Regular expressions-how to replace [ and ] characters from a string

Hi,
my input String is "sdf938 [98033]". Now from this given string, i would like to replace the characters occurring within square brackets to empty string, including the square brackets too.
my output String needs to be "sdf938" in this case.. How should I do it using regular expressions? I tried several possible combinations but didn't get the expected results.

"\\s*\\[[^\\]]+\\]"

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How to replace escape characters in a string ?

Hi All,
In my application I came across a problem where I want to replace a substring (contains escape characters also) with another string. The below shown code will replicate my problem :
public class StringSearchAndReplace {
public static void main(String args[])   {
    String stmt = " \\pntext\\bullet\\tab The question as to ";
    String newStmt = stmt.replaceAll("\\bullet\\tab", "B");
    System.out.println("BEFORE: " + stmt + "\n");
    System.out.println("AFTER: " + newStmt);
}Here I want to replace "\\bullet\\tab" with "B". I am unable to move further. Please help/suggest me in this regard.
Its urgent.
Thanks in advance.

Satyaprasad_Mylavarapu wrote:
Hi All,
In my application I came across a problem where I want to replace a substring (contains escape characters also) with another string. The below shown code will replicate my problem :
public class StringSearchAndReplace {
public static void main(String args[])   {
String stmt = " \\pntext\\bullet\\tab The question as to ";
String newStmt = stmt.replaceAll("\\bullet\\tab", "B");
System.out.println("BEFORE: " + stmt + "\n");
System.out.println("AFTER: " + newStmt);
}Here I want to replace "\\bullet\\tab" with "B". I am unable to move further. Please help/suggest me in this regard.
Its urgent.
Thanks in advance.If the String you're trying to replace contains a slash you need four slashes (double it for java, then again because String.replaceAll takes a regular expression)
So I think what you're looking for is:
String newStmt = stmt.replaceAll("\\\\bullet\\\\tab", "B");I haven't tested that though.

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How to replace NULL values from main table

Dear all,
I like to remove the NULL values from a main table field. Or the question is how to replace any part of the string field in MDM repository main table field.
e.g. I have a middle name field partly the value is NULL in some hundreds of records, I like to replace NULL values with Space
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How can I remove all non-alpha-numeric characters from a string? (i.e. only alpha-numerics should remain in the string).

Or even without a loop ?
Extract from the help for the Search and Replace String function :
Right-click the Search and Replace String function and select Regular Expression from the shortcut menu to configure the function for advanced regular expression searches and partial match substitution in the replacement string.
Extract from the for the advanced search options :
[a-zA-Z0-9] matches any lowercase or uppercase letter or any digit. You also can use a character class to match any character not in a given set by adding a caret (^) to the beginning of the class. For example [^a-zA-Z0-9] matches any character that is not a lowercase or uppercase letter and also not a digit.
Message Edité par JB le 05-06-2008 01:49 PM
Attachments:
Example_VI_BD4.png ‏2 KB

Removing characters from a String (concats, substrings, etc)

This has got me pretty stumped.
I'm creating a class which takes in a string and then returns the string without vowels and without even numbers. Vowels and even characters are considered "invalid." As an example:
Input: "hello 123"
Output: "hll 13"
The output is the "valid" form of the string.
Within my class, I have various methods set up, one of which determines if a particular character is "valid" or not, and it is working fine. My problem is that I can't figure out how to essentially "erase" the invalid characters from the string. I have been trying to work with substrings and the concat method, but I can't seem to get it to do what I want. I either get an OutOfBoundsException throw, or I get a cut-up string that just isn't quite right. One time I got the method to work with "hello" (it returned "hll") but when I modified the string the method stopped working again.
Here's what I have at the moment. It doesn't work properly for all strings, but it should give you an idea of where i'm going with it.
public String getValidString(){
 String valid = str;
 int start = 0;
 for(int i=0; i<=valid.length()-1; i++){
 if(isValid(valid.charAt(i))==false){
 String sub1 = valid.substring(start, i);
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 i++;
 start=i;
 String sub2 = valid.substring(i, valid.length()-1);
 valid = sub1.concat(sub2);
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 }So does anybody have any advice for me or know how I can get this to work?
Thanks a lot.

Thansk for the suggestions so far, but i'm not sure how to implement some of them into my program. I probably wasn't specific enough about what all I have.
I have two classes. One is NoVowelNoEven which contains the code for handling the string. The other is simply a test class, which has my main() method, used for running the program.
Here's my class and what's involved:
public class NoVowelNoEven {
//data fields
 private String str;
//constructors
 NoVowelNoEven(){
 str="hello";
 NoVowelNoEven(String string){
 str=string;
//methods
 public String getOriginal(){
 return str;
 public String getValidString(){
 String valid = str;
 int start = 0;
 for(int i=0; i<=valid.length()-1; i++){
 if(isValid(valid.charAt(i))==false){
 String sub1 = valid.substring(start, i);
 while(isValid(valid.charAt(i))==false)
 i++;
 start=i;
 String sub2 = valid.substring(i, valid.length()-1);
 valid = sub1.concat(sub2);
 return valid;
 public static int countValidChar(String string){
 int valid=string.length();
 for(int i=0; i<=string.length()-1; i++){
 if(isNumber(string.charAt(i))==false){
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 valid--;}
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 valid--;
 return valid;
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 boolean even=false;
 int test=(int)num-48;
 if(test%2==0)
 even=true;
 return even;
 private static boolean isNumber(char chara){
 boolean number=false;
 for(int i=0; i<=9; i++){
 if((int)chara-48==i){
 number=true;
 return number;
 private static boolean isValid(char chara){
 boolean valid=true;
 if(isNumber(chara)==true){
 if(even(chara)==true)
 valid=false;
 if((upperVowel(chara)==true)||(lowerVowel(chara)==true))
 valid=false;
 return valid;
}So in my test class i'd have something like this:
public class test {
public static void main(String[] args){
 NoVowelNoEven test1 = new NoVowelNoEven();
 NoVowelNoEven test2 = new NoVowelNoEven("hello 123");
 System.out.println(test1.getOriginal());
 //This prints hello (default constructor string is "hello")
 System.out.println(test1.countValidChar(test1.getOriginal()));
 //This prints 3
 System.out.println(test1.getValidString());
 //This SHOULD print hll
}

Removing non english characters from my string input source

Guys,
I have problem where I need to remove all non english (Latin) characters from a string, what should be the right API to do this?
One I'm using right now is:
s.replaceAll("[^\\x00-\\x7F]", "");//s is a string having chinese characters.
I'm looking for a standard Solution for such problems, where we deal with multiple lingual characters.
TIA
Nitin

Nitin_tiwari wrote:
I have a string which has Chinese as well as Japanese characters, and I only want to remove only Chinese characters.
What's the best way to go about it?Oh, I see!
Well, the problem here is that Strings don't have any information on the language. What you can get out of a String (provided you have the necessary data from the Unicode standard) is the script that is used.
A script can be used for multiple languages (for example English and German use mostly the same script, even if there are a few characters that are only used in German).
A language can use multiple scripts (for example Japanese uses Kanji, Hiragana and Katakana).
And if I remember correctly, then Japanese and Chinese texts share some characters on the Unicode plane (I might be wrong, 'though, since I speak/write neither of those languages).
These two facts make these kinds of detections hard to do. In some cases they are easy (separating latin-script texts from anything else) in others it may be much tougher or even impossible (Chinese/Japanese).

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i.e) I have to replace '=' with ' '.
I have already tried with REPLACE ALL OCCURRENCES OF '=' IN temp_fill_string WITH ' '
Its not working.

Hi,
Try with this..
call method textedit- >replace_all
exporting
 case_sensitive_mode = case_sensitive_mode
 replace_string = replace_string
 search_string = search_string
 whole_word_mode = whole_word_mode
changing
 counter = counter
exceptions
 error_cntl_call_method = 1
 invalid_parameter = 2.
Parameters Description Possible values
case_sensitive_mode Upper-/lowercase false Do not observe (default value)
 true Observe
replace_string Text to replace the
 occurrences of
 SEARCH_STRING
search_string Text to be replaced
whole_word_mode Only replace whole words false Find whole words and
parts of words (default
value)
 true Only find whole words
counter Return value specifying how
 many times the search string
 was replaced
Regards,
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fais,
Please create the VI you are talking about and save some default data into all of the controls. Also on the front panel, place the session ID that should be generated by that data. Now, post your VI to a response so I can download it. I can then take this VI and help you create the functionality. (Please post what version of LabVIEW you are using.)
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Dear friends,
I am handling sql injection attack to our application with java regular expression. I used it to match that if there are malicious characters or key words injected into the parameter value.
The denied characters and key words can be " ' ", " ; ", "insert", "delete" and so on. The expression I write is String pattern_str="('|;|insert|delete)+".
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Edited by: Ricky Ru on 28/04/2011 02:29

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Regular expressions-how to replace [ and ] characters from a string

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