Post increment problem. please help to solve it

Question

public class test {
public static void main(String args[])
     int i=10;
     i=i++;
     System.out.println(i); // value of i is 10 why
}

Answer 1

Mostafa.Hashem wrote:
Absofuckinglutely NOT !
1) Save current value of x. That is, 1. This is the value of the expression "x++".
2) Increment x. x is now 2. We have now completed x++
3) Assign value from step 1 into y.i wonder how small point like this takes all that time.
Mr Jverd,
the difference between prefix increment and the postfix increment is :
IN PREFIX INCREMENT THE ASSIGNMENT OF EXPRESSION DONE FIRST THEN THE INCREMENT.
IN POSTFIX INCREMENT THE INCREMENT DONE BEFORE THE ASSIGNMENT.Wrong.
++x and x++ are both expressions. They have a value and a side effect.
In pre-increment (++x) the increment is done before the expression is evaluated. The value of the expression is the new value of x.
In post-increment (x++) the increment is done after the expression is evaluated. The value of the epxression is the original value of x.
In both cases
y = ++x;
y = x++;
The right-hand side is evaulated completely before the assignment to y is done. In fact, in ALL java assignment statements, the RHS is evaluated completely before assigning anything to the LHS.
y = ++x;
is equivalent to
x +=1;
y = x;
y = x++;
is equivalent to
tmp = x;
x += 1;
y = tmp;