Printing a 2d array in matrix format

Question

Hi everyone- first time posting here... I'm an undergrad CS major at the Colorado School of Mines. I'm trying to write a metho that will print out a 2D array (3x3) in matrix form. Here is what I have:
public static void printArray(int[][]array3){
for (int i=0; i<array3.length; i++)
for (int j = 0; j<array3[0].length; j++) {
int count=0;
if (count % 3 ==0){
System.out.println(array3[i][j] + " ");
count++;
else{
System.out.print(array3[i][j] + " ");
count++;
All it does is list the elements of the array as follows.
Sample:
1, 2, 3 input array
prints:
1
2
3
Any help would be appreciated.

Answer 1

1 public static void printArray(int[][]array3){
2       for (int i=0; i<array3.length; i++)
3         for (int j = 0; j<array3[0].length; j++) {
4           int count=0;
5           if (count % 3 ==0){
6             System.out.println(array3[i][j] + " ");
7             count++;
8           }
9           else{
10             System.out.print(array3[i][j] + " ");
11             count++;
12           }
13         }
14     }Lets just run through it, step by step
-1
   i = Out of scope
   j = out of scope
   count = out of scope
-2
   i = 0
   j = out of scope
   count = out of scope
-3
   i = 0
   j = 0
   count = out of scope
-4
   i = 0
   j = 0
   count = 0
-5
   i = 0
   j = 0
   count = 0
   (count % 3 ) = 0
-6
   i = 0
   j = 0
   count = 0
   print 1<new line>
-7
   i = 0
   j = 0
   count = 1
-8
   i = 0
   j = 0
   count = 1
-13
   i = 0
   j = 0
   count = out of scope
-3
   i = 0
   j = 1
   count = out of scope
-4
   i = 0
   j = 1
   count = 0Hint: You don't need count, you have a counter (i*3)+j, and even a counter than just goes between 0 to 2.