PPI/ LPI assignment.. I'm confused.

Pardon me, for I am new to Illustrator.
For my class assignment,
I must to put my art in the proper PPI vs. LPI size.
The documents are all suposed to be at 100 percent,
so that's not an issue.
However, it is Photoshop that I am accustomed to using
(Image Size) to input that kind of distinction.
(for ppi, etc.)
My assignment is for the file to be created in Illustrator,
placed in InDesign, and then printed, but with examples in various
line screen.. how should this be done?
The only reason I ask is because I am confused...I do not see that Illustrator or InDesign lets you change ppi settings,
(which would help me with determining what the linescreen vs. ppi is)
In Illustrator and InDesign, I only see that you can alter the crop, layout, or color gamut, instead. (which has to be CMYK)
Do I need to put my files in Photoshop for this?
Thank you!!

PPI refers only to raster images (your Photoshop images). There is no "PPI" per se for an InDesign or Illustrator *document*. An InDesign or Illustrator document can contain any number of raster images, each of which can have a different PPI.
For example: Place a 300ppi image in InDesign (or Illustrator) at 100%. Duplicate it. Scale it to 200%. Now your document contains two raster images, one at 300ppi, one at 150ppi. There is no document-level ppi that affects both images.
Now, depending upon whether you use certain features in the program, there may be *some* raster images in the document for which the ppi is determined by document-level settings. Those are raster images which the page program generates on-the-fly, for things like drop shadows and other raster effects. Those effects get "nailed down" to your pre-determined resolution when you print or export.
LPI only comes into play when you print. It is a printer setting. It determines how course or fine the array of halftone dots is when printed.
For acceptable output results, there is a practical balance between the ppi of the images on your page and the lpi at which it will be printed. Essentially, the higher the lpi, the higher ppi your images should be.
That's easiest to understand if you consider a single image pixel. If that pixel is so large that it will span across several halftone dots, then it is possible that the pattern of halftone dots will be able to suggest the square shape of the single pixel. That results in the blocky pixelated appearance when ppi is too low for the halftone ruling (lpi).
The general rule of thumb is: Adequate ppi is 1 to 2 times the intended lpi. Again, consider a single pixel. Halftone dots are generally round. If a particluar pixel has to be rendered by a single halftone dot, you are not going to be able to see the square shape of the pixel. (How can a single round dot accurately "render" a square?)
Disregarding other printing factors (dot gain, absorbancy of paper, etc.) a 1:1 ratio between ppi and lpi can look a little "dull" or "soft" when compared side-by-side to higher ratios. But this is also affected by whether the image was properly sharpened. And, there are some raster images for which that does not matter, the typical soft drop shadow being an example. As long as the shadow's pixels can't be individually discerned, why would you need a higher lpi/ppi ratio than 1:1? The subtle softness of 1:1 doesn't hurt a thing in the case of soft drop shadows. (It amuses me when users think that 300ppi is required for the Document Raster Effects Resolution, just because the file will be offset printed at 150 lpi.)
On the other hand, if the drop shadow overlays a photo, I set the shadow settings to the ppi of the photo.
1:2 builds in a little "wiggle room" in case you do any on-page transformations of the image. That is, you can do a little stretching or shrinking of the image and still stay between the 1:1 and 1:2 bounds. Because 150 lpi is a very common halftone ruling, you'll often hear it said that "all raster images should be 300ppi." That's largely ka-ka, but that's where it comes from.
In my experience, 1:1.5 is virtually indistinguishable from 1:2. But I sharpen my images before placing them, and do not do on-page transformations.
> My assignment is for the file to be created in Illustrator,
placed in InDesign, and then printed, but with examples in various
line screen.. how should this be done?
What will be the content of the Illustrator file? If the Illustrator file contains only a raster image, why would you be using Illustrator at all? Why would you not just place the raster image directly in InD? If the Illustrator contains vector artwork (what Illustrator is primarily for), then ppi is not an issue.
JET

Similar Messages

PPI/ LPI... now I'm really confused.

I posted this in the Illustrator forum too.. 'cause things are pretty down to the wire.
Pardon me, for I am new to Illustrator.
For my class assignment,
I must to put my art in the proper PPI vs. LPI size.
The documents are all suposed to be at 100 percent,
so that's not an issue.
However, it is Photoshop that I am accustomed to using
(Image Size) to input that kind of distinction.
(for ppi, etc.)
My assignment is for the file to be created in Illustrator,
placed in InDesign, and then printed, but with examples in various
line screen.. how should this be done?
The only reason I ask is because I am confused...I do not see that Illustrator or InDesign lets you change ppi settings,
(which would help me with determining what the linescreen vs. ppi is)
In Illustrator and InDesign, I only see that you can alter the crop, layout, or color gamut, instead. (which has to be CMYK)
Do I need to put my files in Photoshop for this?
Thank you!!

>The only reason I ask is because I am confused...I do not see that Illustrator or InDesign lets you change ppi settings,
You can't resample images inside ID. You can see an image's effective resolution by selecting it and looking in the Info panel. You do have the option to lower the effective resolution of placed images when you export to PDF.
LPI would be a function of the printer, so you would need to output separations to a Postscript printer that prints halftone screens, and set the LPI in the Output tab of the Print dialog.
Rob

Help with a Boolean/Satisfiability assignment

Hey everyone, first time posting here.
I have an assignment which im working on atm but im stuck and was wondering if anyone can give me a general direction to start on. The basic parts of the program are as follows:
1. Obtains the problem instance name from the command line
2. Reads the instance from a file
3. Displays the instance on the screen exactly as it appears in the file
4. Constructs an internal data structure representing the formula, using specified types
5. Displays the instance on the screen in "human readable" form
6. Determines if the instance has a solution (i.e. a satisfying assignment)
7. If there is a solution, displays the solution on the screen; (in "human readable" form); if there
is no solution, displays an appropriate message
8. Displays also how long it took to determine if there was a solution or not
9. Saves a report (roughly, the previous two items) to a file
I am currently stuck on part 6 of the assignment.
When you read in an instance for processing, you must represent it with and instance of
Formula. This object will have an instance variable that stores a collection of Proposition
instances, representing the variables, and an instance variable that stores a collection of Clause
instances, representing the clauses, as read from the file.
Each of these classes must have a method public String toString() that returns a string
representing its contents. These should be implemented so that, if F is a Formula instance,
executing System.out.print( F ) will print the "human readable" form of the formula as
described above.
What would be a good way of determing how the instance has a solution? I've considered using a truth table or even using binary but cant think of a way to do this properly.
Thanks all!

Input: myInstance
Number of Variables: 3
Variables:
we are in vancouver
it is summer
it is raining
Number of Clauses: 2
Clauses:
( NOT we are in vancouver OR it is summer OR it is raining )
( NOT we are in vancouver OR NOT it is summer OR NOT it is raining )
( !v | s | r ) & ( !v | !s | !r ) is the condition so I do have to use and
The satisfying assignments are:
v=true, s=true, r=false
v=true, s=false, r=true
v=false, s=true, r=true
v=false, s=true, r=false
v=false, s=false, r=true
v=false, s=false, r=false
This assignment is bloody confusing -_-

In Lightroom 4, is it possible to change the resolution when exporting to Facebook?

Is it possible to change the resolution when exporting a photo to Facebook using either the regular plugin or Jeffrey Friedl's plugin? I can't seem to do it; I only have control over the image dimensions, not the resolution and the dimensions, as you can see in the screen shots below:
I have control over both when I export to my hard drive (or a flash drive, etc.), as you can see below:
I can't find the option to control the resolution when I try to export to Facebook. Before I got Lightroom 4, I would create whole new low-resolution files of images I wanted to post online using Photoshop. The image size settings I would use are a longest edge of 10 inches at 72ppi, and I would like to continue doing this. If I can only set the longest side to 720 pixels (I can't even seem to set the longest edge to an inches value - I can only choose a pixels value) and not change the resolution from 300ppi to 72ppi, then my photos' longest edge will only be less than 3 inches long (right?). Thus, I really want to be able to upload low-resolution photos to Facebook via Lightroom with the ability to change both the resolution and the image dimensions. Any idea how to do it without having to export to my hard drive first? Thanks!

Rob Cole wrote:
I'd be inclined to set it to zero so it obviously doesn't mean anything
You can set it to whatever you like, and it makes no difference. Most of the time (depending on how you saved it), it will still open as "72".
When you save an image for web, the resolution is usually stripped from the file. It's simply not there anymore. That's probably what happens in the Lr facebook module, and that's why there's no entry for it.
But when you open that image somewhere else, that default of 72 ppi is assigned. Most apps need to know what to do with a file if asked to print it out. So there is a default, and that's usually 72, mostly by convention. With that default ppi, it prints out at a comparable size to what you see on screen at 1:1 display.
And when people see that, they think "hey, web images are 72 ppi". But they're not - that figure is just inserted there by the opening application.

Lightroom 3 and Photoshop CS6 problem when editing

Hi,
I have just upgraded to Photoshop CS6 and now when I 'edit in Photoshop CS6' from lightroom and save it, the image doesn't appear next to the original RAW file as it did before. Now lightroom creates its own folder with the edited files in.
For example, I edited a RAW file from a folder called Bissoe valley from Lightroom and saved it. When I go back to Lightroom the edited image is not next to the original file but in a seperate folder called 'Bissoe valley'. I then try to drag the edited image back into the original 'Bissoe valley folder with the original RAW file and it says 'the file already exists at the destination'
I appologise if this has already been asked. I'm guessing I need to buy Lightroom 4 because of incompatibility issues? It wouldn't surprise me if this is the case.
Thanks in advance for any help.

Victoria....you are a legend!
You can see here lightroom has created folders identically named to the folder which the original files belong to (coco, Harriet, Bissoe and independent assignment)
The really confusing part is that when I look in the original folder outside of Lightroom, the saved Tiff image is there next to the original.
I think I will try uninstalling ps cs6 and go back to cs5 to see if it solves the problem and take it from there....

How can I change how email "from" and "to" are being handled by Groupware?

When a follow-up business activity (e.g. sales visit) is created in CRM and assigned to another by the "person responsible" field, it triggers the following action in Outlook:
u2022 Outlook recognizes that "created by" and "person responsible" are different
u2022 This recognition triggers sending an email invitation for an appointment
u2022Groupware presents / Outllok reads the "person responsible" to populate "from" Email field and "created by" to populate "to" Email field
u2022Outlook Email invitation is received by creator of the assigned follow-up (confusing the user since they are naturally thinking that the person they made responsible for the follow-up would need to accept the assignment)
How can I change how the email "from" and "to" are being handled by Groupware/Outlook ... in standard functionality? ... In custom work?
Edited by: Daniel A. Joseph on Jul 24, 2008 4:00 PM

Welcome to the Apple Community.
If you have a @me.com address, you can change the address you use to send email from using the drop down box in the from field in your email.

FacesContext Issue what is wrong

hi i have this code using the FacesContext to talk inbetween my session bean and the page request bean basically this method is attached to a command button that will save an ID and then move to the next page with the "success" action
i find this kind of weird cause usually this works fine but this time it keeps buging with a null pointer exception
if someone could tell me what is wrong with this or tell me an alternative method to do this
FacesContext facesContext = FacesContext.getCurrentInstance();
SuperSaver neededBean = (SuperSaver)FacesContext.getApplication().getVariableResolver().resolveVariable(facesContext, "backing");
CoreOutputText var=this.getGetter();
//this is just a test line
System.out.println(var.getValue().toString());
try{
neededBean.setpersonid(var.getValue().toString());
catch(Exception e){
System.out.println("this does not work");
return "success";
Message was edited by:
staind_art

then i am a bit confused i have been spending the last 2 days trying to solve an issue i have this is my first real jsf application using ADF BC and i dont get a couple of little details maybe you clear my mind.
1--> I start with a simple employee creation form. (one table)
2--> then i have to assign them a country -- a location -- and a department (all different views)
that part is fine i use the navigation list but from then and on it gets harder
cause on the same form i dont understand how to make dependant drop down menu available inside this second form i thought of doing it into 2 pages
3-->thirdly i have to save the id from the first pages which is a DBSequence(that is fine) but i have to push it inside the form for the employee assignment THAT really confuses me
if you could have any advices on how i should or could proceed or if my method should change or whatever comment you have i would greatly appreciate it and my BOSS even more :0)
thx Art

Has anyone been able to create a Mavericks clean install flash drive?

like David Pogue explains in his book OSX Mavericks The Missing Manual on age 792. He tells how to create a Homemade Installer of Mavericks so one could wipe their hard drive and install a clean copy of Mavericks. I've followed the instructions religiously and have yet to end up with a usable startup flash drive. Though I name the flash drive something recognizable, when it finishes copying the Install OS X Mavericks from my applications folder it has the name OS X Install ESD rather than the name I assigned "Cruzer_Mavericks_Startup" which confuses the system. Inside is a folder labeled "Packages." This flash drive will not startup my iMac. Help if you can.

S&G wrote:
Eric Root's posting answered my question. He said to downlaod DiskmakerX. It worked like a charm to create a bootable Mavericks Installer Flash Drive.
tips on use: https://discussions.apple.com/message/18705466

Wired to wireless help needed please.

Hey all,
I got a small network of 2pcs and a network printer using a wired linksys router. All works great. But I now want to change the wired router out for a wirless one, so we can use some laptops in the office too.
My question is, if I replace the wired router with the wireless one, am Im going to have to reconfigure it all for the new router? Is there a simple way to keep the settings in the wired router and transfer it over to the wireless one?
Im not so good at networking and setting up the wired network wasnt as easy as I thought it was when I 1st did that. It took a couple days and lots of phone calls to get it up and running the way we need it.
The wired network now allows all of us to surf the web, print to the netowork printer and transfer files to each other. And thats what I want to be able to do once I get a wireless router too. But I would hate to get it and it be a nightmare to configure.
Keep in mind, I can setup a wireless router, but when it comes to multi PCs and a network printer, I get a little confusied. Is thats assigning IPs that confuse me.
Any suggestions for a n00b?
Thanks all!

Thank you both for you help. I think Im going to keep the existing hardwired router in place and just all another wireless to it. That sounds easier for a n00b like me.
However, I did want to learn more about the wireless access point thing compaired to a wireless router.
Whats the big difference between the two? I assume the access point is much easier to get up and running?
Thanks again to you both! It helps!
Message Edited by ramman949 on 04-26-200701:52 PM

Lenticular Printing

I need to understand how to calculate how many lenticular images I need to interlace if my printer resolution has 9600 x 2400 dpi and the lens has 200 lenses per inch? I think that I am doing a mistake using the manufacturers dpi resolution and that I should be using PPI instead?

Do not confuse DPI (Dot per Inch) with PPI (Pixel per Inch). The first is the number of ink dots and it is used to product a higher gamut, the number of colors that can be produced by the printer in a single pixel.
PPI is the actual native resolution and you should use this value instead.
The native resolution of a printer is an information not easy to gather.
Based on my current experience:
All Canon printers (home or professional) have a native resolution of 600PPI.
All Epson printers (home or professional) have a native resolution of 720PPI and they are used by many "3D photographers beause they can give you a 20% bit more depth.
All HP printers (home or professional) have a native resolution of 600PPI even if they state it is 1200PPI.
These information come from experiments that I made myself and and confirmed by technicians at latest Drupa fair.
I doubt you can go other 720PPI printing on paper, even if you use high quality paper.
There are printers that can produce higher resolution printing on plastic.
Another thing... Keep in mind that when you buy lenticular lenses they are never 40LPI, 60LPI etc.: they can be 40.040LPI or 59.095LPI and this little deviation makes a big difference in the final print. You need to figure out the exact value yourself (called mechanical pitch test) and use a software that keeps this exact value into account when generate the interlaced image.
Hope this helps :-)
Giovanni
www.framedlives.com/3d.html

Exponential Base Solver

Alright, with much fretting I decided to sign up on here to ask some questions. I thought I could do this project on my own, but it seems that I cannot.
Okay, this is the assignment (it is confusing, but then again my professor is not the best at english - as he continues to mention):
Write a program that computes the nth root of a number. Given a real number X greater than 1 and less than -1 and given an integer Y, computer the nth root Z such that Z*Z*Z*Z*Z*Z*Z..(Y times)..Z*Z = X, or Z^Y = X (Remember if X is negative Y must be odd.) The user enters values for X and Y and the porgram calculates Z. Compute Z so that when Z is multiplied Y times it will produce an X which is + or - 0.0000001 of the original value of X. You may only use simple arithmetic to do these computations. That is you may only use multiplication, division, addition, and subtraction.
We are using a class called SavitchIn (which I'm sure some of you are familiar with) for input/output. We are not allowed to use any of the classes in Java that allow for higher math functions. Somehow the prof. wants us to basically create a binary search algorithm, yet we haven't even went over them in the book yet. This project was given out at the point where were learning loops - so that's about as complex as the program can get I suppose (although I've noticed some of the more experienced programmers in our class are using arrays - which isn't what the professor described, yet he's marking them off as finished :-/ ). This is a beginner's programming class mind you, but I think the professor expects us to have had experience with programming. :-/ I've made 7 programs up to this point and have had little trouble.
I ask for tips and maybe some example code, but that is all. I'd like to be able to figure it out on my own (I'm a newbie mind you). :-) And remember, only simple math and SavitchIn may be used.
So here's my base code. It isn't the greatest code in the world, or close to being finished - let alone correct, lol. And some of the variable types I put in the code I haven't actually used yet (most of the stuff in this code will probably have to go). I hope the code isn't too confusing:
public class BinarySearchTest2
     public static void main(String[] args)
          System.out.println("This program will calculate the base when the user gives the input of an answer and an exponent for the base");
          System.out.println( );
          double base, exp, ans = 0, testAns = 0, lBase = 1, mid, uBase, count;
          char answer;
          System.out.print("Please enter a number to be used as an exponent.\nExponent: ");
          exp = SavitchIn.readLineDouble( );
          System.out.println( );
          System.out.print("Please enter a number to be used as an answer.\nAnswer: ");
          ans = SavitchIn.readLineDouble( );
          System.out.println( );
          if ((ans > 1) || (ans < -1) && (exp > 0))
               if (exp == 1)
                    System.out.println("The base is: " + ans);
               base = ans/2;
               for (count = 0; count <= exp - 2; count++)
                    if (exp > 1)
                         testAns = base * base;
               if (testAns == ans)
                    System.out.println ("The base is: " + base);
}

I think you may possibly be deficient in Math rather than programming. Do you know what the Nth root of a number is?
What you need to do is make an algo that will multiply itself N times and give you a target number, or I believe you said to devide a target number by another N times and success is measured by an acceptable error value (small difference between the result and the number being used as a divisor)
The problem can be worked very well by using looping stuctures, that is why it has been assigned as such. The people that are using array are probably making lookup tables where say for a value of 2 you would have....
2 4 8 16 32 64 128 256
so when you want say the 5th root of 32, you go to the 5th colum and search down until you find 32. Once you find it, then you know you have the 5th root in column 1 of the row you are searching. If you have to find roots numbers that are not perfect powers raised to N, then you have to find a bound (and I suspect that is what the arrays are about if you have to find roots of any numbers). Using the lookup method described you can get a boundary for you upper and lower values (my number is between say 16 and 81 and I need the 4th root of it. You will be bounded by 2 and 3 so then you make you estimations say 2.5, and lets say 50 is my number. You try 2.5^4 and get 39.0625 too low so you increast at half the distance between 2.5 and your upper bound of 3, and come up with 2.75 and so on.
If this doesn't get you started, then you need to find a different line of work, or read the book, or talk with your prof, or ...

Raptor (07.15) almost had compilation warnings

The version 07.15 of the Raptor had a feature that would be useful: PL/SQL
compilation warnings. However it had two problems: 1: the warnings were
actually
errors, which alone made the tool unusable, 2: some messages were generated
without any cause.
This can be seen in the following:
INSERT INTO priceloki(t) VALUES (loki_seq.NEXTVAL,
'Virhe : ' || module || '
hi_hinnoittelu_pac.hae_hinnastovoimassa_pvm Sqlerr: ' || err_num || ' Errmsg: '
|| err_msg
Error(68,107): PLW-07202: bind type would result in
conversion away from column type
It seems that using expression in assigning to t confuses the compiler, since
simple variable assignments work correctly.
In the version 07.96 all traces of the "modern" warning feature are away,
probably because of field feedback.

yep. I have warnings in user_errors after compilation.
It would be better to catch warnings somewhere (into separate output window?) or let user specify compilation level settings...
select * from user_errors;
NAME TYPE SEQUENCE LINE POSITION TEXT ATTRIBUTE MESSAGE_NUMBER
ILOAD_PREPARE_FINISH_CM_PRO PROCEDURE 1 3 5 PLW-07203: parametr 'P_RET_CODE_VC' můe vyuívat nápovědu kompilátoru NOCOPY WARNING 7203
ILOAD_PREPARE_FINISH_CM_PRO PROCEDURE 2 4 5 PLW-07203: parametr 'P_RET_TEXT_VC' můe vyuívat nápovědu kompilátoru NOCOPY WARNING 7203

Photo resolution help

How can I find out what the resolution of scanned photos are? I looked in properties and that sort of thing, but I want a DPI number (I have to submit a photo for an essay contest, and they want at least a resolution of 300 DPI). Is 300 DPI particularly good quality? How can I ensure that the things I scan are good enough?
Thanks!

First off, it's PPI not DPI. [DPI is just a meaningless printer spec.]
A scanned image would typically not have a PPI value assigned - although a particular scanner might assign it's sampling resolution. What setting was the scanner on?
You could email me an image check if you like - colin_walls AT yahoo DOT com

Very confused about ppi, resolution, and image size...

I have read so much on these things and even posted along these lines here and there, but remain totally confused.
Say the size of my pictures is around 2000 x 3000. Once I download them to PSE, the resolution is 72ppi. Is this default and could I/should I change this?
I generally do four things with my pictures.
First I edit them.
Next I email to family members.
Then I order prints (99% are 5x7 or smaller)
Finally I store them (on computer with CD backup).
Now, space is a bigger concern than quality since I print small prints generally. So what would be my best options for saving my files, but getting very nice prints?
Right now, once I edit, I save my files in .jpg, baseline "optimized" at 72ppi. Only following the computer defaults though, not because I think this is best. Would I be better off saving in TIFF or is this not necessary?
Any links with further info would be appreciated also.
Thank you,
Amy

Amy,
1. I just took a picture today, and when I look in Image>resize>image size the dimensions are as follows:
W=2288px H=1712px W=31.778" H=23.778" @72px/in. resolution
When I change resolution to 325 px/in., W=7.04" H=5.268"
As the resolution is increased, the dimensions decrease. This is what is called an inverse relation.
Why did I change to 325px/in? Because for printing it is desirable to have a resolution of 240-300 px/in, or so. Also, note that this resolution gives me almost a perfect 5x7 size format, and one can crop off the excess readily. If one desires 4x6 size, one can crop to that dimension.
2. I enhance the pictures next, leaving sharpening for the last step
3. I save primarily in PSD and/or JPEG. Both PSD and TIFF allow one to retain layers, are lossless, and thus one avoids degradation with sequential editing. JPEG is is a compression format which conserves disk space (in comparison to PSD and TIFF), and is most likely required for your e-mail and your photo finisher. I save some of the JPEG files. I usually elect baseline optimized, and the JPEG allows me to elect quality 8, which is good for my purpose and results in a manageable file size.
4. Right after I download my picture files from the camera, I burn them to a CD (i.e. before I do anything else), and right after I finish the final edits I burn them to CD as well. This is my "film", if you will. If the computer fails or if I should accidentally delete a file from disk, I still have it available.
I am sure that others will post, but that is my current work flow.
Ken

PPI Confusion

Hi there. I'm still fairly new to all of this and trying to navigate my around the digital world. I'm using LR 2 on a Mac and PS CS 4, as well. Due to an earlier bug with an old version of Capture One I had been exporting my RAW files as 16-bit Tiffs and then finishing up my edits on those files before making a final Jpg. But those Tiff files are huge and so I started playing around with exporting a dupe RAW file to work on in Photoshop. What I don't understand, though, is that the default ppi setting is 240. Does that matter? If I want the option of creating larger prints, I'd like to go with at least 300 as my ppi setting. Can I just change that in PS and then save it out with my other changes in PS as a Jpg, or am I interpolating the pixels in this case and therefor, harming the file? Love to get an answere here. Many thanks.

While it is possible to change the PPI setting to whatever you want it to be, it really isn't going to change the actual physical dimensions of your image. If you change the PPI setting to 300 in Photoshop, then look at the image size, Photoshop will simply report how big the image will print at that setting. Changing the PPI setting does not alter the image at all. It is simply an indicator of how big the image will be at that setting.
As an example, if I take a "typical" 6 MP image at 240 PPI, Photoshop will report the image size as roughly 8x12 inches (give or take a little). If I change the setting to 300 PPI, that same image will print at roughly 10x7 if I don't resample the image. You can resample the image and let Photoshop physically make the image larger, but it won't necessarily make the image better in quality because Photoshop is creating pixels that were not part of the original image.
Bottom line, if you want high quality larger images, you need a camera that will take images with more megapixels.

PPI/ LPI assignment.. I'm confused.

Similar Messages

Maybe you are looking for