Path to class file

hi,
how can i determine the path to of a class file? For example i have a class
public class ABC {
public ABC() {
System.out.println(<print file path of this>);
}For example, if ABC was in C:\code....
Thanks

I know I dont need the path ..i am just curious...basically i have an app being deployed and i wanna see where the class file actually exists on the file system when it is loaded...thats all, not for any program reason.
thanks, anyone else?

Similar Messages

How to run a class file from windows ?

hi, i have created a shorcut to run my java application from my windows desktop, but i have the error message "Couldn't find the main class, programm will exit",
the shortcut is as follow
[%windir%\System32\javaw.exe C:\ProgramFiles\\Main]
thanks for you help,

Im new to running java from a shortcut but this may help. I hope this helps.
this is the command you ned to write and refer to my example;
javaw.exe -cp <path to class file> packageName.className
This is an example of wat i have typed to run my program from a shortcut;
C:\JBuilder3\java\bin\javaw.exe -cp C:\jbuilder3\myclasses\welcome.jar welcome.welcome
Hope this helps
good luck!!!
Matx3001

How to get *.class file path....

how could find the executable file path at execution time..
if there is one *.class file, then i will paste it to another location . next i will execute that .class file. how to find that path from execution program ....

Try the following
URL path = getClass().getProtectionDomain().getCodeSource().getLocation();

Howto resolve the path to the class file

hi @ all,
i'm currently developing a package for ldap operations. now i want to write down all the real basic configuration for that package into a xml file which i want to save in the folder where the compiled class files are stored. my problem is that i do not know how i can resolve the absolute path to that xml file later. i mean, how can i load this file if the package is, e.g. exported as an jar file and i do not know where this jar file will be stored by the users of my package.
can anyone help me with that please?
thx in advance
dialsc

k, cool...
looks like it goes into the right direction.
with this statement i get the path where the jar is stored, right.
in my current situation this is the path to the src directory which i configured my eclipse ide to store the class files under.
let's say this path is d:\tmp\src
my package is tdl.domain.utils.ldap
so in fact at the moment my class files are stored under d:\tmp\src\tdl\domain\utils\ldap and the xml file too.
first:
that statement returns /D:/tmp/src
as you can see it uses unix path separators. do i have to replace them with the machine specific pathSeparatorChar?
second:
can is simply add the path tdl\domain\utils\ldap to that one (using the according machine specific pathSeparatorChar) and will this also work when i build a jar file of my package?
sorry for all that questions but i realy need this...
thx
dialsc

How to use Class-Path in Manifest file

hi,
I want to add jar files in another executable jar file but the Class-Path in Manifest file is not set correctly,please give an example for setting a Class-Path attribute in Manifest class.
regards,
selvaraj

You looked into the Jar section of the Sun tutorial did you?

Get installation path of web application from class file

Can anybody tell me how I can get the path on disk to the root of my web application from a class file. Im running under Tomcat 5.5 and I have 3 copies of the same webapp under 3 differenet directories:
C:\xxx\dev\yyy
C:\xxx\test\yyy
C:\xxx\prod\yyy
Based on which directory the web-app, I need to do a lookup on a properties file to pull the right jdbc connection to connect to the appropriate database. So it would be similar to using getServletContext().getRealPath("/") from a .jsp file.
Thanks,
Jason

Sorry for not clarifying. I have a properties file with name/value pairs. I know where this properties file is and I can do a lookup in it. In this file, I have jdbc connection names which point to corresponding jdbc resources in my context.xml file.
jdbcDevDatabase=jdbc/tfmDev
jdbcTestDatabase=jdbc/tfmTest
jdbcProdDatabase=jdbc/tfmProd
These connections are for dev, test and prod databases. Now based on where the web-app is installed on disk, i.e-dev dir, test dir, prod dir, I want to retrieve the corresponding connection. The problem is I don't know how to get a handle to the web apps real path on disk without access to the request object or using getServletContext().getRealPath("/") which are not available to me in a class file.
Thanks,
Jason

PATH VARIABLES AND RUNNING CLASS FILES

People:
I'm a complete Java neophyte and (slowly) learning. Rather than using the NetBeans IDE I have installed, I'm taking the text editor approach to type my source code.
After I type code into my text editor, does it necessarily matter where I save my text files? For my first application, I created HelloWorldApp.java in Notepad, originally saving the file to the same folder where my J2SE 5.0 installation is stored, which is:
C:\Program Files\Java
My javac (Java compiler) is located in:
C:\Program Files\Java\jdk1.5.0_01\bin
When I was first trying to compile HelloWorldApp.java, I received errors saying the Java compiler couldn't be found; I was told to create a path environment variable so the javac could be found to compile my code. When I went to the control panel to set an appropriate path variable, I deleted a (wacky!) Roxio path (don't even know how that got there), entering in its place:
C:\Program Files\Java
as the new path name, although, again, my Java compiler is located in
C:\Program Files\Java\jdk1.5.0_01\bin
After restarting my computer to implement the new path variable into the operating system, I tried compiling my program, but still got error messages. However, when I moved my HelloWorldApp.java text file from the location where I originally saved it, which was:
C:\Program Files\Java
to
C:\Program Files\Java\jdk1.5.0_01\bin
my HelloWorldApp.java finally compiled to a class file, which I finally ran! Did my program run because I moved the HelloWorldApp text file from C:\Program Files\Java into the C:\Program Files\Java\jdk1.5.0_01\bin folder where the javac is located?
Or did my C:\Program Files\Java path variable allow for the Java compiler to be found, although it's located in C:\Program Files\Java\jdk1.5.0_01\bin ? (This is why I asked above if it matters where you save your text document source code.)
In using a text editor to type source code, where should I save my Java text files next time?
Any help would be much appreciated! Thanks!

Add the following directories to the PATH variable.
C:\Program Files\Java\jdk1.5.0_01\bin
I agree with this part.
and add the following to the CLASSPATH variable
C:\Program Files\Java\jdk1.5.0_01\lib;C:\Program
Files\Java\jdk1.5.0_01\jre\lib;.
Where is this insanity coming from?
You do not need to set your classpath unless you are using a third party library or you have different parts of your program stored under different paths.
OP: You can store your source files anywhere you want to. You should put them somewhere that is easy for you to access. Most people have a common directory for all of their projects, with subdirectories for each project.
The only real restriction on where you put your source files is that the directory struction they are in must match the package statement at the top of the source file.
So, if your file has:
package chat.client.events;
at the top, then the source file must be in a directory named chat/client/events relative to where you keep your source files.

How to find path from within java class where .class file is located

I have a situation where my Servlet is running.
I need to access a text file which is locted in the same
place where the .class file for this Servlet is located.
I cannot specify absolute path in my java file.
I am in Windows platform.
My filename is specified as
File("myfile.txt");
the problem is it says file not found.
how do i fix this prob?
thanks in advance

String filename="/relative_path/file_name.txt";
try {
   //static method approach
   InputStream is = YourClassName.class.getResourceAsStream(filename);
   //non-static method approach
   InputStream is = getClass().getResourceAsStream(filename);
} catch (IOException e) { ... }tajenkins

How to convert class file

Hi all, I am new in java card development.
This is my environment setting:
@echo off
set JC_HOME=C:\JavaCard\java_card_kit-2_2
set JAVA_HOME=C:\j2sdk14103
set PATH=.;%JC_HOME%\bin;%PATH%
I have created the Wallet applet according to 'Zhiqun Chen" text book and named it WalletApp.java.
I have compiled this file to a class file.
This is where is I saved my file
C:\JavaCard\java_card_kit-2_2\samples\src\com\sun\javacard\samples\WalletApp\WalletApp.java.
But I don't really understand how to convert the class file.
May I know what is this for?
-out EXP JCA CAP
-exportpath
-applet 0xa0:0x0:0x0:0x0:0x62:0x3:0x1:0xc:0x1:0x1
com.sun.javacard.samples.HelloWorld.HelloWorld
com.sun.javacard.samples.HelloWorld
0xa0:0x0:0x0:0x0:0x62:0x3:0x1:0xc:0x1 1.0
must save this in what file?
I tried to type in the command line below (and the result):
C:\JavaCard\java_card_kit-2_2\samples>converter -config scr\com\sun\javacard\sap
les\Wallet\Wallet.opt
error: file scr\com\sun\javacard\saples\Wallet\Wallet.opt could not be found
Usage: converter <options> package_name package_aid major_version.minor_ver
sion
OR
converter -config <filename>
use file for all options and parameters to converter
Where options include:
-classdir <the root directory of the class hierarchy>
set the root directory where the Converter
will look for classes
-i support the 32-bit integer type
-exportpath <list of directories>
list the root directories where the Converter
will look for export files
-exportmap use the token mapping from the pre-defined export
file of the package being converted. The converter
will look for the export file in the exportpath
-applet <AID class_name>
set the applet AID and the class that defines the
install method for the applet
-d <the root directory for output>
-out [CAP] [EXP] [JCA]
tell the Converter to output the CAP file,
and/or the JCA file, and/or the export file
-V, -version print the Converter version string
-v, -verbose enable verbose output
-help print out this message
-nowarn instruct the Converter to not report warning messages
-mask indicate this package is for mask, so restrictions on
native methods are relaxed
-debug enable generation of debugging information
-nobanner suppress all standard output messages
-noverify turn off verification. Verification is default
*********************************************************May I know What is the correct command line to convert the class file and what must I do to before converting the class file?
I saw some article saying we must use JDK1.3, is it a must?
Your solution is highly appreciated.
Thank you!

Hi Ricardo,
I saved the file below as WalletApp.opt in the directory of scr\com\sun\javacard\samples\WalletApp
-out EXP JCA CAP
-exportpath c:\javacard\java_card_kit-2_2\api_export_files
-applet 0xa0:0x0:0x0:0x0:0x62:0x3:0x1:0xc:0x2:0x1 WalletApp.WalletApp
WalletApp 0xa0:0x0:0x0:0x0:0x62:0x3:0x1:0xc:0x2 1.0
But I still have the problem below:
C:\JavaCard\java_card_kit-2_2\samples>converter -config scr\com\sun\javacard\sam
ples\WalletApp\WalletApp.opt
error: file scr\com\sun\javacard\samples\WalletApp\WalletApp.opt could not be fo
und
Usage: converter <options> package_name package_aid major_version.minor_ver
sion
OR
converter -config <filename>
May I know What's wrong with my command or file?
Where can I download JDK because what I can find is J2SDK.
Thank you!

Importing my class files from another folder

hello everybody ,im creating a software package for a new company and want to organise my class files into different folders so that it would be easier for someone to navigate through them and update if necessary ,how do i import an instance of a class in a file that is in a subfolder of the folder that contains the class that is calling it.(sorry for being a bit long winded) iv tried diff things and they didn't work.
At the moment i have all the files in the one folder,but as i said above want to put them into appropriate folders.
I would be very gratefull if someone could give me some examples and if not some appropriate links,thanks iv tried looking for this on the net but could not find anything.

What you should probably do is to organise your classes into a heirarchy of packages not merely folders. Java expects the package structure to be reflected in the directory structure holding both the source and class files. If it's looking for a class called, say, com.mycompany.widgets.MainWidget it expects to find it in a directory com//mycompany/widgets relative the the directory on the class path.
Use the package directive in each source file to indicate the package path.

Adding .class files to your project and making them work.

Ok, im fairly new to java and having trouble understanding how to make importing of .class files work. Im using eclipse 3.2
I have the files in a directory and I have gone to project->properties->java build path->libraries->add external class folder and pointed it to the correct place.
Now, I am trying to use some of the classes it provides. I get no errors when creating the object with this code:
com.ECS.client.jax.ItemSearchRequest itemRequest = new com.ECS.client.jax.ItemSearchRequest();
Before I did the add external class folder that code would error cause it didnt know what com.ECS was. Now it works fine. My problem is that when I try to use a class, it does not recognize it as a class. After doing the above code I have:
itemRequest.setSearchIndex("Books");
its giving me an error on the period, saying: "Syntax error on token(s), misplaced construct(s)". Its not seeing that it is a class, so I can't use it. But when I am creating the object I get no errors. For reference, here is the chunk of code:
com.ECS.client.jax.ItemSearchRequest itemRequest = new com.ECS.client.jax.ItemSearchRequest();
itemRequest.setSearchIndex("Books");
the second line of which errors. So my question is, how do I get it to recognize that the itemRequest is a class when I have imported the .class files to my project already?

It's working fine. It's just that you have to put your code in a method.

How do I make a batch file if the .class file uses a foreign package?

I am trying to make an MS-DOS batch file using the bytecode file from the Java source file, called AddFields.java. This program uses the package BreezySwing; which is not standard with the JDK. I had to download it seperately. I will come back to this batch file later.
But first, in order to prove the concept, I created a Java file called Soap.java in JCreator. It is a very simple GUI program that uses the javax.swing package; which does come with the JDK. The JDK is currently stored in the following directory: C:\Program Files\Java\jdk1.6.0_07. I have the PATH environment variable set to the 'bin' folder of the JDK. I believe that it is important that this variable stay this way because C:\Program Files\Java\jdk1.6.0_07\bin is where the file 'java.exe' and 'javac.exe' are stored. Here is my batch file so far for Soap:
@echo off
cd \acorn
set path=C:\Program Files\Java\jdk1.6.0_07\bin
set classpath=.
java Soap
pause
Before I ran this file, I compiled Soap.java in my IDE and then ran it successfully. Then I moved the .class file to the directory C:\acorn. I put NOTHING ELSE in this folder. then I told the computer where to find the file 'java.exe' which I know is needed for execution of the .class file. I put the above text in Notepad and then saved it as Soap.bat onto my desktop. When I double click on it, the command prompt comes up in a little green box for a few seconds, and then the GUI opens and says "It Works!". Now that I know the concept of batch files, I tried creating another one that used the BreezySwing package.
After I installed my JDK, I installed BreezySwing and TerminalIO which are two foreign packages that make building code much easier. I downloaded the .zip file from Lambert and Osborne called BreezySwingAndTerminalIO.zip. I extracted the files to the 'bin' folder of my JDK. Once I did this, and set the PATH environment variable to the 'bin' folder of my JDK, all BreezySwing and TerminalIO programs that I made worked. Now I wanted to make a batch file from the program AddFields.java. It is a GUI program that imports two packages, the traditional GUI javax.swing package and the foreign package BreezySwing. The user enters two numbers in two DoubleField objects and then selects one of four buttons; one for each arithmetic operation (add, subtract, multiply, or divide). Then the program displays the solution in a third DoubleField object. This program both compiles and runs successfully in JCreator. So, next I moved the .class file from the MyProjects folder that JCreator uses to C:\acorn. I put nothing else in this folder. The file Soap.class was still in there, but I did not think it would matter. Then I created the batch file:
@echo off
cd \acorn
set path=C:\Program Files\Java\jdk1.6.0_07\bin
set classpath=.
java AddFields
pause
As you can see, it is exactly the same as the one for Soap. I made this file in Notepad and called it AddFields.bat. Upon double clicking on the file, I got this error message from command prompt:
Exception in thread "main" java.lang.NoClassDefFoundError: BreezySwing/GBFrame
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClass(ClassLoader.java:620)
at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:12
4)
at java.net.URLClassLoader.defineClass(URLClassLoader.java:260)
at java.net.URLClassLoader.access$000(URLClassLoader.java:56)
at java.net.URLClassLoader$1.run(URLClassLoader.java:195)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:188)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:276)
at java.lang.ClassLoader.loadClass(ClassLoader.java:251)
at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:319)
Caused by: java.lang.ClassNotFoundException: BreezySwing.GBFrame
at java.net.URLClassLoader$1.run(URLClassLoader.java:200)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:188)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:276)
at java.lang.ClassLoader.loadClass(ClassLoader.java:251)
at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:319)
... 12 more
Press any key to continue . . .
I know that most of this makes no sense; but that it only means that it cannot find the class BreezySwing or GBFrame (which AddFields extends). Notice, however that it does not give an error for javax.swing. If I change the "set path..." command to anything other than the 'bin' folder of my JDK, I get this error:
'java' is not recognized as an internal or external command,
operable program or batch file.
Press any key to continue . . .
I know this means that the computer cannot find the file 'java.exe' which I believe holds all of the java.x.y.z style packages (native packages); but not BreezySwing or any other foreign packages. Remember, I do not get this error for any of the native Java packages. I decided to compare the java.x.y.z packages with BreezySwing:
I see that all of the native packages are not actually visible in the JDK's bin folder. I think that they are all stored in one of the .exe files in there because there are no .class files in the JDK's bin folder.
However, BreezySwing is different, there is no such file called "BreezySwing.exe"; there are just about 20 .class files all with names like "GBFrame.class", and "GBActionListener.class". As a last effort, I moved all of these .class files directly into the bin folder (they were originally in a seperate folder called BreezySwingAndTerminalIO). This did nothing; even with all of the files in the same folder as java.exe.
So my question is: What do I need to do to get the BreezySwing package recognized on my computer? Is there possibly a download for a file called "BreezySwing.exe" somewhere that would be similar to "java.exe" and contain all of the BreezySwing packages?

There is a lot of detail in your posts. I won't properly quote everything you put (too laborious). Instead I'll just put your words inside quotes (").
"..there are some things about the interface that I do not like."
Like +what?+ This is not a help desk, and I would appreciate you participating in this discussion by providing details of what it is about the 'interface' of webstart that you 'do not like'. They are probably misunderstandings on your part.
"Some of the .jar files I made were so dangerously corrupt, that I had to restart my computer before I could delete them."
Corrupt?! I have never once had the Java tools produce a corrupt Jar. OTOH, the 'cannot delete' problem might relate to the JRE gaining a file lock on the archive at run-time. If the file lock persisted after ending the app., it suggests that the JRE was not properly shut down. This is a bug in the code and should be fixed. Deploying as .class files will only 'hide' the problem (from casual inspection - though the Task Manager should show the orphaned 'java' process).
"I then turned to batch files for their simple structure and portability (I managed to successfully transport a java.util containing batch file from my computer to another). This was what I did:
- I created a folder called Task
- Then I copied three things into this folder: 1. The file "java.exe" from my JDK. 2. The program's .class file (Count.class). and 3. The original batch file.
- Then I moved the folder from a removable disk to the second computer's C drive (C:\Task).
- Last, I changed the code in the batch file...:"
That is the +funniest+ thing I've heard on the forums in the last 72 hours. You say that is easy?! Some points.
- editing batch files is not scalable to 100+ machines, let alone 10000+.
- The fact that Java worked on the target machine was because it was +already installed.+ Dragging the 'java.exe' onto a Windows PC which has no Java will not magically make it 'Java enabled'.
And speaking of Java on the client machine. Webstart has in-built mechanisms to ensure that the end user has the minimum required Java version to run the app. - we can also use the [deployJava.js|http://java.sun.com/javase/6/docs/technotes/guides/jweb/deployment_advice.html#deplToolkit] on the original web page, to check for minimum Java before it puts the link to download/install the app. - if the user does not have the required Java, the script should guide them through installing it.
Those nice features in deployJava.js are available to applets and apps. launched using webstart, but they are not available for (plain) Jar's or loose class files. So if 'ensuring the user has Java' is one of the requirements for your launch, you are barking up the wrong tree by deploying loose class files.
Note also that if you abandon webstart, but have your app. set up to work from a Jar, the installation process would be similar to above (though it would not need a .bat file, or editing it). This basic strategy is one way that I provide [Appleteer (as a downloadable ZIP archive)|http://pscode.org/appleteer/#download]. Though I side-step your part 1 by putting the stuff into a Jar with the path Appleteer/ - when the user expands the ZIP, the parts of the app. are already in the Appleteer directory.
Appleteer is also provided as a webstart launched application (and as an applet). Either of those are 'easier' to use than the downloadable ZIP, but I thought I would provide it in case the end user wants to save it to disk and transport the app. to a machine with no internet connection, but with Java (why they would be testing applets on a PC with no internet connection, I am not sure - but the option is there).
"I know that .jar and .exe files are out because I always get errors and I do not like their interfaces. "
What on earth are you talking about? Once the app. is on-screen, the end user would not be able to distinguish between
1) A Jar launched using a manifest.
2) A Jar launched using webstart.
3) Loose class files.
Your fixation on .bat files sounds much like the adage that 'If the only tool you have is a hammer, every job starts to look like a nail'.
Get over them, will you? +Using .bat files is not a practical way to provide a Java app. to the end user+ (and launching an app. from a .bat looks quite crappy and 'second hand' to +this+ user).
Edit 1:
The instructions for running Appleteer as a Jar are further up the page, in the [Running Appleteer: Application|http://pscode.org/appleteer/#application] section.
Edited by: AndrewThompson64 on May 19, 2009 12:06 PM

How to compile and register a Java CFX tag with multiple class files?

All-
If this is the wrong forum for CFX questions, please let me
know.
I need to determine how to compile and register a Java CFX
tag that contains multiple class files. One class file implements
the CustomTag interface and the other class files implement various
supporting classes. All of the documentation that I have found
talks about using a single class file. I am assuming that a JAR
file will be involved, but I am not sure of the specifics.
Thanks in advance for your help.
-Josh

Yes, it will involve a jar. Use your java IDE (eclipse,
etcetera ..) to create a jar containing all of the classes. Check
your ide's documentation for how to create jar files. After you
have created the jar, place the jar in the CF class path so CF will
recognize it. For example the {cf_root}/WEB-INF/lib directory. CF
must be restarted before it will detect the new jar. After
restarting CF, register the CFX tag in the ColdFusion Administrator
using the name of the class that implements the CustomTag
interface.
Though it is worth noting you can also instantiate java
classes directly from ColdFusion (ie without using a CFX
tag).

How can i run a java class file from shell?

Hi all,
I've a .class file named "File" that contains Main method, it is in the package "File2".
How can I run it by shell command?
PS: "java -cp . file" doesn't work it launch->
Exception in thread "main" java.lang.NoClassDefFoundError: File2/File (wrong name: File2/File)
Thanks in advance.

Just to understand: is File2 ar jar archive or not? If it is a jar archive, have you tried open File2.jar? If File2 is a directory within the current directory, have you tried java -cp . File2/File? I just tested with a set of classes and it works... Let me be precise:
* Let us imagine you are working in a directory whole path is PathToDir/
* in this directory you have the classes put in a directory called File2
* in order to launch File.class then you would have to invoke :
cd PathToDir/ (just to be sure)
java -cp . File2/File
*if you were to do the following then you would have the problem you describe
cd PathToDir/File2/
java -cp . File

How to access a class file outside the package?

created a two java files Counter.java and TestCounter.java as shown below:
public class Counter
     public void print()
          System.out.println("counter");
package foo;
public class TestCounter
     public static void main(String args[])
          Counter c = new Counter();
          c.print();
Both these files are stored under "D:\Test". I first compiled Counter.java and got Counter.class which resides in folder "D:\Test"
when i compile TestCounter.java i got the following error message:
D:\Test>javac -classpath "d:\Test" -d "d:\Test" TestCounter.java
TestCounter.java:6: cannot find symbol
symbol : class Counter
location: class foo.TestCounter
Counter c = new Counter();
^
TestCounter.java:6: cannot find symbol
symbol : class Counter
location: class foo.TestCounter
Counter c = new Counter();
^
2 errors
what could be the problem. Is it possible to access a class file outside the package?

ya that's fine..if we have two java files where both resides in the same package works fine or two java files which donot have a package statement also works fine. But my doubt is, i have a Counter.class which does not reside in a package and i have a TestCounter.class which resides in a package "foo", in such a scenario, how do i tell to the compiler that "Counter.class resides in such a path, please look at that and give me TestCounter.class". i cannot use import statement to import Counter.class in TestCounter.java because i donot have a package for Counter.java.

Path to class file

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