PHP Help with inherited database site
Hope someone can help with this, although I might be a bit vague. (But will be happy to post any code that might help.)
Basically I do a few sites for a company, and everything is coming together nicely moving everything to a new reseller hosting account where everything can site. I'm basically doing some redesign and new database work for them.
But there's one site I'm basically just trying to move over, that already has a database. I've copied the site onto the new hosting, copied the database across and created a new connection file.
I must admit the code is all a bit more PHPO heavy than what I'm used to working with. so have run into a problem trying to figure out what data is not displaying due to queries failing. As far as I can tell the connection is working, and the queries have not changed.
Anyway - the main page is here, where you should be able to click on the furniture images to go to the product page :
http://www.miradatravelmedia.com/lusty/public_html/index.php
But when you click through the product page query is failing :
http://www.miradatravelmedia.com/lusty/public_html/products.php?category=1
The products page is mostly PHP and looks like this :
[PHP]<?php
if (!@empty($_REQUEST["img"])) {
require_once("../includes/hft_image.php");
$img = new hft_image($_REQUEST["img"]);
$img->resize(200,180,"-");
$img->output_resized("");
exit;
$page = "products";
include("../includes/header.php");
include("../includes/db_open.php");
$sql = "SELECT `id`, `name` FROM `categories` WHERE `id` = '" . $_REQUEST["category"] . "'";
$result = mysql_query($sql) or die("Query failed : $sql at line " . __line__);
$category = mysql_fetch_assoc($result);
?>
<div id="trail"><a href="shop.php">Shop</a> > Lloyd Loom <?php echo $category["name"]?></div>
<div class="clear" id="divider1"><img src="images/spacer.gif" alt="<?php echo keyword()?>" /></div>
<h1>Lloyd Loom <?php echo $category["name"]?></h1>
<?php
$sql =
"SELECT * " .
"FROM `products` " .
"WHERE `category` = '" . $_REQUEST["category"] . "' " .
"ORDER BY `order`";
$result = mysql_query($sql) or die("Query failed : $sql at line " . __line__);
if (mysql_num_rows($result) == 0) {
?>
<p>Coming soon ...</p>
<?php
} else {
$n = 0;
while ($row = mysql_fetch_assoc($result)) {
$n++;
?>
<a href="product.php?id=<?php echo $row["id"]?>" class="product"<?php if ($n == mysql_num_rows($result)) echo " id=\"last\""?>>
<?php
if ($file = glob("images/products/" . $row["id"] . "_*.*")) {
?>
<img src="img.php?img=<?php echo $file[0]?>&width=200&height=180" alt="<?php echo $row["code"]?>" />
<?php
} else {
?>
<div id="no_image">No image found</div>
<?php
?>
<?php echo $row["code"]?>
</a>
<?php
if (is_int($n / 4)) {
?>
<div class="clear"><img src="images/spacer.gif" alt="<?php echo keyword()?>" /></div>
<?php
?>
<div class="clear" id="divider2"><img src="images/spacer.gif" alt="<?php echo keyword()?>" /></div>
<?php
include("../includes/footer.php");
?>[/PHP]
If anyone could shed any light on what's going wrong still, that would be much appreciated.
Thanks.
Iain71 wrote:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''categories' WHERE 'id' = '1'' at line 1
So it does look a bit odd with the quotes.
Column names in a SQL query must not be in quotes. The MySQL error message tells you that the SQL syntax error is "near" the section it refers to. In other words, the error is just before that part of the query. Normally, you need to display the whole query to spot the error, but it's obvious in this particular case, because there's a quotation mark after categories, indicating that you've put the column name in quotes. Anyway, you've solved that problem by using the version I suggested.
I still haven't managed to establish where this vat.php file is - is there any explanation for it not being visible on the original hosting server where the site is working? And could it have anything to do with the query not working?
No, it has nothing to do with the query not working, and the reason you can't see it on the live site is because there's no error. The error message on your test site tells you exactly where to look for the problem. The file vat.php is included by header.php on line 19. Either vat.php isn't on your server, or the code on line 19 of header.php is pointing to the wrong location.
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display
immediately if they select "Yes."
2. It physically prints out: <?php if
(isset($_POST[\'currentdomain\']))
echo htmlentities($_POST[\'currentdomain\']);?> - as the
value of the
textfield instead of leaving it blank/printing the previously
entered text.
How can I fix these, guys? Thank you!
Shane H
[email protected]
http://www.avenuedesigners.com
=============================================
Proud GAWDS Member
http://www.gawds.org/showmember.php?memberid=1495
Delivering accessible websites to all ...
=============================================you can apply a show-hide layer behavior to the YES check box
(onClick="MM_ShowHideLayers...)
and have the inverse show;hide behavior applied toi the NO
checkbox.
Once you have a Layer on your page and have applied the
behavior, you change that Layer into a
regular div by the way, just leave the same id.
Then, for validating the question only if yes is selected:
<?php
if ($_POST['have_a_website'] == 'yes' &&
empty($_POST['question'])){
$error = TRUE;
?>
Shane H wrote:
> Hey everyone -
>
> I have a quote form on my website that I'd like to tweak
a bit. There are
> some fields that have a drop-down box of "Yes" or "No"
and directly after
> that it says, "If Yes, ..." So, no matter which option
is chosen, the user
> still sees that even if it doesn't apply to them - which
I'm OKAY with for
> the time being, but wish to implement it differently.
>
> If the user selects "Yes" - I'd like the the field that
says the question I
> *need* to ask the user if they choose "Yes." If they
select "No," than the
> box is never shown. Sounds simple enough, right? Right
>
> My concern is a). how to show this hide/don't hide
functionality, and b).
> how to validate (require) the box being "shown" if they
choose "Yes" and to
> NOT validate (require) if they choose "No."
>
> I'm going to upload a .html file to my server that has
the full code for my
> quote.php page in plain text, so someone can help me
implement this.
>
> Quote source code:
>
http://www.avenuedesigners.com/tests/quote_source.html
>
> I colored the big chunks of PHP code red, and the form
blue for ease.
>
> I've tried something like this:
>
> <?php
> if ($_POST['havewebsite'] == "Yes") {
> echo ('<p class="labelbold">If yes, What is the
Domain Name?</p>
> <input name="currentdomain" type="text"
class="contactfield2 inputstyled"
> id="currentdomain" value="<?php if
(isset($_POST[\'currentdomain\'])) echo
> htmlentities($_POST[\'currentdomain\']);?>"
tabindex="11" />');
> }
> ?>
>
> And run into two problems:
>
> 1. It only shows up when the page is submitted, and I'm
naturally assuming
> this is because of the $_POST being in there. I need it
to display
> immediately if they select "Yes."
>
> 2. It physically prints out: <?php if
(isset($_POST[\'currentdomain\']))
> echo htmlentities($_POST[\'currentdomain\']);?> - as
the value of the
> textfield instead of leaving it blank/printing the
previously entered text.
>
> How can I fix these, guys? Thank you!
>
seb ( [email protected])
http://webtrans1.com | high-end web
design
Downloads: Slide Show, Directory Browser, Mailing List
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