Pls query help hurry

Question

SELECT
TRANS_CAT_TYPE,
CUSTOMER_CODE,
CUSTOMER_NAME,
CUR_SHORT_NAME,
OWN_BRANCH_CODE,
TRANSMIT_LC_NO,
--CHARGE
DECODE(TRANS_CAT_TYPE,'1', CATEGORY_DESC) CHARGE_DESC ,
DECODE(TRANS_CAT_TYPE,'1', AMOUNT_CCY) CHARGE_AMOUNT_CCY,
DECODE(TRANS_CAT_TYPE,'1', AMOUNT_LCY) CHARGE_AMOUNT_LCY,
--COMMISSION
DECODE(TRANS_CAT_TYPE,'2', CATEGORY_DESC) COMM_DESC ,
DECODE(TRANS_CAT_TYPE,'2', AMOUNT_CCY) COMM_AMOUNT_CCY,
DECODE(TRANS_CAT_TYPE,'2', AMOUNT_LCY) COMM_AMOUNT_LCY,
--OTHERS
DECODE(SIGN(TRANS_CAT_TYPE-2),'1', CATEGORY_DESC) OTHER_DESC ,
DECODE(SIGN(TRANS_CAT_TYPE-2),'1', AMOUNT_CCY) OTHER_AMT_CCY ,
DECODE(SIGN(TRANS_CAT_TYPE-2),'1', AMOUNT_LCY) OTHER_AMT_LCY
FROM FE_VW_INCOME_ANALYSIS_LCOPEN
RESULT
LC_TRANMIT_NO CHARGE_DESC COMM_DESC
1 SWIFT 0
1 0 COMMITION
BUT I WANT
LC_TRANMIT_NO CHARGE_DESC COMM_DESC
1 SWIFT COMMITION

Answer 1

why does the column lc_no mean in the o/p?
without it:
SQL> with tab1 as (select 1 lc_no, 'swift' des from dual union all
  2                select 1, 'photograp' from dual union all
  3                select 1, 'handicap' from dual union all
  4                select 2, 'commission' from dual)
  5                --
  6                select max(decode(lc_no, 1, des, null)) for1,
  7                       max(decode(lc_no, 2, des, null)) for2
  8                  from (select t.*,
  9                               row_number() over(partition by lc_no order by des) rn
10                          from tab1 t) tt
11                 group by rn
12  /
FOR1       FOR2
handicap   commission
photograp 
swift      next time you can try to search, it was discussed many times in the forum.