PHP: automatically replace alphanumeric characters in a string

Quick question:
How do I program a PHP script to replace all non-alphanumeric
charters within a string, with underscores?

.oO(AngryCloud)
>Yes, this does help, although it is only alphabetic.
>
>Will changing the line to this make it alphanumeric?:
>
>$new_string = preg_replace("/[^a-zA-Z0-9]/", "_",
$string);
Did you try it? ;-)
You could also use this shorter pattern:
/[^a-z\d]/i
Should be the same (\d matches decimals and the /i modifier
makes the
entire thing case-insensitive).
Micha

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Need help in replacing special characters in a string

Hi,
please let me know the best way to replace all the special characters in a string with space.
other than alphabets and numbers
with regards.
sumanth.

please let me know the best way to replace all the special characters in a string with space.
other than alphabets and numbers
>
Sumanth Nag Kristam wrote:
> actually i need to replace hexa decimal char 0X1A in a string.... that is 'substitue' as per the chart
> any pointers....
>
> chk the link for the ASCII codes
> http://www.techonthenet.com/ascii/chart.php
But in Hexa decimal value there is no special characters?

Replace multiple characters in a string

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Will

replace(replace(replace(replace(x,'ô','ō'),'û','ū'),'Ô','Ö'),'Û','Ü');
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Replacing Unicode characters in a String

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:-) Interesting - twice in 10 minutes I'm recommending the use of Elliott Hughes' class. See http://elliotth.blogspot.com/2004/07/java-implementation-of-rubys-gsub.html .
You just have to write a regular expression to match the terms ( "&#(\\\d+)"), extract the number as a string (group(1)) then use the Integer.parseInt(the numeric string) and cast to a char.
Edited by: sabre150 on Feb 9, 2012 9:53 AM
This is an example I wrote a couple of years ago (and published on the old Sun site forums) that does pretty much exactly what you need
import e.util.Rewriter;
public class Sabre20090919
    public static void main(String[] args) throws Exception
        String title = "& #26412;& #26399;& #28136;& #21033;\n" +
                "& #22522;& #26412;& #27599;& #32929;& #30408;& #39192;\n" +
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                "& #26222;& #36890;& #32929;& #27599;& #32929;& #30408;& #39192;\n" +
                "& #31232;& #37323;& #27599;& #32929;& #30408;& #39192;\n";
        Rewriter rewriter = new Rewriter("&\\s*#(\\d+);")
            @Override
            public String replacement()
                return Character.toString((char) Integer.parseInt(group(1)));
        title = rewriter.rewrite(title);
        System.out.println(title);
        System.out.print("Unicode :\"");
        for (char ch : title.toCharArray())
            System.out.printf("\\u%04x", (int) ch);
        System.out.println("\"");
        byte[] asBytes = title.getBytes("big5");
        for (byte b : asBytes)
            System.out.printf("%02x ", (int) (b & 0xff));
        System.out.println();
}The rest is just a test harness.
Edited by: sabre150 on Feb 9, 2012 10:02 AM
Removed redundant code

How to replace escape characters in a string ?

Hi All,
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public class StringSearchAndReplace {
public static void main(String args[])   {
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    String newStmt = stmt.replaceAll("\\bullet\\tab", "B");
    System.out.println("BEFORE: " + stmt + "\n");
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}Here I want to replace "\\bullet\\tab" with "B". I am unable to move further. Please help/suggest me in this regard.
Its urgent.
Thanks in advance.

Satyaprasad_Mylavarapu wrote:
Hi All,
In my application I came across a problem where I want to replace a substring (contains escape characters also) with another string. The below shown code will replicate my problem :
public class StringSearchAndReplace {
public static void main(String args[])   {
String stmt = " \\pntext\\bullet\\tab The question as to ";
String newStmt = stmt.replaceAll("\\bullet\\tab", "B");
System.out.println("BEFORE: " + stmt + "\n");
System.out.println("AFTER: " + newStmt);
}Here I want to replace "\\bullet\\tab" with "B". I am unable to move further. Please help/suggest me in this regard.
Its urgent.
Thanks in advance.If the String you're trying to replace contains a slash you need four slashes (double it for java, then again because String.replaceAll takes a regular expression)
So I think what you're looking for is:
String newStmt = stmt.replaceAll("\\\\bullet\\\\tab", "B");I haven't tested that though.

Replace Special Characters in a string + XQUERY

Hi All,
I am using the following replace function to replace the special characters in my XQUERY.
*replace($string1, '[&"-*;-`!|:,¿/{}@#$%^*~()_+-]', ' ')*
Fortunately it is replacing all the special characters. But the only problem here is it is even replacing capitol letters in to spaces, which I don't want.
Please help me out!!

Hi
<<< What did u change >?> I dont see any change with the Regex ? >>
if you observe in the modified function, he just removed (*) inside the replace funtion.
Thanks
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A clever way of replacing some characters in a string

I have a string passed between methods in classes. Due to a face that I don't have all data ready when the string is constructed at the first place. I need to a few of sections in the string before I can use it. I am wondering any clever way to carry out this task.
Here is a sample of such string:
<web site name>/book.html?bookid=<book id data + series data>&language=<language data>
where <web site name> <series data> from the first method and <book id data> and <language data> from the second method.

One way would be to pass a String array that contains the sections that need to have other pieces inserted between them:
[ "/book.html?bookid=" , "&language=" ]That's not a very flexible solution though, a better way would be to pass a Map<String, String> around, which holds the bookid, language, etc. Strings as keys, and lets the other methods map them to <book id data + series data>, <language data>, etc. values. Then when they're all populated, construct the final url from those values.
That way if the params of the string change, it's easier to change the methods that populate the values.

Replace characters in a string

Hi,
I need to replace all occurrences of control characters except space,newline,tabs in a string . I can give a replace statement for each of these characters but I want to avoid this by making use of regular expressions. Can anyone help me in this regard.
I tried using the following replace statements with regular expression, but i am not getting the required results:
replace all occurrences of REGEX '[[:cntrl:]]' in lv_char with space replacement count lv_count_r.
---> this replaces even the spaces
replace all occurrences of REGEX '[[:cntrl:]][^[:space:]]' in lv_char with space replacement count lv_count_r.
--> this replaced even some alpha numeric characters
Thanks and Regards,
Shankar

is there anyway to do this without using regular
expressions.. regular expressions are the last
solution for me..Remember that you can never really replace the characters of a String. Strings are immutable. Once created they cannot change.

Replace multiple characters to single character

Hi friends,
I would like to replace multiple characters in a string to a single character. The character may be a pipe (|) or a tilde (~).
For example "|||asdf||123|xyz||" should be changed to "asdf|123|xyz".
I use Oracle 11g2.
Thanks in advance!

Without regexp
with testdata as (
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    select 'asdf|123|||||||xyz||||' from dual union all
    select '||||||asdf|||123||||||xyz||||||' from dual
select
trim (both '|' from
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        replace (
            replace (str,'|','|'||chr(0))
            ,chr(0)||'|'
        ,chr(0)
) str
from testdata
STR
"asdf|123|xyz"
"asdf|123|xyz"
"asdf|123|xyz"
with regexp
with testdata as (
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    select 'asdf|123|||||||xyz||||' from dual union all
    select '||||||asdf|||123||||||xyz||||||' from dual
select
trim (both '|' from
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        str
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        ,'|'
) str
from testdata
STR
"asdf|123|xyz"
"asdf|123|xyz"
"asdf|123|xyz"
Message was edited by: chris227 regexp added

RegEx in TSQL - replace non-alphanumeric characters etc

Hi guys, I have this function in VB that I used in Access to replace all non-alphanumeric characters, including spaces and anything in brackets.
Public Function charactersonly(inputString As String) As String
Dim RE As Object
Set RE = CreateObject("vbscript.regexp")
RE.Pattern = "$[^)]+$|[^\w]|_"
RE.Global = True
charactersonly = RE.Replace(inputString, "")
Set RE = Nothing
End Function
Now, I moved to SQL server and I'm writing scripts to do same thing.
How can I use RegEx in TSQL?
Only thing I will do is that function.

As alternative
declare @string varchar(200)
set @string = 'gg$%^^&is%^& s2342jjk23&&({}e c76l232e+_+a#n/ c][#o''y#e'
select cast(cast((select substring(@string,n,1)
from numbers
where n <= len(@string)
and substring(@string,n,1) like '[0-9 ]' for xml path('')) as xml)as varchar(max))
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
MS SQL Consulting:
Large scale of database and data cleansing
Remote DBA Services:
Improves MS SQL Database Performance
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Business Intelligence

How to replace special characters in string.

Hello,
I want to replace special characters such as , or ; with any other character or " ".I find out there is no such function is java for this.There is only replace() but it accepts only chars.If anybody know how to do this?.
Thanks,

Hello,
I want to replace special characters such as , or ;
with any other character or " ".I find out there is no
such function is java for this.There is only replace()
but it accepts only chars.If anybody know how to do
this?.
Thanks,Can't you just do the following?
public class Test
     public static void main(String[] args)
     String testString = "Hi, there?";
     System.out.println(testString.replace(',',' '));
}

Problem in replacing characters of a string ?

Hello everybody,
I want to replace a few characters with their corresponding unicode codepoint values.
I have a userdefined method that gets the unicode codepoint value for a character.
1. I want to know how to replace the characters and have the replaced string after the comparision is over in the for loop in my main.
Currently , i am able to replace , but i am not able to have the replacements done in a single variable.
The output of the code is
e\u3006ame
ena\u3005e
But i want the output i require is,
e\u3006a\u3005e
Please offer some help in this regard
import java.io.*;
class Read1
     public static void main(String s[])
         String rp,snd;
         String tmp="ename";
         for(int i=0;i<tmp.length();i++)
             snd=getCodepoint(tmp.charAt(i));
             if(snd!=null)
                rp=replace(tmp,String.valueOf(tmp.charAt(i)),"\\u"+snd);
                System.out.println(rp);
public static String replace(String source, String pattern, String replace)
     if (source!=null)
         final int len = pattern.length();
         StringBuffer sb = new StringBuffer();
         int found = -1;
         int start = 0;
         while( (found = source.indexOf(pattern, start) ) != -1)
             sb.append(source.substring(start, found));
             sb.append(replace);
             start = found + len;
         sb.append(source.substring(start));
         return sb.toString();
     else return "";
...,Any help in this regard would be useful
Thanks
khurram

This manual replacement thingy reminds me of quite an old technique, when
64KB of memory was considered enough for 20 users (at the same time that is!)
Suppose you have a buffer of, say, n characters. Starting at location i, a region
of chars have to be swapped with bytes starting at location j >= i+l_i; the lengths
of the two regions are l_i and l_j respectively.
Suppose the following method is available:public void reverse(char[] buffer, int f, int l_f) {
   for (int t= f+l_f; --t > f; f++) {
      char tmp=buffer[f]; buffer[f]= buffer[t]; buffer[t]= tmp;
}i.e. the above method reverses a region of characters, starting at position f
with length l_f. Given this simple method, the original problem can be solved
using the following simple sequence:reverse(buffer, i, j+l_j);
reverse(buffer, i, l_j);
reverse(buffer, i+l_j, j-i-l_i);
reverse(buffer, j+l_j-l_i, l_i);Of course, when replacing characters we don't need the last reversal.
kind regards,
Jos (dinosaurus)

Produce random alphanumeric characters: dukes available

Time for another duke giveaway
On Saturday 6th March, approx 8.00PM (GMT) the following program will be run;-
CodeMaker.javapublic class CodeMaker{
   public static void main(String []params){
      StringBuffer sb = new StringBuffer();
      java.util.Random r = new java.util.Random();
      for(char c='A'; c<='Z'; c++) sb.append(c);
      for(char c='a'; c<='z'; c++) sb.append(c);
      for(int i=0; i<=10; i++) sb.append(i);
      for(int i=0; i<8; i++) System.out.print(sb.charAt(r.nextInt(sb.length()) ) );
ALL ARE WELCOME TO GUESS THE OUTCOME OF THIS PROGRAM AND EARN FREE DUKES!
- simply add to this thread with your guess of the 8 alphanumeric characters.
- the more characters you guess right the more you earn.
- only one guess permitted per contestant (schizoids such as the Scarlet Pimpernel excl.)
- any other rules may or may not be made by me at any time (after all it is my game so ner-ner-nee-ner-ner)
- that's all I can think of for the moment, good luck t'y'all.
The points system awarded will be determined by the following program;-
CodeScorer.javapublic class CodeScorer{
   public static void main(String []params){
      String luckyDukeWinner = params[0];
      String codeToCrack = params[1];
      String luckyDukeWinnerGuess = params[2];
      new CodeScorer(luckyDukeWinner, codeToCrack, luckyDukeWinnerGuess);
   private CodeScorer(String name, String code, String guess){
      int same = calcSame(code, guess, 0);
      int correct = calcCorrect(code, guess, 0);
      System.out.println("Number of letters correct = "+same);
      System.out.println("Number of letters exactly correct = "+correct);
      System.out.println("Dukes earned by "+name+": "+calcScore(same, correct));
   private int calcCorrect(String code, String guess, int tally){
      for (int i=0; i< code.length(); i++)
         if(guess.charAt(i) == code.charAt(i)) tally++;
      return tally;
   private int calcSame(String code, String guess, int tally){
      StringBuffer buf = new StringBuffer(code);
      for (int i=0; i< buf.length(); i++){
         for (int j=0; j< buf.length(); j++)
            if (guess.charAt(i) == buf.charAt(j)){
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   private int calcScore(int same, int correct){
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}

I thought this
for(int i=0; i<=10; i++) sb.append(i);
would do this
for(int i=0; i<=10; i++) sb.append((char)i);
I'm so humilitated....All punters may assume henceforth that line 7 char 22 is herewith removed (I'm humiliated too)

PHP: automatically replace alphanumeric characters in a string

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