Foo();
        foo.bar = 3;
class Passer2 {
     String str;
     int i;
     Passer2(String str, int i) {
     this.str = str;
     this.i = i;
     void test(Passer2 pass) {
     pass.str = "silver";
     pass.i = 7;
class Passer3 {
     public static void main(String[] args) {
     Passer2 p = new Passer2("gold", 5);
     System.out.println(p.str+" "+p.i);  //prints gold 5
     p.test(p);
     System.out.println(p.str+" "+p.i);   //prints silver 7
}

Answer 1

private static void baz(Foo foo) {
foo.bar = 2;
foo = new Foo();
foo.bar = 3;This sets the bar variable in the object reference by
foo to 2.
It then creates a new Foo and references it by foo
(foo is a copy of the passed reference and cannot be
seen outside the method).
It sets the bar variable of the newly created Foo to
3 and then exits the method.
The method's foo variable now no longer exists and
now there is no longer any reference to the Foo
created in the method.thanks, i think i followed what you said.
so when i pass the object reference to the method, the parameter is a copy of that reference, and it can be pointed to a different object.
is that correct?